Biochemistry Quiz: Oxidation Of Fatty Acids And Regulation

What this quiz covers

This quiz focuses on Oxidation Of Fatty Acids And Regulation, giving you a quick way to practice the rules, question types, and explanations that matter most for Biochemistry.

How to use this quiz

Try each quiz question before looking at the correct answer. Use the explanations to review missed ideas, then come back to similar questions until the pattern feels familiar.

Question 1

1. trans-Δ²-Octenoyl-CoA (correct answer)
2. β-Hydroxyoctanoyl-CoA
3. Octanoyl-CoA
4. β-Ketooctanoyl-CoA

Explanation: When you encounter questions about metabolic pathway disruptions, focus on understanding where the block occurs and what substrate would accumulate immediately before that step. β-oxidation follows a specific four-step cycle: (1) acyl-CoA dehydrogenase creates a trans double bond, (2) enoyl-CoA hydratase adds water across the double bond, (3) β-hydroxyacyl-CoA dehydrogenase oxidizes the hydroxyl group, and (4) thiolase cleaves off acetyl-CoA. Since enoyl-CoA hydratase is missing in this yeast strain, the pathway stops after step 1. Starting with octanoyl-CoA from octanoic acid, the first enzyme (acyl-CoA dehydrogenase) will successfully convert it to trans-Δ²-octenoyl-CoA by introducing a double bond between carbons 2 and 3. However, without enoyl-CoA hydratase, this product cannot proceed to the next step, causing trans-Δ²-octenoyl-CoA to accumulate massively. This makes A correct. B is wrong because β-hydroxyoctanoyl-CoA is the product of step 2, which cannot occur without the missing enzyme. C is incorrect because octanoyl-CoA gets efficiently converted by the functional first enzyme, so it won't accumulate significantly. D is wrong because β-ketooctanoyl-CoA is produced in step 3, which is even further downstream from the enzymatic block. Remember this principle: in metabolic pathway knockouts, the substrate that accumulates is always the one that feeds directly into the missing enzyme. Identify the blocked step, then look for the immediate substrate of that reaction.

Question 2

1. Increased production of malonyl-CoA allosterically activates the β-oxidation enzymes, preparing them for the fed state.
2. Increased production of malonyl-CoA inhibits carnitine palmitoyltransferase I (CPT I), preventing fatty acid entry into mitochondria. (correct answer)
3. The resulting decrease in cytosolic acetyl-CoA levels slows down fatty acid activation by acyl-CoA synthetase.
4. The phosphorylation cascade initiated by insulin directly inhibits the dehydrogenase enzymes of the β-oxidation pathway.

Explanation: Acetyl-CoA carboxylase (ACC) catalyzes the formation of malonyl-CoA from acetyl-CoA, which is the first committed step of fatty acid synthesis. In the fed state, high levels of malonyl-CoA act as a potent allosteric inhibitor of carnitine palmitoyltransferase I (CPT I). This inhibition prevents the transport of newly synthesized fatty acids into the mitochondrial matrix, thereby preventing a futile cycle where fatty acids are synthesized and immediately degraded.

Question 3

1. Epinephrine directly activates carnitine palmitoyltransferase I (CPT I) in muscle via a phosphorylation event.
2. Epinephrine stimulates the breakdown of muscle glycogen, producing acetyl-CoA that allosterically activates β-oxidation.
3. Epinephrine signaling in muscle inactivates acetyl-CoA carboxylase (ACC), reducing malonyl-CoA levels and thus de-inhibiting CPT I. (correct answer)
4. Epinephrine increases the expression of β-oxidation enzymes, a slow process that supports sustained, long-term exercise.

Explanation: Similar to glucagon in the liver, epinephrine signaling in muscle activates protein kinase A (PKA). PKA phosphorylates and inactivates acetyl-CoA carboxylase (ACC), the enzyme that produces malonyl-CoA. The resulting drop in malonyl-CoA concentration relieves the inhibition on CPT I, allowing fatty acids (mobilized from adipose tissue) to enter the mitochondria for β-oxidation at a higher rate. This provides ATP for muscle contraction.

Question 4

1. The β-hydroxyacyl-CoA dehydrogenase-catalyzed oxidation of the β-hydroxyacyl-CoA. (correct answer)
2. The carnitine palmitoyltransferase I (CPT I) mediated transport into the mitochondria.
3. The thiolase-catalyzed cleavage of the β-ketoacyl-CoA.
4. The acyl-CoA dehydrogenase-catalyzed formation of the trans-Δ² double bond.

