How to find the height of a 45/45/90 right isosceles triangle - Geometry

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Question

$\fn_cm In;\Delta ABC,;\angle BAC=45^{\circ }.$

$\angle BCA = , ?$

Answer

$The;degrees;in;a;triangle;sum;to;180^{\circ}. ; 180^{\circ}-90^{\circ}-45^{\circ}=45^{\circ}.$

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Question

Find the height of the 45-45-90 right triangle with a hypotenuse of $15\sqrt{6}$ .

Answer

If the hypotenuse of a 45-45-90 right triangle is $15\sqrt{6}$ then:

The height and the base of the triangle will be the same length since it is a 45-45-90 triangle (isosceles).

Since both a and b will be equal let's use a=b=x and $c=15\sqrt{6}$ :

$x^2 +x^2=(15\sqrt{6})^2$

$x=\sqrt{675}$

$x=\sqrt{225*3}$

$x=\sqrt{225}, \sqrt{3}$

$x=15\sqrt{3}$

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Question

What is the height of a triangle if its hypotenuse is $2\sqrt7$ cm.

Answer

Given that is a 45/45/90 triangle, it means that it's also isosceles. Because the hypotenuse if 2√7 cm, that means that the base and the height (the two remaining sides) will be equivalent.

The length of one of the legs can be solved for in one of two ways.

1. The Pythagorean Theorem

2. Using

Using the Pythagorean Theorem, , we've already determined that "a" and "b" are the same number. Lets say . This allows for the equation to be rewritten as , which may be simplified into ${\color{Purple} 2s^2=c^2}$

Because s is our unknown, we will be solving for s.

$2s^2=(2\sqrt{7})^2$

$2s^2=4\sqrt{49}$

$s^2=\frac{28}{2}$

$\sqrt{s^2}=\sqrt{14}$

${\color{Blue} s=\sqrt{14} cm}$

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Question

If the hypotenuse of an isoceles right triangle is , what is the length of the height of the triangle?

Answer

An isoceles right triangle is another way of saying that the triangle is a triangle.

Now, recall the Pythagorean theorem:

$\text{base}^2+\text{height}^2=\text{hypotenuse}^2$

Because we are working with a triangle, the base and the height have the same length. We can rewrite the above equation as the following:

$\text{height}^2+\text{height}^2=\text{hypotenuse}^2$

$2(\text{height})^2=\text{hypotenuse}^2$

$\text{height}^2=\frac{\text{hypotenuse}^2}{2}$

$\text{height}=\sqrt{\frac{\text{hypotenuse}^2}{2}}$

Simplify.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}$

Multiply the fraction by one in the form of:

$1\rightarrow \frac{\sqrt{2}}{\sqrt{2}}$

Substitute.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}\times \frac{\sqrt{2}}{\sqrt{2}}$

Solve.

$\text{height}=\frac{\text{hypotenuse}(\sqrt2)}{2}{}$

Now, substitute in the value of the hypotenuse to find the height for the given triangle.

$\text{height}=\frac{12\sqrt2}{2}$

Simplify.

$\text{height}=6\sqrt2$

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Question

If the hypotenuse of an isoceles right triangle is , what is the length of the height?

Answer

An isoceles right triangle is another way of saying that the triangle is a triangle.

Now, recall the Pythagorean theorem:

$\text{base}^2+\text{height}^2=\text{hypotenuse}^2$

Because we are working with a triangle, the base and the height have the same length. We can rewrite the above equation as the following:

$\text{height}^2+\text{height}^2=\text{hypotenuse}^2$

$2(\text{height})^2=\text{hypotenuse}^2$

$\text{height}^2=\frac{\text{hypotenuse}^2}{2}$

$\text{height}=\sqrt{\frac{\text{hypotenuse}^2}{2}}$

Simplify.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}$

Multiply the fraction by one in the form of:

$1\rightarrow \frac{\sqrt{2}}{\sqrt{2}}$

Substitute.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}\times \frac{\sqrt{2}}{\sqrt{2}}$

Solve.

