Find Volume With Fractional Edge Lengths

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6th Grade Math › Find Volume With Fractional Edge Lengths

Questions 1 - 10
1

A rectangular prism has a base area of $12\tfrac{1}{2}\text{ cm}^2$ and a height of $\tfrac{4}{5}\text{ cm}$. What is the volume of the prism in cubic centimeters? (Use $V=bh$.)

$10\text{ cm}^2$

$13.3\text{ cm}^3$

$16\text{ cm}^3$

$10\text{ cm}^3$

Explanation

This question tests calculating the volume of rectangular prisms with fractional edge lengths using V=bh, base area times height, and understanding that packing with fractional unit cubes gives the same result. Base 12 1/2 cm²=25/2 cm², height 4/5 cm, V=(25/2)×(4/5)=(25×4)/(2×5)=100/10=10 cm³. If dimensions were known, V=lwh would match. Packing: suppose base fits certain cubes, but formula directly gives 10 cm³. Units cm³. Mistake like adding 12.5 + 0.8=13.3, or multiplying wrongly to 16. Calculate: (25/2)×(4/5)=10 cm³.

2

A rectangular prism has dimensions $\tfrac{3}{4}\text{ ft} \times 2\text{ ft} \times 1\tfrac{1}{2}\text{ ft}$. What is its volume in cubic feet?

$\tfrac{9}{8}\text{ ft}^3$

$\tfrac{9}{4}\text{ ft}^3$

$\tfrac{9}{4}\text{ ft}$

$\tfrac{17}{4}\text{ ft}^3$

Explanation

This question tests calculating the volume of rectangular prisms with fractional edge lengths using V=lwh, where you multiply the three edges, and understanding that packing with fractional unit cubes yields the same result. Dimensions: 3/4 ft × 2 ft × 1 1/2 ft (convert to 3/2 ft), so V=(3/4)×2×(3/2)=(3/4)×(3/2)×2=(9/8)×2=18/8=9/4 ft³. Or base (3/4)×2=3/2 ft², times height 3/2 ft = (3/2)×(3/2)=9/4 ft³. Packing with 1/4 ft cubes: along 3/4 fits 3, 2 fits 8, 3/2 fits 6, total 3×8×6=144 cubes each (1/4)³=1/64 ft³, 144×1/64=144/64=9/4 ft³. Units ft³. Error like adding fractions wrongly to 3/4 + 2 + 3/2 = 17/4. Steps: convert mixed to improper; multiply (3/4)×2×(3/2)=9/4.

3

A rectangular prism is filled by packing $\tfrac{1}{2}\text{ ft} \times \tfrac{1}{2}\text{ ft} \times \tfrac{1}{2}\text{ ft}$ unit cubes. The prism’s dimensions are $2\text{ ft} \times 1\text{ ft} \times \tfrac{1}{2}\text{ ft}$. How many of these $\tfrac{1}{2}$-foot cubes fit exactly in the prism?

2

4

6

8

Explanation

This question tests calculating the volume of rectangular prisms with fractional edge lengths using V=lwh (multiply three edges) or V=bh (base area times height), understanding packing with fractional unit cubes gives same result. Volume V=lwh: multiply length, width, height (2 ft × 3 ft × (1/2) ft = 2×3×0.5=3 ft³, fractional edges multiply like any numbers). Or V=bh: base area l×w times height (base 5×4=20 m², height 2.5 m, volume 20×2.5=50 m³). Packing: fill prism with unit cubes (if edge 1/2 ft, unit cube is (1/2)³=1/8 ft³, box 2×1×(1/2) holds 2÷(1/2)×1÷(1/2)×(1/2)÷(1/2)=4×2×1=8 cubes of 1/8 ft³ each, total 8×(1/8)=1 ft³—same as V=lwh). Units: cubic (ft³, cm³, in³—length unit cubed). For this prism, number of cubes: (2/(1/2)) × (1/(1/2)) × ((1/2)/(1/2)) = 4×2×1=8. Common errors include multiplying dimensions instead of dividing or miscounting fits.

