IB PHYSICS • SPACE, TIME AND MOTION

Understand Work, Energy & Power — Understand A.3 Work, energy and power

Discover how forces transfer energy and how quickly that transfer happens in real-world systems.

Historical Context & Motivation

The concepts of work, energy, and power did not appear overnight. They were forged through centuries of scientific inquiry, driven by practical questions: How do machines lift heavy loads? Why does a moving cannonball cause damage? How much fuel does a steam engine need? Before these ideas were formalized, physicists struggled to describe the transfer of motion from one object to another. The journey from vague notions of "living force" to the precise equations you will learn in this lesson is a fascinating chapter in the history of physics.

1687
Newton's Laws of Motion
Isaac Newton published the Principia, establishing force and acceleration as the backbone of mechanics, but he did not explicitly define work or energy.
1807
Thomas Young Coins "Energy"
The English polymath Thomas Young first used the word "energy" in a physics context, referring to the quantity ½mv², moving the concept toward formal recognition.
1829
Coriolis Defines "Work"
French engineer Gaspard-Gustave de Coriolis defined mechanical work as force multiplied by displacement, giving engineers a precise way to measure what machines accomplish.
1845
Joule's Mechanical Equivalent of Heat
James Prescott Joule demonstrated that mechanical work and heat are interchangeable, laying the groundwork for the law of conservation of energy. The SI unit of energy (the joule) honors his contribution.
1882
Watt and the Concept of Power
Although James Watt improved the steam engine a century earlier, the formal unit of power—the watt—was adopted in his honor, quantifying how quickly energy is transferred.

The central question these scientists pursued is one you will answer in this lesson: How do we measure the effect of a force acting over a distance, and how fast is that effect delivered? Understanding work, energy, and power gives you a toolkit that is often simpler and more powerful than analyzing forces alone.

Core Principles & Definitions

Work, energy, and power are tightly connected, but each has a distinct meaning. Before diving into equations, it is essential to understand what each term really means and how they relate to one another. These three concepts together allow you to analyze any physical process in terms of energy transfer rather than individual forces.

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Work (W)

Work is the energy transferred to or from an object by a force acting over a displacement. If the force has a component in the direction of motion, positive work is done. If the force opposes the motion, negative work is done. Work is measured in joules (J).
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Energy (E)

Energy is the capacity to do work. It exists in many forms—kinetic, gravitational potential, elastic potential, thermal, and more. Energy can be transferred between objects or converted from one form to another, but the total energy in a closed system remains constant.
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Power (P)

Power is the rate at which work is done or energy is transferred. Two machines may do the same total work, but the one that finishes faster has greater power. Power is measured in watts (W), where 1 W = 1 J s⁻¹.
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Conservation of Energy

Energy cannot be created or destroyed—it can only be transferred or transformed. This principle, often called the work–energy theorem in mechanics, means the net work done on an object equals its change in kinetic energy.
5

Efficiency

No real machine converts 100 % of input energy into useful output. Efficiency measures the fraction of input energy that becomes useful output, expressed as a percentage: η = (useful output / total input) × 100 %.
KEY TAKEAWAY
Think of work as a bank transaction for energy. When you push a box across the floor, you are making a deposit of energy into that box's motion. Power is how fast you make that deposit—like the difference between slowly counting out coins and instantly swiping a card. Both can move the same amount, but at very different rates.

Visual Explanation — Force, Displacement & Work

One of the trickiest parts of understanding work is the role of the angle between the applied force and the displacement. Work depends not just on how hard you push and how far the object moves, but also on the direction of the force relative to the displacement. The diagram below illustrates this relationship for a force applied at an angle θ to the horizontal displacement.

A force F is applied at angle θ to the horizontal displacement d. Only the horizontal component, F cos θ, contributes to the work done. The vertical component, F sin θ, acts perpendicular to the motion and does zero work.

Notice how the force vector is split into two perpendicular components. The horizontal component (F cos θ) is parallel to the displacement and is the only part that does work. The vertical component (F sin θ) is perpendicular to the displacement, so it contributes nothing to the work. This is why carrying a heavy suitcase along a level corridor does zero work on the suitcase—the lifting force is straight up while the displacement is horizontal, making θ = 90° and cos 90° = 0.

