IB PHYSICS • WAVE BEHAVIOUR

Apply Doppler Effect — Apply C.5 Doppler effect in problem-solving and explanations

Understand why a siren's pitch changes as it passes you, and master the equations behind it.

Historical Context & Motivation

You have probably noticed that the pitch of an ambulance siren sounds higher as it approaches you and drops lower once it passes. This everyday experience is the Doppler effect, a phenomenon that connects wave physics to everything from weather forecasts to the expanding universe. Understanding the Doppler effect allows physicists to measure speeds remotely—without ever touching the moving object—and it forms a cornerstone of modern astrophysics, medical imaging, and radar technology.

1842
Doppler's Proposal
Austrian physicist Christian Doppler published a paper predicting that the observed frequency of a wave changes when the source or observer is in motion. He initially applied the idea to light from stars.
1845
Buys Ballot's Train Experiment
Dutch meteorologist Christophorus Buys Ballot tested Doppler's theory by placing musicians on a moving train while stationary listeners noted the pitch change, confirming the effect for sound waves.
1929
Hubble and Redshift
Edwin Hubble used the Doppler shift of light from distant galaxies to show that the universe is expanding. Galaxies moving away from us display redshift—a lower observed frequency of light.
1960s
Doppler Radar & Medical Ultrasound
Engineers applied the Doppler effect to radar systems for tracking weather patterns and aircraft. Around the same time, Doppler ultrasound was developed to measure blood flow velocity in the human body.

The central question behind the Doppler effect is deceptively simple: If a wave source or an observer is moving, what frequency does the observer actually detect? Answering this question precisely is the goal of IB Physics topic C.5, and it unlocks powerful applications across science and engineering.

Core Principles & Definitions

The Doppler effect rests on a few foundational ideas about how waves propagate through a medium. Before diving into equations, it helps to establish the key concepts clearly. Each of the principles below applies to mechanical waves (such as sound) travelling through a medium like air, and some extend to electromagnetic waves (such as light) with a slightly different treatment.

1

Wave Speed Is Set by the Medium

The speed of a wave (v) is determined by the properties of the medium it travels through—not by the motion of the source. Sound travels at about 340 m s−1 in air regardless of how fast the siren moves.
2

Frequency vs. Wavelength

When a source moves toward an observer, the wavefronts bunch together, producing a shorter wavelength and a higher observed frequency. The reverse happens when the source moves away.
3

Observer Motion Matters Too

If the observer moves toward a stationary source, they encounter wavefronts more frequently. If they move away, they encounter wavefronts less frequently. Both source and observer motion affect the observed frequency.
4

Blueshift & Redshift

When source and observer approach each other, the observed frequency increases (blueshift). When they move apart, the observed frequency decreases (redshift). These terms originate from the light spectrum.
KEY TAKEAWAY
Think of running into rain. If you stand still, a certain number of raindrops hit you each second. If you run toward the rain, more drops hit you per second—the "frequency" of impacts goes up. If you run away, fewer drops hit you per second. The rain itself hasn't changed—just your motion relative to it. The Doppler effect works the same way with wavefronts instead of raindrops.

Visualising the Doppler Effect

The diagram below shows how wavefronts change when a source is in motion. On the left, a stationary source emits circular wavefronts that are equally spaced in all directions. On the right, a moving source compresses the wavefronts ahead of it and stretches them behind it.

Left: A stationary source emits circular wavefronts with equal spacing (constant wavelength) in every direction. Right: A moving source shifts the wavefront centres, compressing waves ahead (higher frequency) and stretching waves behind (lower frequency). Observer A detects a higher pitch; Observer B detects a lower pitch.

Notice that the wave speed itself has not changed—the circles expand at the same rate in both diagrams. What changes is where the source is when it emits each wavefront. Because the source keeps moving forward between emissions, the wavefronts pile up in front and spread apart behind. This asymmetry is the physical origin of the frequency shift.

Mathematical Framework

The IB Physics syllabus (C.5) provides a single master equation that covers both source and observer motion for sound waves. The key is choosing the correct signs. Let's build up the equation step by step.

