IB PHYSICS • SPACE, TIME AND MOTION

Understand Forces & Momentum — Understand A.2 Forces and momentum

Discover how forces change motion and why momentum is the universe's favourite conserved quantity.

Historical Context & Motivation

For thousands of years, people assumed that objects naturally slow down and stop unless something keeps pushing them. The ancient Greek philosopher Aristotle taught that a force is required to maintain any motion at all — a reasonable idea if you only watch carts rolling to a halt on dusty roads. It took nearly two millennia before thinkers began to question that assumption and realise that friction, not some innate tendency, is what brings objects to rest.

The revolution came when Galileo Galilei imagined perfectly smooth surfaces and concluded that an object in motion would continue forever without friction. Isaac Newton then formalised this insight into three elegant laws of motion and introduced the concept of momentum — a quantity he called the "quantity of motion." These ideas remain at the heart of IB Physics topic A.2 and underpin everything from car-crash safety engineering to rocket propulsion.

~350 BCE
Aristotle's Natural Motion
Aristotle proposes that objects require a continuous force to remain in motion. Heavy objects fall faster because they seek their "natural place."
1638
Galileo's Thought Experiments
Galileo publishes Two New Sciences, arguing that without friction a body on a level surface would move forever — the seed of inertia.
1687
Newton's Principia
Newton publishes his three laws of motion and defines momentum (p = mv). The impulse–momentum theorem connects force and time to changes in momentum.
1743
D'Alembert & Analytical Mechanics
Jean le Rond d'Alembert reformulates Newton's second law for constrained systems, extending momentum ideas into engineering.
1905
Einstein's Relativistic Momentum
Einstein shows that at speeds near light, momentum must be redefined with a Lorentz factor, preserving conservation laws in special relativity.

The central question this topic addresses is: How do forces change the motion of objects, and what quantity is always conserved when objects interact? Understanding the answer connects you to collision analysis, safety design, space travel, and the deepest symmetries of nature.

Core Principles & Definitions

Before diving into calculations, you need a solid grip on the foundational ideas. IB topic A.2 revolves around Newton's laws of motion, the definition of linear momentum, and the powerful principle that momentum is conserved in all isolated interactions. Let's lay out these ideas systematically.

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Newton's First Law (Inertia)

An object remains at rest or moves at constant velocity unless acted upon by a net external force. This defines inertia — resistance to changes in motion.
2

Newton's Second Law

The net force on an object equals the rate of change of its momentum: Fnet = Δp / Δt. For constant mass this simplifies to F = ma.
3

Newton's Third Law

When object A exerts a force on object B, B exerts an equal and opposite force on A. These action–reaction pairs always act on different objects.
4

Linear Momentum

Momentum is a vector quantity defined as p = mv, measured in kg·m·s⁻¹. It captures both how massive and how fast an object is.
5

Conservation of Momentum

In an isolated system (no net external force), the total momentum before an interaction equals the total momentum after. This applies to all collisions and explosions.
KEY TAKEAWAY
Think of momentum like a bank account for motion. When two skaters push off each other on ice, no "motion-money" is created or destroyed — it just transfers between them. One skater gains forward momentum while the other gains the same amount of backward momentum, keeping the total balance exactly the same. That's conservation of momentum in action.

Visual Explanation — Forces & Momentum in a Collision

The diagram below illustrates a one-dimensional collision between two carts on a frictionless track. It shows the momentum vectors before and after the collision and highlights the key idea that total momentum is conserved even though individual momenta change. Pay attention to the relative lengths of the arrows — they represent the magnitude of each cart's momentum.

Cart A (cyan, 2 kg) approaches stationary Cart B (pink, 3 kg). After an elastic collision, Cart A bounces back while Cart B moves forward. The total momentum of the system remains 6 kg·m·s⁻¹ throughout.

Notice that after the collision, Cart A's momentum arrow points to the left (negative direction) while Cart B's arrow points to the right. When you add these signed values (−1.2 + 7.2 = 6.0), you recover the same total momentum as before the collision. This is the conservation principle at work. In the IB course, you need to be comfortable setting up these momentum accounts for both elastic and inelastic collisions.

Mathematical Framework

The mathematics of forces and momentum in IB Physics A.2 centres on four key equations. Each one connects force, mass, velocity, and time in a slightly different way. Master these and you can tackle any collision, explosion, or force problem on the exam.

