PHYSICS 2 • ELECTROMAGNETIC INDUCTION

Energy Stored in Inductors — Energy stored in an inductor

Understanding how inductors store energy in magnetic fields and the derivation of ½LI² from first principles.

Historical Context & Motivation

The notion that a coil of wire carrying current could store energy invisibly in the space around it took decades to crystallize. In the early nineteenth century, most natural philosophers viewed electricity and magnetism as instantaneous forces acting at a distance, and the idea that empty space itself could hold energy was profoundly counter-intuitive. The story of inductor energy storage is inseparable from the broader development of electromagnetic theory, spanning from Faraday's laboratory experiments to Maxwell's mathematical synthesis and the practical electrical engineering that followed.

1831
Faraday's Law of Induction
Michael Faraday demonstrated that a changing magnetic flux through a conducting loop induces an electromotive force (EMF). His concept of lines of force filling space laid the groundwork for understanding that magnetic fields carry energy.
1851
Self-Inductance Quantified
Heinrich Lenz and others systematically studied how a coil resists changes in its own current. The parameter L, self-inductance, was defined to quantify this resistance, setting the stage for energy calculations.
1861–1865
Maxwell's Electromagnetic Theory
James Clerk Maxwell unified electricity and magnetism into a single theoretical framework. His equations showed that the magnetic field possesses an energy density of B²/(2μ₀), confirming that inductors store energy in their surrounding magnetic fields.
1886
Practical Inductive Circuits
Oliver Heaviside reformulated Maxwell's equations into their modern vector form and developed the operational calculus for analyzing transient circuits. His work made the energy stored in inductors a routine engineering calculation for telegraph and early power systems.
20th Century
Modern Applications
Inductor energy storage became central to technologies ranging from radio tuning circuits and power supplies to superconducting magnetic energy storage (SMES) systems and the massive toroidal magnets in particle accelerators and fusion reactors.

The central question this lesson addresses is deceptively simple: when current flows through an inductor, work must be done against the back-EMF to establish the magnetic field. Where does that energy go, and how much is stored? Answering this requires connecting Faraday's law, the definition of inductance, and the concept of magnetic field energy density into a coherent quantitative picture.

Core Principles & Definitions

Before deriving the energy formula, we need to establish four foundational ideas that connect circuit behavior to field energy. An inductor is any circuit element whose primary function is to produce a magnetic flux proportional to the current it carries. In ideal form, it has inductance L but zero resistance. When the current through an inductor changes, the inductor develops a back-EMF that opposes the change, a direct consequence of Faraday's law. It is precisely this opposition that requires an external source to do work, and that work is stored as energy in the magnetic field threading the inductor.

1

Self-Inductance (L)

Self-inductance relates the total magnetic flux linkage Φ through a coil to the current I producing it: L = NΦ/I. Measured in henrys (H), it depends on geometry and core material, not on current.
2

Back-EMF (Lenz's Law)

A changing current dI/dt induces a voltage ε = −L(dI/dt) across the inductor. The negative sign (Lenz's law) ensures the induced EMF opposes the change in current, acting as a kind of electromagnetic inertia.
3

Work Against Back-EMF

To increase current through an inductor, an external source must push charge against the back-EMF. The instantaneous power delivered is P = LI(dI/dt). Integrating this power over time yields the total energy stored.
4

Magnetic Field Energy Density

The energy isn't stored in the wire itself but in the magnetic field permeating the space around and inside the inductor. The energy per unit volume is u = B²/(2μ₀), connecting circuit-level and field-level descriptions.
KEY TAKEAWAY
Think of an inductor as a flywheel for electric current. Just as a spinning flywheel stores kinetic energy (½Iω²) and resists changes in rotational speed, an inductor stores magnetic energy (½LI²) and resists changes in current. The inductance L plays the role of rotational inertia, and the current I plays the role of angular velocity. Trying to instantaneously stop current through a large inductor is like trying to instantly stop a heavy flywheel—the stored energy must go somewhere.

Visual Explanation — Energy in the Magnetic Field

The diagram shows a simple circuit with a voltage source driving current I through an inductor of self-inductance L. The dashed ellipses represent the magnetic field lines (B) threading and surrounding the coil. Energy is stored not in the wire but in the magnetic field region, as indicated by the yellow label. The total stored energy is given by U = ½LI².

