MCAT Physical › Wavelength, Frequency, and Period
Waves hit a beach every three seconds. The horizontal distance between an adjacent maximum and minimum is one meter. What is the speed of the waves?
Wave velocity is given by the product of frequency and wavelength:
In the question, we are given the period (waves per second). To find the frequency, we will need to take the reciprocal of the period.
Using the values given in the question, we can find the velocity of the waves. The wavelength is twice the distance between adjacent maxima and minima, making our wavelength two meters.
Picture a transverse wave traveling through water. After the crest of one wave hits a stationary object in the water, an observer counts eight more crests hitting the same object in fifteen seconds. The frequency of the waves is __________.
0.53s-1
1.9s-1
1.9s
120s
Right away you can rule out the answers with units in seconds, as the unit of frequency is an inverse second, or Hz. Frequency is measured in cycles per second. If eight crests pass a given point in fifteen seconds, the frequency is given by the number of crests divided by the time period.
An electron falls from an excited state to its ground state, emitting a photon at . What is the frequency of the emitted light?
The relationship between wavelength and frequency is given by the equation:
In this case, the velocity will be equal to the speed of light.
Using this value and the given wavelength, we can find the frequency of the photon. Keep in mind that the wavelength must be given in meters.
An incandescent light bulb is shown through a glass prism. The certain wavlength of the light is then directed into a glass cuvette containing an unknown concentration of protein. Commonly, this process is called spectroscopy and is used to determine the concentrations of DNA, RNA, and proteins in solutions. The indices of reflection of air, glass, and the solution are 1, 1.5, and 1.3, respectively.
What property of light does not change when it enters the prism?
Frequency
Wavelength
Velocity
More than one of these stays constant
The frequency of light does not change when it enters a medium with a different index of refraction; in this case, that new medium is the glass of the prism. From the velocity of light equation we know the relationship between velocity and frequency.
v is the velocity of light, is the wavelength, and f is the frequency. When light enters the prism, its velocity changes due to the new index of refraction, but its frequency remains constant.
Because the frequency does not change, we can see that velocity is directly proportional to wavelength; thus, the shorter the wavelength, the slower the velocity. So both wavelength and velocity change when frequency is constant.
A transverse wave has a velocity of 5.2m/s. If ten cycles pass a given point in 1.6s, what are the wave’s period and wavelength?
0.16s and 0.83m
0.16s and 8.3m
6.25s and 0.83m
6.25s and 8.3m
First calculate the frequency of the wave (cycles/sec). The problem tells us that there are ten cycles in 1.6s.
Next find the period by taking the inverse of the frequency.
Finally, find the wavelength by dividing the velocity by the frequency.
A stretched string of length L, mass M, and tension T is vibrating at its fundamental frequency. Which of the following changes takes place if the vibration frequency of the string increases, but tension and mass density remain constant?
Wavelength decreases
Number of nodes decreases
Velocity increases
More than one of the other options
None of the other options
We can use the equation together with
. If T is constant, v cannot change assuming the mass density, m/L, is constant. Thus,
must be constant; if f increases,
must decrease.
What are the frequency and wavelength of a sound wave with a period of 0.04s and a velocity of 575m/s?
25Hz and 23m
25Hz and 0.44m
1.0Hz and 14,400m
25Hz and 14,400m
Solve for frequency by taking the inverse of the period.
Next, solve for wavelength by dividing velocity by frequency.
What is the beat frequency if f1 = 200Hz and f2 = 150Hz?
50Hz
350Hz
35Hz
100Hz
200Hz
Beat frequency is the difference between the two frequencies.
200Hz – 150Hz = 50Hz
What is the relationship between frequency and period of a sine wave?
The period of a wave is equal to the reciprocal of the frequency:
Respectively, frequency is the reciprocal of period. By definition, the product of two reciprocals is one.
What is the frequency of a typical soundwave traveling at 340m/s with a wavelength of 40mm?
8500Hz
90Hz
300Hz
10000Hz
7500Hz
Using the equation we can find the frequency of the soundwave.