Compare Products to Factor Sizes - 5th Grade Math
Card 1 of 20
Which comparison is correct: $1\times \frac{7}{8}$ compared to $\frac{7}{8}$?
Which comparison is correct: $1\times \frac{7}{8}$ compared to $\frac{7}{8}$?
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$1\times \frac{7}{8}=\frac{7}{8}$. Multiplying by 1 gives the same value.
$1\times \frac{7}{8}=\frac{7}{8}$. Multiplying by 1 gives the same value.
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Which comparison is correct: $\frac{2}{5}\times \frac{7}{4}$ compared to $\frac{2}{5}$?
Which comparison is correct: $\frac{2}{5}\times \frac{7}{4}$ compared to $\frac{2}{5}$?
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$\frac{2}{5}\times \frac{7}{4}>\frac{2}{5}$. Since $\frac{7}{4}>1$, the product is greater than $\frac{2}{5}$.
$\frac{2}{5}\times \frac{7}{4}>\frac{2}{5}$. Since $\frac{7}{4}>1$, the product is greater than $\frac{2}{5}$.
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Which comparison is correct: $\frac{2}{5}\times \frac{3}{4}$ compared to $\frac{2}{5}$?
Which comparison is correct: $\frac{2}{5}\times \frac{3}{4}$ compared to $\frac{2}{5}$?
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$\frac{2}{5}\times \frac{3}{4}<\frac{2}{5}$. Since $\frac{3}{4}<1$, the product is less than $\frac{2}{5}$.
$\frac{2}{5}\times \frac{3}{4}<\frac{2}{5}$. Since $\frac{3}{4}<1$, the product is less than $\frac{2}{5}$.
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Which comparison is correct: $6\times \frac{13}{12}$ compared to $6$?
Which comparison is correct: $6\times \frac{13}{12}$ compared to $6$?
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$6\times \frac{13}{12}>6$. Since $\frac{13}{12}>1$, the product is greater than 6.
$6\times \frac{13}{12}>6$. Since $\frac{13}{12}>1$, the product is greater than 6.
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Which comparison is correct: $6\times \frac{11}{12}$ compared to $6$?
Which comparison is correct: $6\times \frac{11}{12}$ compared to $6$?
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$6\times \frac{11}{12}<6$. Since $\frac{11}{12}<1$, the product is less than 6.
$6\times \frac{11}{12}<6$. Since $\frac{11}{12}<1$, the product is less than 6.
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Which statement is true for $a>0$ if $a\times b<a$?
Which statement is true for $a>0$ if $a\times b<a$?
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$0<b<1$. The product is less than $a$ when the other factor is between 0 and 1.
$0<b<1$. The product is less than $a$ when the other factor is between 0 and 1.
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Which statement is true for $a>0$ if $a\times b>a$?
Which statement is true for $a>0$ if $a\times b>a$?
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$b>1$. The product exceeds $a$ when the other factor is greater than 1.
$b>1$. The product exceeds $a$ when the other factor is greater than 1.
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Identify the correct sign: $\left(\frac{11}{10}\right)\times 30;_;30$
Identify the correct sign: $\left(\frac{11}{10}\right)\times 30;_;30$
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$>$. Since $\frac{11}{10}>1$, the product is greater than 30.
$>$. Since $\frac{11}{10}>1$, the product is greater than 30.
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Which comparison is correct: $14\times \frac{3}{2}$ compared to $14$?
Which comparison is correct: $14\times \frac{3}{2}$ compared to $14$?
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$14\times \frac{3}{2}>14$. Since $\frac{3}{2}>1$, the product is greater than 14.
$14\times \frac{3}{2}>14$. Since $\frac{3}{2}>1$, the product is greater than 14.
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Identify the correct sign: $\left(\frac{9}{10}\right)\times 30; _ ;30$
Identify the correct sign: $\left(\frac{9}{10}\right)\times 30; _ ;30$
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$<$. Since $\frac{9}{10}<1$, the product is less than 30.
