Solve Fraction Addition/Subtraction Problems

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5th Grade Math › Solve Fraction Addition/Subtraction Problems

Questions 1 - 10
1

Two students solved this problem about the same-sized whole pan of brownies: “A pan had $\tfrac{5}{6}$ of the brownies left. Then $\tfrac{1}{4}$ of the whole pan was eaten. How much of the pan is left now?” Fraction operations depend on understanding fraction size. Student 1 found a common denominator and subtracted. Student 2 subtracted $\tfrac{1}{4}$ from $\tfrac{5}{6}$ by subtracting both numerators and denominators to get $\tfrac{4}{2}$. Which explanation shows why the correct method works?

Student 2 is correct because subtraction of fractions works the same no matter which fraction is first.

Student 2 is correct because subtracting denominators tells how many pieces are left.

Neither student can solve it because $\tfrac{5}{6}$ and $\tfrac{1}{4}$ are not parts of the same whole.

Student 1 is correct because both fractions can be renamed with a common denominator before subtracting, keeping the pieces the same size.

Explanation

Fractions can be added or subtracted in context when they refer to parts of the same whole pan, like brownies remaining. Identify the fractions involved as 5/6 left initially and 1/4 eaten then. Make equivalent fractions if needed, converting to twelfths: 5/6 = 10/12 and 1/4 = 3/12. Connect the operation to the situation by subtracting to find remaining: 10/12 - 3/12 = 7/12 of the pan. A common misconception is subtracting numerators and denominators directly, like 5-1 over 6-4 to get 4/2, but this doesn't preserve equal parts. Models like a pan divided into 12 equal pieces can show 10 left minus 3 eaten to leave 7/12. Estimation supports by noting 5/6 is about 0.83 and 1/4 is 0.25, differing by roughly 0.58, matching 7/12 or about 0.583.

2

A student walked $\tfrac{5}{6}$ mile to the library and then walked $\tfrac{1}{3}$ mile back toward home along the same route (same mile is the whole). Fraction operations depend on understanding fraction size. What is the correct answer to the problem: How far from home is the student now?

$\tfrac{6}{9}$ mile

$\tfrac{4}{3}$ mile

$\tfrac{1}{2}$ mile

$\tfrac{4}{18}$ mile

Explanation

Fractions can be added or subtracted in context when they represent distances along the same whole route, like miles on the same path. Identify the fractions involved as 5/6 mile to the library and 1/3 mile back. Make equivalent fractions if needed, such as converting 1/3 to 2/6 to match the denominator of 5/6. Connect the operation to the situation by subtracting to find the distance from home: 5/6 - 2/6 = 3/6 or 1/2 mile. A common misconception is adding instead of subtracting for the return, but the context of moving back requires subtraction. Models like a number line from home to library divided into sixths can show moving 5/6 forward then 2/6 back to 3/6. Estimation supports by noting 5/6 is about 0.83 and 1/3 is 0.33, differing by 0.5, which is exactly 1/2.

3

A number line shows one whole from 0 to 1 split into 12 equal parts. A point starts at $\tfrac{11}{12}$ and moves left by $\tfrac{1}{3}$ (same whole). Fraction operations depend on understanding fraction size and equivalent fractions. How does the model support the solution (what value does the point land on)?

The point lands at $\tfrac{10}{36}$.

The point lands at $\tfrac{12}{15}$.

The point lands at $\tfrac{7}{12}$.

The point lands at $\tfrac{5}{12}$.

Explanation

Fractions can be added or subtracted in context on a number line representing the same whole from 0 to 1. Identify the fractions involved as starting at 11/12 and moving left by 1/3. Make equivalent fractions if needed, converting 1/3 to 4/12 to match the twelfths division. Connect the operation to the situation by subtracting for movement left: 11/12 - 4/12 = 7/12. A common misconception is subtracting without equivalents, like 11-1 over 12-3 to get 10/9, but common denominators ensure accuracy. Models like the given number line in twelfths visually show starting at 11/12 and counting back 4 units to 7/12. Estimation helps by approximating 11/12 as about 0.92 and 1/3 as 0.33, differing by roughly 0.59, close to 7/12 or 0.583.

4

Jada ran $\tfrac{3}{4}$ mile in gym class and then ran $\tfrac{2}{8}$ mile more on the same track (same mile is the whole). Fraction operations depend on understanding fraction size and equivalence. Which explanation shows why the answer makes sense?

Since $\tfrac{2}{8}$ is the same as $\tfrac{1}{4}$, adding $\tfrac{3}{4}+\tfrac{1}{4}$ makes $1$ mile total.

