This question tests determining the unknown whole number in multiplication or division equations (CCSS.3.OA.4), specifically finding the missing value that makes an equation true. To find the unknown in an equation, identify what's missing (factor, product, dividend, divisor, or quotient), then use the relationship between multiplication and division. For multiplication: If one factor and the product are known, divide to find the other factor (8×?=48, so ?=48÷8=6). If both factors are known, multiply to find product (8×6=?, so ?=8×6=48). For division: If dividend and divisor are known, divide to find quotient (48÷8=?, so ?=48÷8=6). If dividend and quotient are known, multiply to find divisor (48÷?=6, so ?=48÷6=8). If divisor and quotient are known, multiply to find dividend (?÷8=6, so ?=6×8=48). In this problem, the equation is 8×?=48. The unknown is a factor. To solve, we need to divide 48 by 8. Choice B is correct because 8×6=48, so 6 makes the equation 8×?=48 true. This value makes the equation true. Choice A is incorrect because 8×7=56, not 48. This error occurs when students make calculation errors or don't verify their answer. To help students find unknowns in equations: Teach the inverse relationship (multiplication ↔ division). Use fact families: If 8×6=48, then 48÷8=6, 48÷6=8, and 6×8=48 (all related). Model thinking aloud: "8 times what number equals 48? I know 8×6=48, so ? is 6." Cover up the unknown with your finger, say the known information, and think what number fits. Practice with manipulatives or arrays (8 rows of ? objects = 48 total, count 6 per row). Always check by substituting back: Does 8×6 really equal 48? Yes! Watch for students who add/subtract instead of multiply/divide, or who don't understand the three numbers are related through multiplication and division.

This question tests determining the unknown whole number in multiplication or division equations (CCSS.3.OA.4), specifically finding the missing value that makes an equation true. To find the unknown in an equation, identify what's missing (factor, product, dividend, divisor, or quotient), then use the relationship between multiplication and division. For multiplication: If one factor and the product are known, divide to find the other factor (8×?=48, so ?=48÷8=6). If both factors are known, multiply to find product (8×6=?, so ?=8×6=48). For division: If dividend and divisor are known, divide to find quotient (48÷8=?, so ?=48÷8=6). If dividend and quotient are known, multiply to find divisor (48÷?=6, so ?=48÷6=8). If divisor and quotient are known, multiply to find dividend (?÷8=6, so ?=6×8=48). In this problem, the equation is ?×6=48. The unknown is a factor. To solve, we need to divide 48 by 6. Choice A is correct because 8×6=48, so 8 makes the equation ?×6=48 true. This value makes the equation true. Choice D is incorrect because selecting 42 (like 6×7=42) shows a calculation error close to 48. This error occurs when students make calculation errors or don't verify their answer. To help students find unknowns in equations: Teach the inverse relationship (multiplication ↔ division). Use fact families: If 8×6=48, then 48÷8=6, 48÷6=8, and 6×8=48 (all related). Model thinking aloud: "What number times 6 equals 48? I know 8×6=48, so ? is 8." Cover up the unknown with your finger, say the known information, and think what number fits. Practice with manipulatives or arrays (8 rows of 6 objects = 48 total). Always check by substituting back: Does 8×6 really equal 48? Yes! Watch for students who add/subtract instead of multiply/divide, or who don't understand the three numbers are related through multiplication and division.

This question tests determining the unknown whole number in multiplication or division equations (CCSS.3.OA.4), specifically finding the missing value that makes an equation true. To find the unknown in an equation, identify what's missing (factor, product, dividend, divisor, or quotient), then use the relationship between multiplication and division. For multiplication: If one factor and the product are known, divide to find the other factor (7×?=56, so ?=56÷7=8). If both factors are known, multiply to find product (7×8=?, so ?=7×8=56). For division: If dividend and divisor are known, divide to find quotient (56÷7=?, so ?=56÷7=8). If dividend and quotient are known, multiply to find divisor (56÷?=8, so ?=56÷8=7). If divisor and quotient are known, multiply to find dividend (?÷7=8, so ?=8×7=56). In this problem, the equation is 56÷7=?. The unknown is the quotient. To solve, we need to divide 56 by 7. Choice B is correct because 56÷7=8, which can be written as 7×8=56. This value makes the equation true. Choice D is incorrect because selecting 49 (like 7×7=49) shows a calculation error. This error occurs when students make calculation errors or don't verify their answer. To help students find unknowns in equations: Teach the inverse relationship (multiplication ↔ division). Use fact families: If 7×8=56, then 56÷7=8, 56÷8=7, and 8×7=56 (all related). Model thinking aloud: "56 divided by 7 is what? I know 7×8=56, so ? is 8." Cover up the unknown with your finger, say the known information, and think what number fits. Practice with manipulatives or arrays (7 rows of 8 objects = 56 total). Always check by substituting back: Does 56÷7 really equal 8? Yes! Watch for students who add/subtract instead of multiply/divide, or who don't understand the three numbers are related through multiplication and division.