The General Doppler Equation for Sound

DOPPLER EFFECT — SOUND
f′ = f × (v ± v_o) / (v ∓ v_s)
Where f′ = observed frequency, f = emitted (source) frequency, v = speed of sound in the medium, vo = speed of observer, vs = speed of source.
⚠️ Sign Convention (IB Approach)
Use the upper signs (+ in numerator, − in denominator) when source and observer move toward each other. Use the lower signs (− in numerator, + in denominator) when they move apart. A simple check: approaching should give f′ > f, and receding should give f′ < f.

Special Cases

MOVING SOURCE, STATIONARY OBSERVER
f′ = f × v / (v ∓ v_s)
Set vo = 0. Use − when source approaches (f′ increases) and + when source recedes (f′ decreases).
MOVING OBSERVER, STATIONARY SOURCE
f′ = f × (v ± v_o) / v
Set vs = 0. Use + when observer approaches and − when observer recedes.

Doppler Effect for Electromagnetic Waves

Light and other electromagnetic waves do not require a medium, so the Doppler equation takes a different form. For speeds much less than the speed of light (v ≪ c), the IB syllabus uses the approximation:

DOPPLER EFFECT — LIGHT (v ≪ c)
Δf / f ≈ Δλ / λ ≈ v / c
Where Δf is the change in frequency, Δλ is the change in wavelength, v is the relative speed between source and observer, and c is the speed of light (3.00 × 10⁸ m s⁻¹).

Applications & Frequency Shift Breakdown

The Doppler effect appears across a surprisingly wide range of fields. The diagram below maps out four major real-world applications, showing how the same physics principle is used in vastly different contexts. After the diagram, a classification table breaks down the type of wave, the quantity measured, and the information extracted.

Four major applications of the Doppler effect. In each case, the same underlying principle is at work: a frequency or wavelength shift reveals the speed of a moving object.
Summary of Doppler effect applications by wave type and output.
ApplicationWave TypeQuantity MeasuredInformation Obtained
Astronomical redshiftVisible light / EMΔλ (wavelength shift)Recession speed of galaxies
Medical ultrasoundSound (ultrasonic)Δf (frequency shift)Blood flow velocity
Speed radar (police)Microwaves / EMΔf (frequency shift)Vehicle speed
Doppler weather radarMicrowaves / EMΔf (frequency shift)Wind speed, storm rotation

Worked Example

Let's walk through a full problem involving a moving source, which is one of the most common Doppler calculations on IB exams.

Ambulance Siren — Moving Source, Stationary Observer
1
Step 1 — Read the ProblemAn ambulance emits a siren at a frequency of 800 Hz. It drives toward a stationary observer at 25 m s⁻¹. The speed of sound in air is 340 m s⁻¹. What frequency does the observer hear?
2
Step 2 — Identify Given Valuesf = 800 Hz (emitted frequency), v = 340 m s⁻¹ (speed of sound), vs = 25 m s⁻¹ (source speed), vo = 0 (observer is stationary). The source is approaching, so we expect f′ > f.
3
Step 3 — Select the Correct EquationSince the observer is stationary, we use: f′ = f × v / (v − vs). We use the minus sign in the denominator because the source is approaching, which should increase the observed frequency (smaller denominator → larger result).
4
Step 4 — Substitute Valuesf′ = 800 × 340 / (340 − 25) = 800 × 340 / 315
5
Step 5 — Calculatef′ = 800 × 1.0794 = 863.5 Hz
f′ ≈ 864 Hz
6
Step 6 — Sense CheckThe observed frequency (864 Hz) is greater than the emitted frequency (800 Hz), which is correct because the source is approaching. The increase is about 8%, which is reasonable for a source moving at roughly 7% of the speed of sound.
💡 Exam Tip
Always do a sense check on your answer. Approaching = higher frequency. Receding = lower frequency. If your answer contradicts this, re-check your signs.

Source Motion vs. Observer Motion

Students sometimes wonder whether it matters if the source moves or the observer moves. For sound waves, these situations are physically different because there is a medium (air) that defines a rest frame. The table below compares the two cases for the same relative approach speed.