Add the denominators: $4+8=12$, so the total must be $\tfrac{5}{12}$ mile.

Subtract because the second run is smaller: $\tfrac{3}{4}-\tfrac{2}{8}=\tfrac{1}{2}$ mile.

Because $\tfrac{3}{4}$ and $\tfrac{2}{8}$ are from different wholes, you cannot find a total.

Explanation

Fractions can be added or subtracted in context when they describe distances on the same whole track, allowing total calculation. Identify the fractions involved as 3/4 mile first and 2/8 mile more. Make equivalent fractions if needed, recognizing 2/8 simplifies to 1/4, matching units with 3/4. Connect the operation to the situation by adding for total distance run: 3/4 + 1/4 = 1 mile. A common misconception is treating unlike denominators as different wholes, but same track means same whole. Models like a number line in fourths can show 3/4 plus another 1/4 reaching 1. Estimation supports by noting 3/4 is 0.75 and 2/8 is 0.25, summing to 1, confirming the total.

5

A recipe uses $\tfrac{3}{4}$ cup of milk. A student has already poured $\tfrac{2}{3}$ cup of milk into the bowl from the same measuring cup set (same-sized cup is the whole). Fraction operations depend on understanding fraction size. What is the correct answer to the problem: How much more milk does the student need to add?

$\tfrac{1}{4}$ cup

$\tfrac{5}{7}$ cup

$\tfrac{1}{6}$ cup

$\tfrac{1}{12}$ cup

Explanation

Fractions can be added or subtracted in context when they refer to parts of the same whole, such as amounts of milk from the same cup measurement. Identify the fractions involved as the required 3/4 cup and the poured 2/3 cup. Make equivalent fractions if needed, like changing 3/4 to 9/12 and 2/3 to 8/12 for a common denominator. Connect the operation to the situation by subtracting to find how much more is needed: 9/12 - 8/12 = 1/12 cup. A common misconception is subtracting without common denominators, like 3/4 - 2/3 = 1/1, but this ignores equal unit sizes. Models like number lines marked in twelfths can show starting at 9/12 and moving back 8/12 to land at 1/12. Estimation helps by approximating 3/4 as 0.75 and 2/3 as 0.67, differing by about 0.08, close to 1/12 or 0.083.

6

A water bottle holds 1 liter when full. It is filled to $\tfrac{7}{10}$ of a liter. After practice, $\tfrac{3}{5}$ of a liter is left in the same bottle. Fraction operations depend on understanding fraction size because both fractions must refer to the same 1-liter whole. What fraction of a liter did the athlete drink?

$\tfrac{4}{50}$ liter

$\tfrac{4}{10}$ liter

$\tfrac{1}{10}$ liter

$\tfrac{10}{5}$ liter

Explanation

Fractions can be added or subtracted in context to find total amounts or differences when they refer to the same whole. In this problem, identify the fractions: 7/10 liter initially and 3/5 liter left, both of the same 1-liter bottle. To subtract, make equivalent fractions with a common denominator of 10, converting 3/5 to 6/10, then 7/10 - 6/10 = 1/10. Subtracting these fractions connects to determining the amount drunk by finding the difference between starting and remaining amounts. A common misconception is subtracting numerators and denominators directly, like 7-3 over 10-5 = 4/5, but this doesn't account for the same whole. Using models like a rectangle divided into tenths can show the one-tenth drunk. Estimation helps by noting 7/10 is 0.7 and 3/5 is 0.6, differing by 0.1, confirming 1/10.

7

A recipe uses $\tfrac{5}{6}$ cup of flour. Jordan already put in $\tfrac{1}{3}$ cup of flour using the same measuring cup size. Fraction operations depend on understanding fraction size (both amounts must be parts of the same 1-cup whole). What fraction of a cup of flour does Jordan still need to add?

$\tfrac{4}{3}$ cup

$\tfrac{4}{9}$ cup

$\tfrac{4}{6}$ cup

$\tfrac{1}{2}$ cup

Explanation

Fractions can be added or subtracted in context to find total amounts or differences when they refer to the same whole. In this problem, identify the fractions: 5/6 cup needed and 1/3 cup already added, both parts of the same cup whole. To subtract, make equivalent fractions with a common denominator of 6, converting 1/3 to 2/6, then 5/6 - 2/6 = 3/6 = 1/2. Subtracting these fractions connects to finding the remaining amount needed to reach the total required for the recipe. A common misconception is subtracting without common denominators, like 5-1 over 6-3 = 4/3, but this ignores equivalent piece sizes. Using models like bar diagrams divided into sixths can illustrate the remaining half cup. Estimation supports by approximating 5/6 as about 0.83 and 1/3 as 0.33, differing by about 0.5, which matches 1/2.

