PHYSICS 2 • CIRCUITS

Current, Voltage, Resistance & Power — Define current, voltage, resistance, and power

Master the four foundational quantities that govern every electrical circuit, from microscopic charge flow to macroscopic energy transfer.

Historical Context & Motivation

The modern understanding of electricity did not emerge from a single insight but from centuries of careful experimentation, fierce debate, and gradual mathematical formalization. Early observations of static electricity by the ancient Greeks gave way to systematic study in the seventeenth and eighteenth centuries, when natural philosophers began distinguishing between the accumulation of charge and the sustained flow of charge through conductors. The pivotal shift came when researchers realized that electricity could be described by a small set of measurable, interrelated quantities—current, voltage, resistance, and power—each of which captures a distinct physical aspect of how charge carriers transport energy through a circuit.

1745
The Leyden Jar
Pieter van Musschenbroek and Ewald Georg von Kleist independently invent the Leyden jar, the first device capable of storing electrical charge and demonstrating that voltage (potential difference) could be accumulated and released.
1800
Volta's Pile
Alessandro Volta constructs the first electrochemical battery, providing a continuous current source rather than a brief discharge—ushering in the age of circuit analysis.
1827
Ohm's Law
Georg Simon Ohm publishes Die galvanische Kette, formalizing the linear proportionality between voltage and current through a conductor and introducing resistance as a material property.
1840
Joule Heating
James Prescott Joule quantifies the thermal energy dissipated in a resistor, linking electrical power to measurable heat production and establishing energy conservation in circuits.
1882
Edison's Pearl Street Station
Thomas Edison opens the first commercial electrical power station, demonstrating that all four quantities—current, voltage, resistance, and power—must be engineered together for practical electricity distribution.

The central question that motivated each of these advances remains the same question at the heart of every circuits course: how do we rigorously define and quantitatively relate the flow of charge, the energy per unit charge available to drive that flow, the opposition a material presents, and the rate at which electrical energy is converted into other forms? Answering that question is the purpose of this lesson.

Core Principles & Definitions

Before diving into equations, it is essential to build clear conceptual definitions of the four quantities. Each one describes a fundamentally different physical aspect of charge transport: the rate of charge flow, the energy landscape that drives it, the material opposition that limits it, and the rate of energy conversion that results. These definitions are not merely pedagogical conveniences—they correspond to distinct, independently measurable quantities with well-defined SI units.

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Electric Current (I)

The net rate at which electric charge flows through a cross-sectional area. Measured in amperes (A), where 1 A = 1 C/s. Conventional current flows from higher to lower potential, opposite to the direction of electron drift in metals.
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Voltage (V)

The electric potential difference between two points, representing the work done per unit charge in moving charge between those points. Measured in volts (V), where 1 V = 1 J/C. It is the driving force that pushes charge carriers through a circuit.
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Resistance (R)

The ratio of voltage across a conductor to the current flowing through it, quantifying how strongly a material opposes charge flow. Measured in ohms (Ω), where 1 Ω = 1 V/A. It depends on material resistivity, geometry, and temperature.
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Electric Power (P)

The rate at which electrical energy is converted into other forms (heat, light, mechanical work). Measured in watts (W), where 1 W = 1 J/s. For a circuit element: P = IV, linking power directly to both the charge flow rate and the energy per charge.
KEY TAKEAWAY
Think of an electric circuit as a ski resort. Voltage is the height of the mountain—the gravitational potential energy available per kilogram of skier. Current is the number of skiers passing a checkpoint each second. Resistance is the roughness and narrowness of the trail—obstacles that slow skiers down. Power is the total rate of kinetic energy the skiers deliver at the bottom. A taller mountain (more voltage) or more skiers per second (more current) both increase the rate of energy delivery.

Visual Explanation — A Simple Circuit

A simple DC circuit with a 12 V battery and a 4 Ω resistor. Conventional current (cyan arrow) flows from the positive terminal through the external circuit to the negative terminal, while electrons (violet arrow) drift in the opposite direction. The computed current is 3 A and the power dissipated in the resistor is 36 W.

The diagram above encapsulates the relationships among all four quantities in the simplest possible circuit. The battery maintains a fixed potential difference of 12 V across its terminals by performing electrochemical work to separate charges internally. This voltage drives charge through the circuit, and the resistance of 4 Ω limits the resulting current to I = V/R = 3 A. The rate at which the resistor converts electrical energy into thermal energy is the power, P = IV = 36 W. Note the distinction between conventional current direction (from + to −, used universally in circuit analysis) and the physical electron drift direction (from − to +), a historical convention that persists because it does not affect the mathematics.

Mathematical Framework

Each of the four circuit quantities has a precise mathematical definition rooted in fundamental physics. Understanding these definitions—not merely memorizing formulas—is what allows you to analyze any circuit, from a flashlight to a microprocessor power supply.

