GRE Quantitative Reasoning › How to find arithmetic mean
Column A: The median of the set
Column B: The mean of the set
Column A is greater.
Column B is greater.
Columns A and B are equal.
Cannot be determined.
The median is the middle number of the data set. If there is an even number of quantities in the data set, take the average of the middle two numbers.
Here, there are 8 numbers, so (18 + 20)/2 = 19.
The mean, or average, is the sum of the integers divided by number of integers in the set: (20 + 35 + 7 + 12 + 73 + 12 + 18 + 31) / 8 = 26
A plane flies from San Francisco to New York City at 600 miles per hour and returns along the same route at 400 miles per hour. What is the average flying speed for the entire route (in miles per hour)?
First, pick a distance, preferably one that is divisible by 400 and 600. As an example, we will use 1,200. If the distance is 1,200, then it took 2 hours to get to New York City and 3 hours to get back to San Francisco. So, the plane traveled 2,400 miles in 5 hours. The average speed is simply 2,400 miles divided by 5 hours, which is 480 miles per hour.
Sample Set A has 25 data points with an arithmetic mean of 50.
Sample Set B has 75 data points with an arithmetic mean of 100.
Quantity A: The arithmetic mean of the 100 data points encompassing A and B
Quantity B: 80
Quantity A is greater.
Quantity B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
Note that:
The arithmetic mean of the 100 data points encompassing A and B =
(total data of Sample Set A + total data of Sample Set B)/100
We have Mean of Sample Set A = 50, or:
(total of Sample Set A) / 25 = 50
And we have Mean of Sample Set B = 100, or:
(total of Sample Set B) / 75 = 100
We get denominators of 100 by dividing both of the equations:
Divide \[(total of Sample Set A) / 25 = 50\] by 4:
(total of Sample Set A) / 100 = 50/4 = 25/2
Multiply \[(total of Sample Set B)/75 = 100\] by 3/4:
(total of Sample Set B)/100 = 75
Now add the two equations together:
(total data of Sample Set A + total data of Sample Set B)/100
= 75 + 25/2 > 80
Looking at all the multiples of 5 from 5 to 50, what is the mean of all of those values?
All of the multiples of 5 from 5 to 50 are
.
The total of all of them is 275.
Then the mean will be 27.5
.
Which statement is true assuming that a represents the range, b represents the mean, c represents the median, and d represents the mode.
which sequence is correct for the number set: 8, 3, 11, 12, 3, 4, 6, 15, 1 ?
The answer is .
First organize the number set 1, 3, 3, 4, 6, 8, 11, 12, 15
a = range = 14
b = mean = 7
c = median = 6
d = mode = 3
so the order is mode<median<mean<range
or d < c < b < a.
Which statement is true assuming that a represents the range, b represents the mean, c represents the median, and d represents the mode.
Which sequence is correct for the number set: 51, 8, 51, 17, 102, 31, 20
c < b < d < a
b < d < c < a
c < a < d < b
a < b < d < c
d < c < a < b
The answer is c < b < d < a.
When we arrange the number set we see: 8, 17, 20, 31, 51, 51, 102
a = range = 94
b = mean = 40
c = median = 31
d = mode = 51
median < mean < mode < range so c < b < d < a
The average of 10 test scores is 120 and the average of 30 additional scores is 100.
Quantity A: The weighted average of these scores
Quantity B: 105
The two quantities are equal
Quantity A is greater
Quantity B is greater
The relationship cannot be determined from the information given
The sum of the first ten scores is 1,200 and the sum of the next 30 scores is 3,000. To take the weighted average of all scores, divide the sum of all scores (4,200) by the total number of scores (40), which would equal 105.
In a given translation project, three translators each took sections of a book to translate. The first translator took 15000 words, which he translated at a rate of 500 words per 20 minutes. The second translator took 200000 words, which he translated at a rate of 1250 words per half hour. The third took 10000 words, which he translated at a rate of 250 words per 15 minutes. In terms of words per hour, what was the overall average translation rate for this project?
667 words per hour
750 words per hour
1667 words per hour
1575 words per hour
2250 words per hour
To find the answer, we need to know the total words and the total number of hours involved.
The first is easy: 15000 + 200000 + 10000 = 225000 words
To ascertain the number of hours, we have to look at each translator separately. Although there are several ways to do this, let's consider it this way:
Translator 1 can translate at 500 words per 20 minutes OR 1500 words per hour.
Translator 2 can translate at 1250 words per half hour OR 2500 words per hour.
Translator 3 can translate at 250 words per 15 minutes OR 1000 words per hour.
Therefore, we know each translator took the following amount of time:
Translator 1: 15000 / 1500 = 10 hours
Translator 2: 200000 / 2500 = 80 hours
Translator 3: 10000 / 1000 = 10 hours
The total number of hours was therefore 10 + 80 + 10 = 100 hours.
The average rate was 225000 words/100 hours, or 2250 words per hour.
Column A
The mean of the sample of numbers 2, 5, and 10.
Column B
The mean of the sample of numbers 1, 5, and 15.
The quantity in Column A is greater.
The quantity in Column B is greater.
The two quantities are equal.
The relationship cannot be determined from the information given.
The arithmetic mean is the average of the sum of a set of numbers divided by the total number of numbers in the set. This is not to be confused with median or mode.
In Column A, the mean of 5.66 is obtained when the sum (17) is divided by the number of values in the set (3).
In Column B, the mean of 7 is obtained when 21 is divided by 3. Because 7 is greater than 5.66, Column B is greater. The answer is Column B.
The combined height of John and Sandy is 130 inches. Sandy, John, and Allen together have a combined height of 215 inches. Sandy and Allen have combined height of 137 inches. How tall is John?
69
75
78
62
67
Translate the question into a series of equations:
J + S = 130; J + S + A = 215; S + A = 137
Although there are several ways of approaching this, let us choose the path that is most direct. Given that J, S, A are all involved in the second equation, we can isolate J if we eliminate S and A - which can be done by using the data we have in the third equation. Since S + A = 137, we can rewrite J + S + A = 215 as:
J + 137 = 215.
Now, we only need to solve for J:
J = 215 - 137
J = 78 inches.