SAT Math › Statistics
If the average of 5k and 3l is equal to 50% of 6l, what is the value of k/l ?
3/5
5/3
9/5
5/9
Since the first part of the equation is the average of 5k and 3l, and there’s two terms, we put 5k plus 3l over 2. This equals 50% of 4l, so we put 6l over 2 so they have common denominators. We can then set 5k+3l equal to 6l. Next, we subtract the 3l on the left from the 6l on the right, giving us 5k=3l. To get the value of k divided by l, we divide 3l by 5, giving us k= 3/5 l. Last we divide by l, to give us our answer 3/5.
If Billy has an average of over 5 tests, what is the lowest score Billy can get over the next 3 tests in order to raise his average up to
?
In order to solve this lets write two general equations that we will solve.
From the first equation, we get.
Substitute tis into the next equation,
Solve for ,
What is the range of the following data set?
Determine the smallest and largest fractions by rewriting all the fractions to a similar denominator.
Multiply all three denominators together to get the least common denominator, and multiply the numerators by what was multiplied by the denominator to obtain the new numerators.
It can then be seen that the smallest fraction is and the largest fraction is
.
Write the range formula and solve.
If the average of 5k and 3l is equal to 50% of 6l, what is the value of k/l ?
3/5
5/3
9/5
5/9
Since the first part of the equation is the average of 5k and 3l, and there’s two terms, we put 5k plus 3l over 2. This equals 50% of 4l, so we put 6l over 2 so they have common denominators. We can then set 5k+3l equal to 6l. Next, we subtract the 3l on the left from the 6l on the right, giving us 5k=3l. To get the value of k divided by l, we divide 3l by 5, giving us k= 3/5 l. Last we divide by l, to give us our answer 3/5.
A police officer walked into a room full of suspects and turn out their pockets. The chart below shows the number of coins each man had.
The police claim the man with the amount of money closest to the arithmetic mean of the group is guilty. Who is it?
Suspect 2
Suspect 1
Suspect 3
Suspect 4
Suspect 6
Summing total money and dividing by the number of suspects gives us an average of approximately $2.73. By comparing it to the amounts held by the suspects, we can see that Suspect #2 is guilty.
If Billy has an average of over 5 tests, what is the lowest score Billy can get over the next 3 tests in order to raise his average up to
?
In order to solve this lets write two general equations that we will solve.
From the first equation, we get.
Substitute tis into the next equation,
Solve for ,
If the average of 5k and 3l is equal to 50% of 6l, what is the value of k/l ?
3/5
5/3
9/5
5/9
Since the first part of the equation is the average of 5k and 3l, and there’s two terms, we put 5k plus 3l over 2. This equals 50% of 4l, so we put 6l over 2 so they have common denominators. We can then set 5k+3l equal to 6l. Next, we subtract the 3l on the left from the 6l on the right, giving us 5k=3l. To get the value of k divided by l, we divide 3l by 5, giving us k= 3/5 l. Last we divide by l, to give us our answer 3/5.
What is the range of the following data set?
Determine the smallest and largest fractions by rewriting all the fractions to a similar denominator.
Multiply all three denominators together to get the least common denominator, and multiply the numerators by what was multiplied by the denominator to obtain the new numerators.
It can then be seen that the smallest fraction is and the largest fraction is
.
Write the range formula and solve.
This semester, Mary had five quizzes that were each worth 10% of her grade. She scored 89, 74, 84, 92, and 90 on those five quizzes. Mary also scored a 92 on her midterm that was worth 25% of her grade, and a 91 on her final that was also worth 25% of her class grade. What was Mary's final grade in the class?
85
87
89
91
93
To find her average grade for the class, we need to multiply Mary's test scores by their corresponding weights and then add them up.
The five quizzes were each worth 10%, or 0.1, of her grade, and the midterm and final were both worth 25%, or 0.25.
average = (0.1 * 89) + (0.1 * 74) + (0.1 * 84) + (0.1 * 92) + (0.1 * 90) + (0.25 * 92) + (0.25 * 91) = 88.95 = 89.
Looking at the answer choices, they are all spaced 2 percentage points apart, so clearly the closest answer choice to 88.95 is 89.
What is the range of the following data set?
Determine the smallest and largest fractions by rewriting all the fractions to a similar denominator.
Multiply all three denominators together to get the least common denominator, and multiply the numerators by what was multiplied by the denominator to obtain the new numerators.
It can then be seen that the smallest fraction is and the largest fraction is
.
Write the range formula and solve.