Mathematical Framework

The mathematics behind work, energy, and power are straightforward but remarkably powerful. Each equation below is a tool that connects force, displacement, mass, velocity, height, and time. Master these relationships and you can solve almost any IB mechanics problem using energy methods.

WORK DONE BY A CONSTANT FORCE
W = F d cos θ
W = work (J), F = magnitude of the applied force (N), d = magnitude of the displacement (m), θ = angle between the force and the displacement. When θ = 0°, the force is parallel to motion and W = Fd. When θ = 90°, the force is perpendicular and W = 0.
KINETIC ENERGY
E_k = ½mv²
Ek = kinetic energy (J), m = mass (kg), v = speed (m s⁻¹). Kinetic energy is the energy an object has because of its motion. Doubling the speed quadruples the kinetic energy.
GRAVITATIONAL POTENTIAL ENERGY
E_p = mgh
Ep = gravitational potential energy (J), m = mass (kg), g = gravitational field strength (≈ 9.81 m s⁻² near Earth's surface), h = height above the chosen reference level (m). This applies near a planet's surface where g is approximately constant.
POWER
P = W / t = Fv
P = power (W), W = work done (J), t = time (s), F = force (N), v = constant velocity (m s⁻¹). The alternative form P = Fv is especially useful when an object moves at constant speed against a resistive force.
Work–Energy Theorem
The net work done on an object equals its change in kinetic energy: Wnet = ΔEk = ½mv² − ½mu². This powerful relationship bridges force analysis and energy analysis, and it is a direct consequence of Newton's second law combined with kinematics.

Energy Transformations & Conservation

In most IB Physics problems, you track how energy converts from one form to another. A roller coaster at the top of a hill has maximum gravitational potential energy. As it descends, that potential energy converts into kinetic energy. At the bottom, its speed is greatest but its height is zero. If friction and air resistance are negligible, the total mechanical energy stays the same throughout the ride.

At Point A (highest point), all energy is gravitational potential. At Point B (lowest point), all energy has transformed into kinetic energy. At intermediate points like C and D, the energy is split between kinetic and potential forms, but their sum remains constant.

When friction or air resistance is present, some mechanical energy is converted to thermal energy (internal energy of the surfaces and the surrounding air). The total energy of the universe is still conserved, but the useful mechanical energy of the system decreases. This is why real roller coasters slow down over successive hills unless an engine adds energy back into the system.

CONSERVATION WITH FRICTION
E_k,initial + E_p,initial = E_k,final + E_p,final + E_thermal
The thermal energy term Ethermal equals the work done against friction: Ethermal = ffriction × d, where d is the distance traveled along the surface.

Worked Example — Energy on a Slope

A 5.0 kg block starts from rest at the top of a frictionless ramp that is 3.0 m high. Determine (a) the speed of the block at the bottom of the ramp, and (b) the power delivered by gravity if the block takes 2.5 s to reach the bottom.

Block Sliding Down a Frictionless Ramp
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Step 1 — Identify Given ValuesMass m = 5.0 kg, height h = 3.0 m, initial speed u = 0 m s⁻¹, g = 9.81 m s⁻². The ramp is frictionless, so no energy is lost to thermal energy.
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Step 2 — Apply Conservation of EnergyAt the top, the block has gravitational potential energy and zero kinetic energy. At the bottom, all potential energy has been converted to kinetic energy. mgh = ½mv² Notice that mass m appears on both sides and cancels: gh = ½v²
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Step 3 — Solve for vv² = 2gh = 2 × 9.81 × 3.0 = 58.86 v = √58.86 ≈ 7.67 m s⁻¹
v ≈ 7.7 m s⁻¹
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Step 4 — Calculate Work Done by GravityThe work done by gravity equals the loss in potential energy: W = mgh = 5.0 × 9.81 × 3.0 = 147.15 J
W ≈ 147 J
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Step 5 — Calculate PowerPower is work divided by time: P = W / t = 147.15 / 2.5 = 58.86 W
P ≈ 59 W
💡 IB Exam Tip
In IB Physics, always state the principle you are using (e.g., "By conservation of energy…") before writing equations. Examiners award marks for clear communication of your reasoning, not just the final number.

Strengths & Limitations of the Energy Approach

You might wonder why we bother with energy methods when Newton's laws already let us calculate acceleration and velocity. The answer is that each approach has distinct advantages depending on the situation. The table below compares the two strategies.

