CALCULUS 1 • APPLICATIONS OF DERIVATIVES: ANALYTICAL

Increasing/Decreasing Intervals — Determining Intervals on Which a Function is Increasing or Decreasing

Use the first derivative to pinpoint exactly where a function rises, falls, or levels off.

Historical Context & Motivation

Long before calculus existed, mathematicians and scientists cared deeply about how things change. Ancient Greek astronomers tracked the rising and setting of celestial bodies, noting periods when a planet appeared to speed up or slow down across the sky. Describing these changes precisely, however, required tools that wouldn't be invented for nearly two thousand years.

In the seventeenth century, Isaac Newton and Gottfried Wilhelm Leibniz independently developed calculus, giving mathematicians a rigorous way to study rates of change. The derivative became the key tool for answering a fundamental question: on which intervals does a function go up, and on which does it go down? This question is not just academic — engineers use it to optimize designs, economists use it to model profit, and physicists use it to analyze motion.

~300 BCE
Euclid's Elements
Greek mathematicians studied geometric properties of curves, but lacked algebraic tools to describe where a curve rises or falls.
1665–1676
Newton & Leibniz Develop Calculus
Both independently created the concept of a derivative, enabling precise analysis of how functions change at every point.
1691
Rolle's Theorem Published
Michel Rolle proved that between two roots of a function, the derivative must be zero at least once — a foundation for analyzing increasing and decreasing behavior.
1823
Cauchy Formalizes the First Derivative Test
Augustin-Louis Cauchy rigorously connected the sign of the first derivative to whether a function is increasing or decreasing, establishing the method students use today.

The central question this lesson addresses is straightforward: given a function f(x), how do you determine exactly which intervals correspond to the function climbing upward and which correspond to it falling downward? The answer lies in analyzing the sign of the first derivative, f′(x).

Core Principles & Definitions

Before diving into calculations, you need to understand the vocabulary and the logic that connects derivatives to the behavior of a function. The ideas are intuitive once you see how the slope of a tangent line tells you the direction a curve is headed.

1

Increasing Function

A function f is increasing on an interval if, for any two numbers a < b in that interval, f(a) < f(b). In other words, as you move right, the outputs go up.
2

Decreasing Function

A function f is decreasing on an interval if, for any two numbers a < b in that interval, f(a) > f(b). As you move right, the outputs go down.
3

Critical Numbers

A critical number of f is a value c in the domain of f where f′(c) = 0 or f′(c) does not exist. These are the only places where the function can switch between increasing and decreasing.
4

Sign of the Derivative

If f′(x) > 0 on an interval, f is increasing there. If f′(x) < 0 on an interval, f is decreasing there. The derivative's sign is the direct indicator of the function's direction.
5

The First Derivative Test Process

Find f′(x), locate critical numbers, set up a sign chart by testing f′ in each sub-interval, and read off where f is increasing or decreasing.
KEY TAKEAWAY
Think of driving on a hilly road. If you're pressing the gas and gaining speed (positive acceleration), you're going uphill — that's like f′(x) > 0. If you're coasting and losing speed, you're going downhill — that's like f′(x) < 0. The hilltops and valley bottoms are where the slope is momentarily zero — those are the critical numbers. By checking what happens between each hilltop and valley, you map out the entire ride.

Visual Explanation

The diagram below shows a polynomial function along with annotations that highlight its increasing and decreasing intervals. Notice how the tangent lines tilt upward (positive slope) in the green-shaded regions and tilt downward (negative slope) in the red-shaded regions. At the critical points, the tangent line is perfectly horizontal.

The violet curve represents f(x). Green-shaded regions show intervals where f′(x) > 0 (increasing), and red-shaded regions show where f′(x) < 0 (decreasing). The amber dots mark critical points where the slope is zero.

Notice the pattern: every time the function switches from increasing to decreasing (or vice versa), it passes through a critical point. At the local maximum, the curve stops rising and starts falling. At the local minimum, the curve stops falling and starts rising. Between critical points, the derivative maintains a constant sign — either entirely positive or entirely negative.

Mathematical Framework

The process for finding increasing and decreasing intervals follows a systematic series of steps. Each step builds on the previous one, and the entire method rests on a single powerful theorem.

INCREASING / DECREASING TEST
If f′(x) > 0 for all x in (a, b), then f is increasing on (a, b). If f′(x) < 0 for all x in (a, b), then f is decreasing on (a, b).
Here, (a, b) is an open interval. The function f must be continuous on [a, b] and differentiable on (a, b).

