PSAT Math Flashcards: Equations With Two Variables

Study Equations With Two Variables in PSAT Math with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

PSAT Math

Equations With Two Variables

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QUESTION
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Identify the xx-intercept of the line given by 4x+3y=124x+3y=12.

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ANSWER

33. Substitute y=0y=0: 4x=124x=12, so x=3x=3.

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This deck focuses on Equations With Two Variables, giving you a quick way to review the definitions, rules, and examples that matter most for PSAT Math.

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Flashcard 1: Identify the xx-intercept of the line given by 4x+3y=124x+3y=12.

Answer: 33. Substitute y=0y=0: 4x=124x=12, so x=3x=3.

Flashcard 2: Identify whether (2,3)(2,3) is a solution to x+y=5x+y=5.

Answer: Yes. Check: 2+3=52+3=5

Flashcard 3: Identify the yy-intercept of the line 4x+2y=104x+2y=10.

Answer: 55. Set x=0x=0: 2y=102y=10, so y=5y=5.

Flashcard 4: What is the point-slope form of a linear equation through (x1,y1)(x_1,y_1) with slope mm?

Answer: yy1=m(xx1)y-y_1=m(x-x_1). Directly uses the given point and slope to write the equation.

Flashcard 5: What is the slope of the line given by x=4x=4?

Answer: Undefined. Vertical lines have no defined slope.

Flashcard 6: What is the equation of a line with slope 22 and yy-intercept 3-3?

Answer: y=2x3y=2x-3. Use slope-intercept form with given mm and bb.

Flashcard 7: What is the equation of the line through (0,2)(0,-2) and (4,6)(4,6)?

Answer: y=2x2y=2x-2. Find slope m=6(2)40=2m=\frac{6-(-2)}{4-0}=2, then use y=mx+by=mx+b.

Flashcard 8: Identify the slope of Ax+By=CAx+By=C in terms of AA and BB (assume B0B\ne 0).

Answer: m=- rac{A}{B}. Solve for yy to get y=ABx+CBy=-\frac{A}{B}x+\frac{C}{B}.

Flashcard 9: What condition on slopes shows two lines are parallel?

Answer: Equal slopes: m1=m2m_1=m_2. Parallel lines never intersect, so they have identical slopes.

Flashcard 10: Write the equation in slope-intercept form: 2x+y=72x+y=7.

Answer: y=2x+7y=-2x+7. Isolate yy by subtracting 2x2x from both sides.

Flashcard 11: What does it mean if an ordered pair (x,y)(x,y) is a solution to an equation in two variables?

Answer: Substitution makes the equation true. The xx and yy values satisfy the equation.

Flashcard 12: Identify whether (1,2)(1,-2) is a solution to 2xy=02x-y=0.

Answer: No. Check: 2(1)(2)=2+2=402(1)-(-2)=2+2=4\ne 0.

Flashcard 13: Find the slope of the line through (1,3)(1,3) and (5,1)(5,1).

Answer: - rac{1}{2}. Use slope formula: m= rac{1-3}{5-1}= rac{-2}{4}=- rac{1}{2}.

Flashcard 14: Find the missing value kk so that (3,k)(3,k) satisfies 2x+y=112x+y=11.

Answer: 55. Substitute: 2(3)+k=112(3)+k=11, so 6+k=116+k=11, thus k=5k=5.

Flashcard 15: What condition on slopes shows two nonvertical lines are parallel?

Answer: m1=m2m_1=m_2. Parallel lines have same steepness, thus equal slopes.

Flashcard 16: What is the slope of the line given by Ax+By=CAx+By=C in terms of AA and BB?

Answer: m=ABm=-\frac{A}{B}. Derived by solving Ax+By=CAx+By=C for yy to get slope-intercept form.

Flashcard 17: Identify the equation of the vertical line through x=3x=-3.

Answer: x=3x=-3. Vertical lines have constant xx-value for all yy.

Flashcard 18: What is the yy-intercept of y=3x+5y=-3x+5, stated as a point?

Answer: (0,5)(0,5). When x=0x=0, y=5y=5.

Flashcard 19: Identify the equation of the line with slope 22 and yy-intercept 3-3.

Answer: y=2x3y=2x-3. Direct substitution into y=mx+by=mx+b form.