Explanation: When you encounter questions about metabolic regulation, focus on how cofactor ratios directly affect the enzymes that use those cofactors. A high NADH/NAD⁺ ratio means the cell has abundant reducing power and doesn't need to generate more through β-oxidation. The β-hydroxyacyl-CoA dehydrogenase reaction directly uses NAD⁺ as a cofactor, converting it to NADH while oxidizing β-hydroxyacyl-CoA to β-ketoacyl-CoA. When NADH levels are high relative to NAD⁺, this enzyme faces product inhibition—there's insufficient NAD⁺ substrate available, and excess NADH product inhibits the forward reaction. This is the most direct point where a high NADH/NAD⁺ ratio blocks β-oxidation. Choice B is incorrect because CPT I is primarily inhibited by malonyl-CoA, not directly by NADH/NAD⁺ ratios. While high energy charge affects CPT I indirectly through acetyl-CoA carboxylase regulation, this isn't the most direct inhibition point. Choice C is wrong because thiolase doesn't use NAD⁺ as a cofactor—it performs a thiolytic cleavage reaction that's not directly sensitive to NADH/NAD⁺ ratios. Choice D is incorrect because acyl-CoA dehydrogenase uses FAD, not NAD⁺, as its electron acceptor. While this step can be affected by high energy charge through other mechanisms, it's not directly inhibited by NADH/NAD⁺ ratios. Remember: when analyzing metabolic inhibition, look for the enzyme that directly uses the inhibiting cofactor. The cofactor ratios most directly affect the reactions that depend on those specific cofactors.

Question 5

1. Palmitic acid (16:0)
2. Oleic acid (18:1, Δ⁹)
3. Margaric acid (17:0) (correct answer)
4. Arachidonic acid (20:4, Δ⁵,⁸,¹¹,¹⁴)

Explanation: Vitamin B₁₂ (as adenosylcobalamin) is a required cofactor for the enzyme methylmalonyl-CoA mutase. This enzyme catalyzes the conversion of L-methylmalonyl-CoA to succinyl-CoA. This reaction is a key step in the pathway that allows the carbon atoms from odd-chain fatty acids to enter the citric acid cycle. Margaric acid (17:0) is an odd-chain fatty acid; its final round of β-oxidation produces propionyl-CoA, which is converted to succinyl-CoA via the B₁₂-dependent mutase. The other fatty acids listed have an even number of carbons and their β-oxidation yields only acetyl-CoA, a process that does not require vitamin B₁₂.

Question 6

1. High levels of plasma free fatty acids, high levels of ketone bodies, and hyperglycemia.
2. Low levels of plasma free fatty acids, low levels of ketone bodies, and hypoglycemia.
3. High levels of plasma free fatty acids, accumulation of long-chain acylcarnitines in mitochondria, and hypoketotic hypoglycemia. (correct answer)
4. High levels of plasma free fatty acids, accumulation of malonyl-CoA in the cytosol, and normoglycemic hyperketosis.

Explanation: CPT II is located on the inner mitochondrial membrane and is responsible for converting acylcarnitine back to acyl-CoA inside the mitochondrial matrix. A deficiency means long-chain acylcarnitines can enter the intermembrane space via CPT I but cannot enter the matrix for β-oxidation. During a fast, lipolysis is stimulated, leading to high plasma free fatty acids. However, their oxidation is blocked, causing severe hypoketotic (low ketone) hypoglycemia (low blood sugar) because the liver cannot produce ketones or sufficient ATP from fats to fuel gluconeogenesis. The trapped long-chain acylcarnitines accumulate in the mitochondrial intermembrane space and can be detected in plasma.

Question 7

1. It requires an investment of ATP to power the isomerase and reductase enzymes, decreasing the net ATP yield.
2. It produces fewer molecules of NADH because the hydration step is bypassed at each double bond location.
3. It produces fewer molecules of FADH₂ because some double bonds bypass the FAD-dependent acyl-CoA dehydrogenase step. (correct answer)
4. It requires additional oxidation by NAD⁺ to reduce the double bonds prior to isomerization, increasing the net NADH yield.

