Solve Scale Drawing Problems

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7th Grade Math › Solve Scale Drawing Problems

Questions 1 - 10
1

A map uses a scale of $1:50{,}000$ (so $1\text{ cm}$ on the map represents $50{,}000\text{ cm}$ in real life). Two towns are $4\text{ cm}$ apart on the map. What is the actual distance between the towns in kilometers?

$20\text{ km}$

$200\text{ km}$

$0.08\text{ km}$

$2\text{ km}$

Explanation

This question tests scale drawing problems: finding actual lengths/areas from scaled drawings (multiply by scale, use scale² for areas) and reproducing drawings at different scales. Scale 1:50,000 means 1 cm on the drawing equals 50,000 cm actual (multiply drawing by 50,000 for actual, divide actual by 50,000 for drawing). Example: map scale 1:50,000, 4 cm on map represents 4×50,000=200,000 cm=2 km actual (multiply drawing by scale factor). Areas scale by factor²: drawing 2 cm × 3 cm = 6 cm² at 1:100 scale represents actual 200 cm × 300 cm = 60,000 cm² (or 6×100²=60,000), factor squared because area is length×width both scaled. Reproducing: original 6 cm at 1:50 (actual: 6×50=300 cm), new scale 1:25 (new drawing: 300÷25=12 cm—half the scale factor means twice the drawing size). In this case, the map distance is 4 cm at 1:50,000, computing actual 200,000 cm=2 km (since 200,000 cm ÷ 100,000 cm/km = 2 km). The correct calculation is multiplying the drawing length by the scale factor and converting units properly.

2

A city map uses a scale of $1:50{,}000$ (so 1 cm on the map represents 50,000 cm in real life). Two landmarks are 4 cm apart on the map. What is the actual distance between the landmarks in kilometers?

$20$ km

$0.08$ km

$200$ km

$2$ km

Explanation

This problem tests scale drawing problems by finding the actual length from a scaled map, where you multiply the map distance by the scale factor to get the real distance. A scale of 1:n means 1 unit on the drawing equals n units in actual, so multiply drawing by n for actual, or divide actual by n for drawing. For this map scale of 1:50,000, 4 cm on the map represents 4 × 50,000 = 200,000 cm actual. To convert, 200,000 cm = 2,000 m = 2 km, since there are 100 cm in a meter and 1,000 m in a km. A common error is dividing instead of multiplying, like 4 ÷ 50,000 = 0.00008, claiming that's the actual in km. Steps: (1) identify scale 1:50,000 and drawing 4 cm, (2) determine direction (drawing to actual: multiply), (3) calculate 4 × 50,000 = 200,000 cm, (4) convert to km (200,000 / 100,000 = 2 km). Common mistakes include wrong direction (dividing for actual), inconsistent units (not converting cm to km), or misinterpreting scale backwards.

3

A classroom floor plan uses a scale of 1 inch : 5 feet. A wall is 15 feet long in real life. How long should that wall be on the floor plan (in inches)?

75 inches

10 inches

3 inches

0.3 inches

Explanation

This problem tests scale drawing problems by finding the drawing length from an actual measurement, where you divide the actual by the scale factor to get the drawing size. A scale of 1:n means 1 unit on the drawing equals n units in actual, so multiply drawing by n for actual, or divide actual by n for drawing. For this floor plan scale of 1 inch:5 feet, a 15-foot wall on the plan is 15 ÷ 5 = 3 inches. This correct scaling calculation ensures the plan accurately represents the real dimensions in reduced form. A common error is multiplying instead of dividing, like 15 × 5 = 75 inches, which would be too large for the plan. Steps: (1) identify scale 1:5 (inches to feet) and actual 15 feet, (2) determine direction (actual to drawing: divide), (3) calculate 15 ÷ 5 = 3 inches. Common mistakes include wrong direction (multiplying for drawing size), units inconsistent (mixing feet and inches without conversion), or scale ratio interpreted backwards.

4

A model car is built at a scale of $1:25$ (so $1\text{ cm}$ on the model represents $25\text{ cm}$ in real life). The model car is $18\text{ cm}$ long. What is the car's actual length in meters?