Flashcard 20: What does it mean for (x,y)(x,y) to be a solution to an equation in two variables?

Answer: (x,y)(x,y) makes the equation true when substituted for xx and yy. The point satisfies the equation when its coordinates are plugged in.

Flashcard 21: What is the slope formula using two points (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2)?

Answer: m= rac{y_2-y_1}{x_2-x_1}. Rise over run between two points gives the slope.

Flashcard 22: What is the solution to the system 2x+y=92x+y=9 and x+y=6x+y=6?

Answer: (3,3)\left(3,3\right). Subtract second from first: x=3x=3; substitute to get y=3y=3.

Flashcard 23: Which option is the standard form of y=3x5y=3x-5 with integer coefficients?

Answer: 3xy=53x-y=5. Move all terms to one side: 3xy5=03x-y-5=0 or 3xy=53x-y=5.

Flashcard 24: What is the equation of the line perpendicular to y=13x4y=\frac{1}{3}x-4 passing through (0,2)(0,2)?

Answer: y=3x+2y=-3x+2. Perpendicular slope is 3-3, passes through (0,2)(0,2).

Flashcard 25: What is the slope of the line in standard form Ax+By=CAx+By=C (with B0B\ne 0)?

Answer: m=ABm=-\frac{A}{B}. Rearrange to slope-intercept form: y=ABx+CBy=-\frac{A}{B}x+\frac{C}{B}.

Flashcard 26: What is the slope between points (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2) (with x2x1x_2\ne x_1)?

Answer: m=y2y1x2x1m=\frac{y_2-y_1}{x_2-x_1}. Rise over run: change in yy divided by change in xx.

Flashcard 27: Identify the slope of the line 3x6y=123x-6y=12.

Answer: 12\frac{1}{2}. Rewrite as y=12x2y=\frac{1}{2}x-2; coefficient of xx is the slope.

Flashcard 28: What condition on slopes shows two nonvertical lines are perpendicular?

Answer: m1m2=1m_1m_2=-1. Perpendicular slopes multiply to 1-1 (negative reciprocals).

Flashcard 29: Identify the slope of 2x+5y=102x+5y=10.

Answer: m=25m=-\frac{2}{5}. Use m=ABm=-\frac{A}{B} with A=2A=2, B=5B=5.

Flashcard 30: Identify the xx-intercept of the line 5x3y=155x-3y=15.

Answer: 33. Set y=0y=0: 5x=155x=15, so x=3x=3.

Flashcard 31: What does it mean for an ordered pair (x,y)(x,y) to be a solution to 2x+3y=122x+3y=12?

Answer: (x,y)(x,y) makes 2x+3y=122x+3y=12 true when substituted. The values satisfy the equation when plugged in.

Flashcard 32: Identify the yy-intercept of 2x+3y=122x+3y=12.

Answer: (0,4)(0,4). Set x=0x=0: 3y=123y=12, so y=4y=4.

Flashcard 33: Identify the yy-intercept of the line y=3x+5y=-3x+5.

Answer: b=5b=5. Constant term in slope-intercept form.

Flashcard 34: What is the point-slope form of a line through (x1,y1)(x_1,y_1) with slope mm?

Answer: yy1=m(xx1)y-y_1=m(x-x_1). Uses a known point and the slope to define the line.

Flashcard 35: What is the yy-intercept of the line Ax+By=CAx+By=C when B0B\ne 0?

Answer: (0,CB)\left(0,\frac{C}{B}\right). Set x=0x=0 and solve for yy to find where line crosses yy-axis.

Flashcard 36: What is the xx-intercept of 5x+y=105x+y=10?

Answer: (2,0)\left(2,0\right). Set y=0y=0: 5x=105x=10, so x=2x=2.

Flashcard 37: Identify the slope of a horizontal line written as y=cy=c.

Answer: m=0m=0. Horizontal lines have no change in yy.

Flashcard 38: What is the condition for two nonvertical lines with slopes m1m_1 and m2m_2 to be perpendicular?

Answer: m1m2=1m_1m_2=-1. Perpendicular slopes multiply to 1-1.

Flashcard 39: What is the xx-intercept of a line found by setting which variable equal to 00?

Answer: Set y=0y=0. The x-intercept occurs where the line crosses the x-axis.

Flashcard 40: What is the equation of the horizontal line through y=3y=-3?

