Factoring Polynomials - Math
Card 0 of 64
Factor the following expression:

Factor the following expression:
You can see that each term in the equation has an "x", therefore by factoring "x" from each term you can get that the equation equals
.
You can see that each term in the equation has an "x", therefore by factoring "x" from each term you can get that the equation equals .
Compare your answer with the correct one above
Find the zeros.

Find the zeros.
This is a difference of perfect cubes so it factors to
. Only the first expression will yield an answer when set equal to 0, which is 1. The second expression will never cross the
-axis. Therefore, your answer is only 1.
This is a difference of perfect cubes so it factors to . Only the first expression will yield an answer when set equal to 0, which is 1. The second expression will never cross the
-axis. Therefore, your answer is only 1.
Compare your answer with the correct one above
Find the zeros.

Find the zeros.
Factor the equation to
. Set
and get one of your
's to be
. Then factor the second expression to
. Set them equal to zero and you get
.
Factor the equation to . Set
and get one of your
's to be
. Then factor the second expression to
. Set them equal to zero and you get
.
Compare your answer with the correct one above
Factor 
Factor
Use the difference of perfect cubes equation:

In
,
and ![b=\sqrt[3]{64}=4](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/94643/gif.latex)


Use the difference of perfect cubes equation:
In ,
and
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Factor this expression:

Factor this expression:
First consider all the factors of 12:
1 and 12
2 and 6
3 and 4
Then consider which of these pairs adds up to 7. This pair is 3 and 4.
Therefore the answer is
.
First consider all the factors of 12:
1 and 12
2 and 6
3 and 4
Then consider which of these pairs adds up to 7. This pair is 3 and 4.
Therefore the answer is .
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Factor the following polynomial:

Factor the following polynomial:
Begin by extracting
from the polynomial:


Now, factor the remainder of the polynomial as a difference of cubes:

Begin by extracting from the polynomial:
Now, factor the remainder of the polynomial as a difference of cubes:
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Factor the following polynomial:

Factor the following polynomial:
Begin by rearranging like terms:


Now, factor out like terms:

Rearrange the polynomial:

Begin by rearranging like terms:
Now, factor out like terms:
Rearrange the polynomial:
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Factor the following polynomial:

Factor the following polynomial:
Begin by rearranging like terms:


Now, factor out like terms:

Rearrange the polynomial:

Factor:


Begin by rearranging like terms:
Now, factor out like terms:
Rearrange the polynomial:
Factor:
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Factor the following polynomial:

Factor the following polynomial:
Begin by separating
into like terms. You do this by multiplying
and
, then finding factors which sum to 


Now, extract like terms:

Simplify:

Begin by separating into like terms. You do this by multiplying
and
, then finding factors which sum to
Now, extract like terms:
Simplify:
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Factor the following polynomial:

Factor the following polynomial:
To begin, distribute the squares:

![[(3a-4b)+(a+3b)][(3a-4b)-(a+3b)]](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/153192/gif.latex)
Now, combine like terms:

To begin, distribute the squares:
Now, combine like terms:
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Factor the following polynomial:

Factor the following polynomial:
Begin by extracting
from the polynomial:


Now, distribute the cubic polynomial:

Begin by extracting from the polynomial:
Now, distribute the cubic polynomial:
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Factor the following polynomial:

Factor the following polynomial:
Begin by extracting like terms:


Now, rearrange the right side of the polynomial by reversing the signs:

Combine like terms:

Factor the square and cubic polynomial:

Begin by extracting like terms:
Now, rearrange the right side of the polynomial by reversing the signs:
Combine like terms:
Factor the square and cubic polynomial:
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Factor the following polynomial:

Factor the following polynomial:
Begin by rearranging the terms to group together the quadratic:


Now, convert the quadratic into a square:

Finally, distribute the
:

Begin by rearranging the terms to group together the quadratic:
Now, convert the quadratic into a square:
Finally, distribute the :
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Factor the following polynomial:

Factor the following polynomial:
Begin by extracting
from the polynomial:


Now, rearrange to combine like terms:

Extract the like terms and factor the cubic:

Simplify by combining like terms:

Begin by extracting from the polynomial:
Now, rearrange to combine like terms:
Extract the like terms and factor the cubic:
Simplify by combining like terms:
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Factor the following polynomial:

Factor the following polynomial:
Begin by extracting
from the polynomial:


Now, rearrange to combine like terms:

Extract the like terms and factor the cubic:

Simplify by combining like terms:




Begin by extracting from the polynomial:
Now, rearrange to combine like terms:
Extract the like terms and factor the cubic:
Simplify by combining like terms:
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Factor the following expression:

Factor the following expression:
You can see that each term in the equation has an "x", therefore by factoring "x" from each term you can get that the equation equals
.
You can see that each term in the equation has an "x", therefore by factoring "x" from each term you can get that the equation equals .
Compare your answer with the correct one above
Find the zeros.

Find the zeros.
This is a difference of perfect cubes so it factors to
. Only the first expression will yield an answer when set equal to 0, which is 1. The second expression will never cross the
-axis. Therefore, your answer is only 1.
This is a difference of perfect cubes so it factors to . Only the first expression will yield an answer when set equal to 0, which is 1. The second expression will never cross the
-axis. Therefore, your answer is only 1.
Compare your answer with the correct one above
Find the zeros.

Find the zeros.
Factor the equation to
. Set
and get one of your
's to be
. Then factor the second expression to
. Set them equal to zero and you get
.
Factor the equation to . Set
and get one of your
's to be
. Then factor the second expression to
. Set them equal to zero and you get
.
Compare your answer with the correct one above
Factor 
Factor
Use the difference of perfect cubes equation:

In
,
and ![b=\sqrt[3]{64}=4](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/94643/gif.latex)


Use the difference of perfect cubes equation:
In ,
and
Compare your answer with the correct one above
Factor this expression:

Factor this expression:
First consider all the factors of 12:
1 and 12
2 and 6
3 and 4
Then consider which of these pairs adds up to 7. This pair is 3 and 4.
Therefore the answer is
.
First consider all the factors of 12:
1 and 12
2 and 6
3 and 4
Then consider which of these pairs adds up to 7. This pair is 3 and 4.
Therefore the answer is .
Compare your answer with the correct one above