This question tests solving two-step word problems using multiple operations (CCSS.3.OA.8), specifically using addition and division to solve a problem, representing it with an equation, and checking reasonableness. Two-step problems require two operations to solve—you can't find the answer in just one step. Strategy: (1) Read carefully and identify what you know and what you need to find. (2) Determine which operations are needed and in what order. (3) Do step 1, then use that result in step 2. (4) Write an equation using a letter for the unknown (like n, x, or s). (5) Check if answer is reasonable using estimation. Example: "Had 24 stickers, bought 3 packs of 8, how many now?" Step 1: Find stickers bought: 3×8=24. Step 2: Add to original: 24+24=48. Equation: 24+3×8=s or s=24+3×8. Check: About 20+30=50, so 48 is reasonable. In this problem, a class earns 28 points Monday and 20 Tuesday, sharing total equally among 6 teams, asking points per team. This requires addition to find total points, then division per team. Choice A is correct because Step 1: 28+20=48 total. Step 2: 48÷6=8 per team. Equation: s=(28+20)÷6=8. This answer is reasonable because about 30+20=50 divided by 5 is 10, but 6 teams make about 8, so 8 makes sense. Choice C is incorrect because it adds to 48 but doesn't divide by 6. This error occurs when students stop after one step. To help students solve two-step problems: Teach systematic approach: read, identify knowns/unknowns, plan operations, solve step-by-step, check. Model writing equations with unknowns (use letters students choose). Practice estimation BEFORE solving: "About 20+30=50" helps catch errors. Check reasonableness: "Does 847 stickers make sense from buying 3 packs? No!" Use bar models or diagrams to visualize steps. Emphasize order of operations: parentheses matter—(12+8)÷4 ≠ 12+8÷4. Connect to real life: students naturally solve two-step problems (saved $5 per week for 4 weeks, spent $12, how much left?). Watch for students who add all numbers regardless of context, or who stop after one step.

This question tests solving two-step word problems using multiple operations (CCSS.3.OA.8), specifically using addition and division to solve a problem, representing it with an equation, and checking reasonableness. Two-step problems require two operations to solve—you can't find the answer in just one step. Strategy: (1) Read carefully and identify what you know and what you need to find. (2) Determine which operations are needed and in what order. (3) Do step 1, then use that result in step 2. (4) Write an equation using a letter for the unknown (like n, x, or s). (5) Check if answer is reasonable using estimation. Example: "Had 24 stickers, bought 3 packs of 8, how many now?" Step 1: Find stickers bought: 3×8=24. Step 2: Add to original: 24+24=48. Equation: 24+3×8=s or s=24+3×8. Check: About 20+30=50, so 48 is reasonable. In this problem, Tia picks 15 apples and then 9 more, putting them equally into 6 bags, asking how many per bag. This requires addition to find total apples, then division to find per bag. Choice A is correct because Step 1: 15+9=24 total. Step 2: 24÷6=4 per bag. Equation: s=(15+9)÷6=4. This answer is reasonable because about 15+10=25 apples in 5 bags would be 5 each, but 6 bags make about 4, so 4 makes sense. Choice C is incorrect because it adds to 24 but doesn't divide by 6. This error occurs when students stop after one step. To help students solve two-step problems: Teach systematic approach: read, identify knowns/unknowns, plan operations, solve step-by-step, check. Model writing equations with unknowns (use letters students choose). Practice estimation BEFORE solving: "About 20+30=50" helps catch errors. Check reasonableness: "Does 847 stickers make sense from buying 3 packs? No!" Use bar models or diagrams to visualize steps. Emphasize order of operations: parentheses matter—(12+8)÷4 ≠ 12+8÷4. Connect to real life: students naturally solve two-step problems (saved $5 per week for 4 weeks, spent $12, how much left?). Watch for students who add all numbers regardless of context, or who stop after one step.

This question tests solving two-step word problems using multiple operations (CCSS.3.OA.8), specifically using subtraction and division to solve a problem, representing it with an equation, and checking reasonableness. Two-step problems require two operations to solve—you can't find the answer in just one step. Strategy: (1) Read carefully and identify what you know and what you need to find. (2) Determine which operations are needed and in what order. (3) Do step 1, then use that result in step 2. (4) Write an equation using a letter for the unknown (like n, x, or s). (5) Check if answer is reasonable using estimation. Example: "Had 24 stickers, bought 3 packs of 8, how many now?" Step 1: Find stickers bought: 3×8=24. Step 2: Add to original: 24+24=48. Equation: 24+3×8=s or s=24+3×8. Check: About 20+30=50, so 48 is reasonable. In this problem, a store has 64 balloons, sells 16, then shares rest equally into 6 bags, asking how many per bag. This requires subtraction to find remaining, then division per bag. Choice A is correct because Step 1: 64-16=48 remaining. Step 2: 48÷6=8 per bag. Equation: s=(64-16)÷6=8. This answer is reasonable because about 60-20=40 divided by 5 is 8, close to actual. Choice C is incorrect because it subtracts to 48 but doesn't divide by 6. This error occurs when students stop after one step. To help students solve two-step problems: Teach systematic approach: read, identify knowns/unknowns, plan operations, solve step-by-step, check. Model writing equations with unknowns (use letters students choose). Practice estimation BEFORE solving: "About 20+30=50" helps catch errors. Check reasonableness: "Does 847 stickers make sense from buying 3 packs? No!" Use bar models or diagrams to visualize steps. Emphasize order of operations: parentheses matter—(12+8)÷4 ≠ 12+8÷4. Connect to real life: students naturally solve two-step problems (saved $5 per week for 4 weeks, spent $12, how much left?). Watch for students who add all numbers regardless of context, or who stop after one step.

