6th Grade Math Flashcards: Find Area By Composing And Decomposing

Study Find Area By Composing And Decomposing in 6th Grade Math with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

6th Grade Math

Find Area By Composing And Decomposing

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QUESTION
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A floor section is a trapezoid with bases 8 m8\text{ m} and 12 m12\text{ m} and height 5 m5\text{ m}. What area is covered?

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ANSWER

50 m250\text{ m}^2. Trapezoid: 12(8+12)×5=50\frac{1}{2}(8+12) \times 5 = 50.

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Flashcard 1: A floor section is a trapezoid with bases 8 m8\text{ m} and 12 m12\text{ m} and height 5 m5\text{ m}. What area is covered?

Answer: 50 m250\text{ m}^2. Trapezoid: 12(8+12)×5=50\frac{1}{2}(8+12) \times 5 = 50.

Flashcard 2: What is the area of an LL-shape made from a 10×810\times 8 rectangle with a 4×34\times 3 corner removed?

Answer: 68 square units68\text{ square units}. Large rectangle minus removed corner: 8012=6880-12=68.

Flashcard 3: What is the area of a rhombus with diagonals d1=10d_1=10 and d2=6d_2=6 units?

Answer: 30 square units30\text{ square units}. Apply A=12d1d2A=\frac{1}{2}d_1d_2: 12(10)(6)=30\frac{1}{2}(10)(6)=30.

Flashcard 4: What is the area of a right triangle with legs 66 and 88?

Answer: 2424 square units. Right triangle area: 12×6×8=24\frac{1}{2} \times 6 \times 8 = 24.

Flashcard 5: What is the area of a trapezoid with b1=6b_1=6, b2=10b_2=10, and h=5h=5 square units?

Answer: 4040. Apply A=12(6+10)×5=12×16×5A = \frac{1}{2}(6+10) \times 5 = \frac{1}{2} \times 16 \times 5.

Flashcard 6: What is the area of a rectangle with l=11l=11 and w=3w=3 square units?

Answer: 3333. Multiply length by width: 11×3=3311 \times 3 = 33.

Flashcard 7: What is the height hh of a trapezoid with area 4545 and bases b1=5b_1=5, b2=10b_2=10?

Answer: 66. Solve 45=12(5+10)×h45 = \frac{1}{2}(5+10) \times h for hh.

Flashcard 8: State the formula for the area of a triangle using base bb and height hh.

Answer: A=12bhA=\frac{1}{2}bh. Half the base times height gives triangle area.

Flashcard 9: Identify the height to use if a triangle has base 1010 and perpendicular height 77.

Answer: h=7h=7. The perpendicular height is always used in area calculations.

Flashcard 10: What is the height of a parallelogram with area 5656 and base 77?

Answer: 88. Solve 56=7×h56 = 7 \times h for hh.

Flashcard 11: What is the area of a triangle with base 1212 units and height 55 units?

Answer: 30 square units30\text{ square units}. Apply A=12bhA=\frac{1}{2}bh: 12(12)(5)=30\frac{1}{2}(12)(5)=30.

Flashcard 12: Which measurement must be perpendicular to the base when finding area with A=bhA=bh?

Answer: The height (altitude)\text{The height (altitude)}. Height must form a 90°90° angle with the base.

Flashcard 13: What is the base of a triangle with area 3030 and height 66?

Answer: 1010. Solve 30=12×b×630 = \frac{1}{2} \times b \times 6 for bb.

Flashcard 14: What is the area of a composite shape: a 9×69\times 6 rectangle plus a triangle with base 99 and height 44?

Answer: 7272. Rectangle 5454 plus triangle 12×9×4=18\frac{1}{2} \times 9 \times 4 = 18.

Flashcard 15: A triangular sign has base 14 cm14\text{ cm} and height 9 cm9\text{ cm}. What is its area?

Answer: 63 cm263\text{ cm}^2. Apply triangle formula: 12×14×9\frac{1}{2} \times 14 \times 9.

Flashcard 16: What is the area of a rhombus with diagonals 1212 and 55?

Answer: 3030 square units. Apply 12×12×5=30\frac{1}{2} \times 12 \times 5 = 30.

Flashcard 17: What is the area of a composite shape: rectangle 8×58\times 5 plus right triangle with legs 44 and 66?

Answer: 52 square units52\text{ square units}. Rectangle: 8×5=408×5=40; triangle: 12(4)(6)=12\frac{1}{2}(4)(6)=12; total: 5252.

Flashcard 18: What is the area of a square with side length 77 units?

Answer: 49 square units49\text{ square units}. Square area is side squared: 72=497^2=49.

Flashcard 19: Identify the correct base-height pair for A=12bhA=\frac{1}{2}bh in any triangle.

Answer: A base and its perpendicular height. Height must be perpendicular to the chosen base.

Flashcard 20: Find the missing height hh of a parallelogram with area 4545 and base 99.

Answer: 55. Solve 45=9h45 = 9h to find height.

Flashcard 21: What is the area of a trapezoid with bases 66 and 1010 and height 55?

Answer: 4040 square units. Average bases (6+10)/2=8(6+10)/2 = 8, times height 55.

Flashcard 22: What is the area of a polygon split into two triangles with areas 1818 and 2525 square units?

Answer: 43 square units43\text{ square units}. Add the areas of component shapes: 18+25=4318+25=43.

Flashcard 23: What is the area of a right triangle with legs 66 and 88 units?

Answer: 24 square units24\text{ square units}. Use A=12bhA=\frac{1}{2}bh with legs as base and height: 12(6)(8)=24\frac{1}{2}(6)(8)=24.

Flashcard 24: What is the area of an L-shape formed from a 10×810\times 8 rectangle with a 4×34\times 3 rectangle removed?