Answer: y=3y=-3. Horizontal lines have zero slope and constant yy-value.

Flashcard 41: What is the slope between points (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2) with x1x2x_1\ne x_2?

Answer: m=y2y1x2x1m=\frac{y_2-y_1}{x_2-x_1}. Rise over run: change in yy divided by change in xx.

Flashcard 42: Identify the equation of the line through (0,4)(0,4) and (2,0)(2,0).

Answer: y=2x+4y=-2x+4. Slope m=0420=2m=\frac{0-4}{2-0}=-2; use point-slope form.

Flashcard 43: What is the equation of the line through (0,2)(0,2) and (4,6)(4,6) in slope-intercept form?

Answer: y=x+2y=x+2. Slope is 6240=1\frac{6-2}{4-0}=1, passes through (0,2)(0,2).

Flashcard 44: What is the xx-intercept of Ax+By=CAx+By=C (assume A0A\ne 0)?

Answer: (CA,0)\left(\frac{C}{A},0\right). Set y=0y=0 and solve for xx: Ax=CAx=C, so x=CAx=\frac{C}{A}.

Flashcard 45: What is the equation of the vertical line through x=5x=5?

Answer: x=5x=5. Vertical lines have undefined slope and constant xx-value.

Flashcard 46: What is the slope-intercept form of a linear equation in two variables?

Answer: y=mx+by=mx+b. mm is slope and bb is y-intercept.

Flashcard 47: What is the equation of the line with slope 4-4 passing through (0,6)(0,6)?

Answer: y=4x+6y=-4x+6. Point (0,6)(0,6) is the y-intercept, so b=6b=6.

Flashcard 48: Identify whether (2,1)(2,1) is a solution to 3x+2y=43x+2y=4.

Answer: No. Check: 3(2)+2(1)=6+2=843(2)+2(1)=6+2=8≠4

Flashcard 49: What is the xx-intercept of Ax+By=CAx+By=C when y=0y=0?

Answer: x=CAx=\frac{C}{A}. Set y=0y=0 and solve for xx.

Flashcard 50: What is the slope of the line given by y=6y=6?

Answer: 00. Horizontal lines have zero slope.

Flashcard 51: Find the xx-intercept of the line 2x+5y=102x+5y=10.

Answer: (5,0)(5,0). Set y=0y=0: 2x=102x=10, so x=5x=5.

Flashcard 52: What is the slope of the line in Ax+By=CAx+By=C in terms of AA and BB?

Answer: m=ABm=-\frac{A}{B}. Rearrange to slope-intercept form: y=ABx+CBy=-\frac{A}{B}x+\frac{C}{B}.

Flashcard 53: What condition on slopes m1m_1 and m2m_2 means two lines are parallel?

Answer: m1=m2m_1=m_2. Parallel lines have equal slopes.

Flashcard 54: What is the equation of a vertical line through x=kx=k?

Answer: x=kx=k. All points have the same xx-coordinate.

Flashcard 55: Solve for yy in terms of xx: 3x+2y=83x+2y=8.

Answer: y=- rac{3}{2}x+4. Isolate yy: 2y=83x2y=8-3x, then divide by 2.

Flashcard 56: Identify the slope of the line through (1,2)(1,2) and (5,10)(5,10).

Answer: 22. Use m= rac{y_2-y_1}{x_2-x_1}= rac{10-2}{5-1}= rac{8}{4}.

Flashcard 57: What is the condition on slopes for two nonvertical lines to be perpendicular?

Answer: Their slopes satisfy m1m2=1m_1m_2=-1. Perpendicular lines meet at 90°; slopes are negative reciprocals.

Flashcard 58: State the condition on slopes m1m_1 and m2m_2 for two nonvertical lines to be parallel.

Answer: m1=m2m_1=m_2. Parallel lines have equal slopes.

Flashcard 59: Find the slope of the line 2x+5y=102x+5y=10.

Answer: m=25m=-\frac{2}{5}. Rewrite as y=25x+2y=-\frac{2}{5}x+2 to identify slope m=25m=-\frac{2}{5}.

Flashcard 60: What is the definition of a solution to an equation in two variables such as 2x+3y=72x+3y=7?

Answer: An ordered pair (x,y)(x,y) that makes the equation true. When substituted, both sides of the equation must be equal.

