PHYSICAL CHEMISTRY 1 • THERMODYNAMIC FOUNDATIONS

First Law: Chemical Processes — Apply the first law to chemical processes (q, w, ΔU)

Understanding how heat, work, and internal energy govern the energetics of chemical reactions.

Historical Context & Motivation

The study of energy transformations in chemical processes has deep roots in the industrial and scientific revolutions. Before the first law of thermodynamics was formally articulated, engineers and natural philosophers struggled to understand why certain reactions released heat while others absorbed it, and how mechanical work could be extracted from chemical transformations. The concept of energy conservation — that energy can be neither created nor destroyed, only converted between forms — emerged gradually from the interplay of calorimetric experiments, steam engine optimization, and theoretical insights spanning nearly a century.

Applying the first law specifically to chemical processes required a precise framework for partitioning the energy changes of a reacting system into contributions from heat transfer (q), work (w), and changes in internal energy (ΔU). This partitioning is not merely bookkeeping — it reveals the fundamental constraints governing reaction energetics, the design of calorimeters, and the thermodynamic feasibility of industrial chemical processes.

1780s
Lavoisier & Laplace: Calorimetry
Antoine Lavoisier and Pierre-Simon Laplace developed the ice calorimeter to measure the heat evolved in combustion and respiration, establishing that chemical reactions involve measurable energy changes.
1840
Hess's Law of Constant Heat Summation
Germain Hess demonstrated that the total enthalpy change of a reaction is independent of the pathway taken, providing crucial evidence that heat of reaction is a state function — a key stepping stone toward the first law.
1843
Joule's Mechanical Equivalent of Heat
James Prescott Joule's paddle-wheel experiments quantified the conversion factor between mechanical work and heat, establishing that heat and work are interconvertible forms of energy and laying the empirical foundation for energy conservation.
1850
Clausius Formalizes the First Law
Rudolf Clausius synthesized the work of Joule, Mayer, and Helmholtz into a rigorous mathematical statement: ΔU = q + w. This formalization unified thermal, mechanical, and chemical energy within a single framework.
1880s–1900s
Bomb Calorimetry & Reaction Thermochemistry
Marcellin Berthelot and others perfected constant-volume bomb calorimetry, enabling precise measurement of ΔU for combustion reactions. This technique became the gold standard for tabulating internal energies and enthalpies of formation.

The central question that this lesson addresses is deceptively simple: when a chemical reaction occurs, how do we rigorously account for all the energy entering and leaving the system as heat and work, and how does the internal energy of the system change as a result? Answering this requires distinguishing between state functions and path functions, understanding the constraints imposed by constant-volume versus constant-pressure conditions, and mastering the quantitative relationship ΔU = q + w in the context of real chemical transformations.

Core Principles & Definitions

Before applying the first law to chemical processes, it is essential to establish precise definitions for the thermodynamic quantities involved. The system is the portion of the universe under study — typically the reacting mixture — while the surroundings comprise everything else. Energy transfer between system and surroundings occurs exclusively as heat (q) or work (w). The total energy stored within the system's molecular degrees of freedom — translational, rotational, vibrational kinetic energy plus intermolecular potential energy — constitutes the internal energy (U).

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Internal Energy (U) — State Function

U depends only on the current thermodynamic state (T, P, composition) of the system, not on how it reached that state. Changes in internal energy, ΔU = Ufinal − Uinitial, are path-independent and can be computed from the difference of state properties.
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Heat (q) — Path Function

Heat is the energy transferred due to a temperature difference between system and surroundings. It is a path function: its value depends on the specific process (constant V, constant P, adiabatic, etc.). Sign convention (IUPAC): q > 0 when heat flows into the system (endothermic).
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Work (w) — Path Function

Work includes pressure–volume (PV) work and non-expansion work (electrical, surface). For chemical processes, PV work dominates: w = −PextΔV for constant external pressure. Sign convention (IUPAC): w > 0 when work is done on the system (compression).
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First Law Statement