This question tests solving two-step word problems using multiple operations (CCSS.3.OA.8), specifically using division and addition to solve a problem, representing it with an equation, and checking reasonableness. Two-step problems require two operations to solve—you can't find the answer in just one step. Strategy: (1) Read carefully and identify what you know and what you need to find. (2) Determine which operations are needed and in what order. (3) Do step 1, then use that result in step 2. (4) Write an equation using a letter for the unknown (like n, x, or s). (5) Check if answer is reasonable using estimation. Example: "Had 24 stickers, bought 3 packs of 8, how many now?" Step 1: Find stickers bought: 3×8=24. Step 2: Add to original: 24+24=48. Equation: 24+3×8=s or s=24+3×8. Check: About 20+30=50, so 48 is reasonable. In this problem, 48 cookies are shared equally into 8 bags, then 2 more added to each, asking how many per bag now. This requires division to find initial per bag, then addition to add the extra. Choice A is correct because Step 1: 48÷8=6 initial. Step 2: 6+2=8 per bag. Equation: s=(48÷8)+2=8. This answer is reasonable because 50÷8≈6, plus 2 is 8, and adding 16 total cookies makes sense in context. Choice C is incorrect because it only does the division (48÷8=6) without adding 2. This error occurs when students stop after one step. To help students solve two-step problems: Teach systematic approach: read, identify knowns/unknowns, plan operations, solve step-by-step, check. Model writing equations with unknowns (use letters students choose). Practice estimation BEFORE solving: "About 20+30=50" helps catch errors. Check reasonableness: "Does 847 stickers make sense from buying 3 packs? No!" Use bar models or diagrams to visualize steps. Emphasize order of operations: parentheses matter—(12+8)÷4 ≠ 12+8÷4. Connect to real life: students naturally solve two-step problems (saved $5 per week for 4 weeks, spent $12, how much left?). Watch for students who add all numbers regardless of context, or who stop after one step.

This question tests solving two-step word problems using multiple operations (CCSS.3.OA.8), specifically using multiplication and subtraction to solve a problem, representing it with an equation, and checking reasonableness. Two-step problems require two operations to solve—you can't find the answer in just one step. Strategy: (1) Read carefully and identify what you know and what you need to find. (2) Determine which operations are needed and in what order. (3) Do step 1, then use that result in step 2. (4) Write an equation using a letter for the unknown (like n, x, or s). (5) Check if answer is reasonable using estimation. Example: "Had 24 stickers, bought 3 packs of 8, how many now?" Step 1: Find stickers bought: $3 \times 8 = 24$. Step 2: Add to original: $24 + 24 = 48$. Equation: $24 + 3 \times 8 = s$ or $s = 24 + 3 \times 8$. Check: About 20+30=50, so 48 is reasonable. In this problem, Liam starts with $60 and buys 7 notebooks at $6 each, asking how much money is left. This requires multiplication to find the total cost, then subtraction to find the remainder. Choice A is correct because Step 1: $7 \times 6 = 42$ spent. Step 2: $60 - 42 = 18$ left. Equation: $s=60-7\times6=18$. This answer is reasonable because 7 notebooks at about $5 each cost around $35, leaving about $25 from $60, but actual $42 spent leaves $18, which is close. Choice B is incorrect because it represents the total spent ($7\times6=42$) without subtracting from 60. This error occurs when students stop after one step. To help students solve two-step problems: Teach systematic approach: read, identify knowns/unknowns, plan operations, solve step-by-step, check. Model writing equations with unknowns (use letters students choose). Practice estimation BEFORE solving: "About 20+30=50" helps catch errors. Check reasonableness: "Does 847 stickers make sense from buying 3 packs? No!" Use bar models or diagrams to visualize steps. Emphasize order of operations: parentheses matter—$(12+8) \div 4 \neq 12 + 8 \div 4$. Connect to real life: students naturally solve two-step problems (saved $5 per week for 4 weeks, spent $12, how much left?). Watch for students who add all numbers regardless of context, or who stop after one step.