4

A rectangular prism is $1\text{ ft}$ long, $\tfrac{1}{2}\text{ ft}$ wide, and $\tfrac{1}{2}\text{ ft}$ tall. If you pack it completely with cubes that each have edge length $\tfrac{1}{2}\text{ ft}$, how many such cubes fit inside?

1

2

4

8

Explanation

To calculate the volume of a rectangular prism with fractional edge lengths, use the formula V = l × w × h, where you multiply the three dimensions, or V = base area × height, and understand that packing the prism with fractional unit cubes yields the same result. For example, with dimensions 2 ft × 3 ft × (1/2) ft, V = 2 × 3 × 0.5 = 3 ft³; alternatively, using base area, if the base is 5 m × 4 m = 20 m² and height 2.5 m, then V = 20 × 2.5 = 50 m³; packing with 1/2 ft cubes in a 2 × 3 × (1/2) prism holds 4 × 6 × 1 = 24 cubes, each 1/8 ft³, totaling 3 ft³, with units always in cubic form like ft³ though here it's count. Another example: a prism 2 ft × 3 ft × (1/2) ft has V = 2 × 3 × (1/2) = 3 ft³; or 2.5 cm × 4 cm × 3 cm: V = 30 cm³; or base 6 × 5 = 30 cm², height 2.5 cm, V = 75 cm³. For this prism 1 ft × (1/2) ft × (1/2) ft packed with (1/2) ft cubes, along length 1/(1/2)=2, width (1/2)/(1/2)=1, height (1/2)/(1/2)=1, so 2 × 1 × 1 = 2 cubes. Common errors include thinking volume is 1 × 0.5 × 0.5 = 0.25 then dividing wrong to 1 or 8, confusing with cube volume $(1/2)^3$=1/8 then miscounting to 4, adding, or ignoring packing. To calculate packing, divide each dimension by cube edge: 1/(0.5)=2, etc., multiply counts 2×1×1=2; relates to V / cube volume = (0.25) / (0.125) = 2. Packing verifies formula; real for storage; avoid misdividing, confusing volume with count, adding, wrong units.

5

A small science container is shaped like a rectangular prism measuring $2.5\text{ cm} \times 4\text{ cm} \times 3\text{ cm}$. What is its volume?

$30\text{ cm}^3$

$9.5\text{ cm}^3$

$30\text{ cm}^2$

$100\text{ cm}^3$

Explanation

To calculate the volume of a rectangular prism with fractional edge lengths, use the formula V = l × w × h, where you multiply the three dimensions, or V = base area × height, and understand that packing the prism with fractional unit cubes yields the same result. For example, with dimensions 2 ft × 3 ft × (1/2) ft, V = 2 × 3 × 0.5 = 3 ft³; alternatively, using base area, if the base is 5 m × 4 m = 20 m² and height 2.5 m, then V = 20 × 2.5 = 50 m³; packing with 1/2 ft cubes in a 2 × 3 × (1/2) prism holds 4 × 6 × 1 = 24 cubes, each 1/8 ft³, totaling 3 ft³, with units always in cubic form like cm³. Another example: a prism 2 ft × 3 ft × (1/2) ft has V = 2 × 3 × (1/2) = 3 ft³; or 2.5 cm × 4 cm × 3 cm: V = 2.5 × 4 × 3 = 30 cm³; or base 6 × 5 = 30 cm², height 2.5 cm, V = 30 × 2.5 = 75 cm³. For this science container measuring 2.5 cm × 4 cm × 3 cm, the volume is 2.5 × 4 × 3 = 30 cm³. Common errors include adding dimensions like 2.5 + 4 + 3 = 9.5, forgetting cubic units to get 30 cm², mishandling decimals such as 2.5 × 4 = 100 incorrectly, using V = l + w + h, multiplying only two like 2.5 × 4 = 10 then forgetting 3, or errors like 2.5 × 4 = 1. For calculating, identify dimensions l=2.5, w=4, h=3, multiply as 2.5 × 4 = 10 then 10 × 3 = 30, and use cm³; mixed numbers convert to decimals like 1(1/2)=1.5 for multiplication. Base-height method: find base l × w, multiply by h; packing confirms formula; real uses include storage, aquariums, rooms; avoid adding, wrong units, fraction mishaps, missing dimensions, sum formulas.

