Geometry Lesson

Derive the Equation of a Parabola

Learn Derive the Equation of a Parabola.

Where Parabolas Come From: A Brief History

People have been studying parabolas for more than two thousand years. The curve shows up everywhere—from the arc of a basketball shot to the shape of satellite dishes—but it was ancient Greek mathematicians who first pinned down what a parabola actually is . Understanding this history helps you see that the equation you're about to derive isn't an arbitrary formula; it's the end result of centuries of curiosity about a beautifully simple shape.

The central question this lesson answers is deceptively simple: If every point on a parabola is the same distance from a fixed point (the focus) and a fixed line (the directrix), what equation does that condition produce? The answer connects geometry to algebra in a powerful way.

Core Definitions You Need First

Before we derive anything, let's lock down the vocabulary. A parabola is defined as the set of all points in a plane that are equidistant from a fixed point called the focus and a fixed line called the directrix . Every concept below flows from that single rule.

1

Focus

A fixed point that sits inside the "bowl" of the parabola. All points on the curve are equidistant from the focus and the directrix. Denoted (0, p) when the vertex is at the origin and the parabola opens vertically.
2

Directrix

A fixed line that sits outside the parabola, on the opposite side from the focus. For a parabola with vertex at the origin opening upward, the directrix is the horizontal line y = −p.
3

Vertex

The turning point of the parabola. It lies exactly halfway between the focus and the directrix, at a distance of |p| from each.
4

Axis of Symmetry

The line passing through the focus and vertex, perpendicular to the directrix. The parabola is a mirror image on either side of this line.
5

Parameter p

The directed distance from the vertex to the focus. If p > 0, the parabola opens upward (or rightward); if p < 0, it opens downward (or leftward).
KEY TAKEAWAY
Think of the focus and directrix as two "targets" competing for your attention. Every point on the parabola is like a person standing so that their distance to one target (the focus) is exactly equal to their distance to the other target (the directrix). The curve is the collection of every such balanced position—like standing at the exact halfway point between two speakers that are equally loud.

Seeing the Parabola: Focus, Directrix, and Equal Distances

The diagram below is the visual centerpiece of this lesson. It shows a parabola with its vertex at the origin, its focus at (0, p), and its directrix at y = −p. Notice the dashed lines from a general point (x, y) on the curve: one goes to the focus and the other drops straight down to the directrix. Those two distances are always equal—that's the whole definition in a picture.

Study this diagram closely. The point P(x, y) sits on the parabola. The dashed pink line d₁ shows the distance from P to the focus , while the dashed purple line d₂ shows the perpendicular distance from P down to the directrix . Because the parabola is defined by the condition d₁ = d₂ , those two dashed lines are always the same length for any point on the curve. The vertex sits exactly halfway between the focus and the directrix, at a distance of p from each.

The Derivation, Step by Step

Now for the main event. We'll use the distance formula from Algebra 1 to turn the geometric definition into an algebraic equation. The setup is simple: place the vertex of the parabola at the origin, let the focus be at (0, p) , and let the directrix be the line y = −p . Take any point P(x, y) on the parabola. We want to find the relationship between x and y.

Equation
Step 1 — Write the Equal-Distance Condition: distance from P to focus = distance from P to directrix

The distance from P(x, y) to the focus (0, p) uses the standard distance formula: √[(x − 0)² + (y − p)²], which simplifies to √[x² + (y − p)²]. The distance from P to the directrix y = −p is the vertical distance |y − (−p)| = |y + p|. Since every point on the parabola lies on the same side of the directrix as the focus, we can write this as (y + p) when the parabola opens upward, because y ≥ 0 at the vertex and y + p is always positive. Setting these equal:

Equation
Step 2 — Set Up the Equation: √(x² + (y − p)²) = y + p

To eliminate the square root, square both sides of the equation. This is a valid algebraic move because both sides represent distances (which are non-negative).

Equation
Step 3 — Square Both Sides: x² + (y − p)² = (y + p)²

Now expand both squared binomials. On the left, (y − p)² = y² − 2py + p². On the right, (y + p)² = y² + 2py + p².

Equation
Step 4 — Expand: x² + y² − 2py + p² = y² + 2py + p²

Notice that y² and p² appear on both sides. Subtract them from each side, and everything simplifies dramatically:

Equation
Step 5 — Simplify: x² − 2py = 2py
Equation
Step 6 — Solve for y: x² = 4py

That's it! The equation x² = 4py is the standard form of a parabola with vertex at the origin that opens upward (when p > 0) or downward (when p < 0). If you prefer to solve for y, you can write y = x² / (4p) . The number p controls how "wide" or "narrow" the parabola is: a larger |p| means a wider, shallower curve, while a smaller |p| means a tighter, steeper one.

KEY TAKEAWAY
The derivation works like a recipe: start with the geometric definition (equal distances), translate it into algebra (distance formula), then simplify. You go from a picture to an equation in six clean steps. It's like converting a verbal driving direction ("turn left at the park") into GPS coordinates—same information, different language.

All Four Orientations and the General Vertex Form

The derivation above assumed a parabola opening upward with its vertex at the origin, but parabolas can open in any direction and be centered anywhere. The table below summarizes all four standard orientations, and the diagram that follows shows them side by side.