Explanation: Processing of double bonds that end up in the wrong position or have the wrong stereochemistry requires isomerases and, for polyunsaturated fats, reductases. When a double bond starting on an odd-numbered carbon (like Δ⁹ and Δ¹⁵) is processed, the FAD-dependent acyl-CoA dehydrogenase step is bypassed, resulting in one fewer FADH₂ produced for each such bond. Double bonds starting on even-numbered carbons (like Δ¹²) require a reductase (which consumes NADPH, an energetic cost) and an isomerase, which also results in bypassing an FAD-dependent step. Therefore, the overall yield of FADH₂ is significantly lower for linolenic acid than for stearic acid.

Question 8

1. the first oxidation step is catalyzed by a dehydrogenase that uses NAD⁺ as the electron acceptor, producing NADH.
2. the first oxidation step is catalyzed by an oxidase that transfers electrons directly to O₂, producing hydrogen peroxide (H₂O₂). (correct answer)
3. peroxisomal oxidation can only process short-chain fatty acids, while mitochondria handle long-chain fatty acids.
4. the initial activation of the fatty acid to its CoA derivative occurs inside the peroxisome, unlike in the cytosol for mitochondria.

Explanation: In mitochondrial β-oxidation, the first step is catalyzed by acyl-CoA dehydrogenase, which transfers electrons to FAD to form FADH₂. In contrast, the first step in peroxisomal β-oxidation is catalyzed by a FAD-containing acyl-CoA oxidase. This enzyme transfers electrons directly from the substrate to molecular oxygen (O₂), producing hydrogen peroxide (H₂O₂). The H₂O₂ is then detoxified by catalase. This means the energy from this first oxidation step is not captured as FADH₂ for ATP synthesis in the electron transport chain.

Question 9

1. provide a mechanism for carnitine to allosterically activate the matrix dehydrogenase enzymes upon entry.
2. allow for the regulation of fatty acid oxidation independently of fatty acid synthesis by segregating pools of Coenzyme A.
3. generate a proton gradient across the inner mitochondrial membrane during the transport process.
4. circumvent the general impermeability of the inner mitochondrial membrane to Coenzyme A and its derivatives. (correct answer)

Explanation: The fundamental reason for the carnitine shuttle's existence is a permeability barrier. The inner mitochondrial membrane is highly impermeable to most polar molecules, including Coenzyme A (CoA) and fatty acyl-CoA esters. The shuttle effectively transports the acyl group by attaching it to the smaller, transportable carrier molecule, carnitine. While segregating CoA pools (Choice B) is an important regulatory consequence, the primary, underlying reason is the impermeability of the membrane to acyl-CoAs.

Question 10

1. Oxaloacetate, due to its diversion into the gluconeogenic pathway. (correct answer)
2. Succinyl-CoA, due to its use in heme synthesis.
3. Citrate, due to its export to the cytosol for fatty acid synthesis.
4. α-Ketoglutarate, due to increased rates of amino acid transamination.

Explanation: When you encounter questions about metabolic shifts during starvation, focus on how the body prioritizes glucose production over other metabolic processes. During fasting, the liver must produce glucose through gluconeogenesis to maintain blood sugar levels for glucose-dependent tissues like the brain. The key insight here is understanding the dual role of oxaloacetate in metabolism. Normally, acetyl-CoA from β-oxidation enters the citric acid cycle by condensing with oxaloacetate to form citrate. However, during starvation, oxaloacetate becomes heavily recruited for gluconeogenesis as a precursor to phosphoenolpyruvate and eventually glucose. This creates a metabolic bottleneck: when oxaloacetate is diverted away from the citric acid cycle, acetyl-CoA can no longer efficiently enter this pathway for complete oxidation. With limited oxaloacetate available, excess acetyl-CoA from continued fatty acid oxidation gets redirected into ketogenesis, producing ketone bodies as an alternative fuel source. This is why option A is correct. Option B is wrong because succinyl-CoA depletion for heme synthesis wouldn't significantly impact acetyl-CoA entry into the cycle. Option C incorrectly suggests citrate export increases during starvation, when actually fatty acid synthesis is suppressed. Option D misidentifies α-ketoglutarate as the limiting factor, though amino acid transamination does increase during starvation. Remember this pattern: during starvation, think "glucose first." The body will sacrifice other metabolic pathways to ensure glucose production, and oxaloacetate depletion for gluconeogenesis is the classic trigger for ketogenesis.