LINEAR MOMENTUM
p = m × v
Where p is momentum (kg·m·s⁻¹), m is mass (kg), and v is velocity (m·s⁻¹). Momentum is a vector — direction matters.
NEWTON'S SECOND LAW (MOMENTUM FORM)
F_net = Δp / Δt
The net force equals the change in momentum divided by the time interval. This is actually Newton's original formulation — F = ma is a special case for constant mass.
IMPULSE–MOMENTUM THEOREM
J = F_net × Δt = Δp = m × Δv
Impulse J (in N·s) equals the area under a force–time graph. A larger impulse produces a larger change in momentum. This explains why airbags work: they increase Δt, which decreases the force for the same Δp.
CONSERVATION OF MOMENTUM
m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'
For a two-body isolated system, the total momentum before (left side) equals the total momentum after (right side, with primes). This holds for elastic, inelastic, and perfectly inelastic collisions.
💡 IB Exam Tip
The IB data booklet provides F = Δp/Δt rather than F = ma. Always start from the momentum form in exam answers — it earns full marks and handles variable-mass problems (like rockets) that F = ma cannot.

Types of Collisions & Impulse

Not all collisions are the same. The IB syllabus requires you to distinguish between elastic, inelastic, and perfectly inelastic collisions. In every case, momentum is conserved — the difference lies in what happens to kinetic energy.

Comparison of collision types — momentum is always conserved in an isolated system.
Collision TypeMomentum Conserved?Kinetic Energy Conserved?Example
ElasticYesYes — total KE is unchangedTwo billiard balls colliding
InelasticYesNo — some KE is lost to heat, sound, or deformationA car crash where bumpers crumple
Perfectly InelasticYesNo — maximum KE loss; objects stick togetherA ball of clay hitting a wall and sticking
Two force–time curves with identical impulse (area under curve). The red triangle represents a short-duration, high-force impact (no airbag). The green triangle represents a longer-duration, lower-force impact (with airbag). Same momentum change, much safer.

The force–time diagram above is one of the most important graphs in IB Physics A.2. The area under the F–t curve equals the impulse, which equals the change in momentum. Safety features like airbags, crumple zones, and helmets all work by increasing the collision time Δt, thereby reducing the peak force experienced by the passenger while keeping the impulse the same.

Worked Example — Perfectly Inelastic Collision

A 1 200 kg car travelling east at 15 m·s⁻¹ collides head-on with a 800 kg car travelling west at 10 m·s⁻¹. The two cars lock together after the collision (a perfectly inelastic collision). Find the velocity of the wreckage immediately after the collision and the kinetic energy lost.

Perfectly Inelastic Collision
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Step 1 — Define Direction & Identify GivensLet east be positive. Car A: mA = 1 200 kg, vA = +15 m·s⁻¹. Car B: mB = 800 kg, vB = −10 m·s⁻¹ (west, so negative).
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Step 2 — Calculate Total Momentum Beforeptotal = mAvA + mBvB = (1 200 × 15) + (800 × (−10)) = 18 000 − 8 000 = 10 000 kg·m·s⁻¹.
ptotal = 10 000 kg·m·s⁻¹ (east)
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Step 3 — Apply Conservation of MomentumSince the cars stick together, mtotal = 1 200 + 800 = 2 000 kg. Using ptotal = mtotal × v': v' = 10 000 / 2 000 = 5.0 m·s⁻¹.
v' = 5.0 m·s⁻¹ east
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Step 4 — Calculate Kinetic Energy BeforeKEbefore = ½mAvA² + ½mBvB² = ½(1 200)(15²) + ½(800)(10²) = 135 000 + 40 000 = 175 000 J.
KEbefore = 175 000 J
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Step 5 — Calculate Kinetic Energy After & Energy LostKEafter = ½(2 000)(5.0²) = 25 000 J. Energy lost = 175 000 − 25 000 = 150 000 J. This energy is transformed into heat, sound, and deformation of the car bodies.
KE lost = 150 000 J (85.7% of original KE)
Check Your Work
In perfectly inelastic collisions, the wreckage always moves in the direction of the object with greater momentum. Here, Car A's momentum (18 000) exceeds Car B's (8 000), so the wreckage moves east — consistent with our answer of +5.0 m·s⁻¹.

Applications, Strengths & Limitations

Newton's force and momentum framework is extraordinarily powerful, but it does have boundaries. Understanding where these ideas shine — and where they break down — will help you navigate IB exam questions and appreciate why physicists eventually developed relativity and quantum mechanics.

