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This deck focuses on Probability, giving you a quick way to review the definitions, rules, and examples that matter most for GRE Quantitative.
Study Probability in GRE Quantitative with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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Identify P(A∩B) if P(A)=0.3 and P(B∣A)=0.5.
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0.15. Apply the multiplication rule: P(A∩B)=0.3×0.5=0.15.
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This deck focuses on Probability, giving you a quick way to review the definitions, rules, and examples that matter most for GRE Quantitative.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: 0.15. Apply the multiplication rule: P(A∩B)=0.3×0.5=0.15.
Answer: P(E)=#(S)#(E). In a finite sample space where all outcomes are equally likely, the probability of event E is the number of favorable outcomes divided by the total number of outcomes.
Answer: P(≥1)=1−P(0). The probability of at least one occurrence is one minus the probability of zero occurrences in independent trials.
Answer: 0.87. Use the complement rule: P(Ac)=1−0.13=0.87.
Answer: P(A∩B)=P(A)P(B∣A). The multiplication rule expresses the joint probability as the product of one event's probability and the conditional probability of the other given the first.
Answer: (rn)=r!(n−r)!n!. Combinations count the number of ways to choose r items out of n distinct ones, where order does not matter.
Answer: 41. With replacement, P(both red)=5226×5226=21×21=41.
Answer: P(n,r)=(n−r)!n!. Permutations count the number of ways to arrange r items out of n distinct ones, where order matters.
Answer: 0.4. Use the conditional probability formula: P(A∣B)=0.30.12=0.4.
Answer: P(A∪B)=P(A)+P(B)−P(A∩B). The addition rule accounts for the overlap by subtracting the intersection probability from the sum of individual probabilities.
Answer: 0.7. Apply the addition rule: P(A∪B)=0.4+0.5−0.2=0.7.
Answer: 3. For binomial, E[X]=np=10×0.3=3.
Answer: Var(X)=np(1−p). The variance of a binomial random variable measures spread as np times the failure probability.
Answer: 87. Calculate as 1−P(all tails)=1−(21)3=1−81=87.
Answer: 3611. Calculate as 1−P(no 6)=1−(65)2=1−3625=3611.
Answer: P(A∣B)=P(B)P(A∩B). Conditional probability measures the likelihood of A occurring given B has occurred, by dividing the joint probability by P(B).
Answer: 0.12. For independent events, P(A∩B)=0.2×0.6=0.12.
Answer: P(A∪B)=P(A)+P(B). For mutually exclusive events, there is no overlap, so their union probability is simply the sum of their individual probabilities.
Answer: E[X]=np. The expected value of a binomial random variable is the product of the number of trials and the success probability per trial.
Answer: P(A∩B)=P(A)P(B). Events A and B are independent if their joint probability equals the product of their marginal probabilities.
Answer: P(A∣B)=P(A). For independent events, the occurrence of B does not affect the probability of A, so the conditional equals the unconditional probability.
Answer: (kn)pk(1−p)n−k. The binomial probability formula gives the likelihood of exactly k successes in n independent trials each with success probability p.
Answer: 83. Use binomial formula: (23)(21)3=3×81=83.
Answer: P(Ac)=1−P(A). The complement rule states that the probability of an event not occurring equals one minus the probability of it occurring.