Practice Test 1

$\y=\frac{1}{7}x^4-\frac{1}{4}x^2+cx^{-3} \text{Transient Term}=cx^{-3}$

$\y=\frac{1}{7}x^4-\frac{1}{4}x+cx^{-3} \text{Transient Term}=cx^{-3}$

$\y=\frac{1}{7}x^3-\frac{1}{4}x+cx^{-3} \text{Transient Term}=cx^{-3}$

$\y=\frac{1}{7}x^4-\frac{1}{4}x^3+cx^{-3} \text{Transient Term}=cx^{-3}$

$\y=\frac{1}{7}x^4-\frac{1}{4}x+cx^{-3} \text{Transient Term}=cx^{3}$