ELECTRIC CURRENT
I = dQ / dt
Where I is the current in amperes (A), Q is the net charge in coulombs (C), and t is time in seconds (s). For steady-state (DC) current, this simplifies to I = ΔQ / Δt. One ampere corresponds to one coulomb of charge passing a cross-section per second, which is approximately 6.24 × 10¹⁸ elementary charges per second.
VOLTAGE (ELECTRIC POTENTIAL DIFFERENCE)
V = W / Q = −∫ₐᵇ E⃗ · dl⃗
Where V is the potential difference in volts (V), W is the work done on a test charge in joules (J), and E⃗ is the electric field. The integral form connects voltage to the underlying field; in a circuit with lumped elements, we typically use the scalar V = W/Q directly. One volt means one joule of energy is exchanged per coulomb of charge transferred.
RESISTANCE (OHM'S LAW)
R = V / I ⟹ V = IR
Where R is the resistance in ohms (Ω). Ohm's law holds for ohmic materials—those for which R is independent of V and I. For a uniform conductor of length L and cross-sectional area A: R = ρL/A, where ρ is the material's resistivity in Ω·m.
ELECTRIC POWER
P = IV = I²R = V² / R
Where P is power in watts (W). The three equivalent forms arise from substituting Ohm's law into P = IV. The form P = I²R emphasizes that power dissipation is proportional to the square of the current—doubling the current quadruples the power lost as heat. Conversely, P = V²/R shows that for a fixed voltage, decreasing resistance increases power dissipation.
📐 Derivation Note
The three power expressions are not independent equations—they are algebraically equivalent. Starting from P = IV and substituting V = IR yields P = I(IR) = I²R. Alternatively, solving Ohm's law for I = V/R and substituting gives P = (V/R)V = V²/R. In any given problem, choose the form that uses the two quantities you already know.

Detailed Breakdown — How the Quantities Interrelate

The four circuit quantities are not isolated—they form a tightly coupled web described by Ohm's law and the power equation. The diagram below organizes all twelve possible rearrangements of these two fundamental relationships into a single reference, commonly known as the Ohm's Law Wheel or Power Wheel. Each quadrant of the wheel corresponds to one of the four quantities, and each expression within a quadrant gives a formula for computing that quantity from two of the remaining three.

The Ohm's Law and Power Wheel organizes twelve equivalent formulas for the four circuit quantities. Each quadrant lists three ways to compute that quantity from combinations of the other two. This is a powerful reference for circuit problem-solving.
Summary of units and dimensions for the four fundamental circuit quantities.
QuantitySymbolSI UnitUnit EquivalenceNamed After
CurrentIAmpere (A)C/sAndré-Marie Ampère
VoltageVVolt (V)J/C = kg·m²·s⁻³·A⁻¹Alessandro Volta
ResistanceROhm (Ω)V/A = kg·m²·s⁻³·A⁻²Georg Simon Ohm
PowerPWatt (W)J/s = V·A = kg·m²·s⁻³James Watt

Worked Example — Designing a Heater Element

Consider a portable space heater that must deliver 1500 W of thermal power when plugged into a standard North American 120 V outlet. We wish to determine the operating current, the resistance of the heating element, and the total energy consumed during 8 hours of continuous operation.

Space Heater Analysis
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Step 1 — Identify Given ValuesWe are given the power rating P = 1500 W and the supply voltage V = 120 V. We need to find the current I, the resistance R, and the total energy E consumed in t = 8 h.
Known: P = 1500 W, V = 120 V, t = 8 h = 28800 s
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Step 2 — Calculate CurrentUsing P = IV, we solve for current: I = P / V = 1500 W / 120 V.
I = 12.5 A
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Step 3 — Calculate ResistanceApplying Ohm's law: R = V / I = 120 V / 12.5 A. Equivalently, we could use R = V² / P = (120)² / 1500 = 14400 / 1500.
R = 9.60 Ω
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Step 4 — Verify with P = I²RAs a consistency check: P = I²R = (12.5)² × 9.60 = 156.25 × 9.60 = 1500 W. ✓ The result matches the rated power, confirming our values are internally consistent.
Verification passed: P = 1500 W ✓
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Step 5 — Calculate Total Energy ConsumedEnergy is power multiplied by time: E = P × t = 1500 W × 28800 s = 43,200,000 J = 43.2 MJ. In the more practical unit of kilowatt-hours: E = 1.5 kW × 8 h = 12.0 kWh. At a typical electricity rate of $0.12/kWh, this costs $1.44 per day of operation.
E = 12.0 kWh = 43.2 MJ

Strengths, Limitations & Common Misconceptions

The definitions of current, voltage, resistance, and power presented so far assume steady-state DC conditions and ohmic materials. While this framework is extraordinarily useful, it has boundaries that become important as circuits grow more complex.