Step-by-Step Procedure

  1. Step 1: Find f′(x) by differentiating f(x).
  2. Step 2: Set f′(x) = 0 and solve. Also identify any x-values where f′(x) does not exist but f(x) does. These are your critical numbers.
  3. Step 3: Plot the critical numbers on a number line, dividing it into sub-intervals.
  4. Step 4: Pick a test value in each sub-interval and evaluate f′ at that test value. Record whether f′ is positive or negative.
  5. Step 5: Conclude: f is increasing where f′ > 0 and decreasing where f′ < 0.
CRITICAL NUMBER CONDITION
f′(c) = 0 or f′(c) does not exist (c in domain of f)
Only values in the domain of f qualify as critical numbers. If c is not in the domain of f, it is not a critical number — it may be a vertical asymptote or a point of discontinuity.
💡 Why Test Values Work
Between consecutive critical numbers, f′(x) cannot change sign (it would have to pass through zero or be undefined, creating another critical number). So a single test point reveals the sign of f′ across the entire sub-interval. This is why the sign chart method is so efficient.

Sign Charts & Classification

A sign chart (also called a sign diagram or number-line test) is the organizational tool that ties everything together. It provides a clear, visual way to track the sign of f′(x) across all sub-intervals. The diagram below demonstrates a sign chart for the function f(x) = x³ − 3x, whose derivative is f′(x) = 3x² − 3 = 3(x − 1)(x + 1).

This sign chart shows f′(x) = 3(x − 1)(x + 1) for f(x) = x³ − 3x. The amber tick marks at x = −1 and x = 1 are the critical numbers. Test values in each sub-interval confirm the sign of f′, which determines the behavior of f.
Sign analysis for f′(x) = 3x² − 3
IntervalTest Valuef′(test)Signf Behavior
(−∞, −1)x = −23(4 − 1) = 9+Increasing
(−1, 1)x = 03(0 − 1) = −3Decreasing
(1, ∞)x = 23(4 − 1) = 9+Increasing

The table and diagram confirm that f(x) = x³ − 3x is increasing on (−∞, −1) ∪ (1, ∞) and decreasing on (−1, 1). Notice that the critical numbers themselves are not included in the intervals because those are the transition points — at x = −1 and x = 1, the function is neither increasing nor decreasing; it's momentarily flat.

Worked Example

Let's work through a complete example with a function that has a slightly more complex derivative. We'll find the intervals on which f(x) = 2x³ + 3x² − 12x + 1 is increasing and decreasing.

Find the Increasing and Decreasing Intervals of f(x) = 2x³ + 3x² − 12x + 1
1
Step 1 — Differentiate f(x)Apply the power rule to each term: f′(x) = 6x² + 6x − 12. We can factor out a 6 to simplify: f′(x) = 6(x² + x − 2).
f′(x) = 6(x² + x − 2)
2
Step 2 — Factor and Find Critical NumbersFactor the quadratic: x² + x − 2 = (x + 2)(x − 1). Set f′(x) = 0: 6(x + 2)(x − 1) = 0. Since 6 ≠ 0, we get x + 2 = 0 or x − 1 = 0.
Critical numbers: x = −2 and x = 1
3
Step 3 — Create Sub-IntervalsThe critical numbers x = −2 and x = 1 divide the number line into three intervals: (−∞, −2), (−2, 1), and (1, ∞).
Sub-intervals: (−∞, −2), (−2, 1), (1, ∞)
4
Step 4 — Test Each IntervalChoose test values and plug them into f′(x) = 6(x + 2)(x − 1). For x = −3: f′(−3) = 6(−3 + 2)(−3 − 1) = 6(−1)(−4) = 24 > 0. For x = 0: f′(0) = 6(0 + 2)(0 − 1) = 6(2)(−1) = −12 < 0. For x = 2: f′(2) = 6(2 + 2)(2 − 1) = 6(4)(1) = 24 > 0.
f′(−3) = +24, f′(0) = −12, f′(2) = +24
5
Step 5 — State the ConclusionSince f′(x) > 0 on (−∞, −2) and (1, ∞), the function is increasing on those intervals. Since f′(x) < 0 on (−2, 1), the function is decreasing on that interval.
Increasing on (−∞, −2) ∪ (1, ∞). Decreasing on (−2, 1).
Bonus Insight
From this analysis, you can also identify local extrema. Since f changes from increasing to decreasing at x = −2, there is a local maximum at x = −2. Since f changes from decreasing to increasing at x = 1, there is a local minimum at x = 1. This is the essence of the First Derivative Test.

Common Pitfalls & Best Practices

Even students who understand the theory can make careless mistakes in practice. The table below compares common errors with the correct approach, so you can avoid these traps on homework and exams.