This question tests determining the unknown whole number in multiplication or division equations (CCSS.3.OA.4), specifically finding the missing value that makes an equation true. To find the unknown in an equation, identify what's missing (factor, product, dividend, divisor, or quotient), then use the relationship between multiplication and division. For multiplication: If one factor and the product are known, divide to find the other factor (9×?=72, so ?=72÷9=8). If both factors are known, multiply to find product (9×8=?, so ?=9×8=72). For division: If dividend and divisor are known, divide to find quotient (72÷9=?, so ?=72÷9=8). If dividend and quotient are known, multiply to find divisor (72÷?=8, so ?=72÷8=9). If divisor and quotient are known, multiply to find dividend (?÷9=8, so ?=8×9=72). In this problem, the equation is 72÷?=8. The unknown is the divisor. To solve, we need to divide 72 by 8. Choice A is correct because checking: 72÷9=8, confirming 9 is correct. This value makes the equation true. Choice C is incorrect because selecting 72 (a known value) instead of solving for the unknown. This error occurs when students don't solve for unknown or make calculation errors. To help students find unknowns in equations: Teach the inverse relationship (multiplication ↔ division). Use fact families: If 9×8=72, then 72÷9=8, 72÷8=9, and 8×9=72 (all related). Model thinking aloud: "72 divided by what equals 8? I know 72÷9=8, so ? is 9." Cover up the unknown with your finger, say the known information, and think what number fits. Practice with manipulatives or arrays (9 rows of 8 objects = 72 total). Always check by substituting back: Does 72÷9 really equal 8? Yes! Watch for students who add/subtract instead of multiply/divide, or who don't understand the three numbers are related through multiplication and division.

This question tests determining the unknown whole number in multiplication or division equations (CCSS.3.OA.4), specifically finding the missing value that makes an equation true. To find the unknown in an equation, identify what's missing (factor, product, dividend, divisor, or quotient), then use the relationship between multiplication and division. For multiplication: If one factor and the product are known, divide to find the other factor ($8 \times ? = 48$, so $? = 48 \div 8 = 6$). If both factors are known, multiply to find product ($8 \times 6 = ?$, so $? = 8 \times 6 = 48$). For division: If dividend and divisor are known, divide to find quotient ($48 \div 8 = ?$, so $? = 48 \div 8 = 6$). If dividend and quotient are known, multiply to find divisor ($48 \div ? = 6$, so $? = 48 \div 6 = 8$). If divisor and quotient are known, multiply to find dividend ($? \div 8 = 6$, so $? = 6 \times 8 = 48$). In this problem, the equation is $? \div 6 = 8$. The unknown is the dividend. To solve, we need to multiply 8 by 6. Choice B is correct because $48 \div 6 = 8$, which can be written as $6 \times 8 = 48$. This value makes the equation true. Choice A is incorrect because using $6 + 8 = 14$ instead of $6 \times 8 = 48$ shows wrong operation. This error occurs when students use wrong operation or don't verify their answer. To help students find unknowns in equations: Teach the inverse relationship (multiplication ↔ division). Use fact families: If $6 \times 8 = 48$, then $48 \div 6 = 8$, $48 \div 8 = 6$, and $8 \times 6 = 48$ (all related). Model thinking aloud: "What number divided by 6 equals 8? I know $6 \times 8 = 48$, so ? is 48." Cover up the unknown with your finger, say the known information, and think what number fits. Practice with manipulatives or arrays ($48$ objects divided by $6$ = $8$ groups). Always check by substituting back: Does $48 \div 6$ really equal 8? Yes! Watch for students who add/subtract instead of multiply/divide, or who don't understand the three numbers are related through multiplication and division.