$\text{height}=\frac{\text{hypotenuse}(\sqrt2)}{2}{}$

Now, substitute in the value of the hypotenuse to find the height for the given triangle.

$\text{height}=\frac{13\sqrt2}{2}$

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Question

If the hypotenuse of an isoceles right triangle is , what is the length of the height of the triangle?

Answer

An isoceles right triangle is another way of saying that the triangle is a triangle.

Now, recall the Pythagorean theorem:

$\text{base}^2+\text{height}^2=\text{hypotenuse}^2$

Because we are working with a triangle, the base and the height have the same length. We can rewrite the above equation as the following:

$\text{height}^2+\text{height}^2=\text{hypotenuse}^2$

$2(\text{height})^2=\text{hypotenuse}^2$

$\text{height}^2=\frac{\text{hypotenuse}^2}{2}$

$\text{height}=\sqrt{\frac{\text{hypotenuse}^2}{2}}$

Simplify.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}$

Multiply the fraction by one in the form of:

$1\rightarrow \frac{\sqrt{2}}{\sqrt{2}}$

Substitute.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}\times \frac{\sqrt{2}}{\sqrt{2}}$

Solve.

$\text{height}=\frac{\text{hypotenuse}(\sqrt2)}{2}{}$

Now, substitute in the value of the hypotenuse to find the height for the given triangle.

$\text{height}=\frac{21\sqrt2}{2}$

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Question

If the hypotenuse of an isoceles right triangle is , what is the length of the height?

Answer

An isoceles right triangle is another way of saying that the triangle is a triangle.

Now, recall the Pythagorean theorem:

$\text{base}^2+\text{height}^2=\text{hypotenuse}^2$

Because we are working with a triangle, the base and the height have the same length. We can rewrite the above equation as the following:

$\text{height}^2+\text{height}^2=\text{hypotenuse}^2$

$2(\text{height})^2=\text{hypotenuse}^2$

$\text{height}^2=\frac{\text{hypotenuse}^2}{2}$

$\text{height}=\sqrt{\frac{\text{hypotenuse}^2}{2}}$

Simplify.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}$

Multiply the fraction by one in the form of:

$1\rightarrow \frac{\sqrt{2}}{\sqrt{2}}$

Substitute.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}\times \frac{\sqrt{2}}{\sqrt{2}}$

Solve.

$\text{height}=\frac{\text{hypotenuse}(\sqrt2)}{2}{}$

Now, substitute in the value of the hypotenuse to find the height for the given triangle.

$\text{height}=\frac{212\sqrt2}{2}$

Simplify.

$\text{height}=106\sqrt2$

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Question

If the hypotenuse of an isoceles right triangle is , what is the length of the height?

Answer

An isoceles right triangle is another way of saying that the triangle is a triangle.

Now, recall the Pythagorean theorem:

$\text{base}^2+\text{height}^2=\text{hypotenuse}^2$

Because we are working with a triangle, the base and the height have the same length. We can rewrite the above equation as the following:

$\text{height}^2+\text{height}^2=\text{hypotenuse}^2$

$2(\text{height})^2=\text{hypotenuse}^2$

$\text{height}^2=\frac{\text{hypotenuse}^2}{2}$

$\text{height}=\sqrt{\frac{\text{hypotenuse}^2}{2}}$

Simplify.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}$

Multiply the fraction by one in the form of:

$1\rightarrow \frac{\sqrt{2}}{\sqrt{2}}$

Substitute.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}\times \frac{\sqrt{2}}{\sqrt{2}}$

Solve.

$\text{height}=\frac{\text{hypotenuse}(\sqrt2)}{2}{}$

Now, substitute in the value of the hypotenuse to find the height for the given triangle.

$\text{height}=\frac{56\sqrt2}{2}$

Simplify.

$\text{height}=28\sqrt2$

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Question

If the hypotenuse of an isoceles right triangle is , what is the length of the height?

