CALCULUS 1 • LIMITS & CONTINUITY

Continuity over an Interval — Confirming Continuity over an Interval

Learn how to verify that a function has no breaks, jumps, or holes across an entire interval.

Historical Context & Motivation

For centuries, mathematicians intuitively understood that certain curves could be drawn without lifting a pen from paper. However, formalizing what it means for a function to be continuous — not just at a single point, but across an entire interval — took remarkable intellectual effort. The need to rigorously define continuity arose from paradoxes and strange functions that defied common sense, pushing mathematicians to develop the precise language of limits and epsilon-delta definitions we use today.

1748
Euler's Intuitive Continuity
Leonhard Euler described continuous functions as those given by a single "analytic expression." His intuition was sound but lacked the precision needed to handle trickier cases.
1817
Bolzano's Rigorous Definition
Bernard Bolzano provided one of the first rigorous definitions of continuity at a point and proved the Intermediate Value Theorem, linking point-continuity to interval behavior.
1821
Cauchy Formalizes Limits
Augustin-Louis Cauchy published his foundational textbook defining continuity using limits. His framework became the standard approach still taught in calculus courses.
1861
Weierstrass and Epsilon-Delta
Karl Weierstrass refined Cauchy's ideas into the epsilon-delta definition, giving mathematicians an airtight way to confirm continuity at a point and, by extension, over an interval.

The central question these mathematicians worked to answer is the one we tackle in this lesson: How do you confirm that a function is continuous not just at one point, but over an entire interval? Understanding this process is essential because many of calculus's most powerful theorems — like the Intermediate Value Theorem and the Extreme Value Theorem — require continuity over an interval as a prerequisite.

Core Principles & Definitions

Before we can confirm continuity over an interval, we need to recall what continuity at a single point means. A function f is continuous at a point c if three conditions hold: f(c) is defined, the limit of f(x) as x approaches c exists, and that limit equals f(c). When we extend this idea to an entire interval, we check these conditions at every point in the interval — but the endpoints require special treatment.

1

Continuity at an Interior Point

At any point c strictly inside the interval (a, b), we require the full two-sided limit: lim(x→c) f(x) = f(c). The function must approach the same value from both the left and the right.
2

Right-Continuity at the Left Endpoint

At x = a (the left endpoint of a closed interval), we only check the right-hand limit: lim(x→a⁺) f(x) = f(a). We can't approach from the left because the interval doesn't extend that way.
3

Left-Continuity at the Right Endpoint

At x = b (the right endpoint of a closed interval), we only check the left-hand limit: lim(x→b⁻) f(x) = f(b). We can't approach from the right because the interval stops at b.
4

Open vs. Closed Intervals

On an open interval (a, b), every point is an interior point, so we use two-sided limits everywhere. On a closed interval [a, b], we add the one-sided limit checks at each endpoint.
KEY TAKEAWAY
Think of continuity over an interval like driving on a highway. If the road is smooth at every single mile marker between your entrance ramp (left endpoint) and your exit ramp (right endpoint), then the entire stretch is smooth. At the entrance, you only care about the road ahead of you. At the exit, you only care about the road behind you. That's exactly how one-sided limits work at the endpoints of a closed interval.

Visual Explanation

Continuous vs. Discontinuous on an Interval

The left panel shows a function that is continuous on the entire closed interval [a, b] — no breaks, jumps, or holes anywhere. The middle panel shows a jump discontinuity at an interior point c where the left-hand and right-hand limits are different. The right panel shows a removable discontinuity (a hole) where the limit exists but the function value at c doesn't match the limit.

Notice the filled and open circles in the diagrams. A filled circle means the function is defined at that point (the point is included on the graph). An open circle means the graph approaches that location, but the function either isn't defined there or takes a different value. When you're confirming continuity over an interval, you scan the entire graph looking for any open circles, jumps, or vertical asymptotes — any of these breaks would make the function discontinuous on that interval.

Mathematical Framework

Let's now state the formal definitions. We begin with continuity at a single point and build up to continuity over both open and closed intervals. These definitions give you a checklist you can follow every time you need to confirm continuity.