This question tests determining the unknown whole number in multiplication or division equations (CCSS.3.OA.4), specifically finding the missing value that makes an equation true. To find the unknown in an equation, identify what's missing (factor, product, dividend, divisor, or quotient), then use the relationship between multiplication and division. For multiplication: If one factor and the product are known, divide to find the other factor (9×?=81, so ?=81÷9=9). If both factors are known, multiply to find product (9×9=?, so ?=9×9=81). For division: If dividend and divisor are known, divide to find quotient (81÷9=?, so ?=81÷9=9). If dividend and quotient are known, multiply to find divisor (81÷?=9, so ?=81÷9=9). If divisor and quotient are known, multiply to find dividend (?÷9=9, so ?=9×9=81). In this problem, the equation is 9×?=81. The unknown is a factor. To solve, we need to divide 81 by 9. Choice A is correct because 9×9=81, so 9 makes the equation 9×?=81 true. This value makes the equation true. Choice B is incorrect because 9×8=72, not 81. This error occurs when students make calculation errors or don't verify their answer. To help students find unknowns in equations: Teach the inverse relationship (multiplication ↔ division). Use fact families: If 9×9=81, then 81÷9=9, and 9×9=81 (all related). Model thinking aloud: "9 times what number equals 81? I know 9×9=81, so ? is 9." Cover up the unknown with your finger, say the known information, and think what number fits. Practice with manipulatives or arrays (9 rows of 9 objects = 81 total). Always check by substituting back: Does 9×9 really equal 81? Yes! Watch for students who add/subtract instead of multiply/divide, or who don't understand the three numbers are related through multiplication and division.

This question tests determining the unknown whole number in multiplication or division equations (CCSS.3.OA.4), specifically finding the missing value that makes an equation true. To find the unknown in an equation, identify what's missing (factor, product, dividend, divisor, or quotient), then use the relationship between multiplication and division. For multiplication: If one factor and the product are known, divide to find the other factor (6×?=42, so ?=42÷6=7). If both factors are known, multiply to find product (6×7=?, so ?=6×7=42). For division: If dividend and divisor are known, divide to find quotient (42÷6=?, so ?=42÷6=7). If dividend and quotient are known, multiply to find divisor (42÷?=7, so ?=42÷7=6). If divisor and quotient are known, multiply to find dividend (?÷6=7, so ?=7×6=42). In this problem, the equation is 6×□=42. The unknown is a factor. To solve, we need to divide 42 by 6. Choice C is correct because 6×7=42, so 7 makes the equation 6×□=42 true. This value makes the equation true. Choice D is incorrect because selecting 36 (like 6×6=36) shows a calculation error. This error occurs when students make calculation errors or don't verify their answer. To help students find unknowns in equations: Teach the inverse relationship (multiplication ↔ division). Use fact families: If 6×7=42, then 42÷6=7, 42÷7=6, and 7×6=42 (all related). Model thinking aloud: "6 times what number equals 42? I know 6×7=42, so □ is 7." Cover up the unknown with your finger, say the known information, and think what number fits. Practice with manipulatives or arrays (6 rows of 7 objects = 42 total). Always check by substituting back: Does 6×7 really equal 42? Yes! Watch for students who add/subtract instead of multiply/divide, or who don't understand the three numbers are related through multiplication and division.

This question tests determining the unknown whole number in multiplication or division equations (CCSS.3.OA.4), specifically finding the missing value that makes an equation true. To find the unknown in an equation, identify what's missing (factor, product, dividend, divisor, or quotient), then use the relationship between multiplication and division. For multiplication: If one factor and the product are known, divide to find the other factor (8×?=48, so ?=48÷8=6). If both factors are known, multiply to find product (8×6=?, so ?=8×6=48). For division: If dividend and divisor are known, divide to find quotient (48÷8=?, so ?=48÷8=6). If dividend and quotient are known, multiply to find divisor (48÷?=6, so ?=48÷6=8). If divisor and quotient are known, multiply to find dividend (?÷8=6, so ?=6×8=48). In this problem, the equation is 72 ÷ 8 = ?. The unknown is the quotient. To solve, we need to divide 72 by 8. Choice C is correct because 72÷8=9, which can be written as 8×9=72. This value makes the equation true. Choice B is incorrect because selecting 8 (the divisor) instead of solving for the unknown doesn't make the equation true: 72÷8 is not 8. This error occurs when students don't solve for the unknown. To help students find unknowns in equations: Teach the inverse relationship (multiplication ↔ division). Use fact families: If 8×6=48, then 48÷8=6, 48÷6=8, and 6×8=48 (all related). Model thinking aloud: "72 divided by 8 equals what? I know 8×9=72, so ? is 9." Cover up the unknown with your finger, say the known information, and think what number fits. Practice with manipulatives or arrays (72 objects divided into 8 groups, count 9 per group). Always check by substituting back: Does 72÷8 really equal 9? Yes! Watch for students who add/subtract instead of multiply/divide, or who don't understand the three numbers are related through multiplication and division.