This question tests solving two-step word problems using multiple operations (CCSS.3.OA.8), specifically using subtraction and division to solve a problem, representing it with an equation, and checking reasonableness. Two-step problems require two operations to solve—you can't find the answer in just one step. Strategy: (1) Read carefully and identify what you know and what you need to find. (2) Determine which operations are needed and in what order. (3) Do step 1, then use that result in step 2. (4) Write an equation using a letter for the unknown (like n, x, or s). (5) Check if answer is reasonable using estimation. Example: 'Had 24 stickers, bought 3 packs of 8, how many now?' Step 1: Find stickers bought: 3×8=24. Step 2: Add to original: 24+24=48. Equation: 24+3×8=s or s=24+3×8. Check: About 20+30=50, so 48 is reasonable. In this problem, the library has 72 books, 18 checked out, rest placed equally on 9 shelves, asking how many per shelf, which requires first subtraction to find remaining, then division by shelves. Choice B is correct because Step 1: 72-18=54 remaining. Step 2: 54÷9=6 per shelf. Equation: b=(72-18)÷9=6. This answer is reasonable because about 70-20=50 in 10 shelves is 5, but 9 shelves make about 6. Choice D is incorrect because it subtracts but doesn't divide (72-18=54). This error occurs when students stop after one step. To help students solve two-step problems: Teach systematic approach: read, identify knowns/unknowns, plan operations, solve step-by-step, check. Model writing equations with unknowns (use letters students choose). Practice estimation BEFORE solving: 'About 50÷10=5' helps catch errors. Check reasonableness: 'Does 54 per shelf make sense for 9 shelves? Too many!' Use bar models or diagrams to visualize steps. Emphasize order of operations: parentheses matter—(12+8)÷4 ≠ 12+8÷4. Connect to real life: students naturally solve two-step problems (saved $5 per week for 4 weeks, spent $12, how much left?). Watch for students who add all numbers regardless of context, or who stop after one step.

This question tests solving two-step word problems using multiple operations (CCSS.3.OA.8), specifically using addition and division to solve a problem, representing it with an equation, and checking reasonableness. Two-step problems require two operations to solve—you can't find the answer in just one step. Strategy: (1) Read carefully and identify what you know and what you need to find. (2) Determine which operations are needed and in what order. (3) Do step 1, then use that result in step 2. (4) Write an equation using a letter for the unknown (like n, x, or s). (5) Check if answer is reasonable using estimation. Example: 'Had 24 stickers, bought 3 packs of 8, how many now?' Step 1: Find stickers bought: 3×8=24. Step 2: Add to original: 24+24=48. Equation: 24+3×8=s or s=24+3×8. Check: About 20+30=50, so 48 is reasonable. In this problem, Jada collects 9 and 15 shells over two days and makes 4 equal groups, asking how many per group, which requires first addition to find total, then division by groups. Choice B is correct because Step 1: 9+15=24 total. Step 2: 24÷4=6 per group. Equation: s=(9+15)÷4=6. This answer is reasonable because about 10+15=25 in 5 groups is 5, but 4 groups make about 6. Choice A is incorrect because it only adds (9+15=24) without dividing by 4. This error occurs when students stop after one step. To help students solve two-step problems: Teach systematic approach: read, identify knowns/unknowns, plan operations, solve step-by-step, check. Model writing equations with unknowns (use letters students choose). Practice estimation BEFORE solving: 'About 25÷5=5' helps catch errors. Check reasonableness: 'Does 24 per group make sense for 4 groups? Too many!' Use bar models or diagrams to visualize steps. Emphasize order of operations: parentheses matter—(12+8)÷4 ≠ 12+8÷4. Connect to real life: students naturally solve two-step problems (saved $5 per week for 4 weeks, spent $12, how much left?). Watch for students who add all numbers regardless of context, or who stop after one step.