DirectionEquation (vertex at origin)FocusDirectrix
Opens Up (p > 0)x² = 4py(0, p)y = −p
Opens Down (p < 0)x² = 4py [with p < 0, so 4p < 0](0, p), where p < 0y = −p, where −p > 0
Opens Right (p > 0)y² = 4px(p, 0)x = −p
Opens Left (p < 0)y² = 4px [with p < 0, so 4p < 0](p, 0), where p < 0x = −p, where −p > 0

When the vertex is not at the origin but at a point (h, k), the equations shift accordingly. For a vertical parabola, the equation becomes (x − h)² = 4p(y − k) , and for a horizontal one, (y − k)² = 4p(x − h) . The value of p still represents the directed distance from the vertex to the focus.

A quick way to remember the pattern: if x is the squared variable, the parabola opens vertically (up or down). If y is the squared variable, it opens horizontally (left or right). The sign of p tells you which direction. Positive p means toward the positive axis direction (up or right), and negative p means the opposite.

Equation
General Vertex Form — Vertical: (x − h)² = 4p(y − k)
Equation
General Vertex Form — Horizontal: (y − k)² = 4p(x − h)

Worked Example: From Focus and Directrix to Equation

Problem: A parabola has a focus at (0, 3) and a directrix at y = −3. Find the equation of the parabola.

Worked Example: Focus (0, 3) and Directrix y = −3
1
Step 1 — Identify the VertexThe vertex is the midpoint between the focus and the directrix. The focus is at y = 3, and the directrix is at y = −3. The midpoint of those y-values is: vertex y-coordinate = (3 + (−3)) / 2 = 0 / 2 = 0. Since the focus is at x = 0 and the axis of symmetry is vertical, the vertex x-coordinate is also 0.
2
Step 2 — Find pThe value p is the directed distance from the vertex to the focus. The vertex is at y = 0 and the focus is at y = 3, so: p = 3 − 0 = 3
3
Step 3 — Plug into the Standard EquationFor a vertical parabola with vertex at the origin, the equation is x² = 4py. Substitute p = 3: x² = 4(3)y → x² = 12y
4
Step 4 — Verify with a Test PointPick a point that should lie on the parabola. If x = 6, then y = 6²/12 = 36/12 = 3. Check: the distance from (6, 3) to the focus (0, 3) is √(36 + 0) = 6. The distance from (6, 3) to the directrix y = −3 is |3 − (−3)| = 6. Equal! ✓

Strengths, Limitations, and Common Mistakes

The focus-directrix form is powerful, but it's not the only way to write a parabola's equation, and there are some frequent mistakes students make. The table below compares the three common forms you'll encounter.

FormEquationBest ForLimitations
Standard (focus-directrix)x² = 4pyFinding focus, directrix, and geometric properties directlyLess convenient for quick graphing or finding vertex of shifted parabolas
Vertex Formy = a(x − h)² + kGraphing, identifying vertex and direction quicklyRequires conversion to find focus and directrix; a = 1/(4p)
General FormAx² + Dx + Ey + F = 0Connecting to broader conic section theoryRequires completing the square to extract useful geometric information

One of the most common errors is confusing the value of p with the coefficient a in vertex form. Remember: if y = a(x − h)² + k, then a = 1/(4p) . A "tall, narrow" parabola has a large |a| but a small |p|, meaning the focus is close to the vertex. A "wide, shallow" parabola has a small |a| but a large |p|. Another frequent mistake is getting the sign of p wrong, which flips the parabola to open in the wrong direction.

KEY TAKEAWAY
The standard form x² = 4py is the geometric form—it's built from the focus-directrix definition and gives you direct access to the focus and directrix positions. The vertex form y = a(x − h)² + k is the graphing form—it's faster for plotting. They're the same curve written in different "languages," and you should be comfortable converting between them, just like you'd convert between miles and kilometers depending on the situation.

Connection to the Bigger Picture: Conic Sections

The parabola is one member of a family called conic sections —curves formed by slicing a cone at different angles. The other members are the circle , the ellipse , and the hyperbola . What makes the parabola unique is its relationship between the focus and the directrix. Each conic section has a property called eccentricity (symbolized by e ) that describes how "stretched out" it is. For a parabola, the eccentricity is exactly 1.

Conic SectionEccentricity (e)Focus-Directrix RelationshipShape Description
Circlee = 0No directrix (or directrix at infinity)Perfectly round; all points equidistant from center
Ellipse0 < e < 1Distance to focus < distance to directrixOval; two foci, closed curve
Parabolae = 1Distance to focus = distance to directrixOpen U-shaped curve; one focus and one directrix
Hyperbolae > 1Distance to focus > distance to directrixTwo open branches; two foci

In more advanced courses (like precalculus or AP math), you'll study all four conic sections and see how they're connected through the general second-degree equation Ax² + Bxy + Cy² + Dx + Ey + F = 0. The parabola is the special case where the discriminant B² − 4AC = 0. But for now, the key idea is this: the derivation technique you learned today—setting up an equal-distance condition and simplifying—is the same strategy used to derive equations for ellipses and hyperbolas. Master it here, and you've built a foundation that extends well beyond parabolas.

Practice Problems

Try these five problems to solidify your understanding. They start with a conceptual check and build toward multi-step challenges.

PROBLEM 1PROBLEM 1
What is the definition of a parabola in terms of focus and directrix?
PROBLEM 2PROBLEM 2
A parabola has its vertex at the origin and focus at (0, 5). Write the equation of the parabola.
PROBLEM 3PROBLEM 3
Find the focus and directrix of the parabola x² = −8y.
PROBLEM 4PROBLEM 4
A parabola has focus (0, 2) and directrix y = −2. Verify that the point (4, 2) lies on the parabola.
PROBLEM 5PROBLEM 5
Convert x² = 12y to vertex form and identify a and p.
Great work reviewing this lesson.