This question tests determining the unknown whole number in multiplication or division equations (CCSS.3.OA.4), specifically finding the missing value that makes an equation true. To find the unknown in an equation, identify what's missing (factor, product, dividend, divisor, or quotient), then use the relationship between multiplication and division. For multiplication: If one factor and the product are known, divide to find the other factor (8×?=48, so ?=48÷8=6). If both factors are known, multiply to find product (8×6=?, so ?=8×6=48). For division: If dividend and divisor are known, divide to find quotient (48÷8=?, so ?=48÷8=6). If dividend and quotient are known, multiply to find divisor (48÷?=6, so ?=48÷6=8). If divisor and quotient are known, multiply to find dividend (?÷8=6, so ?=6×8=48). In this problem, the equation is 30 ÷ □ = 5. The unknown is the divisor. To solve, we need to divide 30 by 5. Choice A is correct because checking: 30÷5=6, but wait, the equation is 30÷□=5, so □=30÷5=6, confirming 6 is correct. This value makes the equation true. Choice C is incorrect because selecting 5 (the quotient) instead of solving for the unknown doesn't make the equation true: 30÷5=6, not 5. This error occurs when students don't solve for the unknown. To help students find unknowns in equations: Teach the inverse relationship (multiplication ↔ division). Use fact families: If 8×6=48, then 48÷8=6, 48÷6=8, and 6×8=48 (all related). Model thinking aloud: "30 divided by what equals 5? I know 5×6=30, so □ is 6." Cover up the unknown with your finger, say the known information, and think what number fits. Practice with manipulatives or arrays (30 objects divided into groups of ?, with 5 groups). Always check by substituting back: Does 30÷6 really equal 5? Yes! Watch for students who add/subtract instead of multiply/divide, or who don't understand the three numbers are related through multiplication and division.

This question tests determining the unknown whole number in multiplication or division equations (CCSS.3.OA.4), specifically finding the missing value that makes an equation true. To find the unknown in an equation, identify what's missing (factor, product, dividend, divisor, or quotient), then use the relationship between multiplication and division. For multiplication: If one factor and the product are known, divide to find the other factor (8×?=48, so ?=48÷8=6). If both factors are known, multiply to find product (8×6=?, so ?=8×6=48). For division: If dividend and divisor are known, divide to find quotient (48÷8=?, so ?=48÷8=6). If dividend and quotient are known, multiply to find divisor (48÷?=6, so ?=48÷6=8). If divisor and quotient are known, multiply to find dividend (?÷8=6, so ?=6×8=48). In this problem, the equation is 56 ÷ ? = 7. The unknown is the divisor. To solve, we need to divide 56 by 7 or multiply 7 by 8. Choice A is correct because checking: 56÷7=8, but wait, no: the equation is 56÷?=7, so ?=56÷7=8, confirming 8 is correct. This value makes the equation true. Choice B is incorrect because this number doesn't make the equation true: 56÷7=8, not 7. This error occurs when students make calculation errors. To help students find unknowns in equations: Teach the inverse relationship (multiplication ↔ division). Use fact families: If 8×6=48, then 48÷8=6, 48÷6=8, and 6×8=48 (all related). Model thinking aloud: "56 divided by what equals 7? I know 7×8=56, so ? is 8." Cover up the unknown with your finger, say the known information, and think what number fits. Practice with manipulatives or arrays (56 objects divided into groups of ?, with 7 groups). Always check by substituting back: Does 56÷8 really equal 7? Yes! Watch for students who add/subtract instead of multiply/divide, or who don't understand the three numbers are related through multiplication and division.