Answer: 6868. Large rectangle 8080 minus small rectangle 1212.

Flashcard 25: State the formula for the area of a kite or rhombus using diagonals d1d_1 and d2d_2.

Answer: A=12d1d2A=\frac{1}{2}d_1d_2. Half the product of the two diagonals.

Flashcard 26: State the area formula for a triangle using base bb and height hh.

Answer: A=12bhA=\frac{1}{2}bh. Area equals half the product of base and height.

Flashcard 27: What is the area of a right triangle with legs 66 and 88 square units?

Answer: 2424. Right triangle area is 12×6×8=24\frac{1}{2} \times 6 \times 8 = 24.

Flashcard 28: What is the area of a trapezoid with b1=6b_1=6, b2=10b_2=10, and h=5h=5?

Answer: 40 square units40\text{ square units}. Apply formula: 12(6+10)(5)=12(16)(5)=40\frac{1}{2}(6+10)(5)=\frac{1}{2}(16)(5)=40.

Flashcard 29: A triangular sign has base 14 in14\text{ in} and height 9 in9\text{ in}. What is its area?

Answer: 63 in263\text{ in}^2. Apply A=12bhA=\frac{1}{2}bh: 12(14)(9)=63\frac{1}{2}(14)(9)=63 square inches.

Flashcard 30: What is the area of an L-shape formed by a 10×610\times 6 rectangle with a 4×34\times 3 rectangle removed?

Answer: 4848 square units. Large rectangle (60)(60) minus small rectangle (12)(12).

Flashcard 31: What is the area of a parallelogram with base 99 and height 44 units?

Answer: 36 square units36\text{ square units}. Apply A=bhA=bh: (9)(4)=36(9)(4)=36.

Flashcard 32: State the formula for the area of a rectangle with length ll and width ww.

Answer: A=lwA=lw. Length times width for rectangles.

Flashcard 33: Identify the correct method to find a polygon area when no single formula fits the whole shape.

Answer: Decompose into known shapes and add areas\text{Decompose into known shapes and add areas}. Break complex shapes into triangles/rectangles to calculate.

Flashcard 34: What is the height of a triangle with area 4848 and base 1212?

Answer: 88. Solve 48=12×12×h48 = \frac{1}{2} \times 12 \times h for hh.

Flashcard 35: State the area formula for a parallelogram with base bb and height hh.

Answer: A=bhA=bh. Parallelogram area is base times perpendicular height.

Flashcard 36: A rectangle is split by a diagonal into two congruent triangles. If the rectangle area is 5050, what is one triangle's area?

Answer: 2525 square units. Diagonal splits rectangle into two equal triangles.

Flashcard 37: Identify the height to use if a triangle has base 1010 and a perpendicular height of 77.

Answer: 77. Use the perpendicular distance from base to opposite vertex.

Flashcard 38: State the formula for the area of a trapezoid with bases b1,b2b_1,b_2 and height hh.

Answer: A=12(b1+b2)hA=\frac{1}{2}(b_1+b_2)h. Average the parallel bases, then multiply by height.

Flashcard 39: What is the area of a square with side length 99 square units?

Answer: 8181. Square area is side squared: 92=819^2 = 81.

Flashcard 40: What is the area of a parallelogram with base 99 and height 44 square units?

Answer: 3636. Multiply base by height: 9×4=369 \times 4 = 36.

Flashcard 41: Find the missing height hh of a trapezoid with area 4848 and bases 1010 and 66.

Answer: 66. Solve 48=12(10+6)h=8h48 = \frac{1}{2}(10+6)h = 8h for hh.

Flashcard 42: A floor is a rectangle 12 ft×9 ft12\text{ ft}\times 9\text{ ft}. What is its area in ft2\text{ft}^2?

Answer: 108 ft2108\text{ ft}^2. Apply A=lwA=lw: (12)(9)=108(12)(9)=108 square feet.

Flashcard 43: What is the area of a triangle with base 1010 and height 77 square units?

Answer: 3535. Apply A=12bh=12×10×7A = \frac{1}{2}bh = \frac{1}{2} \times 10 \times 7.

Flashcard 44: State the area formula for a trapezoid with bases b1,b2b_1,b_2 and height hh.

Answer: A=12(b1+b2)hA=\frac{1}{2}(b_1+b_2)h. Average the parallel bases, then multiply by height.

Flashcard 45: State the formula for the area of a parallelogram with base bb and height hh.

Answer: A=bhA=bh. Base times perpendicular height for parallelograms.

Flashcard 46: State the area formula for a kite or rhombus using diagonals d1d_1 and d2d_2.

Answer: A=12d1d2A=\frac{1}{2}d_1d_2. Half the product of the two diagonals gives the area.

Flashcard 47: What is the area of a composite shape made of a 6×46\times 4 rectangle plus a right triangle with legs 44 and 33?

Answer: 3030 square units. Rectangle (24)(24) plus triangle (6)(6) equals 3030.

Flashcard 48: What is the area of a rhombus with diagonals d1=12d_1=12 and d2=5d_2=5 square units?

Answer: 3030. Apply A=12×12×5=30A = \frac{1}{2} \times 12 \times 5 = 30.

Flashcard 49: What is the area of a triangle with base 1212 and height 55?

Answer: 3030 square units. Apply A=12bh=12×12×5A = \frac{1}{2}bh = \frac{1}{2} \times 12 \times 5.

Flashcard 50: What is the area of a parallelogram with base 99 and height 44?

Answer: 3636 square units. Multiply base by perpendicular height: 9×49 \times 4.

Flashcard 51: Find the missing height hh of a triangle with area 3636 and base 1212.

Answer: 66. Solve 36=12×12×h36 = \frac{1}{2} \times 12 \times h for hh.