IB MATHEMATICS: ANALYSIS AND APPROACHES • GEOMETRY AND TRIGONOMETRY

Double Angle & Trig Graphs — SL 3.6 Double angle identities and trigonometric graphs (intro)

Transform single-angle trig expressions into powerful double-angle forms and see their impact on graphs.

Historical Context & Motivation

Trigonometry has been a tool for understanding angles and distances for thousands of years, but the idea of relating the sine or cosine of a double angle (like 2θ) back to the original angle θ took centuries to develop. Ancient astronomers needed these relationships to predict planetary positions and eclipses, and over time mathematicians formalized the identities we use today. These double angle identities are not just algebraic tricks — they simplify complex calculations and reveal hidden patterns in trigonometric graphs.

~150 CE
Ptolemy's Chord Tables
Claudius Ptolemy compiled extensive tables of chord lengths in the Almagest, using geometric methods that implicitly contained double-angle relationships to predict celestial motion.
~1400
Islamic Golden Age Refinements
Mathematicians like al-Kāshī extended trigonometric identities, expressing sine and cosine of compound angles with remarkable precision for astronomical calculations.
1748
Euler's Introductio
Leonhard Euler published systematic treatments of trigonometric functions, including compact double angle formulas, connecting them to exponential functions via e.
1800s
Fourier and Wave Analysis
Joseph Fourier showed that complex waves can be decomposed into sums of sine and cosine terms, making double-angle identities essential tools in physics and engineering.

The central question this lesson addresses is: how can we express sin 2θ and cos 2θ in terms of sin θ and cos θ, and what does doubling the angle do to a trigonometric graph? By the end of this lesson, you will be able to apply the double angle identities algebraically and predict how they transform the shape, period, and amplitude of sine and cosine curves.

Core Principles & Definitions

Before diving into formulas, let's establish the foundational ideas. The double angle identities are derived from the compound angle formulas (also called addition formulas) by setting both angles equal. In other words, sin(A + B) becomes sin(θ + θ) = sin 2θ. This simple substitution unlocks three powerful relationships that connect expressions involving 2θ to expressions involving just θ.

1

Double Angle for Sine

sin 2θ = 2 sin θ cos θ. This identity rewrites the sine of a doubled angle as twice the product of sine and cosine of the original angle.
2

Double Angle for Cosine

cos 2θ = cos²θ − sin²θ. This is the primary form; it can also be written as 2cos²θ − 1 or 1 − 2sin²θ using the Pythagorean identity.
3

Three Forms of cos 2θ

Because sin²θ + cos²θ = 1, you can substitute to get three equivalent forms. Choose whichever form best matches the information you're given in a problem.
4

Effect on Graphs

Replacing θ with 2θ inside sin or cos compresses the graph horizontally. The period halves from 2π to π, meaning the wave completes a full cycle in half the distance.
KEY TAKEAWAY
Think of the double angle identity like a camera zoom: when you go from sin θ to sin 2θ, you're not stretching the wave taller — you're squeezing it sideways so it oscillates twice as fast. It's like watching a video at 2× speed: same pattern, but everything happens in half the time. The identities give you the algebraic tools to translate between the "normal speed" expression and the "double speed" one.

Visual Explanation — Sine and Sin 2θ Compared

The violet curve shows y = sin θ with a period of 2π. The cyan curve shows y = sin 2θ, which completes a full cycle in just π. Both curves have the same amplitude of 1, but the doubled angle squeezes the wave horizontally.

Look carefully at the diagram above. The violet sine curve completes one full oscillation from 0 to 2π, which is the standard period of sin θ. Now compare it to the cyan sin 2θ curve, which completes two full oscillations over the same interval. The amplitude (the height from the center line to the peak) stays at 1 for both curves. The only change is in the period: doubling the angle inside the sine function cuts the period in half. In general, the period of sin(Bθ) is 2π ÷ B, so for sin 2θ the period is 2π ÷ 2 = π.

