Question 1
During the synthesis of an RNA transcript, the reaction involves a nucleophilic attack by the 3'-hydroxyl group of the growing chain on the α-phosphate of an incoming ribonucleoside triphosphate (rNTP). Which of the following is an essential cofactor for this reaction and is required to stabilize the transition state?
- A divalent metal ion, typically Mg²⁺, coordinated by the enzyme. (correct answer)
- A pyridoxal phosphate (PLP) cofactor to activate the 3'-hydroxyl group.
- A temporary covalent bond between the enzyme and the rNTP substrate.
- An ATP-dependent hydrolysis step to provide energy for bond formation.
Explanation: The correct answer is A. RNA polymerases are metalloenzymes that typically use two Mg²⁺ ions in their active site. One Mg²⁺ ion interacts with the 3'-hydroxyl group of the growing RNA chain, increasing its nucleophilicity. The other Mg²⁺ ion binds to the incoming rNTP and helps to neutralize the negative charges on the β- and γ-phosphates, stabilizing the pentacovalent transition state and facilitating the departure of the pyrophosphate leaving group. Choice D is incorrect; the energy for phosphodiester bond formation is provided by the cleavage of the high-energy phosphoanhydride bond within the rNTP substrate itself, releasing pyrophosphate (PPi). Choices B and C describe catalytic strategies used by other classes of enzymes, not polymerases.
Question 2
Steroid hormone receptors, such as the glucocorticoid receptor, are ligand-activated transcription factors. What is a key biochemical event that typically occurs immediately following the binding of a steroid hormone to its intracellular receptor?
- The receptor is ubiquitinated and targeted for proteasomal degradation to terminate the signal.
- The receptor undergoes a conformational change, dissociates from inhibitory proteins, and translocates to the nucleus. (correct answer)
- The receptor's intrinsic kinase activity is activated, leading to autophosphorylation and dimerization.
- The receptor binds to a G-protein, which then activates adenylate cyclase to produce a second messenger.
Explanation: The correct answer is B. In the absence of their hormone ligand, steroid receptors are typically held in an inactive state in the cytoplasm, bound to inhibitory heat-shock proteins (HSPs). Hormone binding induces a significant conformational change in the receptor's ligand-binding domain. This change causes the HSPs to dissociate, exposing a nuclear localization signal. The now-active receptor-hormone complex can then dimerize and translocate into the nucleus, where it binds to specific DNA sequences (hormone response elements) and modulates the transcription of target genes. Choice C describes receptor tyrosine kinases, a different class of receptors. Choice D describes G-protein coupled receptors. Choice A describes a mechanism for signal termination, not activation.
Question 3
A graduate student discovers a new bacterial transcriptional regulator protein that binds to a specific DNA sequence upstream of several metabolic genes. When this protein is purified and tested in vitro, it shows strong DNA binding activity at pH 7.0 but no detectable binding at pH 6.0. However, when the same protein is tested in the presence of its target metabolite, it binds DNA strongly at both pH 7.0 and pH 6.0. What is the most likely mechanism for this pH-dependent regulation?
- The metabolite binding exposes basic amino acid residues, allowing the protein to maintain DNA binding even when some residues become protonated at lower pH.
- The protein contains histidine residues in its DNA-binding domain that become protonated at pH 6.0, disrupting DNA contacts unless the metabolite stabilizes the protein-DNA complex. (correct answer)
- The metabolite acts as a pH buffer, preventing the local pH around the protein from dropping below 7.0 and maintaining optimal binding conditions.
- The protein undergoes acid-induced denaturation at pH 6.0, but metabolite binding provides stabilization that prevents this conformational change.
Explanation: The correct answer is B. The pH dependence with a transition between pH 6.0 and 7.0 strongly suggests involvement of histidine residues (pKa ~6.0). At pH 6.0, histidines become protonated, which would disrupt DNA binding if they're involved in making critical contacts. The metabolite binding apparently stabilizes the protein-DNA interaction enough to overcome this pH effect, possibly through allosteric stabilization of the complex. A is incorrect because exposing basic residues would worsen the pH problem. C is incorrect because metabolites don't typically act as pH buffers, and the effect is specifically on the protein. D is incorrect because the sharp pH dependence points to specific ionizable groups rather than general protein stability.