The diagram above illustrates the essential physics. When the voltage source drives a steadily increasing current through the coil, the inductor develops a back-EMF opposing that increase. The work the source must do against this opposition is not dissipated as heat (assuming an ideal inductor with zero resistance) but is instead converted into energy stored in the magnetic field that threads and surrounds the coil. The concentric elliptical field lines represent the spatial distribution of the B field, and the intensity of the stored energy is greatest where the field is strongest—typically inside the coil for a solenoid. If the current is later reduced, the collapsing magnetic field returns that stored energy to the circuit as an induced EMF, potentially driving current through other components.

💡 Physical Intuition
A useful mental model: the magnetic field acts as an elastic medium that is 'compressed' when you push current through the coil. The field stores that mechanical-like energy, and when the current decreases, the field 'expands' back, releasing energy. This is why an inductor can produce dangerously high voltage spikes when a circuit is suddenly opened—the stored energy must be discharged.

Mathematical Framework — Deriving the Energy Formula

We derive the energy stored in an inductor by calculating the total work done by an external source to build the current from zero to a final value I. The derivation begins with the fundamental relationship between the voltage across an ideal inductor and the rate of change of current, then integrates the instantaneous power over time. This approach mirrors the familiar derivation of kinetic energy via ½mv² from Newton's second law, with inductance replacing mass and current replacing velocity.

Step 1: Voltage Across an Inductor

INDUCTOR VOLTAGE
v(t) = L · dI/dt
Where v(t) is the voltage across the inductor (V), L is the self-inductance (H), and dI/dt is the time rate of change of current (A/s).

Step 2: Instantaneous Power Delivered

The instantaneous power delivered to the inductor by the external source is the product of the voltage across it and the current through it. Since the ideal inductor has no resistance, all of this power goes into building the magnetic field.

INSTANTANEOUS POWER
P(t) = v(t) · I(t) = L · I · (dI/dt)
This expression gives the rate at which energy is being transferred into the magnetic field at any instant.

Step 3: Total Energy by Integration

To find the total energy stored when the current has reached a steady value I, we integrate the power over time. A change of variable from dt to dI simplifies the integral elegantly. Since P dt = L · I · dI, the total energy is:

ENERGY STORED IN AN INDUCTOR
U = ∫₀ᴵ L · I′ dI′ = ½LI²
Where U is the energy in joules (J), L is the inductance in henrys (H), and I is the current in amperes (A). The integral evaluates to (L/2)I² = ½LI², analogous to ½mv² for kinetic energy.

Connection to Magnetic Field Energy Density

The circuit-level result U = ½LI² can be recast in terms of the magnetic field. For a long solenoid of length ℓ, cross-sectional area A, and n turns per unit length, we have L = μ₀n²Aℓ and B = μ₀nI. Substituting these into ½LI² and dividing by the volume Aℓ yields the magnetic energy density:

MAGNETIC ENERGY DENSITY
u = B² / (2μ₀)
Where u is energy per unit volume (J/m³), B is the magnetic field strength (T), and μ₀ = 4π × 10⁻⁷ T·m/A is the permeability of free space. This expression is fully general—it applies to any magnetic field, not just solenoids.

Detailed Breakdown — From Circuit Energy to Field Energy

The two expressions for inductor energy—the circuit form ½LI² and the field form ∫(B²/2μ₀)dV—represent the same physical quantity viewed from different perspectives. The circuit perspective treats the inductor as a lumped element characterized by a single parameter L, while the field perspective distributes the energy throughout the volume of space where B ≠ 0. The latter is more fundamental because it generalizes to electromagnetic waves and radiation, where there are no wires at all.

Three parabolic curves show how the stored energy U = ½LI² grows with current for inductors of different inductance values. The cyan curve (L = 0.8 H) stores the most energy at any given current. The annotated point at I = 3 A shows U = ½(0.8)(3²) = 3.6 J. Notice the quadratic growth: doubling the current quadruples the stored energy.

The graph makes two critical features of inductor energy storage visually apparent. First, the energy grows as the square of the current, so doubling the current from 2 A to 4 A does not merely double the stored energy—it quadruples it. This quadratic dependence has important engineering consequences: high-current inductors in power electronics must be carefully designed to handle the enormous stored energy. Second, for a fixed current, the stored energy is directly proportional to the inductance. A larger inductance—achieved by adding more turns, using a ferromagnetic core, or increasing the cross-sectional area—stores proportionally more energy at the same current.