Mathematical Framework

The double angle identities are derived from the addition formulas for sine and cosine. Start with sin(A + B) = sin A cos B + cos A sin B and set A = B = θ. Doing the same for cosine and applying the Pythagorean identity sin²θ + cos²θ = 1 yields three equivalent forms for cos 2θ.

DOUBLE ANGLE — SINE
sin 2θ = 2 sin θ cos θ
Derived from sin(θ + θ) = sin θ cos θ + cos θ sin θ = 2 sin θ cos θ. This is the only form for sin 2θ.
DOUBLE ANGLE — COSINE (FORM 1)
cos 2θ = cos²θ − sin²θ
Derived from cos(θ + θ) = cos θ cos θ − sin θ sin θ. Use this when you know both sin θ and cos θ.
DOUBLE ANGLE — COSINE (FORM 2)
cos 2θ = 2cos²θ − 1
Replace sin²θ with 1 − cos²θ in Form 1. Use when you only know cos θ.
DOUBLE ANGLE — COSINE (FORM 3)
cos 2θ = 1 − 2sin²θ
Replace cos²θ with 1 − sin²θ in Form 1. Use when you only know sin θ.
📘 IB Formula Booklet
In your IB exam, the double angle identities are provided in the formula booklet. However, you should still understand how to derive them and — more importantly — know which form of cos 2θ to choose for each situation.

Graph Transformations with Double Angles

Understanding how the double angle changes a graph is just as important as the algebra. When you replace θ with 2θ inside a trig function, you perform a horizontal compression by a factor of 2. Let's compare the key features of y = cos θ and y = cos 2θ side by side to make this concrete.

The pink curve is y = cos θ (period 2π) and the amber curve is y = cos 2θ (period π). Both have amplitude 1 and start at the point (0, 1), but the amber curve oscillates twice as quickly.
Key features of y = cos θ vs y = cos 2θ
Featurey = cos θy = cos 2θ
Amplitude11
Period2π ≈ 6.28π ≈ 3.14
Zeros in [0, 2π]π/2, 3π/2π/4, 3π/4, 5π/4, 7π/4
Maximum points in [0, 2π]θ = 0, 2πθ = 0, π, 2π
Minimum points in [0, 2π]θ = πθ = π/2, 3π/2

Notice a pattern: the number of zeros, maxima, and minima all double when we go from cos θ to cos 2θ within the interval [0, 2π]. This makes sense because the period is halved, so the curve fits two complete cycles into the same window. The general rule is that for y = sin(Bθ) or y = cos(Bθ), the period equals 2π/B.

Worked Example

Let's work through a full problem that combines the double angle identities with algebraic reasoning, the kind of question you'll see on an IB exam.

Finding Exact Values Using Double Angle Identities
1
Step 1 — Read the ProblemGiven that sin θ = 3/5 and θ is in the first quadrant (0 < θ < π/2), find the exact values of sin 2θ and cos 2θ.
2
Step 2 — Find cos θSince sin²θ + cos²θ = 1, we have cos²θ = 1 − (3/5)² = 1 − 9/25 = 16/25. Because θ is in the first quadrant, cos θ is positive, so cos θ = 4/5.
cos θ = 4/5
3
Step 3 — Apply sin 2θ = 2 sin θ cos θSubstitute the known values: sin 2θ = 2 × (3/5) × (4/5) = 2 × 12/25 = 24/25.
sin 2θ = 24/25
4
Step 4 — Apply cos 2θ = cos²θ − sin²θSubstitute: cos 2θ = (4/5)² − (3/5)² = 16/25 − 9/25 = 7/25. We could also verify using cos 2θ = 1 − 2sin²θ = 1 − 2(9/25) = 1 − 18/25 = 7/25. ✓
cos 2θ = 7/25
5
Step 5 — Verify (Optional Check)We can check: sin²(2θ) + cos²(2θ) = (24/25)² + (7/25)² = 576/625 + 49/625 = 625/625 = 1. ✓ This confirms our answers are consistent.