$7.2\text{ m}$

$0.72\text{ m}$

$4.5\text{ m}$

$45\text{ m}$

Explanation

This question tests scale drawing problems: finding actual lengths/areas from scaled drawings (multiply by scale, use scale² for areas) and reproducing drawings at different scales. Scale 1:25 means 1 cm on the model equals 25 cm actual (multiply model by 25 for actual, divide actual by 25 for model). Example: model scale 1:25, 18 cm on model represents 18×25=450 cm=4.5 m actual (multiply model by scale factor). Areas scale by factor²: drawing 2 cm × 3 cm = 6 cm² at 1:100 scale represents actual 200 cm × 300 cm = 60,000 cm² (or 6×100²=60,000), factor squared because area is length×width both scaled. Reproducing: original 6 cm at 1:50 (actual: 6×50=300 cm), new scale 1:25 (new drawing: 300÷25=12 cm—half the scale factor means twice the drawing size). In this case, model length 18 cm at 1:25, computing actual 450 cm=4.5 m (450÷100=4.5). The correct calculation is multiplying by the scale and converting cm to m properly.

5

On a map, $1\text{ inch}$ represents $4\text{ miles}$. Two landmarks are $3.5\text{ inches}$ apart on the map. What is the actual distance between the landmarks (in miles)?

$28\text{ miles}$

$7.5\text{ miles}$

$14\text{ miles}$

$0.875\text{ miles}$

Explanation

This question tests scale drawing problems: finding actual lengths/areas from scaled drawings (multiply by scale, use scale² for areas) and reproducing drawings at different scales. Scale 1 inch:4 miles means 1 inch on map = 4 miles actual (multiply map by 4 for actual, divide actual by 4 for map). Example: map scale 1 inch:4 miles, 3.5 inches on map represents 3.5×4=14 miles actual (multiply map by scale factor). Areas scale by factor²: drawing 2 cm × 3 cm = 6 cm² at 1:100 scale represents actual 200 cm × 300 cm = 60,000 cm² (or 6×100²=60,000), factor squared because area is length×width both scaled. Reproducing: original 6 cm at 1:50 (actual: 6×50=300 cm), new scale 1:25 (new drawing: 300÷25=12 cm—half the scale factor means twice the drawing size). In this case, map distance 3.5 inches at 1:4, computing actual 3.5×4=14 miles. The correct calculation is multiplying the map distance by the scale factor without unit conversion issues.

6

A rectangular playground is shown on a plan as 4 cm by 5 cm. The scale is $1:200$ (1 cm represents 200 cm). What is the actual area of the playground in square meters?

$8\text{ m}^2$

$800\text{ m}^2$

$0.8\text{ m}^2$

$80\text{ m}^2$

Explanation

This problem tests scale drawing problems by finding actual area from a plan, using scale squared for areas. A scale of 1:n means 1 unit on the drawing equals n units in actual, so multiply drawing by n for lengths, and by n² for areas. For this playground 4 cm × 5 cm at 1:200, actual 800 cm × 1,000 cm, area 800,000 cm² = 80 m² (divide by 10,000). This correct scaling uses area factor 200² = 40,000, so 20 cm² × 40,000 = 800,000 cm² = 80 m². A common error is linear scale for area, like 20 × 200 = 4,000 cm². Steps: (1) identify scale 1:200 and drawing area 20 cm², (2) use scale² = 40,000, (3) calculate 20 × 40,000 = 800,000 cm², (4) convert to m² (800,000 / 10,000 = 80). Common mistakes include forgetting to square, wrong units, or misdirection.

7

A blueprint uses a scale of $1\text{ inch}:8\text{ feet}$. On the blueprint, a rectangular room is $2.5\text{ inches}$ by $1.5\text{ inches}$. What is the actual area of the room in square feet?