CONTINUITY AT A POINT
f is continuous at c ⟺ (1) f(c) is defined, (2) lim(x→c) f(x) exists, (3) lim(x→c) f(x) = f(c)
All three conditions must hold simultaneously. If any one fails, f is discontinuous at c.
CONTINUITY ON AN OPEN INTERVAL
f is continuous on (a, b) ⟺ f is continuous at every point c where a < c < b
Since no endpoints are included, only two-sided limits are needed. Every point is an interior point.
CONTINUITY ON A CLOSED INTERVAL
f is continuous on [a, b] ⟺ (1) f is continuous on (a, b), (2) lim(x→a⁺) f(x) = f(a), (3) lim(x→b⁻) f(x) = f(b)
Condition (2) is right-continuity at the left endpoint. Condition (3) is left-continuity at the right endpoint. These one-sided checks ensure the curve "connects" properly at the boundary.
💡 Important Shortcut
Many common functions — polynomials, sin(x), cos(x), eˣ — are continuous on their entire domain, which is all real numbers. If the interval you're checking lies entirely within the domain of one of these functions, you can immediately confirm continuity without checking individual points. Rational functions, square roots, and logarithms require more care because their domains are restricted.

Step-by-Step Confirmation Checklist

When you're given a function and asked to confirm continuity over an interval, follow this systematic process. The diagram below organizes the decision-making into a clear flowchart so you never miss a step.

This flowchart outlines the four main steps for confirming continuity on a closed interval [a, b]. Start at the top by checking the domain. If at any step a condition fails, the function is not continuous on the given interval. If all steps pass, you've confirmed continuity.
  1. Step 1 — Domain Check: Make sure every x-value in [a, b] is in the domain of f. Watch for division by zero, negative values under even roots, and non-positive arguments of logarithms.
  2. Step 2 — Function Type: Polynomials are continuous everywhere. Rational functions are continuous wherever the denominator is nonzero. The sum, difference, product, quotient, and composition of continuous functions are continuous on their domains.
  3. Step 3 — Piecewise Boundaries: If the function is defined by different formulas on different parts of the interval, evaluate the left- and right-hand limits at each transition point to verify they're equal and match the function value.
  4. Step 4 — Endpoint Limits: At x = a, compute the right-hand limit. At x = b, compute the left-hand limit. Both must equal the function's value at that endpoint.

Worked Example

Let's apply our checklist to a piecewise function. Determine whether the following function is continuous on the interval [−1, 4]:

PIECEWISE FUNCTION
f(x) = { x² + 1, if x < 2 ; 2x + 1, if x ≥ 2 }
The function has two pieces that meet at the transition point x = 2.
Confirm Continuity of f(x) on [−1, 4]
1
Step 1 — Domain CheckThe first piece is x² + 1, a polynomial, which is defined for all real numbers. The second piece is 2x + 1, also a polynomial, defined for all real numbers. Therefore f(x) is defined at every point in [−1, 4].
Domain includes all of [−1, 4]. ✓
2
Step 2 — Function Type on Each Sub-IntervalOn [−1, 2), f(x) = x² + 1 is a polynomial, so it's continuous on that entire sub-interval. On [2, 4], f(x) = 2x + 1 is a polynomial, so it's continuous there too. The only potential problem is at x = 2 where the pieces meet.
Each piece is individually continuous. ✓
3
Step 3 — Check the Transition Point x = 2We compute the left-hand limit using the first piece: lim(x→2⁻) (x² + 1) = (2)² + 1 = 5. We compute the right-hand limit using the second piece: lim(x→2⁺) (2x + 1) = 2(2) + 1 = 5. Both one-sided limits equal 5, so the two-sided limit exists and equals 5. Now check the function value: f(2) = 2(2) + 1 = 5 (using the x ≥ 2 piece). Since lim(x→2) f(x) = 5 = f(2), the function is continuous at x = 2.
lim(x→2⁻) f(x) = lim(x→2⁺) f(x) = f(2) = 5. ✓
4
Step 4 — Check the EndpointsLeft endpoint, x = −1: lim(x→−1⁺) f(x) = lim(x→−1⁺) (x² + 1) = (−1)² + 1 = 2. Also, f(−1) = (−1)² + 1 = 2. So lim(x→−1⁺) f(x) = f(−1). Right endpoint, x = 4: lim(x→4⁻) f(x) = lim(x→4⁻) (2x + 1) = 2(4) + 1 = 9. Also, f(4) = 2(4) + 1 = 9. So lim(x→4⁻) f(x) = f(4).
Both endpoint conditions satisfied. ✓
5
Step 5 — ConclusionEvery condition has been verified: the function is defined everywhere on [−1, 4], each polynomial piece is individually continuous, the transition at x = 2 is seamless, and the one-sided limits at the endpoints match the function values.
f(x) is continuous on [−1, 4].

Common Pitfalls & Tips

Even after learning the checklist, students often make predictable mistakes. The table below lists the most common pitfalls alongside tips for avoiding them.