Comparison of circuit-level and field-level energy descriptions
QuantityCircuit ExpressionField Expression
Total EnergyU = ½LI²U = ∫(B²/2μ₀) dV
Energy DensityU/(Volume) for uniform fieldsu = B²/(2μ₀)
UnitsJoules (J)J/m³
ApplicabilityLumped circuit elementsAny magnetic field configuration

Worked Example — Energy in a Solenoid

Consider a solenoid with 500 turns, a length of 0.25 m, a cross-sectional area of 4.0 × 10⁻⁴ m², and an air core (μ₀ = 4π × 10⁻⁷ T·m/A). A current of 6.0 A flows through the solenoid. Calculate: (a) the self-inductance, (b) the total energy stored, and (c) the magnetic energy density inside the solenoid.

Energy Stored in an Air-Core Solenoid
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Step 1 — Identify Given ValuesNumber of turns N = 500, length ℓ = 0.25 m, cross-sectional area A = 4.0 × 10⁻⁴ m², current I = 6.0 A, and μ₀ = 4π × 10⁻⁷ T·m/A. The turn density is n = N/ℓ = 500/0.25 = 2000 turns/m.
n = 2000 turns/m
2
Step 2 — Calculate Self-InductanceFor an ideal solenoid, L = μ₀n²Aℓ. Substituting: L = (4π × 10⁻⁷)(2000)²(4.0 × 10⁻⁴)(0.25). First, n² = 4.0 × 10⁶. Then μ₀n² = (4π × 10⁻⁷)(4.0 × 10⁶) = 16π × 10⁻¹ ≈ 5.027 T²·m/A². Multiplying by Aℓ = (4.0 × 10⁻⁴)(0.25) = 1.0 × 10⁻⁴ m³ gives L = 5.027 × 1.0 × 10⁻⁴ ≈ 5.03 × 10⁻⁴ H.
L ≈ 0.503 mH
3
Step 3 — Calculate Total Stored EnergyUsing U = ½LI²: U = ½(5.03 × 10⁻⁴)(6.0)² = ½(5.03 × 10⁻⁴)(36) = ½(1.811 × 10⁻²) = 9.05 × 10⁻³ J.
U ≈ 9.05 mJ
4
Step 4 — Calculate Magnetic Field InsideThe magnetic field inside an ideal solenoid is B = μ₀nI = (4π × 10⁻⁷)(2000)(6.0) = 4π × 10⁻⁷ × 1.2 × 10⁴ = 4.8π × 10⁻³ ≈ 1.508 × 10⁻² T.
B ≈ 15.1 mT
5
Step 5 — Calculate Energy DensityUsing u = B²/(2μ₀): u = (1.508 × 10⁻²)² / (2 × 4π × 10⁻⁷) = (2.274 × 10⁻⁴) / (2.513 × 10⁻⁶) ≈ 90.5 J/m³. As a consistency check, the total energy should equal u × Volume = 90.5 × (1.0 × 10⁻⁴) = 9.05 × 10⁻³ J = 9.05 mJ, which matches our Step 3 result.
u ≈ 90.5 J/m³ ✓ Consistent with U = 9.05 mJ
Consistency Check
Whenever you compute both ½LI² and ∫(B²/2μ₀)dV, verify that they agree. This cross-check catches algebraic errors and reinforces the physical equivalence of the circuit and field descriptions of inductor energy.

Inductor vs. Capacitor Energy Storage

Inductors and capacitors are the two fundamental energy-storage elements in circuits, but they store energy in complementary ways. A capacitor stores energy in an electric field between its plates (U = ½CV²), while an inductor stores energy in a magnetic field around its coil (U = ½LI²). Understanding this duality is essential for analyzing oscillatory circuits, filters, and energy conversion systems. The table below summarizes the key parallels.

Inductor vs. Capacitor: a systematic comparison of energy storage properties
PropertyInductorCapacitor
Energy formulaU = ½LI²U = ½CV²
Field typeMagnetic (B)Electric (E)
Energy densityu = B²/(2μ₀)u = ½ε₀E²
Opposes changes inCurrent (electromagnetic inertia)Voltage
Mechanical analogyMass / flywheel (½mv²)Spring (½kx²)
Ideal behaviorZero resistance, passes DCZero leakage, blocks DC
Energy release riskHigh-voltage spike on open circuitHigh-current surge on short circuit
LC DUALITY
In an LC oscillator, energy sloshes back and forth between the magnetic field of the inductor and the electric field of the capacitor, much like a pendulum converting between kinetic and potential energy. The total energy U = ½LI² + ½CV² remains constant in the ideal (lossless) case. This interchange is the basis for radio tuning circuits, where the resonant frequency is f = 1/(2π√(LC)).