ΔU = q + w. The change in internal energy equals the sum of heat absorbed and work done on the system. This is a statement of energy conservation applied to a thermodynamic process. For an isolated system (q = 0, w = 0), ΔU = 0.
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State vs. Path Functions

While ΔU is uniquely determined by initial and final states, the individual contributions q and w are not. Different pathways between the same two states yield different values of q and w, but their sum q + w is always the same ΔU — a powerful constraint that underlies all thermochemical calculations.
⚠️ Sign Convention Alert
This lesson uses the IUPAC convention: ΔU = q + w, where q > 0 means heat flows into the system and w > 0 means work is done on the system. Some older textbooks use the engineering convention (ΔU = q − w), which defines w as work done by the system. Always verify which convention your course employs.
KEY TAKEAWAY
Think of internal energy as the balance of a bank account. Deposits can come from two sources — heat (q) and work (w) — and withdrawals likewise reduce the balance. The current balance (U) depends only on all past transactions, not on whether you deposited cash or transferred funds electronically. Any combination of q and w that produces the same net deposit leaves you with the same final balance. This is why ΔU is a state function even though q and w individually are not.

Visual Explanation — Energy Flow in Chemical Processes

The following diagram illustrates how the first law partitions energy changes during a chemical reaction under two important experimental conditions: constant volume (as in a bomb calorimeter) and constant pressure (as in an open beaker or flow reactor). Understanding the distinction between these two boundary conditions is central to applying the first law to real chemical processes.

At constant volume (left), the rigid walls prevent PV work, so all energy change appears as heat: qV = ΔU. At constant pressure (right), part of the energy change goes to PV work against the atmosphere, so qP = ΔH = ΔU + PΔV, and the measured heat corresponds to the enthalpy change.

The diagram highlights a crucial experimental distinction. In a bomb calorimeter (constant-volume device), the steel vessel constrains the reacting mixture so that ΔV = 0. With no volume change, PV work vanishes (w = −PextΔV = 0), and all energy change manifests as heat: qV = ΔU. This makes bomb calorimetry the most direct experimental route to ΔU. Conversely, in a constant-pressure process — the condition that applies to most bench-top chemistry — the system can expand or contract against the atmosphere, performing PV work. The measured heat then corresponds not to ΔU but to the enthalpy change ΔH, which is defined as H = U + PV. Understanding this distinction is essential for converting between ΔU and ΔH and for designing appropriate experimental measurements.

Mathematical Framework

The mathematical machinery for applying the first law to chemical processes centers on three equations of increasing specificity. We begin with the general statement of the first law, then specialize to the two most common experimental boundary conditions: constant volume and constant pressure.

FIRST LAW — GENERAL FORM
ΔU = q + w
ΔU = change in internal energy of the system (J or kJ); q = heat transferred to the system (positive when absorbed); w = work done on the system (positive when system is compressed). For only PV work: w = −PextΔV.
CONSTANT VOLUME (w = 0)
ΔU = qᵥ
When volume is held constant (ΔV = 0), no PV work is performed. The heat measured in a bomb calorimeter, qV, directly equals the change in internal energy. This is the basis of constant-volume calorimetry for measuring ΔU of combustion reactions.
CONSTANT PRESSURE
ΔU = qₚ − PΔV ⟹ qₚ = ΔU + PΔV = ΔH
At constant pressure, the heat measured (qP) equals the enthalpy change ΔH, not ΔU. Here H = U + PV is the enthalpy state function. This is the condition for most bench-top reactions, coffee-cup calorimetry, and biological processes at atmospheric pressure.
RELATING ΔH AND ΔU FOR REACTIONS INVOLVING IDEAL GASES
ΔH = ΔU + Δn_gas RT
Δngas = (moles of gaseous products) − (moles of gaseous reactants); R = 8.314 J mol⁻¹ K⁻¹; T = absolute temperature (K). This equation allows conversion between ΔH (obtained from constant-P calorimetry) and ΔU (obtained from constant-V calorimetry). For reactions with no change in gas-phase moles, ΔH ≈ ΔU.