Flashcard 61: Identify the slope of the line given by 3x+6y=123x+6y=12.

Answer: - rac{1}{2}. Rewrite as y=- rac{1}{2}x+2 to find slope m=- rac{1}{2}.

Flashcard 62: What is the standard form of a linear equation in two variables?

Answer: Ax+By=CAx+By=C. AA, BB, and CC are constants with AA and BB not both zero.

Flashcard 63: Find the equation in standard form for the line through (0,4)(0,4) and (2,0)(2,0).

Answer: 2x+y=42x+y=4. Slope m=0420=2m=\frac{0-4}{2-0}=-2; use point-slope form.

Flashcard 64: What is the yy-intercept of Ax+By=CAx+By=C when x=0x=0?

Answer: y=CBy=\frac{C}{B}. Set x=0x=0 and solve for yy.

Flashcard 65: Find the equation of the line with slope 2-2 passing through (1,3)(1,3) in slope-intercept form.

Answer: y=2x+5y=-2x+5. Use y3=2(x1)y-3=-2(x-1), then simplify to get y=2x+5y=-2x+5.

Flashcard 66: What is the equation in standard form for the line y=3x+7y=-3x+7?

Answer: 3x+y=73x+y=7. Move xx term to left side.

Flashcard 67: Identify whether (2,1)(2,-1) is a solution to 3x+2y=43x+2y=4.

Answer: Yes. 3(2)+2(1)=62=43(2)+2(-1)=6-2=4

Flashcard 68: Identify the yy-intercept of the line 4x+5y=104x+5y=10.

Answer: (0,2)\left(0,2\right). Set x=0x=0: 5y=105y=10, so y=2y=2.

Flashcard 69: Determine whether (2,3)(2,3) is a solution to x+y=6x+y=6.

Answer: No, because 2+362+3\ne 6. Check: 2+3=562+3=5\ne 6.

Flashcard 70: What is the slope of the line given by Ax+By=CAx+By=C (with B0B\ne 0)?

Answer: m=ABm=-\frac{A}{B}. Derived by solving Ax+By=CAx+By=C for yy and identifying slope.

Flashcard 71: What is the slope of the line in Ax+By=CAx+By=C (assume B0B\ne 0)?

Answer: m=ABm=-\frac{A}{B}. Rearrange to slope-intercept form: y=ABx+CBy=-\frac{A}{B}x+\frac{C}{B}.

Flashcard 72: What is the slope of Ax+By=CAx+By=C (assume B0B\ne 0)?

Answer: m=ABm=-\frac{A}{B}. Rearrange to slope-intercept form to find slope.

Flashcard 73: What is the equation of the line with slope 2-2 passing through (3,1)(3,1)?

Answer: y=2x+7y=-2x+7. Use y1=2(x3)y-1=-2(x-3) and simplify.

Flashcard 74: Identify whether (1,4)(1,4) is a solution to 2x+y=52x+y=5.

Answer: No. Check: 2(1)+4=652(1)+4=6≠5, so not a solution.

Flashcard 75: Write the equation of the line with slope 33 and yy-intercept 2-2.

Answer: y=3x2y=3x-2. Direct substitution into y=mx+by=mx+b.

Flashcard 76: What does it mean for an ordered pair (x,y)(x,y) to be a solution of ax+by=cax+by=c?

Answer: (x,y)(x,y) makes ax+by=cax+by=c true when substituted. Substituting the values satisfies the equation.

Flashcard 77: What is the equation in slope-intercept form for 2x+3y=122x+3y=12?

Answer: y=- rac{2}{3}x+4. Solve for yy: 3y=122x3y=12-2x, then divide by 33.

Flashcard 78: Identify whether (2,1)(2,1) is a solution to 3x2y=43x-2y=4.

Answer: Yes. Check: 3(2)2(1)=62=43(2)-2(1)=6-2=4

Flashcard 79: What is the equation of the line with slope 33 and yy-intercept 5-5?

Answer: y=3x5y=3x-5. Use slope-intercept form with m=3m=3 and b=5b=-5.

Flashcard 80: What is the yy-intercept of a line found by setting which variable equal to 00?

Answer: Set x=0x=0. The y-intercept occurs where the line crosses the y-axis.