Connections to Advanced Theory

The formula U = ½LI² is the starting point for several more advanced topics in electromagnetism and engineering. Understanding how it connects to these areas helps contextualize why inductor energy is a central concept, not merely a textbook exercise.

How inductor energy concepts extend into advanced electromagnetic theory
Basic ConceptAdvanced Extension
U = ½LI² for a single inductorFor coupled inductors: U = ½L₁I₁² + ½L₂I₂² + MI₁I₂, where M is mutual inductance. Critical for transformer design and wireless power transfer.
Energy density u = B²/(2μ₀)In magnetic materials, u = ∫₀ᴮ H · dB, which accounts for hysteresis losses and nonlinear permeability. The area inside the B–H loop represents energy dissipated per cycle.
Magnetic field energyCombined with electric field energy, it gives the total electromagnetic energy density: u = ½ε₀E² + B²/(2μ₀). This appears in the Poynting vector formalism for energy flow in electromagnetic waves.
Ideal inductor (no resistance)Real inductors dissipate energy through winding resistance, core losses (hysteresis + eddy currents), and radiation. Quality factor Q = ωL/R quantifies how ideal the inductor is at a given frequency.
RL transient energyIn an RL circuit with time constant τ = L/R, the inductor's stored energy ½LI² is exponentially dissipated in the resistor when the source is removed: U(t) = ½LI₀²e^(−2t/τ).

One particularly striking application is superconducting magnetic energy storage (SMES). Because a superconducting coil has zero resistance, current circulates indefinitely without loss, and the stored energy ½LI² can be held for extended periods. SMES systems are used for grid-scale power quality applications, delivering megajoules of energy on millisecond timescales—something no battery can match. The same principle underpins the enormous magnetic energy stored in MRI solenoids and the superconducting magnets at CERN's Large Hadron Collider.

🔭 Looking Ahead
In your study of electromagnetic waves, you will see that the energy density formula u = B²/(2μ₀) combines with u = ½ε₀E² to give the total energy carried by a wave. The ratio E/B = c (the speed of light) ensures that the electric and magnetic contributions are equal—a beautiful symmetry that Maxwell's equations predict.

Practice Problems

PROBLEM 1CONCEPTUAL
An ideal inductor carrying a steady 5 A current is connected across a perfect (zero-resistance) short circuit. What happens to the energy stored in the inductor immediately after the short is applied? Where is the energy, and why doesn't the current decay?
PROBLEM 2BASIC CALCULATION
A 200 mH inductor carries a current of 3.0 A. Calculate the energy stored in the inductor.
PROBLEM 3INTERMEDIATE
Two inductors, L₁ = 50 mH and L₂ = 120 mH, are connected in series (with no mutual coupling) and carry a common current of 4.0 A. (a) What is the total energy stored? (b) What fraction of the total energy resides in L₂?
PROBLEM 4APPLIED
A superconducting solenoid for an MRI machine has an inductance of 8.0 H and carries a current of 150 A. (a) How much energy is stored? (b) If this energy were used to lift a 1000 kg mass against gravity (g = 9.8 m/s²), to what height could the mass be raised?
PROBLEM 5CRITICAL THINKING
Starting from the magnetic energy density u = B²/(2μ₀), derive the total energy stored in a toroidal inductor of N turns, mean radius R, and circular cross-section of radius a (where a ≪ R), carrying current I. Show that your result is consistent with U = ½LI² using the known formula for the inductance of a toroid.

Lesson Summary

An inductor stores energy in the magnetic field that surrounds and threads its coil. When an external source drives increasing current through an inductor, it does work against the back-EMF (ε = −L dI/dt). Integrating the instantaneous power P = LI(dI/dt) from zero current to a final current I yields the fundamental energy formula U = ½LI². This expression is analogous to ½mv² for kinetic energy, with inductance L playing the role of mass and current I playing the role of velocity.

Equivalently, the energy is distributed throughout space with a magnetic energy density u = B²/(2μ₀), so U = ∫u dV over the volume where the field exists. The circuit description (½LI²) and the field description (B²/2μ₀) always agree, providing a powerful internal consistency check. This concept underpins LC oscillatory circuits, transformer coupling, RL transient analysis, and modern technologies including superconducting magnetic energy storage (SMES) systems and the massive magnets in MRI machines and particle accelerators.

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