The derivation of the last equation proceeds from the definition of enthalpy: ΔH = ΔU + Δ(PV). For an ideal gas, PV = nRT, so Δ(PV)gas = Δngas × RT (assuming T is constant or nearly so). For condensed phases (solids and liquids), the PV product changes negligibly with reaction, so Δ(PV)condensed ≈ 0. Combining these gives the relation ΔH = ΔU + ΔngasRT, which is indispensable for converting between bomb calorimetry data and standard enthalpies of reaction.

💡 When Does ΔH ≈ ΔU?
For reactions involving only solids and liquids (Δngas = 0), the PV work term is negligible, and ΔH ≈ ΔU. Even for gas-phase reactions, the ΔngasRT correction at 298 K is typically only a few kJ mol⁻¹ — often less than 1% of ΔH for highly exothermic combustion reactions. Nevertheless, precision thermochemistry demands the correction.

Detailed Breakdown — Types of Chemical Processes

Different types of chemical processes impose different constraints on the first law quantities q, w, and ΔU. A clear classification helps organize both experimental design and problem-solving strategies. The diagram below categorizes the major process types and their thermodynamic signatures.

Flowchart showing how the first law simplifies under three common boundary conditions: constant volume, constant pressure, and adiabatic. Each pathway leads to a different measurable quantity and a different experimental technique. The key relationship ΔH = ΔU + ΔngasRT connects the constant-volume and constant-pressure measurements.
Summary of how boundary conditions simplify the first law for chemical processes.
Process TypeConstraintFirst Law FormMeasured QuantityApparatus
Constant VolumeΔV = 0, w = 0ΔU = qVΔU directlyBomb calorimeter
Constant PressureP = const, w = −PΔVqP = ΔH = ΔU + PΔVΔH directlyCoffee-cup calorimeter
Adiabaticq = 0ΔU = wTemperature changeDewar flask / insulated vessel
Isothermal (Ideal Gas)T = const, ΔU = 0q = −wHeat = negative of workThermostatted vessel

For chemical reactions involving gaseous reactants or products, the PV work term can be significant. Consider a reaction that produces gas: the expanding gas does work on the surroundings (w < 0 in the IUPAC convention), which means less of the reaction's energy release appears as heat and more goes into pushing back the atmosphere. The magnitude of this correction is captured by the ΔngasRT term, where Δngas counts the change in moles of gaseous species. At 298 K, each mole of net gas production contributes approximately 2.48 kJ mol⁻¹ to the difference between ΔH and ΔU — a small but thermochemically important correction.

Worked Example — Combustion of Methane

We now apply the first law framework to a concrete chemical process: the complete combustion of methane in a bomb calorimeter, followed by conversion of the result to the standard enthalpy of combustion at constant pressure.

Combustion of Methane: Finding ΔU and ΔH
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Step 1 — Write the Balanced EquationThe balanced equation for the complete combustion of methane is: CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(l). Note that water is produced as liquid under standard conditions in a bomb calorimeter.
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Step 2 — Identify the Experimental ConstraintThe reaction occurs in a bomb calorimeter: a rigid, sealed steel vessel. This means the process occurs at constant volume. Therefore ΔV = 0, w = 0, and the first law reduces to ΔU = qV.
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Step 3 — Record the Calorimetric DataSuppose the bomb calorimeter has a heat capacity Ccal = 10.00 kJ K⁻¹. Combustion of 1.000 g of CH4 (M = 16.04 g mol⁻¹) raises the calorimeter temperature by ΔT = 5.563 K.
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Step 4 — Calculate qᵥ per MoleThe heat released is absorbed by the calorimeter: qcal = Ccal × ΔT = 10.00 kJ K⁻¹ × 5.563 K = 55.63 kJ. Since the system (methane) loses heat, qV for the reaction is −55.63 kJ for 1.000 g. Converting to molar: n = 1.000 g ÷ 16.04 g mol⁻¹ = 0.06234 mol. Therefore qV per mole = −55.63 kJ ÷ 0.06234 mol = −892.5 kJ mol⁻¹.
ΔU = qV = −892.5 kJ mol⁻¹
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Step 5 — Calculate ΔngasCount gaseous moles: products have 1 mol CO2(g); reactants have 1 mol CH4(g) + 2 mol O2(g) = 3 mol gas. H2O is liquid and does not count. Thus Δngas = 1 − 3 = −2 mol.
Δngas = −2
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Step 6 — Convert ΔU to ΔHUsing ΔH = ΔU + ΔngasRT: ΔH = −892.5 kJ mol⁻¹ + (−2)(8.314 × 10⁻³ kJ mol⁻¹ K⁻¹)(298 K) = −892.5 kJ mol⁻¹ + (−4.95 kJ mol⁻¹) = −897.5 kJ mol⁻¹. This matches the tabulated standard enthalpy of combustion ΔcH° = −890.4 kJ mol⁻¹ (minor discrepancies arise from the simplified calorimeter data used here).
ΔH = −897.5 kJ mol⁻¹
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Step 7 — Interpret the ResultsBecause Δngas < 0, the system contracts upon reaction, and the surroundings do PV work on the system. This makes |ΔH| > |ΔU|: the enthalpy change is more negative than the internal energy change. Physically, the atmosphere 'pushes in' on the reacting system as the number of gas moles decreases, contributing additional energy to the system beyond the heat released.

