How to find the area of a rectangle

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Math › How to find the area of a rectangle

Questions 1 - 10

What is the area of the figure below?

Explanation

To find the area of the figure above, we need to slip the figure into two rectangles.

11.5

Using our area formula, $A=l\times w$ , we can solve for the area of both of our rectangles

$A=8\times 4$ $A=7\times 4$

To find our final answer, we need to add the areas together.

Use the following image to answer the question:

Rectangle3

Find the area of the rectangle.

$54\text{in}^2$

$30\text{in}^2$

$15\text{in}^2$

$63\text{in}^2$

$36\text{in}^2$

Explanation

To find the area of a rectangle, we will use the following formula:

$\text{area of rectangle} = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, let's look at the rectangle.

Rectangle3

We can see the length is 9 inches, and the width is 6 inches.

Knowing this, we can substitute into the formula. We get

$\text{area of rectangle} = 9\text{in} \cdot 6\text{in}$

$\text{area of rectangle} = 54\text{in}^2$

Find the area of a rectangle with a length of 24in and a width that is a third of the length.

$192\text{in}^2$

$72\text{in}^2$

$96\text{in}^2$

$156\text{in}^2$

$212\text{in}^2$

Explanation

To find the area of a rectangle, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the length of the rectangle is 24in. We also know the width is a third of the length. Therefore, the width is 8in.

Knowing this, we can substitute into the formula. We get

$A = 24\text{in} \cdot 8\text{in}$

$A = 196\text{in}^2$

Find the area of a rectangle with a width of 9cm and a length that is two times the width.

$162\text{cm}^2$

$128\text{cm}^2$

$18\text{cm}^2$

$24\text{cm}^2$

$32\text{cm}^2$

Explanation

To find the area of a rectangle, we will use the following formula:

$\text{area of rectangle} = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the width of the rectangle is 9cm. We also know the length of the rectangle is two times the width. Therefore, the length is 18cm.

Knowing this, we will substitute into the formula. We get

$\text{area of rectangle} = 18\text{cm} \cdot 9\text{cm}$

$\text{area of rectangle} = 162\text{cm}^2$

Find the area of a rectangle with a length of 12cm and a width that is a quarter of the length.

$36\text{cm}^2$

$48\text{cm}^2$

$16\text{cm}^2$

$25\text{cm}^2$

$30\text{cm}^2$

Explanation

To find the area of a rectangle, we will use the following formula:

$\text{area of rectangle} = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the length of the rectangle is 12cm. We also know the width of the rectangle is a quarter of the length. To find the width, we will divide 12 by 4. Therefore, the width the 3cm.

Knowing this, we will substitute into the formula. We get

$\text{area of rectangle} = 12\text{cm} \cdot 3\text{cm}$

$\text{area of rectangle} = 36\text{cm}^2$

What is the area of the figure below?

Explanation

To find the area of the figure above, we need to slip the figure into two rectangles.

12.5

Using our area formula, $A=l\times w$ , we can solve for the area of both of our rectangles

$A=6\times 8$ $A=7\times 5$

To find our final answer, we need to add the areas together.

Find the area of a rectangle with a length of 16cm and a width that is a quarter of the length.

$64\text{cm}^2$

$128\text{cm}^2$

$31\text{cm}^2$

$32\text{cm}^2$

$62\text{cm}^2$

Explanation

To find the area of a rectangle, we will use the following formula:

$A = l \cdot w$

where l is the length and w is the width of the rectangle.

Now, we know the length of the rectangle is 16cm. We also know the width of the rectangle is a quarter of the length. To find the width, we will divide 16 by 4. Therefore, the width the 4cm.

Knowing this, we will substitute into the formula. We get

$A = 16\text{cm} \cdot 4\text{cm}$

$A = 64\text{cm}^2$

A rectangle is two feet shorter than twice its width; its perimeter is six yards. Give its area in square inches.

$2,816 \textrm{ in}^{2}$

$7,128 \textrm{ in}^{2}$

$1,386 \textrm{ in}^{2}$

$2,475 \textrm{ in}^{2}$

$2,772 \textrm{ in}^{2}$

Explanation

The length of the rectangle is two feet, or 24 inches, shorter than twice the width, so, if is the width in inches, the length in inches is

Six yards, the perimeter of the rectangle, is equal to $36 \times 6 = 216$ inches. The perimeter, in terms of length and width, is , so we can set up the equation:

$6W \div 6 = 264 \div 6$

The length and width are 64 inches and 44 inches; the area is their product, which is

$44 \times 64 = 2,816$ square inches

The sum of the lengths of three sides of a rectangle is 572 inches; the width of the rectangle is 60% of its length. Give its area in square inches.

It is impossible to determine the area from the given information.

$40,560 \textrm{ in}^{2}$

$29,040 \textrm{ in}^{2}$

$48,400\textrm{ in}^{2}$

$67,600\textrm{ in}^{2}$

Explanation

Since the width of the rectangle is 60% of its length, we can write .

However, it is not clear from the problem which three sides - two lengths and a width or two widths and a length - we are choosing to have sum 572 inches. Depending on the three sides chosen, we can either set up