Determine the smallest and largest fractions by rewriting all the fractions to a similar denominator.

Multiply all three denominators together to get the least common denominator, and multiply the numerators by what was multiplied by the denominator to obtain the new numerators.

It can then be seen that the smallest fraction is and the largest fraction is .

Write the range formula and solve.

Determine the smallest and largest fractions by rewriting all the fractions to a similar denominator.

Multiply all three denominators together to get the least common denominator, and multiply the numerators by what was multiplied by the denominator to obtain the new numerators.

It can then be seen that the smallest fraction is and the largest fraction is .

Write the range formula and solve.

The range of scores is from 75 to 100, which is a range of 25 points.

You take the highest score and subtract the lowest score from it.

The highest score is 100 and the lowest score is 75 therefore the range is as follows.

The range of scores is from 75 to 100, which is a range of 25 points.

You take the highest score and subtract the lowest score from it.

The highest score is 100 and the lowest score is 75 therefore the range is as follows.

We don't know what the numbers are yet, so let's just call them a1, a2, a3, a4....a11. Let's assume a1 is the smallest, and a11 is the greatest.

If we were going to find the median of our set, we would need to line them all up, from least to greatest.

a1, a2, a3, a4, a5, a6, a7, a8, a9, a10, a11

The median is the middle number, which in this case about be a6, because there are five numbers before it and five numbers after it.

We know that the median is 62, so that means that there must be five numbers before 62 and five numbers after. Because the numbers are all consecutive even integers, the set must look like this:

52, 54, 56, 58, 60, 62, 64, 66, 68, 70, 72

To find the range of this set, we must find the difference between the largest and smallest numbers. The largest is 72, and the smallest is 52, so the range is 72 - 52 = 20.

The answer is 20.

We don't know what the numbers are yet, so let's just call them a1, a2, a3, a4....a11. Let's assume a1 is the smallest, and a11 is the greatest.

If we were going to find the median of our set, we would need to line them all up, from least to greatest.

a1, a2, a3, a4, a5, a6, a7, a8, a9, a10, a11

The median is the middle number, which in this case about be a6, because there are five numbers before it and five numbers after it.

We know that the median is 62, so that means that there must be five numbers before 62 and five numbers after. Because the numbers are all consecutive even integers, the set must look like this:

52, 54, 56, 58, 60, 62, 64, 66, 68, 70, 72

To find the range of this set, we must find the difference between the largest and smallest numbers. The largest is 72, and the smallest is 52, so the range is 72 - 52 = 20.

The answer is 20.

The range of a set of data is found by subtracting the smallest item from the largest. In this case, 843 - 103 = 740.

The range of the data is the difference between the largest number and the smallest number. The range of the given data is ; therefore, the range of the entire data set must be equal to or greater than . So, it could not be .

The range of the data is the difference between the largest number and the smallest number. The range of the given data is ; therefore, the range of the entire data set must be equal to or greater than . So, it could not be .

The range of a set of data is found by subtracting the smallest item from the largest. In this case, 843 - 103 = 740.