CALCULUS 2 • APPLICATIONS OF INTEGRATION

Cross Sections: Squares & Rectangles — Volumes with Cross Sections: Squares and Rectangles

Compute volumes of solids whose cross-sectional slices are squares or rectangles using definite integration.

Historical Context & Motivation

The problem of computing volumes of irregular solids has occupied mathematicians for over two millennia. Ancient Greek geometers, most notably Archimedes of Syracuse, pioneered the idea of decomposing a solid into thin slices to determine its volume — a technique he called the method of exhaustion. This insight, which predates formal calculus by nearly two thousand years, anticipated the modern strategy of slicing a solid perpendicular to an axis and integrating the resulting cross-sectional areas. The transition from Archimedean exhaustion to Riemann integration represents one of the great continuities in mathematical thought, and the method of known cross sections is its direct descendant.

c. 250 BCE
Archimedes & Exhaustion
Archimedes computes volumes of spheres, paraboloids, and other solids by approximating them with stacks of thin disks — essentially summing cross-sectional areas.
1635
Cavalieri's Principle
Bonaventura Cavalieri formalizes the idea that two solids with identical cross-sectional areas at every height have the same volume, laying the groundwork for integration-based volume formulas.
1665–1676
Newton & Leibniz
The independent invention of calculus provides the definite integral, turning Cavalieri's geometric comparisons into a computational tool: V = ∫ A(x) dx.
1854
Riemann's Integral
Bernhard Riemann provides rigorous underpinnings for the definite integral, justifying the limit-of-sums approach used in cross-section volume calculations.

The central question this lesson addresses is: given a region in the plane and a rule that assigns a square or rectangular cross section to each point along an axis, how do we compute the volume of the resulting three-dimensional solid? Unlike solids of revolution — where the cross sections are always circles — the known-cross-section method handles any geometry that can be expressed as an integrable area function A(x). Squares and rectangles are the most natural starting point because their area formulas are algebraically simple, making them ideal for developing the technique before generalizing to semicircles, triangles, or other shapes.

Core Principles & Definitions

The method of known cross sections rests on a surprisingly compact set of ideas. At its heart, the strategy mirrors what you already know from computing areas: approximate, sum, and take a limit. The only new ingredient is that each infinitesimal strip of width dx now carries an area A(x) instead of a height f(x), so the Riemann sum accumulates volume elements A(x) dx rather than area elements f(x) dx.

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Base Region

A region R in the xy-plane, typically bounded by two curves y = f(x) and y = g(x) on an interval [a, b]. The base region determines the side length of each cross section.
2

Cross-Sectional Shape

The prescribed geometric shape (square, rectangle, semicircle, etc.) erected perpendicular to the slicing axis at each position x. This lesson focuses on square and rectangular cross sections.
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Side Length Function s(x)

The distance between the bounding curves at position x: s(x) = f(x) − g(x). For square cross sections, this is the side of the square; for rectangles, it is one dimension, with the other specified by the problem.
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Area Function A(x)

For squares: A(x) = [s(x)]². For rectangles with height h(x): A(x) = s(x) × h(x). This function is the integrand in the volume integral.
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Volume by Integration

V = ∫ from a to b of A(x) dx. The definite integral sums infinitely many infinitesimally thin slabs, each of volume A(x) dx, to produce the exact volume of the solid.
KEY TAKEAWAY
Think of the solid as a loaf of bread. Each slice is a square or rectangle whose dimensions you can read off from the base region. To find the total volume, you simply sum the volumes of all the infinitesimally thin slices — that sum is the definite integral ∫ A(x) dx. The process is identical to finding area under a curve, except the 'height' at each x is now an area rather than a length.

Visual Explanation

The following diagram illustrates the construction of a solid whose base is the region between y = √x and y = 0 on [0, 4], with square cross sections perpendicular to the x-axis. At each position x, the side of the square equals s(x) = √x − 0 = √x, so the cross-sectional area is A(x) = (√x)² = x. Several representative slices are shown to convey how the solid grows in cross-sectional size as x increases.

Each vertical slice at position x has side length s(x) = √x. The square cross section is erected perpendicular to the x-axis, with one edge sitting on the base curve. As x increases from 0 to 4, the squares grow larger, producing a solid that flares outward.

Notice that each square slice is determined entirely by the value of s(x) at that position. The cross-sectional area function A(x) = [s(x)]² translates the one-dimensional information encoded in the base region into the two-dimensional area of each slice. The integral then aggregates these areas across the full interval, producing a three-dimensional volume. This is Cavalieri's principle in action: the solid is completely characterized by its family of parallel cross sections.

Mathematical Framework

We now formalize the procedure. Suppose a solid has a base region R in the xy-plane between the curves y = f(x) (upper) and y = g(x) (lower) over the interval [a, b]. At each x, a cross section perpendicular to the x-axis is erected with a prescribed shape. The side length of each cross section is the vertical distance between the curves: s(x) = f(x) − g(x).

