Geometry Flashcards - MAP 7th Grade Math

Question

What is the area of the circle provided?

Answer

In order to solve this problem, we need to recall the formula for the area of a circle:

$A= r^2\pi$

The circle in this question provides us with the radius, so we can use the formula to solve:

$A=32^2\pi$

Solve:

$A=1\textup,024\pi\textup{ in}^2$

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Question

The figure represents a set of complementary angles, solve for .

Answer

Complementary angles are defined as two angles that when added together equal $90^\circ$

From the question, we know that the two angles are complimentary, and thus equal $90^\circ$ , so we can set up the following equation:

Next we can solve for :

$\frac{\begin{array}[b]{r}x+20=90\ -20-20\end{array}}{x= 70}$

Compare your answer with the correct one above

Question

Calculate the volume of the provided figure.

Answer

In order to solve this problem, we need to recall the volume formula for a cube:

$V=l\times w\times h$

Now that we have the correct formula, we can substitute in our known values and solve:

$V=6\times6\times6$

$V=216\textup{ in}^3$

Compare your answer with the correct one above

Question

What is the area of the circle provided?

Answer

In order to solve this problem, we need to recall the formula for the area of a circle:

$A= r^2\pi$

The circle in this question provides us with the radius, so we can use the formula to solve:

$A=32^2\pi$

Solve:

$A=1\textup,024\pi\textup{ in}^2$

Compare your answer with the correct one above

Question

The figure represents a set of complementary angles, solve for .

Answer

Complementary angles are defined as two angles that when added together equal $90^\circ$

From the question, we know that the two angles are complimentary, and thus equal $90^\circ$ , so we can set up the following equation:

Next we can solve for :

$\frac{\begin{array}[b]{r}x+20=90\ -20-20\end{array}}{x= 70}$

Compare your answer with the correct one above

Question

Calculate the volume of the provided figure.

Answer

In order to solve this problem, we need to recall the volume formula for a cube:

$V=l\times w\times h$

Now that we have the correct formula, we can substitute in our known values and solve:

$V=6\times6\times6$

$V=216\textup{ in}^3$

Compare your answer with the correct one above

Question

What is the area of the circle provided?

Answer

In order to solve this problem, we need to recall the formula for the area of a circle:

$A= r^2\pi$

The circle in this question provides us with the radius, so we can use the formula to solve:

$A=32^2\pi$

Solve:

$A=1\textup,024\pi\textup{ in}^2$

Compare your answer with the correct one above

Question

The figure represents a set of complementary angles, solve for .

Answer

Complementary angles are defined as two angles that when added together equal $90^\circ$

From the question, we know that the two angles are complimentary, and thus equal $90^\circ$ , so we can set up the following equation:

Next we can solve for :

$\frac{\begin{array}[b]{r}x+20=90\ -20-20\end{array}}{x= 70}$

Compare your answer with the correct one above

Question

Calculate the volume of the provided figure.

Answer

In order to solve this problem, we need to recall the volume formula for a cube:

$V=l\times w\times h$

Now that we have the correct formula, we can substitute in our known values and solve:

$V=6\times6\times6$

$V=216\textup{ in}^3$

Compare your answer with the correct one above

Question

What is the area of the circle provided?

Answer

In order to solve this problem, we need to recall the formula for the area of a circle:

$A= r^2\pi$

The circle in this question provides us with the radius, so we can use the formula to solve:

$A=32^2\pi$

Solve:

$A=1\textup,024\pi\textup{ in}^2$

Compare your answer with the correct one above

Question

The figure represents a set of complementary angles, solve for .

Answer

Complementary angles are defined as two angles that when added together equal $90^\circ$

From the question, we know that the two angles are complimentary, and thus equal $90^\circ$ , so we can set up the following equation:

Next we can solve for :

$\frac{\begin{array}[b]{r}x+20=90\ -20-20\end{array}}{x= 70}$

Compare your answer with the correct one above

Question

Calculate the volume of the provided figure.

Answer

In order to solve this problem, we need to recall the volume formula for a cube:

$V=l\times w\times h$

Now that we have the correct formula, we can substitute in our known values and solve:

$V=6\times6\times6$

$V=216\textup{ in}^3$

Compare your answer with the correct one above

Tap the card to reveal the answer

Geometry - MAP 7th Grade Math

What is the area of the circle provided?