$<$. Since $\frac{9}{10}<1$, the product is less than 30.
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Find and correct the statement: For $a>0$, if $0<b<1$, then $a\times b>a$.
Find and correct the statement: For $a>0$, if $0<b<1$, then $a\times b>a$.
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Correct: if $0<b<1$, then $a\times b<a$. The original statement incorrectly uses $>$ instead of $<$.
Correct: if $0<b<1$, then $a\times b<a$. The original statement incorrectly uses $>$ instead of $<$.
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What is the rule for $a\times b$ compared to $a$ when $b>1$, without multiplying?
What is the rule for $a\times b$ compared to $a$ when $b>1$, without multiplying?
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$a\times b$ is greater than $a$. Multiplying by a number greater than 1 increases the value.
$a\times b$ is greater than $a$. Multiplying by a number greater than 1 increases the value.
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What is the rule for $a\times b$ compared to $a$ when $0<b<1$, without multiplying?
What is the rule for $a\times b$ compared to $a$ when $0<b<1$, without multiplying?
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$a\times b$ is less than $a$. Multiplying by a fraction less than 1 decreases the value.
$a\times b$ is less than $a$. Multiplying by a fraction less than 1 decreases the value.
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What is the rule for $a\times b$ compared to $a$ when $b=1$, without multiplying?
What is the rule for $a\times b$ compared to $a$ when $b=1$, without multiplying?
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$a\times b$ equals $a$. Multiplying by 1 leaves the value unchanged.
$a\times b$ equals $a$. Multiplying by 1 leaves the value unchanged.
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Which statement is always true for $a>0$ and $b>0$: $a\times b>a$ or $a\times b<a$ when $b>1$?
Which statement is always true for $a>0$ and $b>0$: $a\times b>a$ or $a\times b<a$ when $b>1$?
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$a\times b>a$. When $b>1$, multiplying increases the value of $a$.
$a\times b>a$. When $b>1$, multiplying increases the value of $a$.
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Which statement is always true for $a>0$ and $b>0$: $a\times b>a$ or $a\times b<a$ when $0<b<1$?
Which statement is always true for $a>0$ and $b>0$: $a\times b>a$ or $a\times b<a$ when $0<b<1$?
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$a\times b<a$. When $0<b<1$, multiplying decreases the value of $a$.
$a\times b<a$. When $0<b<1$, multiplying decreases the value of $a$.
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Which is larger without multiplying: $\frac{7}{8}\times 9$ or $9$?
Which is larger without multiplying: $\frac{7}{8}\times 9$ or $9$?
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$9$. Since $\frac{7}{8}<1$, the product is less than $9$.
$9$. Since $\frac{7}{8}<1$, the product is less than $9$.
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Which is larger without multiplying: $18\times \frac{2}{3}$ or $18$?
Which is larger without multiplying: $18\times \frac{2}{3}$ or $18$?
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$18$. Since $\frac{2}{3}<1$, the product is less than $18$.
$18$. Since $\frac{2}{3}<1$, the product is less than $18$.
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Which is larger without multiplying: $6\times \frac{11}{10}$ or $6$?
Which is larger without multiplying: $6\times \frac{11}{10}$ or $6$?
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$6\times \frac{11}{10}$. Since $\frac{11}{10}>1$, the product is greater than $6$.
$6\times \frac{11}{10}$. Since $\frac{11}{10}>1$, the product is greater than $6$.
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Which is larger without multiplying: $\frac{3}{5}\times \frac{9}{10}$ or $\frac{3}{5}$?
Which is larger without multiplying: $\frac{3}{5}\times \frac{9}{10}$ or $\frac{3}{5}$?
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$\frac{3}{5}$. Since $\frac{9}{10}<1$, the product is less than $\frac{3}{5}$.
$\frac{3}{5}$. Since $\frac{9}{10}<1$, the product is less than $\frac{3}{5}$.
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