Geometry - Similar Circles: CCSS.Math.Content.HSG-C.A.1

Given $\frac{C}{C'}=55$ , and , what is

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$R'=\frac{18}{55}$

$R'=\frac{55}{18}$

$R'=\frac{1}{18}$

Explanation

In order to do this problem, we need to remember the relationship between Circumference's, and Radii. $\frac{C}{C'}=\frac{R}{R'}$ . With this relationship, we can determine what is.

$\frac{C}{C'}=\frac{R}{R'}$

Substitute for the variables given in the question.

$55=\frac{18}{R'}$

Multiply by on each side.

Divide by to get .

$R'=\frac{18}{55}$

Given $\frac{C}{C'}=113$ , and , what is

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$R'=\frac{16}{113}$

$R'=\frac{113}{16}$

$R'=\frac{1}{16}$

Explanation

In order to do this problem, we need to remember the relationship between Circumference's, and Radii. $\frac{C}{C'}=\frac{R}{R'}$ . With this relationship, we can determine what is.

$\frac{C}{C'}=\frac{R}{R'}$

Substitute for the variables given in the question.

$113=\frac{16}{R'}$

Multiply by on each side.

Divide by to get .

$R'=\frac{16}{113}$

Given $\frac{C}{C'}=115$ , and , what is

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$R'=\frac{9}{115}$

$R'=\frac{115}{9}$

Explanation

In order to do this problem, we need to remember the relationship between Circumference's, and Radii. $\frac{C}{C'}=\frac{R}{R'}$ . With this relationship, we can determine what is.

$\frac{C}{C'}=\frac{R}{R'}$

Substitute for the variables given in the question.

$115=\frac{9}{R'}$

Multiply by on each side.

Divide by to get .

$R'=\frac{9}{115}$

Given $\frac{C}{C'}=58$ , and , what is

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$R'=\frac{3}{29}$

$R'=\frac{29}{3}$

Explanation

In order to do this problem, we need to remember the relationship between Circumference's, and Radii. $\frac{C}{C'}=\frac{R}{R'}$ . With this relationship, we can determine what is.

$\frac{C}{C'}=\frac{R}{R'}$

Substitute for the variables given in the question.

$58=\frac{6}{R'}$

Multiply by on each side.

Divide by to get .

$R'=\frac{6}{58}=\frac{3}{29}$

Given $\frac{C}{C'}=113$ , and , what is

Screen shot 2020 07 01 at 7.06.26 pm

$R'=\frac{12}{113}$

$R'=\frac{113}{12}$

$R'=\frac{1}{12}$

Explanation

In order to do this problem, we need to remember the relationship between Circumference's, and Radii. $\frac{C}{C'}=\frac{R}{R'}$ . With this relationship, we can determine what is.

$\frac{C}{C'}=\frac{R}{R'}$

Substitute for the variables given in the question.

$113=\frac{12}{R'}$

Multiply by on each side.

Divide by to get .

$R'=\frac{12}{113}$

Given $\frac{C}{C'}=40$ , and , what is

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$R'=\frac{1}{5}$

$R'=\frac{1}{40}$

Explanation

In order to do this problem, we need to remember the relationship between Circumference's, and Radii. $\frac{C}{C'}=\frac{R}{R'}$ . With this relationship, we can determine what is.

$\frac{C}{C'}=\frac{R}{R'}$

Substitute for the variables given in the question.

$40=\frac{8}{R'}$

Multiply by on each side.

Divide by to get .

$R'=\frac{8}{40}=\frac{1}{5}$

Given $\frac{C}{C'}=95$ , and , what is

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$R'=\frac{4}{19}$

$R'=\frac{1}{19}$

$R'=\frac{19}{4}$

Explanation

In order to do this problem, we need to remember the relationship between Circumference's, and Radii. $\frac{C}{C'}=\frac{R}{R'}$ . With this relationship, we can determine what is.

$\frac{C}{C'}=\frac{R}{R'}$

Substitute for the variables given in the question.

$95=\frac{20}{R'}$

Multiply by on each side.

Divide by to get .

$R'=\frac{20}{95}=\frac{4}{19}$

Given $\frac{C}{C'}=25$ , and , what is

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$R'=\frac{4}{25}$

$R'=\frac{25}{4}$

Explanation

In order to do this problem, we need to remember the relationship between Circumference's, and Radii. $\frac{C}{C'}=\frac{R}{R'}$ . With this relationship, we can determine what is.

$\frac{C}{C'}=\frac{R}{R'}$

Substitute for the variables given in the question.

$25=\frac{4}{R'}$

Multiply by on each side.

Divide by to get .

$R'=\frac{4}{25}$

Given $\frac{C}{C'}=76$ , and , what is

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$R'=\frac{3}{38}$

$R'=\frac{38}{3}$

$R'=\frac{1}{38}$

Explanation

In order to do this problem, we need to remember the relationship between Circumference's, and Radii. $\frac{C}{C'}=\frac{R}{R'}$ . With this relationship, we can determine what is.

$\frac{C}{C'}=\frac{R}{R'}$

Substitute for the variables given in the question.

$76=\frac{6}{R'}$

Multiply by on each side.

Divide by to get .

$R'=\frac{6}{76}=\frac{3}{38}$

Given $\frac{C}{C'}=92$ , and , what is

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$R'=\frac{5}{92}$

$R'=\frac{92}{5}$

$R'=\frac{1}{92}$

Explanation

In order to do this problem, we need to remember the relationship between Circumference's, and Radii. $\frac{C}{C'}=\frac{R}{R'}$ . With this relationship, we can determine what is.

$\frac{C}{C'}=\frac{R}{R'}$

Substitute for the variables given in the question.

$92=\frac{5}{R'}$