Find the Product of Complex Numbers - Pre-Calculus

Note that this is a geometric series.

Therefore we have:

Note that,

= and since we have .

this shows that the sum is 0.

Note that by FOILing the two binomials we get the following:

Therefore,

We have

.

We know that

Thus this gives us,

.

To evaluate this problem we need to FOIL the binomials.

Now recall that

Thus,

To find the product , FOIL the complex numbers. FOIL stands for the multiplication of the Firsts, Outers, Inners, and Lasts.

Using this method we get the following,

and because

.

The expression can be rewritten as:

Since , the value of .

The correct answer is:

The product is

We note that by FOILing.

We also know that:

We have by using the above rule: n=2 , m=50

Since we know that,

We have then:

Since we know that:

, we use a=2 ,b=i

We have then:

Note that this is a geometric series.

Therefore we have:

Note that,

= and since we have .

this shows that the sum is 0.

Note that by FOILing the two binomials we get the following:

Therefore,

We have

.

We know that

Thus this gives us,

.

To evaluate this problem we need to FOIL the binomials.

Now recall that

Thus,

To find the product , FOIL the complex numbers. FOIL stands for the multiplication of the Firsts, Outers, Inners, and Lasts.

Using this method we get the following,

and because

.

The expression can be rewritten as:

Since , the value of .

The correct answer is:

The product is

We note that by FOILing.

We also know that:

We have by using the above rule: n=2 , m=50

Since we know that,

We have then:

Since we know that:

, we use a=2 ,b=i

We have then:

Note that this is a geometric series.

Therefore we have:

Note that,

= and since we have .

this shows that the sum is 0.

Note that by FOILing the two binomials we get the following:

Therefore,

We have

.

We know that

Thus this gives us,

.