Choosing the Right Form of cos 2θ

One of the trickiest parts of double angle problems is deciding which of the three forms of cos 2θ to use. The choice depends entirely on what information you're given or what you're trying to achieve in a simplification. Here's a guide to help you make the right pick every time.

Decision guide for the three forms of cos 2θ
Form of cos 2θBest Used When…Example Scenario
cos²θ − sin²θYou know both sin θ and cos θGiven sin θ = 3/5 in Q1, you find cos θ = 4/5, then use both.
2cos²θ − 1You only know cos θ, or the expression involves only cos termsSimplify an equation that already has cos²θ terms.
1 − 2sin²θYou only know sin θ, or the expression involves only sin termsGiven sin θ = 0.6, directly compute cos 2θ without finding cos θ.
KEY TAKEAWAY
Think of the three forms of cos 2θ like three different routes to the same destination on a map. They all arrive at the same answer, but depending on where you're starting from (what you know), one route is much faster than the others. If you know cos θ, take the 2cos²θ − 1 highway. If you know sin θ, take the 1 − 2sin²θ shortcut. If you know both, any road works — but cos²θ − sin²θ is the most direct.

Connection to Advanced Topics

The double angle identities you've learned here are a gateway to more advanced trigonometric work. In the IB HL course and beyond, you will encounter half-angle formulas, power-reduction identities, and even triple-angle formulas — all of which build directly on the double angle identities. Additionally, the idea of analyzing how coefficients inside trig functions affect graphs extends to the general sinusoidal model y = a sin(b(x − c)) + d.

How SL 3.6 connects to future topics
What You Know Now (SL 3.6)What Comes Next
sin 2θ = 2 sin θ cos θGeneralise to sin 3θ, or use in integration (HL Calculus)
cos 2θ = 1 − 2sin²θRearrange to get sin²θ = (1 − cos 2θ)/2 (power-reduction)
Period of sin 2θ is πModel real phenomena like sound beats, alternating current, tides
Choosing the right form of cos 2θSolving trig equations analytically (SL 3.8 and HL)

In physics, the double angle identities appear when analyzing projectile motion (the range formula R = v²sin 2θ / g), wave interference, and oscillating circuits. Mastering these identities now will pay dividends across multiple subjects.

Practice Problems

PROBLEM 1CONCEPTUAL
Explain in your own words why sin 2θ ≠ 2 sin θ. Use a specific value of θ to support your reasoning.
PROBLEM 2BASIC CALCULATION
Given that cos θ = 5/13 and 0 < θ < π/2, find the exact values of sin 2θ and cos 2θ.
PROBLEM 3INTERMEDIATE
Show that cos 2θ + 1 = 2cos²θ, and use this result to simplify the expression (cos 2θ + 1) / cos θ for cos θ ≠ 0.
PROBLEM 4APPLIED
In physics, the range of a projectile launched at angle θ with initial speed v is R = (v² sin 2θ) / g. A football is kicked at v = 20 m/s and θ = 30°. Use the double angle identity to compute sin 60° exactly, then find the range (use g = 9.8 m/s²). Round to one decimal place.
PROBLEM 5CRITICAL THINKING
The graph of y = a cos(bx) + d passes through the point (0, 3) and has a minimum value of −1, with a period of π. Determine the values of a, b, and d. Then express y in the form y = p cos 2x + q and state p and q.

Lesson Summary

The double angle identities express trig functions of 2θ in terms of θ: sin 2θ = 2 sin θ cos θ and cos 2θ = cos²θ − sin²θ, with two alternative forms 2cos²θ − 1 and 1 − 2sin²θ. These are derived from the compound angle (addition) formulas by setting both angles equal to θ, and they are provided in the IB formula booklet.

On a graph, replacing θ with 2θ inside sin or cos produces a horizontal compression that halves the period from 2π to π while leaving the amplitude unchanged. When solving problems, choose the form of cos 2θ that matches the information you're given — use 2cos²θ − 1 when you know cos θ, 1 − 2sin²θ when you know sin θ, and always verify your answers using sin²(2θ) + cos²(2θ) = 1.

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