In order to solve this problem, we need to recall the formula for the area of a circle: The circle in this question provides us with the radius, so we can use the formula to solve: Solve:

The figure represents a set of complementary angles, solve for .

Complementary angles are defined as two angles that when added together equal From the question, we know that the two angles are complimentary, and thus equal , so we can set up the following equation: Next we can solve for :

Calculate the volume of the provided figure.

In order to solve this problem, we need to recall the volume formula for a cube: Now that we have the correct formula, we can substitute in our known values and solve:

What is the area of the circle provided?

In order to solve this problem, we need to recall the formula for the area of a circle: The circle in this question provides us with the radius, so we can use the formula to solve: Solve:

The figure represents a set of complementary angles, solve for .

Complementary angles are defined as two angles that when added together equal From the question, we know that the two angles are complimentary, and thus equal , so we can set up the following equation: Next we can solve for :

Calculate the volume of the provided figure.

In order to solve this problem, we need to recall the volume formula for a cube: Now that we have the correct formula, we can substitute in our known values and solve:

What is the area of the circle provided?

In order to solve this problem, we need to recall the formula for the area of a circle: The circle in this question provides us with the radius, so we can use the formula to solve: Solve:

The figure represents a set of complementary angles, solve for .

Complementary angles are defined as two angles that when added together equal From the question, we know that the two angles are complimentary, and thus equal , so we can set up the following equation: Next we can solve for :

Calculate the volume of the provided figure.

In order to solve this problem, we need to recall the volume formula for a cube: Now that we have the correct formula, we can substitute in our known values and solve:

What is the area of the circle provided?

In order to solve this problem, we need to recall the formula for the area of a circle: The circle in this question provides us with the radius, so we can use the formula to solve: Solve:

The figure represents a set of complementary angles, solve for .

Complementary angles are defined as two angles that when added together equal From the question, we know that the two angles are complimentary, and thus equal , so we can set up the following equation: Next we can solve for :

Calculate the volume of the provided figure.

In order to solve this problem, we need to recall the volume formula for a cube: Now that we have the correct formula, we can substitute in our known values and solve:

In order to solve this problem, we need to recall the formula for the area of a circle:

$A= r^2\pi$

The circle in this question provides us with the radius, so we can use the formula to solve:

$A=32^2\pi$

Solve:

$A=1\textup,024\pi\textup{ in}^2$

In order to solve this problem, we need to recall the volume formula for a cube:

$V=l\times w\times h$

Now that we have the correct formula, we can substitute in our known values and solve:

$V=6\times6\times6$

$V=216\textup{ in}^3$

In order to solve this problem, we need to recall the formula for the area of a circle:

$A= r^2\pi$

The circle in this question provides us with the radius, so we can use the formula to solve:

$A=32^2\pi$

Solve:

$A=1\textup,024\pi\textup{ in}^2$

In order to solve this problem, we need to recall the volume formula for a cube:

$V=l\times w\times h$

Now that we have the correct formula, we can substitute in our known values and solve:

$V=6\times6\times6$

$V=216\textup{ in}^3$

In order to solve this problem, we need to recall the formula for the area of a circle:

$A= r^2\pi$

The circle in this question provides us with the radius, so we can use the formula to solve:

$A=32^2\pi$

Solve:

$A=1\textup,024\pi\textup{ in}^2$

In order to solve this problem, we need to recall the volume formula for a cube:

$V=l\times w\times h$

Now that we have the correct formula, we can substitute in our known values and solve:

$V=6\times6\times6$

$V=216\textup{ in}^3$

In order to solve this problem, we need to recall the formula for the area of a circle:

$A= r^2\pi$

The circle in this question provides us with the radius, so we can use the formula to solve:

$A=32^2\pi$

Solve:

$A=1\textup,024\pi\textup{ in}^2$

In order to solve this problem, we need to recall the volume formula for a cube:

$V=l\times w\times h$

Now that we have the correct formula, we can substitute in our known values and solve:

$V=6\times6\times6$

$V=216\textup{ in}^3$