6

A storage box is a rectangular prism with dimensions $2\text{ ft} \times 3\text{ ft} \times \tfrac{1}{2}\text{ ft}$. What is its volume in cubic feet? (Use $V=l\times w\times h$.)

$3\text{ ft}^3$

$6\text{ ft}^3$

$3\text{ ft}$

$5.5\text{ ft}^3$

Explanation

To calculate the volume of a rectangular prism with fractional edge lengths, use the formula V = l × w × h, where you multiply the three dimensions, or V = base area × height, and understand that packing the prism with fractional unit cubes yields the same result. For example, with dimensions 2 ft × 3 ft × (1/2) ft, V = 2 × 3 × 0.5 = 3 ft³; alternatively, using base area, if the base is 2 ft × 3 ft = 6 ft² and height 0.5 ft, then V = 6 × 0.5 = 3 ft³; packing with 1/2 ft cubes, the prism holds 4 along length, 6 along width, and 1 along height for 24 cubes, each 1/8 ft³, totaling 3 ft³, with units always in cubic form like ft³. Another example: a prism 2.5 cm × 4 cm × 3 cm has V = 2.5 × 4 × 3 = 30 cm³; or with base 6 cm × 5 cm = 30 cm² and height 2.5 cm, V = 30 × 2.5 = 75 cm³. For this storage box with dimensions 2 ft × 3 ft × (1/2) ft, the volume is 2 × 3 × 0.5 = 3 ft³. Common errors include adding dimensions like 2 + 3 + 0.5 = 5.5, forgetting cubic units to get 3 ft, mishandling fractions such as 2 × 3 ÷ 2 = 3 but sequenced wrong, using V = l + w + h, multiplying only two dimensions like 2 × 3 = 6, or decimal mistakes like treating 0.5 as 5. To calculate, identify the dimensions l=2, w=3, h=0.5, multiply step-by-step as 2 × 3 = 6 then 6 × 0.5 = 3, and add cubic units ft³; for mixed numbers, convert to improper fractions or decimals like 1(1/2) = 3/2 = 1.5 for easier multiplication. Using the base-height method, compute base area l × w then multiply by h; packing verifies the formula by showing the same volume; in real life, this applies to storage boxes for capacity, aquariums for water volume, or rooms for air space; avoid mistakes like adding instead of multiplying, omitting cubic units, fraction errors, forgetting the third dimension, or using sum formulas.

7

A rectangular prism has dimensions $\tfrac{3}{4}\text{ ft} \times 4\text{ ft} \times 2\text{ ft}$. What is the volume of the prism in cubic feet? (Use $V=lwh$.)

$6\text{ ft}^3$

$8\text{ ft}^3$

$\tfrac{13}{4}\text{ ft}^3$

$\tfrac{3}{2}\text{ ft}^3$

Explanation

This question tests calculating the volume of rectangular prisms with fractional edge lengths using V=lwh (multiply three edges) or V=bh (base area times height), understanding packing with fractional unit cubes gives same result. Volume V=lwh: multiply length, width, height (3/4 ft × 4 ft × 2 ft = (3/4)×4×2=6 ft³, fractional edges multiply like any numbers). Or V=bh: base area l×w times height (base 5×4=20 m², height 2.5 m, volume 20×2.5=50 m³). Packing: fill prism with unit cubes (if edge 1/2 ft, unit cube is (1/2)³=1/8 ft³, box 2×3×(1/2) holds 2÷(1/2)×3÷(1/2)×(1/2)÷(1/2)=4×6×1=24 cubes of 1/8 ft³ each, total 24×(1/8)=3 ft³—same as V=lwh). Units: cubic (ft³, cm³, in³—length unit cubed). For this prism, V=(3/4)×4×2=3×2=6 ft³. Common errors include improper fraction multiplication or adding dimensions.

8

A science lab container is a rectangular prism that measures $2.5\text{ cm} \times 4\text{ cm} \times 3\text{ cm}$. What is its volume in cubic centimeters? (Use $V=lwh$.)