8

Two students are finding $\tfrac{5}{6}-\tfrac{1}{4}$ cups of juice left in a pitcher (both fractions refer to the same 1-cup whole). Fraction operations depend on understanding fraction size. Which explanation shows why the answer makes sense?

Subtract the numerators and denominators: $\tfrac{5-1}{6-4}=\tfrac{4}{2}=2$ cups, which makes sense because you are taking away.

Because $\tfrac{1}{4}$ is smaller than $\tfrac{5}{6}$, the difference should be a little less than $\tfrac{5}{6}$, and rewriting gives $\tfrac{10}{12}-\tfrac{3}{12}=\tfrac{7}{12}$ cup.

Add the fractions because subtraction always makes numbers bigger when denominators are different, so the result should be more than 1 cup.

The answer is $\tfrac{4}{10}$ cup because you subtract the numerators and add the denominators to keep the whole the same size.

Explanation

Fractions can be added or subtracted in context to find total amounts or differences when they refer to the same whole. In this problem, identify the fractions: 5/6 cup and 1/4 cup, both of the same 1-cup whole. To subtract, make equivalent fractions with a common denominator of 12, converting 5/6 to 10/12 and 1/4 to 3/12, then 10/12 - 3/12 = 7/12. Subtracting these fractions connects to finding the remaining juice, which should be slightly less than 5/6. A common misconception is subtracting numerators and denominators separately, like 5-1 over 6-4 = 4/2 = 2, but this doesn't preserve the whole. Using models like fraction bars can show the 7/12 remaining. Estimation helps by noting 5/6 ≈ 0.83 and 1/4 = 0.25, differing by about 0.58, close to 7/12 ≈ 0.583.

9

A garden bed is one whole plot. $\tfrac{2}{9}$ of the plot is planted with carrots and $\tfrac{1}{3}$ of the same plot is planted with lettuce. Fraction operations depend on understanding fraction size (both fractions must refer to the same whole plot). What is the correct total fraction of the plot planted with carrots and lettuce?

$\tfrac{3}{12}$ of the plot

$\tfrac{1}{6}$ of the plot

$\tfrac{5}{9}$ of the plot

$\tfrac{3}{27}$ of the plot

Explanation

Fractions can be added or subtracted in context to find total amounts or differences when they refer to the same whole. In this problem, identify the fractions planted: 2/9 with carrots and 1/3 with lettuce, both of the same plot. To add them, make equivalent fractions with a common denominator of 9, converting 1/3 to 3/9, then 2/9 + 3/9 = 5/9. Adding these fractions connects to combining the areas planted to find the total fraction used. A common misconception is adding numerators and denominators, like 2+1 over 9+3 = 3/12, but this doesn't equalize the parts. Using models like a square divided into ninths can show the five-ninths total. Estimation supports by approximating 2/9 ≈ 0.22 and 1/3 ≈ 0.33, summing to about 0.55, matching 5/9 ≈ 0.556.

10

A ribbon is 1 yard long. Lena used $\tfrac{2}{3}$ of the ribbon for a craft. Then she used $\tfrac{1}{8}$ of the same ribbon for another craft. Fraction operations depend on understanding fraction size because both fractions must be parts of the same whole ribbon. What is the correct total fraction of the ribbon Lena used?

$\tfrac{3}{24}$ of the ribbon

$\tfrac{3}{8}$ of the ribbon

$\tfrac{19}{24}$ of the ribbon

$\tfrac{3}{11}$ of the ribbon

Explanation

Fractions can be added or subtracted in context to find total amounts or differences when they refer to the same whole. In this problem, identify the fractions used: $2/3$ of the ribbon and $1/8$ of the ribbon, both of the same 1-yard whole. To add them, make equivalent fractions with a common denominator of 24, converting $2/3$ to $16/24$ and $1/8$ to $3/24$, then $16/24 + 3/24 = 19/24$. Adding these fractions connects to combining the portions used in different crafts to find the total used. A common misconception is adding without common denominators, like $\frac{2+1}{3+8} = \frac{3}{11}$, but this fails to equalize piece sizes. Using models like a strip divided into 24ths can visually combine to $19/24$. Estimation supports by approximating $2/3$ as 0.67 and $1/8$ as 0.125, summing to about 0.795, close to $19/24$ ≈ 0.792.

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