AspectStrengthLimitation
Ohm's Law (V = IR)Simple, linear relationship; works extremely well for metals and standard resistors at constant temperature.Fails for non-ohmic devices (diodes, transistors, ionized gases) where R depends on V or I.
P = IVAlways valid for any two-terminal device; derived directly from the definitions of V and I.For AC circuits, must account for phase differences: P = IV cos φ (power factor), where cos φ < 1.
Conventional currentConsistent sign conventions simplify circuit analysis (Kirchhoff's laws, mesh analysis).Can cause conceptual confusion because electrons move opposite to conventional current direction.
Lumped-element modelReduces distributed physics to simple R, V, I, P at nodes and branches; fast analysis with Kirchhoff's laws.Breaks down at high frequencies or when component dimensions approach the signal wavelength (transmission-line effects).
COMMON MISCONCEPTION
Students often believe that current is "used up" as it flows through a resistor—that less current exits than enters. In reality, current is the same at every point in a series path (conservation of charge). What the resistor actually converts is electrical energy into heat. Think of it as water flowing through a turbine: the same volume per second flows in and out, but the water exits with lower pressure (lower potential), having surrendered energy to the turbine.

Connection to Advanced Circuit Theory

The four definitions introduced in this lesson form the bedrock upon which all of circuit analysis is built. As you progress through Physics 2 and into electrical engineering, these scalar DC quantities generalize into richer mathematical objects that handle time-varying signals, energy storage, and frequency-dependent behavior. The table below previews how each concept evolves.

How DC definitions generalize to AC and beyond.
DC Concept (This Lesson)AC / Advanced Generalization
Current I (constant)Time-varying current i(t); phasor representation Ĩ = I₀e^(jωt); current density J⃗ = σE⃗
Voltage V (constant)Time-varying voltage v(t); phasor Ṽ; Kirchhoff's voltage law generalized with Faraday's law (−dΦ/dt)
Resistance R (real, scalar)Impedance Z = R + jX (complex); includes reactance from capacitors (X_C = −1/ωC) and inductors (X_L = ωL)
Power P = IV (always positive for a resistor)Complex power S = P + jQ; real power P = VI cos φ; reactive power Q = VI sin φ; apparent power |S| = VI

Even in these more advanced settings, the fundamental definitions you learned today remain at the core. Impedance reduces to resistance when reactance is zero, complex power reduces to P = IV when current and voltage are in phase, and time-varying currents and voltages are still defined as dQ/dt and W/Q respectively—the calculus simply becomes explicit rather than hidden behind the steady-state assumption. Mastering the DC definitions thoroughly now will make every subsequent generalization feel like a natural extension rather than a new topic.

Practice Problems

PROBLEM 1CONCEPTUAL
A student claims that because a 100 W light bulb consumes more power than a 60 W bulb, it must draw more current. Is this statement necessarily true? Under what conditions could it be false?
PROBLEM 2BASIC CALCULATION
A 9.0 V battery drives a current of 0.30 A through a resistor. Calculate (a) the resistance of the resistor, (b) the power dissipated, and (c) the total charge that flows through the resistor in 5.0 minutes.
PROBLEM 3INTERMEDIATE
A nichrome wire heating element has resistivity ρ = 1.10 × 10⁻⁶ Ω·m, length L = 2.5 m, and diameter d = 0.50 mm. It is connected across a 24 V power supply. Find (a) the resistance of the wire, (b) the current through it, and (c) the power dissipated.
PROBLEM 4APPLIED
A USB Type-C cable rated for 5 A carries current from a 20 V adapter to charge a laptop. The cable has a total round-trip resistance of 0.080 Ω. Calculate (a) the power delivered to the laptop, (b) the power lost as heat in the cable, and (c) the efficiency of the power delivery (ratio of power delivered to total power supplied by the adapter).
PROBLEM 5CRITICAL THINKING
Power transmission lines carry electrical power over long distances. Explain, using the equations P = IV and P_loss = I²R, why power companies transmit electricity at very high voltages (e.g., 500 kV) rather than at the 120 V used in homes. If a power plant must deliver 100 MW over a line with total resistance 10 Ω, calculate the I²R losses for transmission at (a) 500 kV and (b) 10 kV, and discuss the implications.

Summary — Current, Voltage, Resistance & Power

Electric current (I) is the rate of charge flow, measured in amperes (A), and defined as I = dQ/dt. Voltage (V) is the electric potential difference between two points, measured in volts (V = J/C), and represents the energy available per unit charge to drive current through a circuit. Resistance (R) quantifies a material's opposition to current flow, measured in ohms (Ω), and is related to material properties through R = ρL/A. Ohm's law (V = IR) connects these three quantities for ohmic materials, establishing that current is directly proportional to voltage and inversely proportional to resistance.

Electric power (P) is the rate of energy conversion, measured in watts (W = J/s), with three equivalent forms: P = IV = I²R = V²/R. The quadratic dependence of power on current (I²R) explains why minimizing current through high-voltage transmission is essential for efficient power delivery. Together, these four quantities and their interrelationships form the complete foundation for DC circuit analysis and generalize naturally into the impedance, phasor, and complex-power frameworks used in AC circuit theory.

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