Card 0 of 996
Find the mean of the following set of numbers:
The mean is equal to the sum of the values divided by the total number of values.
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Find the mean in this set of numbers:
9078, 9008, 9800, 9099, 9009, 9090, 9008
First add all the numbers:
Then, divide that number by 7:
Answer: The mean is 9156
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Find the average of these amounts:
$34.78, $21. 69, $76.89, $47.88
First, add all the amounts:
Then, divide by 4:
Answer: The average is 45.31
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Find the mean of this set of numbers:
First, add the numbers:
Then, divide by 7:
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What is the mode for the following set of numbers?
The mode is the number that occurs most often in the list. Since 12 appears three times, and no other number shows up as often, the mode is 12.
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Find the mean in this set of numbers:
3343, 4434, 4334, 3343, 4343, 3434, 3334
First, add all the numbers in this set:
Then, divide by 7 (the amount of numbers in this set):
Answer: The mean is 3795
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Dave has a sock drawer with 8 blue and 10 black socks.
If Dave pulls out one black sock, what is the probability that the next sock he pulls out of the drawer is also black?
Since the first sock that Dave pulls out is black, there are 17 remaining socks in the drawer, 8 blue and 9 black. The probability that Dave will choose another black is sock is therefore 9 out of 17.
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All of the clubs are removed from a standard fifty-two-card deck. Two cards are then dealt without replacement. What is the probability that both cards will be red?
Wihtout the clubs, the deck comprises 39 cards, 26 of which are red.
The probability that the first card will be red will be . The probability that the second will then also be red will be
. Multiply the probabilities, and result is
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A pair of fair dice are rolled. What is the probability that the sum will be a multiple of 4?
There are three possible multiples of 4 that can come out: 4, 8, and 12. There are 36 equally probable outcomes; the following will result in a multiple of 4:
These are 9 outcomes out of 36, making the probability
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A pair of fair dice are rolled. What is the probability that the sum will be a multiple of 3?
There are four possible multiples of 3 that can come out: 3,6,9, and 12. There are 36 equally probable outcomes; the following will result in a multiple of 3:
These are 12 outcomes out of 36, making the probability
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Some balls are placed in a hat - ten red, four blue, six yellow. What is the probability that a randomly drawn ball will not be blue?
There are 20 balls in the hat. All but four - that is, sixteen - are blue, so the probability of a draw resulting in a non-blue ball is
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The red jacks are removed from a standard deck of fifty-two cards. What is the probability that a card randomly drawn from that modified deck will be black?
The removal of two red jacks - and no black cards - results in there being fifty cards, twenty-six of them black. Therefore, the probability of a randomly drawn card being black is .
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A standard deck of cards is modified by adding the red threes from another deck. What is the probability that a card randomly drawn from that modified deck will be a red card?
The addition of two red threes from another deck results in the deck comprising fifty-four cards, twenty-eight of which are red. Therefore, the probability of a randomly drawn card being red is
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A standard deck of cards is modified by adding the red queens from another deck. What is the probability that a card randomly drawn from that modified deck will be a face card (jack, queen, king)?
There are four cards of each rank in a standard deck; since three ranks - jacks, queens, kings - are considered face cards, this makes twelve face cards out of the fifty-two. But two more face cards - two red queens - have been introduced, so now there are fourteen face cards out of fifty-four. This makes the probability of a randomly drawn card being a face card
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In a bag of marbles, there are blue marbles,
red marbles, and
green marbles. What is the probability of drawing two blue marbles in a row?
The probability of drawing a blue marble on the first try is , since there are
blue marbles out of a total of
marbles. The probability of drawing a second blue marble is
, since now there are
blue marbles remaining out of a total of
remaining marbles. The probability of drawing two blue marbles in a row is the product of the individual probabilities:
.
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If Mark flips a coin and then rolls a die, what are the odds that the coin will be heads and that the die will land on a multiple of 3?
If Mark flips a coin, the chance that it will land on heads is . On a die, there are 2 out of 6 numbers that are a multiple of 3 (3 and 6); therefore, there is a
chance that the dice will be a multiple of 3.
The probability that the coin will land on heads and that the dice will be a multiple of 3 is:
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Lisa and Fred were flipping a quarter and recording whether it was heads or tails. What is the probability they flip a quarter and it lands on heads, heads, tails, heads, tails? (H,H,T,H,T)
There are two possibilities every time you flip a coin and only one outcome. Therefore the probability for flipping either heads or tails each time is . When you have multiple trials in a row you multiply the probabilities of each outcome by each other.
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A large box contains some balls, each of which is marked with a number; one ball is marked with a "1", two balls are marked with a "2". and so forth up to ten balls with a "10". A blank ball is also included.
Give the probability that a ball drawn at random will NOT be an odd-numbered ball.
The number of balls in the box is
;
The number of odd-numbered balls is
.
Therefore, there are balls that are not marked with an odd number, making the probability that one of these will be drawn
.
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A large box contains some balls, each marked with a whole number from "1" to "10". Each odd number is represented by one ball, which is red; each even number is represented by two balls, one red and one green. Five blank yellow balls are then put in the box.
Give the probability that a randomly-drawn ball will be green.
Each whole number from one to ten will be represented by a red ball, for a total of ten balls; each even number will be represented by a green ball, for a total of five balls; there will also be five unmarked yellow balls. The number of balls in the box will be , 5 of which are green, making the probability of a random draw resulting in a green ball
.
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A large box contains some balls, each of which is marked with a number; one ball is marked with a "1", two balls are marked with a "2". and so forth up to ten balls with a "10". Two blank balls are also included.
Give the probability that a ball drawn at random will be an even-numbered ball.
The number of balls in the box is
.
The number of balls with even numbers is
.
Therefore, if a ball is drawn at random, the probability that an even-numbered ball will be selected is
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