Newtonian Mechanics
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AP Physics 1 › Newtonian Mechanics
An 500kg elevator is at rest. If it is raised 50 meters and returns to rest, how much total work was done on the elevator?
Explanation
This can be a tricky question. You need to rely on the work-energy theorem, which states:
Since the elevator is at rest at both the beginning and end, the net work is 0; there is no net change in energy, and therefore no work.
This theorem can be confusing to some since it completely negates potential energy. However, let's think about the situation presented in the problem. A force is required to raise the elevator, meaning that energy is put into the system. However, since it comes back to rest, all of the energy that was put in has been removed by the force of gravity, resulting in a net of zero work.
A semi-truck carrying a trailer has a total mass of . If it is traveling up a slope of
to the horizontal at a constant rate of
, how much power is the truck exerting?
Explanation
Since the truck is traveling at a constant rate, we know that all of the power exerted by the truck is going into a gain in potential energy. The power exerted will be a function of the change in potential energy over time. Therefore, we can write the following formula:
is a vertical height, so we need to write that as a function of distance traveled up the slope:
We can substitute velocity into this equation:
We have values for all of these variables, allowing us to solve:
A rocket is in space at location when it fires it's thrusters. The thrusters provide a force of
. The thusters are turned off at location
.
What is the work done on the rocket by the thrusters?
None of these
Explanation
Because all of the force was in the Y direction, all of the work will come from the change in the Y coordinate.
We will use the definition of work
First we need to find the distance traveled.
Then we can plug that into our work equation.
As a joke, Charlie glues C.J's phone to its receiver, which is bolted to her desk. Trying to extricate it, C.J. pulls on the phone with a force of for
. She then pulls on the phone with a force of
for
. Unfortunately, all of her exertion is in vain, and neither the phone, nor receiver move at all. How much work did C.J. do on the phone in her 25 total seconds of pulling?
Explanation
Work is a measure of force and displacement . Because C.J. did not move the phone at all, no work was done.
An 500kg elevator is at rest. If it is raised 50 meters and returns to rest, how much total work was done on the elevator?
Explanation
This can be a tricky question. You need to rely on the work-energy theorem, which states:
Since the elevator is at rest at both the beginning and end, the net work is 0; there is no net change in energy, and therefore no work.
This theorem can be confusing to some since it completely negates potential energy. However, let's think about the situation presented in the problem. A force is required to raise the elevator, meaning that energy is put into the system. However, since it comes back to rest, all of the energy that was put in has been removed by the force of gravity, resulting in a net of zero work.
Fido, a small dog that weighs , sees a bird in a tree and climbs straight up, at constant velocity, with an average power of
. If it takes Fido
to reach the branch upon which the bird is perched, how high is that branch?
Explanation
We can assume that the dog must carry his entire weight up the tree, and therefore a force is exerted. Using the equation
we can use the evidence provided by the problem to solve for distance.
A car is at rest at the bottom of a
hill.
later, it is at the top of the hill going
. Find the net work done.
Explanation
Initially the car is at rest at the bottom of a hill, this velocity and height are zero.
Converting to
Plugging in values:
How much work (in kilojoules) is done to accelerate a car (3000kg) from rest to .
5400 kilojoules
3000 kilojoules
6200 kilojoules
3400 kilojoules
2300 kilojoules
Explanation
Work is found by finding the change in kinetic energy. Since the car started from rest it had no initial kinetic energy.
Divide by 1000 to convert to kilojoules and get 5400 kilojoules.
A man throws a pizza in the air. If he released it at a height of
, and his throwing motion was a distance of
directly up, determine the average force of the man on the pizza during the throw.
None of these
Explanation
Based on the information given, his throw would have started at above the ground. The pizza gained a maximum height of
. Thus, the gravitational potential energy in relation to the starting position will be:
Since at it's maximum height, all of the energy will be gravitational, the work done on the pizza will be equal to the potential energy, thus:
Using
A woman has a jet pack that has a mass of
. She ignites the jet pack and it accelerates her at a rate of
. Determine the total work done by the jet pack when she has reached a height of
.
None of these