HiSet: High School Equivalency Test: Math
Help Questions
HiSET › HiSet: High School Equivalency Test: Math

The graph on the left shows an object in the Cartesian plane. A transformation is performed on it, resulting in the graph on the right.
Which of the following transformations best fits the graphs?
Translation
Dilation
Rotation about the origin
Reflection in the x-axis
Reflection in the y-axis
Explanation
A dilation is the stretching or shrinking of a figure.
A rotation is the turning of a a figure about a point.
A reflection is the flipping of a figure across a line.
A translation is is the sliding of a figure in a direction.
With a translation, the image is not only congruent to its original size and shape, but its orientation remains the same. A translation fits this figure best because the shape seems to move upward and rightward without changing size, shape, or orientation.
Consider the following data set:
where is an integer from 1 to 10 inclusive.
How many possible values of make 5 the median of the set?
Six
Four
Ten
One
Zero
Explanation
The median of a set of eleven data values - an odd number - is the value that appears in the middle when the values are ranked. For 5 to be the median, 5 must be in the middle - that is, five values must appear before 5, and five values must appear after 8.
We can answer this question by looking at three cases.
Case 1:
Without loss of generality, assume ; this reasoning holds for any lesser value of
. The data set becomes
,
and the median is 4.
Case 2:
The data set becomes
The middle value - the median - is 5.
Case 3:
Without loss of generality, assume ; this reasoning holds for any greater value of
. The data set becomes
Again, the median is 5.
Therefore, we can set equal to 5, 6, 7, 8, 9, or 10 - any of six different values - and make the median of the set 5.
Simplify the expression:
Explanation
An expression with a radical expression in the denominator is not simplified, so to simplify, it is necessary to rationalize the denominator. This is accomplished by multiplying both numerator and denominator by the given square root, , as follows:
The expression can be simplified further by dividing the numbers outside the radical by greatest common factor 5:
This is the correct response.
Simplify:
The expression is already simplified.
Explanation
To simplify a radical expression, first find the prime factorization of the radicand, which is 32 here.
Pair up like factors, then apply the Product of Radicals Property:
,
the simplest form of the radical.
Simplify:
The expression is already simplified.
Explanation
To simplify a radical expression, first find the prime factorization of the radicand, which is 40 here.
Pair up like factors, then apply the Product of Radicals Property:
,
the simplest form of the radical.
Simplify:
The expression is already simplified.
Explanation
To simplify a radical expression, first find the prime factorization of the radicand, which is 120 here.
Pair up like factors, then apply the Product of Radicals Property:
,
the simplest form of the radical.

Examine the figures in the above diagram. The figure at right is the result of performing which of the following transformations on the figure at left?
A clockwise rotation
A clockwise rotation
A counterclockwise rotation
A counterclockwise rotation
None of the other choices gives the correct response.
Explanation
Examine the figure below:

If we connect the horizontal line with the line along the rotated nine at right, we see that it is the result of a one-eighth turn clockwise; the angle between them .
Consider the scenario below:
Helen is a painter. It takes her 3 days to make each painting. She has already made 6 paintings. Which of the following functions best models the number of paintings she will have after days?
Explanation
The question asks, "Which of the following functions best models the number of paintings she will have after days?"
From this, you know that the variable represents the number of days, and that
represents the number of paintings she makes as a function of days spent working.
If it takes 3 days to make a painting, each day results in paintings. Therefore, we have a linear relationship with slope
.
Additionally, she begins with 6 paintings. Therefore, even when zero days are spent working on paintings, she will have 6 paintings. In other words, . This means the y-intercept is 6.
As a result, the function will be
which can be rewritten as
The graph of a function is shown below, with labels on the y-axis hidden.

Determine which of the following functions best fits the graph above.
Explanation
Use the zeroes of the graph to determine the matching function. Zeroes are values of x where . In other words, they are points on the graph where the curve touches zero.
Visually, you can see that the curve crosses the x-axis when ,
, and
. Therefore, you need to look for a function that will equal zero at these x values.
A function with a factor of will equal zero when
, because the factor of
will equal zero. The matching factors for the other two zeroes,
and
, are
and
, respectively.
The answer choice has all of these factors, but it is not the answer because it has an additional zero that would be visible on the graph. Notice it has a factor of
, which results in a zero at
. This additional zero that isn't present in the graph indicates that this cannot be matching function.
is the answer because it has all of the required factors and, as a result, the required zeroes, while not having additional zeroes. Notice that the constant coefficient of negative 2 does not affect where the zeroes are.
Consider Square . Perform two dilations successively, each with scale factor
; the first dilation should have center
, the second,
. Call the image of
under these dilations
; the image of
,
, and so forth.
Which of the following diagrams correctly shows Square relative to Square
?




None of the other choices gives the correct response.
Explanation
To perform a dilation with center and scale factor
, find the midpoints of the segments connecting
to each point, and connect those points. We can simplify the process by finding the midpoints of
,
, and
, and naming them
,
, and
, respectively;
, the image of center
, is just
itself. The figure is below:

Now, do the same thing to the new square, but with as the center. The figure is below:

The final image, relative to the original square, is below:
