Texas HS Algebra 2 Question of the Day

Recursive: $B_0=500$, $B_{n+1}=2B_n$; Explicit: $B(t)=500\cdot 2^t$

Recursive: $B_0=500$, $B_{n+1}=1.06B_n$; Explicit: $B(t)=500(1.06)^t$

Recursive: $B_0=500$, $B_{n+1}=2^{1/6}B_n$; Explicit: $B(t)=500\cdot 2^{t/6}$

Recursive: $B_0=500$, $B_{n+1}=\tfrac{1}{2}B_n$; Explicit: $B(t)=500\cdot\left(\tfrac{1}{2}\right)^{t/6}$