Flashcard 81: Rewrite 4x+2y=84x+2y=8 in slope-intercept form.

Answer: y=2x+4y=-2x+4. Solve for yy: 2y=4x+82y=-4x+8, so y=2x+4y=-2x+4.

Flashcard 82: What is the point-slope form of a linear equation through (x1,y1)(x_1,y_1) with slope mm?

Answer: yy1=m(xx1)y-y_1=m(x-x_1). Uses a known point and the slope to define the line.

Flashcard 83: What is the slope of the line in standard form Ax+By=CAx+By=C when B0B\ne 0?

Answer: m=ABm=-\frac{A}{B}. Rearrange to slope-intercept form: y=ABx+CBy=-\frac{A}{B}x+\frac{C}{B}.

Flashcard 84: What is the slope between points (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2)?

Answer: m=y2y1x2x1m=\frac{y_2-y_1}{x_2-x_1}. Rise over run: change in yy divided by change in xx.

Flashcard 85: Find yy when x=2x=-2 for the equation y=4x1y=4x-1.

Answer: y=9y=-9. Substitute: y=4(2)1=81=9y=4(-2)-1=-8-1=-9.

Flashcard 86: What is the point-slope form of a line with slope mm through (x1,y1)(x_1,y_1)?

Answer: yy1=m(xx1)y-y_1=m(x-x_1). Uses a known point and slope to define the line.

Flashcard 87: State the condition on slopes m1m_1 and m2m_2 for two nonvertical lines to be perpendicular.

Answer: m1m2=1m_1m_2=-1. Perpendicular slopes multiply to 1-1.

Flashcard 88: What is the point-slope form of a line through (x1,y1)(x_1,y_1) with slope mm?

Answer: yy1=m(xx1)y-y_1=m(x-x_1). Uses known point (x1,y1)(x_1,y_1) and slope mm to define the line.

Flashcard 89: Identify the slope of the line 3x2y=83x-2y=8.

Answer: 32\frac{3}{2}. Rewrite as y=32x4y=\frac{3}{2}x-4; coefficient of xx is the slope.

Flashcard 90: What is the slope formula for two points (x1,y1)(x_1,y_1) and (x2,y2)(x_2,y_2)?

Answer: m= rac{y_2-y_1}{x_2-x_1}. Rise over run between two points.

Flashcard 91: What is the xx-intercept of y=2x+8y=-2x+8?

Answer: 44. Set y=0y=0: 0=2x+80=-2x+8, so x=4x=4.

Flashcard 92: Find the xx-intercept of the line 3x+6y=123x+6y=12.

Answer: (4,0)\left(4,0\right). Set y=0y=0: 3x=123x=12, so x=4x=4.

Flashcard 93: Find the yy-intercept of the line 2x+5y=102x+5y=10.

Answer: (0,2)(0,2). Set x=0x=0: 5y=105y=10, so y=2y=2.

Flashcard 94: What is the condition for two lines with slopes m1m_1 and m2m_2 to be parallel?

Answer: m1=m2m_1=m_2. Parallel lines have equal slopes.

Flashcard 95: What is the equation of the line parallel to y=12x+3y=-\frac{1}{2}x+3 passing through (2,1)(2,1)?

Answer: y=12x+2y=-\frac{1}{2}x+2. Same slope 12-\frac{1}{2}, use point-slope form.

Flashcard 96: What is the equation of a vertical line through x=ax=a?

Answer: x=ax=a. All points have the same xx-coordinate aa.

Flashcard 97: What is the yy-intercept of Ax+By=CAx+By=C (assume B0B\ne 0) written as a point?

Answer: (0,CB)\left(0,\frac{C}{B}\right). Set x=0x=0 and solve for yy to get y=CBy=\frac{C}{B}.

Flashcard 98: What is the definition of the solution set of an equation in two variables?

Answer: All ordered pairs (x,y)(x,y) that satisfy the equation. The collection of all points that make the equation true.

Flashcard 99: Find the equation of the line with slope 33 and yy-intercept 2-2.

Answer: y=3x2y=3x-2. Use y=mx+by=mx+b with m=3m=3 and b=2b=-2.

Flashcard 100: Find the xx-intercept of 3x2y=123x-2y=12.

Answer: (4,0)(4,0). Set y=0y=0: 3x=123x=12, so x=4x=4.