Answer

An isoceles right triangle is another way of saying that the triangle is a triangle.

Now, recall the Pythagorean theorem:

$\text{base}^2+\text{height}^2=\text{hypotenuse}^2$

Because we are working with a triangle, the base and the height have the same length. We can rewrite the above equation as the following:

$\text{height}^2+\text{height}^2=\text{hypotenuse}^2$

$2(\text{height})^2=\text{hypotenuse}^2$

$\text{height}^2=\frac{\text{hypotenuse}^2}{2}$

$\text{height}=\sqrt{\frac{\text{hypotenuse}^2}{2}}$

Simplify.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}$

Multiply the fraction by one in the form of:

$1\rightarrow \frac{\sqrt{2}}{\sqrt{2}}$

Substitute.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}\times \frac{\sqrt{2}}{\sqrt{2}}$

Solve.

$\text{height}=\frac{\text{hypotenuse}(\sqrt2)}{2}{}$

Now, substitute in the value of the hypotenuse to find the height for the given triangle.

$\text{height}=\frac{66\sqrt2}{2}$

Simplify.

$\text{height}=33\sqrt2$

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Question

If the hypotenuse of an isoceles right triangle is , what is the length of the height?

Answer

An isoceles right triangle is another way of saying that the triangle is a triangle.

Now, recall the Pythagorean theorem:

$\text{base}^2+\text{height}^2=\text{hypotenuse}^2$

Because we are working with a triangle, the base and the height have the same length. We can rewrite the above equation as the following:

$\text{height}^2+\text{height}^2=\text{hypotenuse}^2$

$2(\text{height})^2=\text{hypotenuse}^2$

$\text{height}^2=\frac{\text{hypotenuse}^2}{2}$

$\text{height}=\sqrt{\frac{\text{hypotenuse}^2}{2}}$

Simplify.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}$

Multiply the fraction by one in the form of:

$1\rightarrow \frac{\sqrt{2}}{\sqrt{2}}$

Substitute.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}\times \frac{\sqrt{2}}{\sqrt{2}}$

Solve.

$\text{height}=\frac{\text{hypotenuse}(\sqrt2)}{2}{}$

Now, substitute in the value of the hypotenuse to find the height for the given triangle.

$\text{height}=\frac{68\sqrt2}{2}$

Simplify.

$\text{height}=34\sqrt2$

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Question

If the hypotenuse of an isoceles right triangle is , what is the length of the height?

Answer

An isoceles right triangle is another way of saying that the triangle is a triangle.

Now, recall the Pythagorean theorem:

$\text{base}^2+\text{height}^2=\text{hypotenuse}^2$

Because we are working with a triangle, the base and the height have the same length. We can rewrite the above equation as the following:

$\text{height}^2+\text{height}^2=\text{hypotenuse}^2$

$2(\text{height})^2=\text{hypotenuse}^2$

$\text{height}^2=\frac{\text{hypotenuse}^2}{2}$

$\text{height}=\sqrt{\frac{\text{hypotenuse}^2}{2}}$

Simplify.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}$

Multiply the fraction by one in the form of:

$1\rightarrow \frac{\sqrt{2}}{\sqrt{2}}$

Substitute.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}\times \frac{\sqrt{2}}{\sqrt{2}}$

Solve.

$\text{height}=\frac{\text{hypotenuse}(\sqrt2)}{2}{}$

Now, substitute in the value of the hypotenuse to find the height for the given triangle.

$\text{height}=\frac{88\sqrt2}{2}$

Simplify.

$\text{height}=44\sqrt2$

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Question

If the hypotenuse of an isoceles right triangle is , what is the length of the height?

Answer

An isoceles right triangle is another way of saying that the triangle is a triangle.

