IB PHYSICS • FIELDS

Apply Electric & Magnetic Fields — Apply D.2 Electric and magnetic fields in problem-solving and explanations

Master the forces, fields, and motion of charged particles through electric and magnetic environments.

Historical Context & Motivation

For thousands of years, people observed lightning, static cling, and mysterious lodestones that attracted iron. Yet nobody could explain what connected these phenomena. The breakthrough came when scientists realized that electric forces and magnetic forces are two faces of the same underlying interaction. Understanding how charged particles behave in electric and magnetic fields opened the door to technologies we rely on every day — from smartphones and MRI scanners to particle accelerators that probe the building blocks of matter.

1785
Coulomb's Law
Charles-Augustin de Coulomb experimentally quantified the force between two point charges, establishing the inverse-square law for electrostatic interactions.
1820
Ørsted's Discovery
Hans Christian Ørsted observed that an electric current deflects a nearby compass needle, revealing the deep link between electricity and magnetism.
1831
Faraday's Induction
Michael Faraday demonstrated that a changing magnetic field induces an electric current, introducing the concept of the 'field' as a physical entity rather than just a mathematical tool.
1865
Maxwell's Equations
James Clerk Maxwell unified electricity and magnetism into a single electromagnetic theory, predicting electromagnetic waves and the speed of light.
1897
Thomson's Cathode Rays
J.J. Thomson used electric and magnetic fields to deflect cathode rays, measuring the charge-to-mass ratio of the electron and proving that subatomic particles exist.

The central question for IB Physics Topic D.2 is this: when a charged particle enters a region containing an electric field, a magnetic field, or both, how do we predict the force on the particle and its resulting motion? Answering this question requires combining Coulomb's law, the electric field concept, and the magnetic force law into a coherent problem-solving framework.

Core Principles & Definitions

Before diving into calculations, you need a clear mental map of the key ideas that govern how charges interact with fields. The following four foundational concepts form the backbone of every D.2 problem you will encounter.

1

Electric Field (E)

A region around a charged object where another charge would experience a force. Defined as force per unit positive test charge: E = F/q. The field points in the direction a positive charge would be pushed.
2

Magnetic Field (B)

A region around a magnet or current-carrying wire where a moving charge experiences a force. The magnetic force acts perpendicular to both the velocity and the field direction.
3

Coulomb's Law

The electrostatic force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them: F = kq₁q₂/r².
4

Lorentz Force

The total electromagnetic force on a moving charge combines both electric and magnetic contributions: F = qE + qv × B. This is the master equation for D.2 problems.
KEY TAKEAWAY
Think of an electric field like a hill: place a ball (charge) on the slope and gravity (the field) pushes it downhill. The steeper the hill, the stronger the push. A magnetic field is more like a curved ramp at a skate park — it doesn't speed the ball up or slow it down, but it curves the ball's path sideways. Electric fields change a charge's speed; magnetic fields change a charge's direction.

Visualizing Electric & Magnetic Fields

Field lines are the standard way physicists represent electric and magnetic fields visually. For electric fields, lines emerge from positive charges and terminate on negative charges. The density of lines indicates the field strength — more crowded lines mean a stronger field. For magnetic fields created by a current-carrying wire, the field lines form concentric circles around the wire, and the direction is given by the right-hand rule.

Left: Electric field lines between a positive and negative point charge curve from + to −, bunching together where the field is strongest. Right: Between parallel plates of opposite charge, the field lines are straight and equally spaced, producing a uniform electric field described by E = V/d.

Notice the crucial difference between the two scenarios. Between the point charges on the left, the field varies in both strength and direction — it is non-uniform. Between the parallel plates on the right, the field lines are equally spaced and parallel, making the field uniform. Many IB problems focus on the uniform field case because the constant force simplifies the math — a charged particle in a uniform electric field undergoes constant acceleration, just like a projectile in a gravitational field.

Mathematical Framework

The mathematics of D.2 rests on a small set of powerful equations. Mastering when to apply each one is the key skill for IB exam success.