$100\text{ cm}^3$

$30\text{ cm}^3$

$30\text{ cm}^2$

$9.5\text{ cm}^3$

Explanation

This question tests calculating the volume of rectangular prisms with fractional edge lengths using V=lwh (multiply three edges) or V=bh (base area times height), understanding packing with fractional unit cubes gives same result. Volume V=lwh: multiply length, width, height (2.5 cm × 4 cm × 3 cm = 2.5×4×3=30 cm³, fractional edges multiply like any numbers). Or V=bh: base area l×w times height (base 5×4=20 m², height 2.5 m, volume 20×2.5=50 m³). Packing: fill prism with unit cubes (if edge 1/2 ft, unit cube is (1/2)³=1/8 ft³, box 2×3×(1/2) holds 2÷(1/2)×3÷(1/2)×(1/2)÷(1/2)=4×6×1=24 cubes of 1/8 ft³ each, total 24×(1/8)=3 ft³—same as V=lwh). Units: cubic (ft³, cm³, in³—length unit cubed). For this container, V=2.5×4×3=10×3=30 cm³. Common errors include multiplying only two dimensions (2.5×4=10) or using square units (30 cm²).

9

A cube-shaped block has edge length $\tfrac{1}{2}\text{ ft}$. What is the volume of this cube in cubic feet? (Use $V=lwh$.)

$\tfrac{1}{8}\text{ ft}^3$

$\tfrac{1}{8}\text{ ft}$

$\tfrac{3}{2}\text{ ft}^3$

$\tfrac{1}{6}\text{ ft}^3$

Explanation

This question tests calculating the volume of rectangular prisms with fractional edge lengths using $V=lwh$ (multiply three edges) or $V=bh$ (base area times height), understanding packing with fractional unit cubes gives same result. Volume $V=lwh$: multiply length, width, height (for a cube, all equal: $(\frac{1}{2} \text{ ft}) \times(\frac{1}{2} \text{ ft}) \times(\frac{1}{2} \text{ ft}) = (\frac{1}{2})^3 = \frac{1}{8} \text{ ft}^3$, fractional edges multiply like any numbers). Or $V=bh$: base area $l\times w$ times height (base $5\times4=20$ m$^2$, height 2.5 m, volume $20\times2.5=50$ m$^3$). Packing: fill prism with unit cubes (if edge $1/2$ ft, unit cube is $(1/2)^3=1/8$ ft$^3$, box $2\times3\times(1/2)$ holds $2\div(1/2)\times3\div(1/2)\times(1/2)\div(1/2)=4\times6\times1=24$ cubes of $1/8$ ft$^3$ each, total $24\times(1/8)=3$ ft$^3$—same as $V=lwh$). Units: cubic (ft$^3$, cm$^3$, in$^3$—length unit cubed). For this cube, $V=(1/2)\times(1/2)\times(1/2)=1/8$ ft$^3$. Common errors include not cubing the fraction or using linear units ($1/8$ ft).

10

A rectangular prism has dimensions $1\tfrac{1}{4}\text{ m} \times 2\text{ m} \times 3\text{ m}$. What is the volume in cubic meters? (Use $V=lwh$.)

$6\text{ m}^3$

$\tfrac{25}{4}\text{ m}^3$

$7.5\text{ m}^3$

$7.25\text{ m}^3$

Explanation

This question tests calculating the volume of rectangular prisms with fractional edge lengths using V=lwh (multiply three edges) or V=bh (base area times height), understanding packing with fractional unit cubes gives same result. Volume V=lwh: multiply length, width, height (1.25 m × 2 m × 3 m = 1.25×2×3=7.5 m³, fractional edges multiply like any numbers). Or V=bh: base area l×w times height (base 5×4=20 m², height 2.5 m, volume 20×2.5=50 m³). Packing: fill prism with unit cubes (if edge 1/2 ft, unit cube is (1/2)³=1/8 ft³, box 2×3×(1/2) holds 2÷(1/2)×3÷(1/2)×(1/2)÷(1/2)=4×6×1=24 cubes of 1/8 ft³ each, total 24×(1/8)=3 ft³—same as V=lwh). Units: cubic (ft³, cm³, in³—length unit cubed). For this prism, convert 1 1/4 to 1.25, then V=1.25×2×3=2.5×3=7.5 m³. Common errors include not converting mixed numbers or using fractions incorrectly (like 25/4=6.25).

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