Now, recall the Pythagorean theorem:

$\text{base}^2+\text{height}^2=\text{hypotenuse}^2$

Because we are working with a triangle, the base and the height have the same length. We can rewrite the above equation as the following:

$\text{height}^2+\text{height}^2=\text{hypotenuse}^2$

$2(\text{height})^2=\text{hypotenuse}^2$

$\text{height}^2=\frac{\text{hypotenuse}^2}{2}$

$\text{height}=\sqrt{\frac{\text{hypotenuse}^2}{2}}$

Simplify.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}$

Multiply the fraction by one in the form of:

$1\rightarrow \frac{\sqrt{2}}{\sqrt{2}}$

Substitute.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}\times \frac{\sqrt{2}}{\sqrt{2}}$

Solve.

$\text{height}=\frac{\text{hypotenuse}(\sqrt2)}{2}{}$

Now, substitute in the value of the hypotenuse to find the height for the given triangle.

$\text{height}=\frac{124\sqrt2}{2}$

Simplify.

$\text{height}=62\sqrt2$

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Question

If the hypotenuse of an isoceles right triangle is , what is the length of the height?

Answer

An isoceles right triangle is another way of saying that the triangle is a triangle.

Now, recall the Pythagorean theorem:

$\text{base}^2+\text{height}^2=\text{hypotenuse}^2$

Because we are working with a triangle, the base and the height have the same length. We can rewrite the above equation as the following:

$\text{height}^2+\text{height}^2=\text{hypotenuse}^2$

$2(\text{height})^2=\text{hypotenuse}^2$

$\text{height}^2=\frac{\text{hypotenuse}^2}{2}$

$\text{height}=\sqrt{\frac{\text{hypotenuse}^2}{2}}$

Simplify.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}$

Multiply the fraction by one in the form of:

$1\rightarrow \frac{\sqrt{2}}{\sqrt{2}}$

Substitute.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}\times \frac{\sqrt{2}}{\sqrt{2}}$

Solve.

$\text{height}=\frac{\text{hypotenuse}(\sqrt2)}{2}{}$

Now, substitute in the value of the hypotenuse to find the height for the given triangle.

$\text{height}=\frac{144\sqrt2}{2}$

Simplify.

$\text{height}=72\sqrt2$

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Question

If the hypotenuse of an isoceles right triangle is , what is the length of the height of the triangle?

Answer

An isoceles right triangle is another way of saying that the triangle is a triangle.

Now, recall the Pythagorean theorem:

$\text{base}^2+\text{height}^2=\text{hypotenuse}^2$

Because we are working with a triangle, the base and the height have the same length. We can rewrite the above equation as the following:

$\text{height}^2+\text{height}^2=\text{hypotenuse}^2$

$2(\text{height})^2=\text{hypotenuse}^2$

$\text{height}^2=\frac{\text{hypotenuse}^2}{2}$

$\text{height}=\sqrt{\frac{\text{hypotenuse}^2}{2}}$

Simplify.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}$

Multiply the fraction by one in the form of:

$1\rightarrow \frac{\sqrt{2}}{\sqrt{2}}$

Substitute.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}\times \frac{\sqrt{2}}{\sqrt{2}}$

Solve.

$\text{height}=\frac{\text{hypotenuse}(\sqrt2)}{2}{}$

Now, substitute in the value of the hypotenuse to find the height for the given triangle.

$\text{height}=\frac{95\sqrt2}{2}$

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Question

If the hypotenuse of an isoceles right triangle is , what is the length of the height?

Answer

An isoceles right triangle is another way of saying that the triangle is a triangle.

Now, recall the Pythagorean theorem:

$\text{base}^2+\text{height}^2=\text{hypotenuse}^2$

Because we are working with a triangle, the base and the height have the same length. We can rewrite the above equation as the following:

$\text{height}^2+\text{height}^2=\text{hypotenuse}^2$

$2(\text{height})^2=\text{hypotenuse}^2$

$\text{height}^2=\frac{\text{hypotenuse}^2}{2}$

$\text{height}=\sqrt{\frac{\text{hypotenuse}^2}{2}}$

Simplify.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}$

Multiply the fraction by one in the form of:

$1\rightarrow \frac{\sqrt{2}}{\sqrt{2}}$

Substitute.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}\times \frac{\sqrt{2}}{\sqrt{2}}$

Solve.