SIDE LENGTH
s(x) = f(x) − g(x)
f(x) is the upper boundary, g(x) is the lower boundary. This expression gives the base dimension of each cross section at position x.

Square Cross Sections

When every cross section is a square with side length s(x), the area function is simply the square of the side length.

VOLUME — SQUARE CROSS SECTIONS
V = ∫ₐᵇ [s(x)]² dx = ∫ₐᵇ [f(x) − g(x)]² dx
A(x) = [s(x)]² because the area of a square with side s is s². The integral sums the volumes of infinitesimal slabs of thickness dx.

Rectangular Cross Sections

For rectangular cross sections, the problem statement must specify both dimensions. Typically, one dimension equals s(x) and the other is given as a fixed proportion or a separate function h(x). Common variations include rectangles whose height is twice their base, rectangles with a constant height, or rectangles whose height is some function of x.

VOLUME — RECTANGULAR CROSS SECTIONS
V = ∫ₐᵇ s(x) × h(x) dx
Here s(x) = f(x) − g(x) is the base of the rectangle (the chord across the region), and h(x) is the height. If h(x) = k × s(x) for some constant k, then V = k ∫ₐᵇ [s(x)]² dx.
🔄 Slicing Along the y-Axis
If the cross sections are perpendicular to the y-axis instead of the x-axis, reverse the roles: express the side length as s(y) = right(y) − left(y) and integrate with respect to y: V = ∫ A(y) dy. The logic is identical; only the variable of integration changes.

Detailed Breakdown: Squares vs. Rectangles

The diagram below contrasts two solids built on the same base region — the area between y = 1 − x² and y = 0 on [−1, 1] — but with different cross-sectional shapes. On the left, the cross sections are squares; on the right, they are rectangles with height equal to three times the base. Both solids share the same footprint, but the rectangular version is taller and has a correspondingly larger volume.

Left: square cross sections on the parabolic base y = 1 − x², giving V = 16/15. Right: rectangular cross sections with h = 3s on the same base, tripling the volume to V = 16/5. Both solids are symmetric about x = 0.
Summary of area and volume formulas for square and rectangular cross sections
Cross Section TypeArea Formula A(x)Volume Integral
Square[f(x) − g(x)]²∫ₐᵇ [f(x) − g(x)]² dx
Rectangle (h = k × s)k × [f(x) − g(x)]²k ∫ₐᵇ [f(x) − g(x)]² dx
Rectangle (h = h(x))[f(x) − g(x)] × h(x)∫ₐᵇ [f(x) − g(x)] × h(x) dx

Worked Example: Square Cross Sections

Find the volume of the solid whose base is the region enclosed by y = sin(x) and y = 0 on [0, π], with cross sections perpendicular to the x-axis that are squares.

Volume with Square Cross Sections on a Sinusoidal Base
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Step 1 — Identify the Base Region and LimitsThe base region is bounded above by f(x) = sin(x) and below by g(x) = 0 on the interval [0, π]. These curves intersect at x = 0 and x = π, so the limits of integration are a = 0 and b = π.
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Step 2 — Determine the Side Length FunctionAt each x ∈ [0, π], the side of the square cross section equals the vertical distance between the curves: s(x) = sin(x) − 0 = sin(x).
s(x) = sin(x)
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Step 3 — Write the Area FunctionSince each cross section is a square, A(x) = [s(x)]² = sin²(x).
A(x) = sin²(x)
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Step 4 — Set Up the Volume IntegralV = ∫₀π sin²(x) dx. To evaluate this, apply the power-reduction identity: sin²(x) = (1 − cos(2x))/2.
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Step 5 — Evaluate the IntegralV = ∫₀π (1 − cos(2x))/2 dx = (1/2) ∫₀π [1 − cos(2x)] dx = (1/2) [x − sin(2x)/2] evaluated from 0 to π. At x = π: π − sin(2π)/2 = π − 0 = π. At x = 0: 0 − sin(0)/2 = 0. Therefore V = (1/2)(π − 0) = π/2.
V = π/2

Worked Example: Rectangular Cross Sections

Now modify the problem: the base is the same (y = sin(x) on [0, π]), but the cross sections are rectangles whose height is twice the base.

Volume with Rectangular Cross Sections (h = 2s)
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Step 1 — Side Length & HeightAs before, s(x) = sin(x). The height of each rectangle is h(x) = 2 × sin(x).
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Step 2 — Area FunctionA(x) = s(x) × h(x) = sin(x) × 2 sin(x) = 2 sin²(x).
A(x) = 2 sin²(x)
3
Step 3 — Volume IntegralV = ∫₀π 2 sin²(x) dx = 2 × (π/2) = π. We reuse the result from the square case, since the integrand is simply scaled by a factor of 2.
V = π

Strengths, Limitations & Comparisons

The cross-section method is one of several techniques for computing volumes using integration. Understanding its relative strengths and limitations helps you choose the right tool for each problem.