Comparison of moving-source and moving-observer Doppler scenarios for sound.
FeatureMoving SourceMoving Observer
What changes physicallyWavelength is compressed or stretchedObserver intercepts wavefronts more or less frequently
Equation formf′ = f × v / (v ∓ v_s)f′ = f × (v ± v_o) / v
Same relative speed → same f′?No—slightly different resultNo—slightly different result
Why the difference?Sound has a medium; the medium defines which frame is at restSame reason—air is the reference frame
For light (EM waves)No medium → only relative motion mattersSame result as moving source at the same relative speed
KEY TAKEAWAY
For sound, the medium (air) acts like a referee—it distinguishes between a moving source and a moving observer even if the relative speed is the same. For light, there is no medium, so only the relative velocity between source and observer matters. This distinction is exactly why the IB gives you separate equation forms for sound but a single approximation for light.

Connection to Relativistic Doppler & Advanced Theory

The Doppler equations you learn in IB Physics work beautifully for everyday speeds—cars, ambulances, and even orbiting planets. However, when objects move at a significant fraction of the speed of light, Einstein's theory of special relativity changes the picture. The table below previews how the classical Doppler formula for light gives way to the relativistic Doppler equation.

Classical vs. Relativistic Doppler comparison.
AspectClassical (IB Level)Relativistic (University Level)
Speed rangev ≪ c (much less than speed of light)Any v up to c
Equation for lightΔf/f ≈ v/cf′ = f × √((1 − β)/(1 + β)), where β = v/c
Time dilation included?NoYes—built into the equation via the √ factor
Transverse Doppler effect?Not predicted (classical = no shift at 90°)Predicted and experimentally confirmed

You do not need the relativistic formula for IB exams, but it's good to know that the approximation Δf/f ≈ v/c breaks down at high speeds. Quasars, jets from black holes, and particles in accelerators all require the full relativistic treatment. If you continue to university physics, the Doppler effect will reappear in the context of special relativity and cosmological redshift.

Practice Problems

PROBLEM 1CONCEPTUAL
A car horn sounds at a constant frequency as it drives past you. Describe how the pitch you hear changes as the car approaches, passes, and then moves away. Explain your answer in terms of wavefront compression and stretching.
PROBLEM 2BASIC CALCULATION
A train whistle emits sound at 500 Hz. The train moves away from a stationary observer at 30 m s⁻¹. If the speed of sound is 340 m s⁻¹, calculate the frequency heard by the observer.
PROBLEM 3INTERMEDIATE
A police car siren emits sound at 700 Hz and approaches a jogger who is running toward the police car at 3.0 m s⁻¹. The police car travels at 20 m s⁻¹ and the speed of sound is 340 m s⁻¹. What frequency does the jogger hear?
PROBLEM 4APPLIED
An astronomer observes a spectral line from a distant galaxy. The laboratory wavelength of this line is 656.3 nm, but the observed wavelength is 662.1 nm. Calculate the recession speed of the galaxy. (c = 3.00 × 10⁸ m s⁻¹)
PROBLEM 5CRITICAL THINKING
Two identical speakers each emit sound at 1000 Hz. Speaker A is stationary, while Speaker B moves toward a stationary observer at 17 m s⁻¹. The speed of sound is 340 m s⁻¹. (a) Calculate the frequency heard from Speaker B. (b) What beat frequency does the observer hear when both speakers sound simultaneously? (c) Explain what would happen to the beat frequency if Speaker B accelerated to 34 m s⁻¹.

Lesson Summary

The Doppler effect describes how the observed frequency of a wave changes when there is relative motion between the source and the observer. For sound, a moving source compresses wavefronts ahead (higher f′) and stretches them behind (lower f′), while a moving observer intercepts wavefronts at a different rate. The general equation f′ = f × (v ± vo) / (v ∓ vs) handles both cases, with sign choices determined by whether source and observer approach or recede.

For electromagnetic waves at low speeds (v ≪ c), the approximation Δf/f ≈ Δλ/λ ≈ v/c connects redshift and blueshift to the relative speed of source and observer. Applications span astronomy (Hubble's expanding universe), medical imaging (Doppler ultrasound), and radar technology (weather and speed detection). Remember: approaching → higher frequency, receding → lower frequency—always verify your answer against this rule.

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