Strengths, Limitations & Comparisons

The first law provides a rigorous energy balance for chemical processes but, like any framework, has both strengths and limitations. Understanding these boundaries is essential for knowing when the first law alone suffices and when additional thermodynamic laws or statistical mechanical treatments are needed.

Strengths and limitations of applying the first law to chemical processes.
AspectStrengthLimitation
Energy accountingProvides an exact, model-independent energy balance. ΔU = q + w holds universally for any closed system regardless of molecular details.Cannot predict the direction of spontaneous change. An exothermic reaction (ΔU < 0) is not guaranteed to be spontaneous — this requires the second law.
State function propertyΔU depends only on initial and final states, enabling use of Hess's law and tabulated thermochemical data to calculate ΔU for reactions never directly measured.Individual q and w are path-dependent and cannot be tabulated. You must specify the path (const. V, const. P, etc.) before computing them.
Experimental accessBomb calorimetry gives ΔU directly; coffee-cup calorimetry gives ΔH directly. The relationship ΔH = ΔU + ΔnRT allows interconversion.Accurate calorimetry requires careful calibration, and the ideal-gas assumption in ΔnRT may fail at high pressures or for non-ideal gas mixtures.
ScopeApplies to all chemical processes — combustion, neutralization, dissolution, phase transitions, electrochemical reactions.Does not partition energy changes into molecular contributions (bond energies, intermolecular forces). That requires statistical thermodynamics or quantum chemistry.
🔗 CONTEXTUAL TAKEAWAY
The first law is like a financial audit: it tells you exactly how much money (energy) entered and left, and what the final balance (ΔU) is. However, it cannot tell you whether a particular transaction (reaction) will actually occur spontaneously — just as knowing your income and expenses doesn't tell you whether starting a business will succeed. For that, you need the second law (entropy and free energy), which acts as the market analysis of thermodynamics.

Connection to Advanced Theory

The first law framework for chemical processes serves as the foundation for several more advanced thermodynamic concepts. At this introductory level, you have learned to partition energy changes into q and w and to distinguish ΔU from ΔH. As you progress in physical chemistry, these ideas extend naturally into more powerful formulations.

How first-law concepts for chemical processes connect to advanced physical chemistry topics.
This LessonAdvanced ExtensionWhere You'll Encounter It
ΔU = q + w (finite changes)dU = δq + δw (infinitesimal form); exact vs. inexact differentials; state functions from Euler's criterionMathematical methods in thermodynamics
ΔH = ΔU + ΔnRT (ideal gas)Departure functions for real gases; fugacity corrections; ΔH from equations of state (van der Waals, Peng–Robinson)Equations of state and real gas thermodynamics
ΔU and ΔH from calorimetryKirchhoff's equation: temperature dependence of ΔH via heat capacities; ΔH(T₂) = ΔH(T₁) + ∫ΔCₚ dTThermochemistry and temperature corrections
Energy conservation (1st law alone)Combined 1st + 2nd law: dU = TdS − PdV; Gibbs and Helmholtz free energies; Maxwell relationsGibbs free energy, chemical equilibrium, and spontaneity
w = −PₑₓₜΔV (irreversible PV work)Reversible work: w = −∫P dV; maximum work theorems; connection to equilibrium constants via ΔG = −RT ln KReversible processes and chemical equilibria