Common mistakes when confirming continuity over an interval
Common PitfallWhy It's WrongHow to Avoid It
Forgetting to check endpoints separatelyEndpoints require one-sided limits, not two-sided. Checking only the interior doesn't cover the boundary.Always compute lim(x→a⁺) and lim(x→b⁻) explicitly and compare them to f(a) and f(b).
Assuming piecewise functions are automatically discontinuousA piecewise function can be perfectly continuous if the pieces connect smoothly at every transition.Check left-hand and right-hand limits at every boundary between pieces.
Ignoring the domain (e.g., √x on an interval including negatives)A function cannot be continuous at a point where it's not even defined.Step 1 of the checklist: verify the entire interval is within the domain before doing anything else.
Confusing "limit exists" with "function is continuous"The limit can exist at a point even when f(c) differs from the limit value (removable discontinuity).Always check all three conditions: defined, limit exists, limit equals value.
KEY TAKEAWAY
Think of confirming continuity like inspecting a chain link by link. A chain is only as strong as its weakest link, and a function is only as continuous as its worst point. If even one point in the interval fails any of the three continuity conditions, the whole chain breaks — the function is not continuous on that interval. The endpoints are like the clasps of a necklace: they need special attention because they connect differently than the inner links.

Connection to Advanced Theorems

Once you can confirm continuity over an interval, you unlock several of the most powerful results in calculus. These theorems all begin with the phrase "If f is continuous on [a, b], then…" — and now you know exactly what that hypothesis requires.

Major theorems that require continuity on a closed interval as a hypothesis
TheoremStatement (Simplified)Why Continuity on [a, b] Matters
Intermediate Value Theorem (IVT)If f is continuous on [a, b] and N is between f(a) and f(b), then there exists some c in (a, b) with f(c) = N.Without continuity, the function could jump over N. The guarantee of no breaks ensures f hits every intermediate value.
Extreme Value Theorem (EVT)If f is continuous on [a, b], then f attains both an absolute maximum and an absolute minimum on [a, b].A discontinuity or an open interval could allow the function to approach but never reach its extreme values.
Fundamental Theorem of CalculusIf f is continuous on [a, b], then ∫ₐᵇ f(x) dx exists and equals F(b) − F(a) where F' = f.Continuity guarantees that the definite integral is well-defined. Certain types of discontinuities can make integration problematic.

As you continue in calculus, you'll encounter more nuanced types of continuity — uniform continuity, Lipschitz continuity, and continuity of derivatives (smoothness). For now, mastering the basic definition over closed and open intervals gives you the foundation for everything ahead.

Practice Problems

PROBLEM 1CONCEPTUAL
A function f is continuous on the open interval (1, 5) but not on the closed interval [1, 5]. Give one possible reason why this could happen. (Hint: think about what extra condition the closed interval requires.)
PROBLEM 2BASIC CALCULATION
Determine whether f(x) = x³ − 2x + 4 is continuous on [−3, 3]. Justify your answer.
PROBLEM 3INTERMEDIATE
Consider the piecewise function g(x) = { 3x − 1, if x < 1 ; x² + k, if x ≥ 1 }. Find the value of k that makes g continuous on [0, 5].
PROBLEM 4APPLIED
A temperature sensor records the temperature T(t) at time t hours as: T(t) = { 20 + 5t, if 0 ≤ t ≤ 3 ; 35 − 2(t − 3)², if 3 < t ≤ 6 }. Is T(t) continuous on [0, 6]? Explain what your answer means physically about the temperature readings.
PROBLEM 5CRITICAL THINKING
Let h(x) = (x² − 9)/(x − 3) for x ≠ 3, and h(3) = 6. (a) Is h continuous at x = 3? (b) Is h continuous on [0, 5]? (c) Could you redefine h(3) to make h continuous on [0, 5]? If so, what value would you assign?

Lesson Summary

A function is continuous on an open interval (a, b) if it satisfies the three continuity conditions — defined, limit exists, limit equals value — at every interior point. For a closed interval [a, b], you additionally verify right-continuity at x = a (lim(x→a⁺) f(x) = f(a)) and left-continuity at x = b (lim(x→b⁻) f(x) = f(b)).

To confirm continuity over an interval, follow the systematic checklist: check the domain, identify known continuous function types (polynomials, trig, exponentials), verify piecewise transition points by matching one-sided limits and function values, and confirm endpoint conditions. Mastering this process is essential because major theorems like the Intermediate Value Theorem, the Extreme Value Theorem, and the Fundamental Theorem of Calculus all require continuity on a closed interval as their starting hypothesis.

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