Comparison of the known cross-section method with the disk/washer method
CriterionKnown Cross SectionsDisk/Washer Method
Cross-section shapeAny prescribed shape: square, rectangle, triangle, semicircle, etc.Always circles (disks) or annuli (washers)
Axis of revolution required?No — the solid need not be a surface of revolutionYes — the solid must be generated by rotating a region about an axis
Typical difficultyAlgebraic: squaring or multiplying the side-length functionAlgebraic: squaring radius functions, sometimes subtracting inner from outer
When to chooseWhen the problem specifies a non-circular cross-sectional geometryWhen the solid is generated by revolving a region around an axis
Common pitfallConfusing the base dimension with the cross-sectional area — remember to square for squares, multiply for rectanglesForgetting to subtract the inner radius in the washer variant
KEY TAKEAWAY
The disk and washer methods are actually special cases of the known cross-section technique — the 'known cross section' just happens to be a circle or an annulus. Understanding the general method first gives you a unifying framework: once you can write down A(x), computing V = ∫ A(x) dx is always the same integral regardless of whether the cross section is a square, a rectangle, or a circle.

Connection to Advanced Theory

The cross-section slicing strategy extends naturally to several more advanced settings in calculus and beyond. At the most immediate level, you can generalize from square and rectangular cross sections to semicircles, equilateral triangles, and isosceles right triangles — the integral structure remains identical, with only the area formula changing. Beyond single-variable calculus, the slicing idea reappears in multivariable calculus as iterated integration and Fubini's theorem, where a triple integral is computed by integrating an area function over a single variable.

Connections between cross-section volumes and advanced topics
Concept in This LessonAdvanced Extension
V = ∫ A(x) dx with square or rectangular A(x)V = ∫ A(x) dx with semicircular, triangular, or arbitrary A(x)
Slicing a 3D solid into 2D cross sectionsFubini's theorem: reducing a triple integral to iterated single integrals
Side length s(x) from two bounding curvesCross-sectional area from polar boundaries: A(θ) for solids of revolution in polar coordinates
Riemann sum approximation → definite integralMonte Carlo integration for volumes of solids with no closed-form A(x)

In engineering and physics, the slicing approach is fundamental to computing moments of inertia, centers of mass, and fluid pressures on submerged plates. In each case, the strategy is the same: identify the relevant quantity at each cross section (area, mass density × area, pressure × width), write it as a function of the integration variable, and integrate. Mastering the square and rectangular cases gives you the template for all of these applications.

Practice Problems

PROBLEM 1CONCEPTUAL
Explain in your own words why V = ∫ₐᵇ A(x) dx gives the volume of a solid, where A(x) is the cross-sectional area at position x. How does this relate to the Riemann sum interpretation of the definite integral?
PROBLEM 2BASIC CALCULATION
The base of a solid is the region bounded by y = x and y = 0 on [0, 3]. Cross sections perpendicular to the x-axis are squares. Find the volume.
PROBLEM 3INTERMEDIATE
A solid has its base in the region enclosed by y = x² and y = √x (for 0 ≤ x ≤ 1). Cross sections perpendicular to the x-axis are rectangles whose height equals five times the base. Find the volume.
PROBLEM 4APPLIED
An engineer designs a dam whose base profile follows the curve y = 4 − x² (with y in meters) over −2 ≤ x ≤ 2. The dam's thickness at height x is a square cross section perpendicular to the x-axis. Compute the total volume of concrete needed (in cubic meters).
PROBLEM 5CRITICAL THINKING
Let R be the region in the first quadrant bounded by y = e⁻ˣ, y = 0, x = 0, and x = ln 3. Solid A has square cross sections perpendicular to the x-axis, and Solid B has square cross sections perpendicular to the y-axis on the same base. Set up both integrals and determine which solid has the larger volume. What geometric reasoning explains the difference?

Lesson Summary

The method of known cross sections computes the volume of a solid by integrating its cross-sectional area function: V = ∫ₐᵇ A(x) dx. For a solid whose base lies between y = f(x) and y = g(x), the side length is s(x) = f(x) − g(x). When cross sections are squares, the area is A(x) = [s(x)]²; when they are rectangles with height h(x), the area is A(x) = s(x) × h(x).

The procedure always follows the same sequence: (1) identify the base region and limits of integration, (2) determine the side length function from the bounding curves, (3) write the area function A(x) according to the specified cross-sectional shape, and (4) evaluate the definite integral. This framework generalizes readily to semicircular, triangular, and other cross-sectional geometries, and it is the conceptual ancestor of iterated integration in multivariable calculus.

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