COULOMB'S LAW
F = k × q₁ × q₂ / r²
F = electrostatic force (N), k = Coulomb's constant (8.99 × 10⁹ N·m²/C²), q₁ and q₂ = charges (C), r = separation (m). Like charges repel; opposite charges attract.
ELECTRIC FIELD STRENGTH
E = F / q = k × Q / r² (point charge) E = V / d (uniform field between plates)
E = electric field strength (N/C or V/m), Q = source charge, V = potential difference across plates (V), d = plate separation (m).
MAGNETIC FORCE ON A MOVING CHARGE
F = qvB sin θ
F = magnetic force (N), q = charge (C), v = speed (m/s), B = magnetic field strength (T), θ = angle between velocity and field. When θ = 90°, sin θ = 1 and the force is maximum. When θ = 0°, the charge moves parallel to the field and feels no magnetic force.
CIRCULAR MOTION IN A MAGNETIC FIELD
qvB = mv² / r → r = mv / (qB)
When a charge moves perpendicular to a uniform magnetic field, the magnetic force provides the centripetal force needed for circular motion. Here r = radius of the circular path, m = mass of the particle. Faster or heavier particles trace larger circles; stronger fields or larger charges produce tighter circles.
Direction Matters: The Right-Hand Rule
To find the direction of the magnetic force on a positive charge: point your fingers in the direction of v (velocity), curl them toward B (magnetic field), and your thumb points in the direction of F (force). For a negative charge, the force is in the opposite direction — you can use your left hand instead.

Charged Particle Motion in Fields

One of the most important D.2 scenarios involves a charged particle entering a region with a uniform field. The type of field — electric or magnetic — determines the resulting motion. Let's compare the two side by side.

Left: A positive charge entering a uniform electric field perpendicular to its velocity follows a parabolic path (like projectile motion). Right: A positive charge entering a uniform magnetic field (into the page) perpendicular to its velocity follows a circular path with radius r = mv/(qB). Note that the magnetic force F is always perpendicular to the velocity v.
Comparison of charge behavior in electric vs magnetic fields
PropertyElectric FieldMagnetic Field
Force directionAlong the field lines (or opposite for −q)Perpendicular to both v and B
Effect on speedChanges speed (does work on charge)Speed unchanged (does no work)
Path shapeParabolic (if v₀ ⊥ E)Circular (if v ⊥ B)
Force on stationary chargeYes (F = qE)No (needs v ≠ 0)
Work done by fieldW = qEd (can be positive or negative)W = 0 (force ⊥ displacement always)

Worked Example: Proton in a Magnetic Field

A proton moves at 3.0 × 10⁶ m/s perpendicular to a uniform magnetic field of strength 0.50 T. Determine (a) the magnetic force on the proton, (b) the radius of its circular path, and (c) the time for one complete revolution.

Proton in a Uniform Magnetic Field
1
Step 1 — Identify Given ValuesCharge of proton: q = 1.60 × 10⁻¹⁹ C. Speed: v = 3.0 × 10⁶ m/s. Magnetic field: B = 0.50 T. Mass of proton: m = 1.67 × 10⁻²⁷ kg. The velocity is perpendicular to B, so θ = 90° and sin θ = 1.
2
Step 2 — Calculate the Magnetic ForceUse F = qvB sin θ. Substituting: F = (1.60 × 10⁻¹⁹)(3.0 × 10⁶)(0.50)(1).
F = 2.4 × 10⁻¹³ N
3
Step 3 — Find the Radius of Circular MotionThe magnetic force provides the centripetal force: qvB = mv²/r. Rearranging gives r = mv/(qB). Substituting: r = (1.67 × 10⁻²⁷ × 3.0 × 10⁶) / (1.60 × 10⁻¹⁹ × 0.50).
r = 0.063 m ≈ 6.3 cm
4
Step 4 — Calculate the Period of RevolutionThe circumference of the circular path is 2πr. The period T = circumference / speed = 2πr/v. Alternatively, substituting r = mv/(qB) gives T = 2πm/(qB). Using T = 2π(1.67 × 10⁻²⁷) / (1.60 × 10⁻¹⁹ × 0.50).
T = 1.3 × 10⁻⁷ s ≈ 130 ns
5
Step 5 — Reflect on the ResultNotice that the period T = 2πm/(qB) does not depend on the particle's speed. This is a key feature of circular motion in a magnetic field — faster particles trace larger circles but complete each revolution in the same time. This principle is the foundation of the cyclotron, a type of particle accelerator.

Applications, Strengths & Limitations

The principles of D.2 aren't just exam material — they underpin real-world technologies. However, the simplified models we use at the IB level have boundaries. Understanding where these models break down helps you appreciate why more advanced physics (like relativity) becomes necessary.