Strengths and limitations of Newtonian force & momentum analysis
StrengthsLimitations
Conservation of momentum is universally valid — it holds for all interactions in isolated systems, regardless of the internal forces.The equation p = mv breaks down at speeds near the speed of light. Relativistic momentum uses p = γmv, where γ is the Lorentz factor.
F = Δp/Δt works for variable-mass systems like rockets, where F = ma would be incorrect.At the quantum scale, momentum becomes linked to wavelength (de Broglie relation), and precise simultaneous measurement of position and momentum is impossible (Heisenberg's uncertainty principle).
Impulse analysis directly informs safety engineering: airbags, crumple zones, seatbelts, and sports helmets.Newton's third law struggles to describe interactions where forces propagate at finite speeds (e.g., electromagnetic radiation between charged particles).
Momentum is simpler to work with than energy in multi-body problems because it's a vector — direction gives extra information.In systems with continuous mass flow (fluids), the framework must be extended to include pressure and momentum flux terms.
🚀 WHY MOMENTUM MATTERS
Momentum conservation is one of the most fundamental laws in physics because it arises from a deep symmetry of nature: the uniformity of space. The fact that the laws of physics are the same here as they are across the galaxy means momentum must be conserved. This link between symmetry and conservation laws (called Noether's theorem) is one of the most beautiful results in all of physics. For the IB, just remember: if no external force acts on a system, total momentum stays constant. Period.

Connection to Advanced Theory

IB Physics A.2 gives you the classical (Newtonian) picture of forces and momentum. As you progress — particularly if you study IB HL or university physics — you'll encounter situations where Newton's equations need upgrading. Here's a preview of how the key ideas evolve.

From IB A.2 to advanced physics
ConceptClassical (A.2 Level)Advanced Version
Momentump = mvp = γmv (special relativity); p = ℏk (quantum mechanics)
ForceF = Δp/Δt — applied at a point in timeForce fields and Lagrangian mechanics replace point forces with energy landscapes
Conservation lawHolds if no net external force actsDerived from translational symmetry of space via Noether's theorem
CollisionsElastic vs. inelastic classificationParticle physics collisions can create new particles — mass–energy equivalence (E = mc²) is needed

Don't worry about mastering these advanced ideas yet. The critical thing is that conservation of momentum never fails — it just gets reformulated to account for new physics. The Newtonian tools you build in A.2 are the foundation for everything that comes later.

Practice Problems

PROBLEM 1CONCEPTUAL
A 50 kg ice skater and a 70 kg ice skater stand at rest facing each other and then push apart. Explain why the lighter skater moves away faster, even though neither skater pushes harder than the other.
PROBLEM 2BASIC CALCULATION
A 0.45 kg football is kicked from rest and leaves the foot at 20 m·s⁻¹. If the foot is in contact with the ball for 0.050 s, calculate the average force applied to the ball.
PROBLEM 3INTERMEDIATE
A 4.0 kg cart moving east at 6.0 m·s⁻¹ collides elastically with a 2.0 kg cart moving west at 3.0 m·s⁻¹. Using conservation of momentum and conservation of kinetic energy, find the velocity of each cart after the collision.
PROBLEM 4APPLIED
In a crash test, a 1 500 kg car hits a wall at 13 m·s⁻¹ and comes to rest. The crumple zone deforms over 0.12 s. (a) Calculate the impulse on the car. (b) Find the average force. (c) If an improved crumple zone extends the stopping time to 0.20 s, by what factor does the average force decrease?
PROBLEM 5CRITICAL THINKING
A 60 kg astronaut floating in space throws a 5.0 kg toolbox at 4.0 m·s⁻¹ to the right. She then throws a second 5.0 kg toolbox at 4.0 m·s⁻¹ to the right relative to herself. Find her final velocity. Explain why the result differs from simply throwing both toolboxes at once.

Lesson Summary

IB Physics topic A.2 connects Newton's three laws of motion to the concept of linear momentum (p = mv). Newton's second law in its fundamental form, F = Δp/Δt, shows that force is the rate of change of momentum. The impulse–momentum theorem (J = FΔt = Δp) links the area under a force–time graph to the change in momentum, which explains why safety devices like airbags and crumple zones reduce injury by extending collision time.

The most powerful result in this topic is the conservation of momentum: in any isolated system, total momentum before an interaction equals total momentum after. This principle holds for elastic collisions (kinetic energy conserved), inelastic collisions (kinetic energy lost), and perfectly inelastic collisions (objects stick together, maximum kinetic energy loss). Remember: momentum is always conserved in isolated systems; kinetic energy is only conserved in elastic collisions. These tools form the foundation for analysing everything from car crashes to rocket propulsion.

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