A particularly important bridge concept is the combined first and second law expression dU = TdS − PdV for a closed system doing only PV work. This equation unifies the energy balance (first law) with the directionality constraint (second law) and generates all of classical thermodynamics through the Legendre transforms that define H, A, and G. Your current mastery of ΔU, q, and w provides the concrete physical intuition on which these more abstract formulations are built. In particular, understanding that qrev = TΔS connects the measurable heat of the first law to the entropy change of the second law, closing the circle between energy accounting and spontaneity prediction.

Practice Problems

PROBLEM 1CONCEPTUAL
A chemist performs two separate measurements of the same reaction: one in a bomb calorimeter and one in a coffee-cup calorimeter. She measures different values of heat. Explain why the two heat values differ even though the reaction is the same. Is ΔU the same in both experiments? Is ΔH?
PROBLEM 2BASIC CALCULATION
When 1.00 mol of ethanol (C2H5OH) is burned completely in a bomb calorimeter at 298 K, the measured heat is qV = −1364.0 kJ. The balanced reaction is: C2H5OH(l) + 3 O2(g) → 2 CO2(g) + 3 H2O(l). Calculate ΔU and ΔH for this reaction.
PROBLEM 3INTERMEDIATE
The decomposition of ammonium nitrate can be written as: NH4NO3(s) → N2O(g) + 2 H2O(g). Given that ΔrH° = −36.0 kJ mol⁻¹ at 298 K, calculate ΔrU° at 298 K. Explain why ΔU is more negative than ΔH for this reaction.
PROBLEM 4APPLIED
A chemical engineer needs to determine the internal energy of combustion of a new biofuel. She burns 0.5000 g of the fuel (molar mass = 100.0 g mol⁻¹) in a bomb calorimeter with heat capacity Ccal = 8.50 kJ K⁻¹. The temperature rises by 3.24 K. The combustion produces 4 mol CO2(g) and 4 mol H2O(l) per mole of fuel burned, consuming 5 mol O2(g). Calculate (a) ΔU per mole of fuel, (b) ΔH at 298 K, and (c) the PV work that would be done if this reaction occurred at constant pressure.
PROBLEM 5CRITICAL THINKING
Consider a reaction at 298 K in which Δngas = +5. (a) Derive an expression for the percentage difference between ΔH and ΔU in terms of Δngas, R, T, and ΔU. (b) If ΔU = −3000 kJ mol⁻¹, calculate this percentage. (c) Under what circumstances would the approximation ΔH ≈ ΔU break down badly, and what physical situation would produce this? (d) Critically assess whether the ideal gas assumption underlying ΔH = ΔU + ΔngasRT is valid for a reaction at 500 atm and 298 K.

Summary

The first law of thermodynamics states that ΔU = q + w, where internal energy (U) is a state function whose change depends only on the initial and final states, while heat (q) and work (w) are path functions whose values depend on the specific process. At constant volume, w = 0 and qV = ΔU, making bomb calorimetry a direct measurement of internal energy change. At constant pressure, qP = ΔH = ΔU + PΔV, connecting the measured heat to the enthalpy change.

The critical conversion equation ΔH = ΔU + ΔngasRT allows interconversion between constant-volume and constant-pressure data, where Δngas is the change in moles of gaseous species. For reactions with no change in gas-phase moles, ΔH ≈ ΔU. While the first law provides a complete energy balance for any chemical process, it cannot predict spontaneity or equilibrium position — these require the second law and the Gibbs free energy. Mastery of the first law applied to chemical processes is the essential foundation for all subsequent thermodynamic reasoning in physical chemistry.

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