### All Precalculus Resources

## Example Questions

### Example Question #51 : Graphs And Inverses Of Trigonometric Functions

Given , what is the period for the function?

**Possible Answers:**

**Correct answer:**

The formula for the period of a sine/cosine function is .

With the standard form being:

Since , the formula becomes .

Simplified, the period is .

### Example Question #52 : Graphs And Inverses Of Trigonometric Functions

What is the period of this graph?

**Possible Answers:**

**Correct answer:**

One wave of the graph goes exactly from 0 to before repeating itself. This means that the period is .

### Example Question #53 : Graphs And Inverses Of Trigonometric Functions

Please choose the best answer from the following choices.

Find the period of the following function in radians:

**Possible Answers:**

**Correct answer:**

If you look at a graph, you can see that the period (length of one wave) is . Without the graph, you can divide with the frequency, which in this case, is 1.

### Example Question #54 : Graphs And Inverses Of Trigonometric Functions

Please choose the best answer from the following choices.

Find the period of the following function.

**Possible Answers:**

**Correct answer:**

The period is defined as the length of one wave of the function. In this case, one full wave is 180 degrees or radians. You can figure this out without looking at a graph by dividing with the frequency, which in this case, is 2.

### Example Question #55 : Graphs And Inverses Of Trigonometric Functions

What is the period of this sine graph?

**Possible Answers:**

**Correct answer:**

The graph has 3 waves between 0 and , meaning that the length of each of the waves is divided by 3, or .

### Example Question #56 : Graphs And Inverses Of Trigonometric Functions

Write the equation for a cosine graph with a minimum at and a maximum at .

**Possible Answers:**

**Correct answer:**

The equation for this graph will be in the form where A is the amplitude, f is the frequency, h is the horizontal shift, and k is the vertical shift.

To write this equation, it is helpful to sketch a graph:

From sketching the maximum and the minimum, we can see that the graph is centered at and has an amplitude of 2.

The distance between the maximum and the minimum is half the wavelength. Here, it is . That means that the full wavelength is , so the frequency is 1.

The minimum occurs in the middle of the graph, so to figure out where it starts, subtract from the minimum's x-coordinate:

This graph's equation is

.

### Example Question #57 : Graphs And Inverses Of Trigonometric Functions

Give the period and frequency for the equation .

**Possible Answers:**

Period: , Frequency:

Period: , Frequency:

Period: , Frequency:

Period: , Frequency:

Period: , Frequency:

**Correct answer:**

Period: , Frequency:

Our equation is in the form

where A is the amplitude, f is the frequency, h is the horizontal shift, and k is the vertical shift.

We can look at the equation and see that the frequency, , is .

The period is , so in this case .

### Example Question #58 : Graphs And Inverses Of Trigonometric Functions

What is the period of the graph ?

**Possible Answers:**

**Correct answer:**

The equation for this function is in the form

where A is the amplitude, f is the frequency, h is the horizontal shift, and k is the vertical shift.

By looking at the equation, we can see that the frequency, , is .

The period is , so in this case .

### Example Question #59 : Graphs And Inverses Of Trigonometric Functions

What could be the function for the following graph?

**Possible Answers:**

**Correct answer:**

What could be the function for the following graph?

Begin by realizing we are dealing with a periodic function, so sine and cosine are your best bet.

Next, note that the range of the function is and that the function goes through the point .

From this information, we can find the amplitude:

So our function must have a out in front.

Also, from the point , we can deduce that the function has a vertical translation of positive two.

The only remaining obstacle, is whether the function is sine or cosine. Recall that sine passes through , while cosine passes through . this means that our function must be a sine function, because in order to be a cosien graph, we would need a horizontal translation as well.

Thus, our answer is:

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