This question tests solving two-step word problems using multiple operations (CCSS.3.OA.8), specifically using division and addition to solve a problem, representing it with an equation, and checking reasonableness. Two-step problems require two operations to solve—you can't find the answer in just one step. Strategy: (1) Read carefully and identify what you know and what you need to find. (2) Determine which operations are needed and in what order. (3) Do step 1, then use that result in step 2. (4) Write an equation using a letter for the unknown (like n, x, or s). (5) Check if answer is reasonable using estimation. Example: 'Had 24 stickers, bought 3 packs of 8, how many now?' Step 1: Find stickers bought: 3×8=24. Step 2: Add to original: 24+24=48. Equation: 24+3×8=s or s=24+3×8. Check: About 20+30=50, so 48 is reasonable. In this problem, 45 cookies are shared equally into 9 bags, then 2 more added to each, asking how many per bag now, which requires first division to find initial per bag, then addition of 2. Choice A is correct because Step 1: 45÷9=5 per bag. Step 2: 5+2=7 per bag. Equation: c=(45÷9)+2=7. This answer is reasonable because 45 in 9 bags is about 5 each, plus 2 makes 7, and total about 63 cookies makes sense with extras. Choice B is incorrect because it only does step 1 (45÷9=5) without adding 2. This error occurs when students stop after one step. To help students solve two-step problems: Teach systematic approach: read, identify knowns/unknowns, plan operations, solve step-by-step, check. Model writing equations with unknowns (use letters students choose). Practice estimation BEFORE solving: 'About 45÷10=4.5 +2=6.5' helps catch errors. Check reasonableness: 'Does 5 make sense after adding more? No!' Use bar models or diagrams to visualize steps. Emphasize order of operations: parentheses matter—(12+8)÷4 ≠ 12+8÷4. Connect to real life: students naturally solve two-step problems (saved $5 per week for 4 weeks, spent $12, how much left?). Watch for students who add all numbers regardless of context, or who stop after one step.

This question tests solving two-step word problems using multiple operations (CCSS.3.OA.8), specifically using multiplication and addition to solve a problem, representing it with an equation, and checking reasonableness. Two-step problems require two operations to solve—you can't find the answer in just one step. Strategy: (1) Read carefully and identify what you know and what you need to find. (2) Determine which operations are needed and in what order. (3) Do step 1, then use that result in step 2. (4) Write an equation using a letter for the unknown (like n, x, or s). (5) Check if answer is reasonable using estimation. Example: 'Had 24 stickers, bought 3 packs of 8, how many now?' Step 1: Find stickers bought: 3×8=24. Step 2: Add to original: 24+24=48. Equation: 24+3×8=s or s=24+3×8. Check: About 20+30=50, so 48 is reasonable. In this problem, a teacher has 16 pencils and buys 5 packs of 7 each, asking for total pencils, which requires first multiplication to find new pencils, then addition to original. Choice A is correct because Step 1: 5×7=35 bought. Step 2: 16+35=51 total. Equation: p=16+5×7=51. This answer is reasonable because 5 packs of about 5-10 each add 25-50, plus 16 makes 40-65, so 51 fits. Choice B is incorrect because it only multiplies (5×7=35) without adding original 16. This error occurs when students stop after one step. To help students solve two-step problems: Teach systematic approach: read, identify knowns/unknowns, plan operations, solve step-by-step, check. Model writing equations with unknowns (use letters students choose). Practice estimation BEFORE solving: 'About 15+35=50' helps catch errors. Check reasonableness: 'Does 35 total make sense with original 16? No!' Use bar models or diagrams to visualize steps. Emphasize order of operations: parentheses matter—(12+8)÷4 ≠ 12+8÷4. Connect to real life: students naturally solve two-step problems (saved $5 per week for 4 weeks, spent $12, how much left?). Watch for students who add all numbers regardless of context, or who stop after one step.

This question tests solving two-step word problems using multiple operations (CCSS.3.OA.8), specifically using addition and multiplication to solve a problem, representing it with an equation, and checking reasonableness. Two-step problems require two operations to solve—you can't find the answer in just one step. Strategy: (1) Read carefully and identify what you know and what you need to find. (2) Determine which operations are needed and in what order. (3) Do step 1, then use that result in step 2. (4) Write an equation using a letter for the unknown (like n, x, or s). (5) Check if answer is reasonable using estimation. Example: 'Had 24 stickers, bought 3 packs of 8, how many now?' Step 1: Find stickers bought: 3×8=24. Step 2: Add to original: 24+24=48. Equation: 24+3×8=s or s=24+3×8. Check: About 20+30=50, so 48 is reasonable. In this problem, Liam has 5 red and 7 blue marbles, and 3 times as many green as red and blue together, asking for green marbles, which requires first addition of red and blue, then multiplication by 3. Choice A is correct because Step 1: 5+7=12 red and blue. Step 2: 3×12=36 green. Equation: g=3×(5+7)=36. This answer is reasonable because about 5+7=12, times 3 is 36, much more green as stated. Choice D is incorrect because it only adds (5+7=12) without multiplying by 3. This error occurs when students stop after one step. To help students solve two-step problems: Teach systematic approach: read, identify knowns/unknowns, plan operations, solve step-by-step, check. Model writing equations with unknowns (use letters students choose). Practice estimation BEFORE solving: 'About 10×3=30' helps catch errors. Check reasonableness: 'Does 12 green make sense if 3 times more? No!' Use bar models or diagrams to visualize steps. Emphasize order of operations: parentheses matter—(12+8)÷4 ≠ 12+8÷4. Connect to real life: students naturally solve two-step problems (saved $5 per week for 4 weeks, spent $12, how much left?). Watch for students who add all numbers regardless of context, or who stop after one step.