Common mistakes when finding increasing/decreasing intervals
Common MistakeWhy It's WrongCorrect Approach
Forgetting to check where f′ is undefinedPoints where f′ doesn't exist (cusps, vertical tangents) can also be critical numbers that separate increasing/decreasing intervals.Always check both f′(c) = 0 and where f′(c) DNE.
Including critical numbers in the interval notationAt a critical number, the function is neither increasing nor decreasing — it's transitioning. Use open intervals.Write (a, b), not [a, b].
Confusing f(x) values with f′(x) valuesThe sign of f(x) tells you if outputs are positive or negative — not whether the function is rising or falling.Always test with f′(x), never with f(x).
Skipping the factoring stepWithout factoring, you may miss critical numbers or make sign-analysis errors.Factor f′(x) completely before setting it equal to zero.
Assuming f′(x) > 0 means f(x) > 0The derivative's sign indicates direction (up/down), not position (above/below the x-axis). A function can be increasing while having negative y-values.Separate the concepts: sign of f′ = direction; sign of f = position.
KEY TAKEAWAY
Think of a sign chart as a weather forecast for f(x). The critical numbers are the times when the weather changes. Between those times, conditions stay consistent. Just like you'd check the forecast for each block of the day, you test one point in each sub-interval to know the "weather" (positive or negative slope) for the entire stretch. The test point is your thermometer — one reading per interval is all you need.

Connection to Advanced Topics

Understanding increasing and decreasing intervals is not the end of the story — it's the launching pad for several more advanced calculus ideas. The table below shows how this concept connects to what comes next in your calculus journey.

How increasing/decreasing analysis connects to advanced calculus topics
This Lesson (First Derivative Analysis)Advanced Extension
f′(x) > 0 → f is increasingf″(x) > 0 → f is concave up. The second derivative extends the analysis to the shape of the curve (concavity), not just its direction.
Critical numbers where f′(c) = 0The Second Derivative Test uses f″(c) to classify critical points as local maxima or minima without a full sign chart.
Finding local maxima and minimaOptimization problems ask you to find the absolute (global) maximum or minimum on a closed interval, combining increasing/decreasing analysis with endpoint evaluation.
Sign chart for f′(x)Curve sketching combines the sign charts for both f′ and f″ to produce a complete picture of a function's behavior without a graphing calculator.

As you continue in calculus, you'll see that the skills you build here — taking derivatives, finding critical numbers, and constructing sign charts — are reused in almost every major topic. Mastering this process now will make concavity, optimization, and curve sketching feel like natural extensions of what you already know, rather than entirely new concepts.

Practice Problems

Work through these five problems in order. They start with conceptual understanding and progress toward more challenging applications. Try each one on your own before reading the answer.

PROBLEM 1CONCEPTUAL
If f′(x) = 0 at x = 3 and f′(x) > 0 for all other x-values, is f increasing, decreasing, or neither on the interval (0, 5)? Explain your reasoning.
PROBLEM 2BASIC CALCULATION
Find the intervals on which f(x) = x² − 4x + 7 is increasing and decreasing.
PROBLEM 3INTERMEDIATE
Determine the increasing and decreasing intervals for g(x) = x⁴ − 4x³. Include a sign chart of g′(x) in your analysis.
PROBLEM 4APPLIED
A company's revenue (in thousands of dollars) is modeled by R(t) = −t³ + 12t² − 36t + 50, where t is the number of years since the company was founded (t ≥ 0). During which years is the revenue increasing?
PROBLEM 5CRITICAL THINKING
Consider a continuous function h(x) defined on all real numbers whose derivative is h′(x) = (x − 1)²(x + 3). Find the intervals where h is increasing and decreasing, and explain why the critical number at x = 1 does not produce a local extremum.

Lesson Summary

To determine where a function is increasing or decreasing, you follow a clear five-step process. First, compute the first derivative f′(x). Next, find all critical numbers — values of x where f′(x) = 0 or f′(x) does not exist. These critical numbers divide the number line into sub-intervals. Then, pick a test value in each sub-interval and plug it into f′(x) to determine the sign. If f′ is positive, f is increasing; if f′ is negative, f is decreasing.

This technique — organized using a sign chart — is the foundation for the First Derivative Test, which classifies critical points as local maxima or minima based on whether f′ changes from positive to negative or vice versa. Mastering this skill prepares you for concavity analysis, optimization, and complete curve sketching — the next major applications of derivatives in your calculus course.

Varsity Tutors • Calculus 1 • Increasing/Decreasing Intervals