Comparison of force-based and energy-based problem-solving strategies
CriterionForce / Newton's LawsEnergy Methods
Best forFinding acceleration, normal forces, tension at a specific instantFinding speeds, heights, or distances without knowing the path in detail
Requires path info?Yes — must decompose forces along the pathNo — only start and end states matter (for conservative forces)
Handles friction?Yes, but the analysis can become complex on curved surfacesYes — add a thermal energy loss term, but need to know the path length
Vector or scalar?Vector — direction matters at every stepScalar — no direction needed; simpler algebra
LimitationCannot easily find speed at the bottom of a curved ramp without integrationCannot directly find forces (e.g., normal force) or accelerations
KEY TAKEAWAY
Energy methods are like taking the highway — you skip all the winding local roads (force vectors, angles, accelerations) and jump straight from the starting point to the destination. Use Newton's laws when you need to know what happens along the way; use energy when you only care about the outcome.

Connection to Advanced Topics

The ideas of work, energy, and power extend far beyond the ramps and blocks you encounter in A.3. They form the bedrock for topics you will study later in the IB Physics course, including thermal physics, electricity, and even modern physics. The table below previews how these foundational concepts evolve.

How A.3 concepts evolve in later IB Physics topics
Concept in A.3Advanced ExtensionIB Topic
W = Fd cos θWork as the integral of F · ds for variable forces (e.g., springs)A.3 (elastic potential energy) & HL
E_p = mgh (near surface)E_p = −GMm/r for universal gravitation at large distancesD.1 Gravitational fields
Conservation of energyFirst law of thermodynamics: ΔU = Q − WB.1 Thermal energy transfers
P = W / tElectrical power: P = IV = I²RB.5 Current and circuits
Efficiency ηCarnot efficiency and entropy limits in heat enginesB.4 Thermodynamics (HL)

One of the most profound connections is to Einstein's mass–energy equivalence, E = mc². This equation reveals that mass itself is a form of energy — a concept that emerges naturally once you accept that energy is conserved in every interaction. Mastering the basics in A.3 prepares you to appreciate these far-reaching ideas.

Practice Problems

PROBLEM 1CONCEPTUAL
A student carries a 10 kg backpack along a level corridor for 200 m at constant speed. The student claims she has done 19 620 J of work on the backpack (using W = mgh logic with h = 0 doesn't help, so she tries W = Fd with F = mg). Explain why the work done on the backpack by the carrying force is actually zero.
PROBLEM 2BASIC CALCULATION
A 60 N horizontal force pushes a 12 kg crate across a smooth floor for 8.0 m. Calculate the work done on the crate and its final speed if it starts from rest.
PROBLEM 3INTERMEDIATE
A 0.50 kg ball is thrown vertically upward with an initial speed of 12 m s⁻¹. Using energy methods, determine the maximum height reached. Ignore air resistance and use g = 9.81 m s⁻².
PROBLEM 4APPLIED
A 1200 kg car travels at a constant speed of 25 m s⁻¹ along a horizontal road. The total resistive force (friction + air drag) is 800 N. Calculate (a) the power output of the car's engine, and (b) how much fuel energy is consumed in 10 minutes if the engine operates at 28 % efficiency.
PROBLEM 5CRITICAL THINKING
Two identical balls (mass 2.0 kg each) start from rest at the top of a 5.0 m high hill. Ball A slides down a smooth, straight ramp. Ball B rolls down a winding, frictionless track of the same vertical height. Compare their speeds at the bottom and explain why the shape of the path does not matter for conservative forces. Then discuss what would change if friction were present.

Lesson Summary

Work is the energy transferred by a force acting over a displacement and is calculated as W = Fd cos θ. Only the component of force parallel to the displacement contributes to work. Kinetic energy (½mv²) is the energy of motion, and gravitational potential energy (mgh) is the energy stored due to an object's height above a reference level. The work–energy theorem states that the net work done on an object equals its change in kinetic energy.

Conservation of energy means total energy is never created or destroyed — it only changes form. In the absence of friction, total mechanical energy (Ek + Ep) is constant; when friction acts, some mechanical energy becomes thermal energy. Power (P = W/t = Fv) measures the rate of energy transfer, and efficiency (η = useful output / total input × 100 %) quantifies how much of the input energy becomes useful output. These concepts underpin every energy analysis in IB Physics, from mechanics to thermodynamics to electricity.

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