Real-world applications and limitations of the D.2 model
ApplicationPrinciple UsedLimitation of IB Model
Mass SpectrometerIons deflected by B-field; r = mv/(qB) separates ions by massAssumes uniform B-field; real instruments use complex field geometries for focusing
Cathode Ray Tube (CRT)Electrons steered by E-fields between deflection platesIgnores relativistic effects at very high electron energies
CyclotronT = 2πm/(qB) is speed-independent, allowing repeated accelerationBreaks down at relativistic speeds where mass increases with velocity
Velocity SelectorCrossed E and B fields: only charges with v = E/B pass through undeflectedAssumes perfectly uniform, perpendicular fields — real selectors have fringe effects
KEY TAKEAWAY
The velocity selector is like a filter at a water park: only riders (charges) going exactly the right speed pass through the 'gate' where the electric push exactly cancels the magnetic push. Too fast or too slow, and you get deflected to the side. The condition for passing through undeflected is v = E/B, which is independent of charge or mass — a beautifully simple result.

Connection to Advanced Theory

The D.2 framework provides a powerful classical description of electromagnetic forces, but physics doesn't stop here. As you continue in physics, you'll encounter deeper and more general treatments of the same phenomena.

How D.2 concepts connect to university-level physics
IB D.2 LevelAdvanced Treatment
F = qvB sin θ (magnitude only)F = qv × B (full vector cross product, requires linear algebra)
E and B treated as separate fieldsSpecial relativity shows E and B are components of a single electromagnetic field tensor — what looks like a pure E-field in one reference frame can appear as a B-field in another
Constant mass assumed in r = mv/(qB)At speeds approaching c, relativistic mass increase causes the cyclotron radius to grow, requiring the synchrotron design
Classical point chargesQuantum electrodynamics (QED) treats electromagnetic interactions as exchanges of virtual photons

Don't let the advanced column intimidate you — it's included to show where your current knowledge leads. The key point is that the equations you're learning now are not approximations to be discarded later. They remain exactly correct in the non-relativistic limit (v ≪ c), which covers the vast majority of practical engineering applications. You are building a solid foundation that will support everything that comes next.

Practice Problems

PROBLEM 1CONCEPTUAL
A positive charge moves to the right through a magnetic field directed into the page. In what direction does the magnetic force act on the charge? Explain your reasoning using the right-hand rule.
PROBLEM 2BASIC CALCULATION
Two parallel plates are separated by 2.0 cm and connected to a 200 V power supply. Calculate (a) the electric field strength between the plates, and (b) the force on an electron placed between the plates.
PROBLEM 3INTERMEDIATE
An alpha particle (charge +2e, mass 6.64 × 10⁻²⁷ kg) enters a uniform magnetic field of 1.2 T perpendicular to its velocity. The radius of its circular path is measured to be 0.14 m. Determine the speed of the alpha particle.
PROBLEM 4APPLIED
In a velocity selector, an electric field of 3.0 × 10⁴ V/m is directed upward and a magnetic field of 0.60 T is directed into the page. A beam of charged particles travels horizontally to the right. (a) What speed must the particles have to pass through undeflected? (b) If a particle is moving faster than this speed, in which direction will it be deflected? Explain.
PROBLEM 5CRITICAL THINKING
A proton and a deuteron (charge +e, mass ≈ 2 × proton mass) are both accelerated from rest through the same potential difference V and then enter a region of uniform magnetic field B perpendicular to their velocities. Derive an expression for the ratio of their circular path radii r_d / r_p. Does the particle with greater mass always trace the larger circle? Justify your answer.

Lesson Summary

In this lesson, you learned that charged particles experience forces in electric fields (F = qE) and magnetic fields (F = qvB sin θ). The electric force acts along the field direction and can change a particle's speed, while the magnetic force acts perpendicular to both the velocity and the field, changing direction without doing work. Coulomb's law (F = kq₁q₂/r²) governs the force between point charges. In a uniform electric field (E = V/d), a charge undergoes constant acceleration, producing parabolic trajectories analogous to projectile motion.

A charge moving perpendicular to a uniform magnetic field follows a circular path with radius r = mv/(qB) and a period T = 2πm/(qB) that is independent of speed. The velocity selector uses crossed E and B fields to select particles with v = E/B, while the mass spectrometer exploits the mass-dependent radius to separate and identify ions. These principles connect forward to the electromagnetic field tensor in special relativity and quantum electrodynamics, but the classical equations you've mastered here remain essential tools for physics and engineering.

Varsity Tutors • IB Physics • Apply Electric & Magnetic Fields — Apply D.2 Electric and magnetic fields in problem-solving and explanations