$\text{height}=\frac{\text{hypotenuse}(\sqrt2)}{2}{}$

Now, substitute in the value of the hypotenuse to find the height for the given triangle.

$\text{height}=\frac{52\sqrt2}{2}$

Simplify.

$\text{height}=26\sqrt2$

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Question

Find the height of this triangle:

Answer

To find the height, use the Pythagorean Theorem. One of the legs is the missing side, and the other is 1.5, half of 3. The hypotenuse is 5:

$x \approx 4.77$

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Question

$\fn_cm In;\Delta ABC,;\angle BAC=45^{\circ }.$

$\angle BCA = , ?$

Answer

$The;degrees;in;a;triangle;sum;to;180^{\circ}. ; 180^{\circ}-90^{\circ}-45^{\circ}=45^{\circ}.$

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Question

Find the height of the 45-45-90 right triangle with a hypotenuse of $15\sqrt{6}$ .

Answer

If the hypotenuse of a 45-45-90 right triangle is $15\sqrt{6}$ then:

The height and the base of the triangle will be the same length since it is a 45-45-90 triangle (isosceles).

Since both a and b will be equal let's use a=b=x and $c=15\sqrt{6}$ :

$x^2 +x^2=(15\sqrt{6})^2$

$x=\sqrt{675}$

$x=\sqrt{225*3}$

$x=\sqrt{225}, \sqrt{3}$

$x=15\sqrt{3}$

Compare your answer with the correct one above

Question

What is the height of a triangle if its hypotenuse is $2\sqrt7$ cm.

Answer

Given that is a 45/45/90 triangle, it means that it's also isosceles. Because the hypotenuse if 2√7 cm, that means that the base and the height (the two remaining sides) will be equivalent.

The length of one of the legs can be solved for in one of two ways.

1. The Pythagorean Theorem

2. Using

Using the Pythagorean Theorem, , we've already determined that "a" and "b" are the same number. Lets say . This allows for the equation to be rewritten as , which may be simplified into ${\color{Purple} 2s^2=c^2}$

Because s is our unknown, we will be solving for s.

$2s^2=(2\sqrt{7})^2$

$2s^2=4\sqrt{49}$

$s^2=\frac{28}{2}$

$\sqrt{s^2}=\sqrt{14}$

${\color{Blue} s=\sqrt{14} cm}$

Compare your answer with the correct one above

Question

If the hypotenuse of an isoceles right triangle is , what is the length of the height of the triangle?

Answer

An isoceles right triangle is another way of saying that the triangle is a triangle.

Now, recall the Pythagorean theorem:

$\text{base}^2+\text{height}^2=\text{hypotenuse}^2$

Because we are working with a triangle, the base and the height have the same length. We can rewrite the above equation as the following:

$\text{height}^2+\text{height}^2=\text{hypotenuse}^2$

$2(\text{height})^2=\text{hypotenuse}^2$

$\text{height}^2=\frac{\text{hypotenuse}^2}{2}$

$\text{height}=\sqrt{\frac{\text{hypotenuse}^2}{2}}$

Simplify.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}$

Multiply the fraction by one in the form of:

$1\rightarrow \frac{\sqrt{2}}{\sqrt{2}}$

Substitute.

$\text{height}=\frac{\text{hypotenuse}}{\sqrt2}\times \frac{\sqrt{2}}{\sqrt{2}}$

Solve.

$\text{height}=\frac{\text{hypotenuse}(\sqrt2)}{2}{}$

Now, substitute in the value of the hypotenuse to find the height for the given triangle.

$\text{height}=\frac{12\sqrt2}{2}$

Simplify.

$\text{height}=6\sqrt2$

Compare your answer with the correct one above

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