$30\text{ ft}^2$

$240\text{ ft}^2$

$32\text{ ft}^2$

$120\text{ ft}^2$

Explanation

This question tests scale drawing problems: finding actual lengths/areas from scaled drawings (multiply by scale, use scale² for areas) and reproducing drawings at different scales. Scale 1:8 (inches to feet) means 1 inch on the blueprint equals 8 feet actual (multiply blueprint by 8 for actual, divide actual by 8 for blueprint). Example: map scale 1:50,000, 4 cm on map represents 4×50,000=200,000 cm=2 km actual (multiply drawing by scale factor). Areas scale by factor²: blueprint 2.5 in × 1.5 in = 3.75 in² at 1:8 scale represents actual 20 ft × 12 ft = 240 ft² (or 3.75×8²=3.75×64=240), factor squared because area is length×width both scaled. Reproducing: original 6 cm at 1:50 (actual: 6×50=300 cm), new scale 1:25 (new drawing: 300÷25=12 cm—half the scale factor means twice the drawing size). In this case, blueprint area 3.75 in² at 1:8, computing actual 3.75×64=240 ft² using scale² factor. A common error is using linear scale for areas (3.75×8=30 not 3.75×64=240), or miscalculating dimensions (like 2.5×8=20, 1.5×8=12, but forgetting to multiply).

8

A hiking trail is shown on a map with scale $1:50{,}000$. The trail measures $6\text{ cm}$ on the map. What is the actual length of the trail in kilometers?

$3\text{ km}$

$300\text{ km}$

$30\text{ km}$

$0.12\text{ km}$

Explanation

This problem tests scale drawing problems: finding actual lengths/areas from scaled drawings (multiply by scale, use scale² for areas) and reproducing drawings at different scales. Scale 1:n means 1 unit drawing = n units actual (multiply drawing by n for actual, divide actual by n for drawing). Example: map scale 1:50,000, 4 cm on map represents 4×50,000=200,000 cm=2 km actual (multiply drawing by scale factor). Areas scale by factor²: drawing 2 cm × 3 cm = 6 cm² at 1:100 scale represents actual 200 cm × 300 cm = 60,000 cm² (or 6×100²=60,000), factor squared because area is length×width both scaled. Reproducing: original 6 cm at 1:50 (actual: 6×50=300 cm), new scale 1:25 (new drawing: 300÷25=12 cm—half the scale factor means twice the drawing size). For this question, with a hiking trail map scale 1:50,000 and trail measuring 6 cm, the actual length is 6 × 50,000 = 300,000 cm, which converts to 3 km (300,000 cm = 3,000 m = 3 km). Common mistakes include not converting units properly, like stopping at 300,000 cm or dividing instead of multiplying.

9

A model car is built at a scale of $1:25$ (1 cm on the model represents 25 cm on the real car). The model is 18 cm long. How long is the real car in meters?

$4.5$ m

$45$ m

$0.72$ m

$450$ m

Explanation

This problem tests scale drawing problems by finding the actual length from a model, where you multiply the model length by the scale factor. A scale of 1:n means 1 unit on the drawing equals n units in actual, so multiply drawing by n for actual, or divide actual by n for drawing. For this model car at 1:25, 18 cm model means actual 18 × 25 = 450 cm = 4.5 m (divide by 100 cm per m). This correct scaling calculation converts units appropriately after multiplication. A common error is dividing instead, like 18 ÷ 25 = 0.72 m, reversing the direction. Steps: (1) identify scale 1:25 and model 18 cm, (2) determine direction (model to actual: multiply), (3) calculate 18 × 25 = 450 cm, (4) convert to m (450 / 100 = 4.5). Common mistakes include wrong direction (dividing for actual), not converting units (leaving as 450 cm), or interpreting scale backwards.

10

A park map uses a scale of 1 inch : 200 feet. A walking path is 1.5 inches long on the map. What is the actual length of the path in feet?

133 ft

75 ft

3,000 ft

300 ft

Explanation

This problem tests scale drawing problems by finding the actual length from a map, where you multiply the map length by the scale factor. A scale of 1:n means 1 unit on the drawing equals n units in actual, so multiply drawing by n for actual, or divide actual by n for drawing. For this park map at 1 inch:200 feet, 1.5 inches means actual 1.5 × 200 = 300 feet. This correct scaling calculation directly applies the factor to the given units. A common error is wrong multiplication, like 1.5 ÷ 200 = 0.0075, or misapplying units. Steps: (1) identify scale 1:200 (inches to feet) and map 1.5 inches, (2) determine direction (map to actual: multiply), (3) calculate 1.5 × 200 = 300 feet. Common mistakes include dividing instead of multiplying, inconsistent units, or scale ratio backwards.