Question 11

1. rapid onset of ketoacidosis due to accelerated acetyl-CoA production.
2. elevated blood glucose due to increased reliance on gluconeogenesis.
3. accumulation of fatty acyl-carnitine derivatives in the mitochondrial matrix.
4. impaired ketone body synthesis and severe hypoglycemia. (correct answer)

Explanation: The acyl-CoA dehydrogenases catalyze the first, FAD-dependent step of each β-oxidation cycle. Inhibiting these enzymes would completely block β-oxidation. During a fast, the body relies on β-oxidation to produce acetyl-CoA for ketone body synthesis (in the liver) and ATP production in other tissues. Blocking this pathway would prevent the formation of both ketone bodies and the ATP needed to power gluconeogenesis. The result would be a state of hypoketotic (low ketone) hypoglycemia (low blood glucose), which can be life-threatening.

Question 12

1. ensure that acetyl-CoA produced from β-oxidation is preferentially used for the TCA cycle rather than for synthesis.
2. prevent a futile cycle where newly synthesized fatty acids are immediately transported into mitochondria and oxidized. (correct answer)
3. synchronize the rates of fatty acid oxidation with the rates of cholesterol biosynthesis in the cytosol.
4. conserve carnitine by preventing its unnecessary transport into the mitochondrial matrix when energy is abundant.

Explanation: When cellular energy is high and there is an abundance of precursors (e.g., after a carbohydrate meal), fatty acid synthesis is active. The first committed step of synthesis produces malonyl-CoA. If the products of synthesis (fatty acids) were immediately oxidized, the net result would be the hydrolysis of ATP with no useful work done—a futile cycle. Malonyl-CoA's inhibition of CPT I elegantly prevents this by blocking the entry of newly made fatty acyl-CoAs into the mitochondrial matrix, thus ensuring that synthesis and degradation pathways do not operate simultaneously at high rates.

Question 13

1. Inhibition of thiolase activity, preventing the final step of each β-oxidation cycle and reducing acetyl-CoA production
2. Allosteric inhibition of CPT-I activity, reducing fatty acid entry into mitochondria while promoting cytosolic fatty acid synthesis (correct answer)
3. Competitive inhibition of acyl-CoA dehydrogenase by malonyl-CoA, slowing the initial oxidation step of the β-oxidation cycle
4. Feedback inhibition of fatty acid mobilization from adipose tissue, reducing the substrate availability for continued β-oxidation

Explanation: Malonyl-CoA is a potent allosteric inhibitor of CPT-I, the rate-limiting enzyme that transports fatty acids into mitochondria for β-oxidation. This creates a reciprocal regulatory mechanism: when fatty acid synthesis is active (high malonyl-CoA), β-oxidation is inhibited, preventing the futile cycle of simultaneously synthesizing and degrading fatty acids. Choice A is incorrect because malonyl-CoA doesn't directly inhibit thiolase. Choice C is wrong because malonyl-CoA doesn't competitively inhibit acyl-CoA dehydrogenase. Choice D is incorrect because malonyl-CoA acts at the mitochondrial level, not on adipose tissue mobilization.

Question 14

1. Enhanced fatty acid oxidation due to AMP activation of acetyl-CoA carboxylase, increasing malonyl-CoA production and CPT-I activity
2. Reduced fatty acid oxidation because decreased citrate leads to lower acetyl-CoA carboxylase activity and reduced CPT-I substrate availability
3. Enhanced fatty acid oxidation because AMP activates AMP-activated protein kinase, which phosphorylates and inactivates acetyl-CoA carboxylase, reducing malonyl-CoA levels (correct answer)
4. No significant change in fatty acid oxidation because AMP and citrate effects on CPT-I regulation cancel each other out during exercise conditions

Explanation: High AMP levels activate AMP-activated protein kinase (AMPK), which phosphorylates acetyl-CoA carboxylase (ACC), inactivating it. This reduces malonyl-CoA production, relieving the allosteric inhibition of CPT-I and enhancing fatty acid oxidation. Additionally, low citrate levels also reduce ACC activity (citrate is an allosteric activator of ACC). Both signals promote fatty acid oxidation to meet energy demands. Choice A is incorrect because AMP doesn't directly activate ACC. Choice B misunderstands the relationship between citrate and CPT-I. Choice D is wrong because both signals work synergistically to promote fatty acid oxidation.

Question 15

1. Frequent feeding with medium-chain triglycerides to bypass the enzymatic block and provide ketone precursors for brain metabolism
2. Administration of glucagon during fasting episodes to stimulate hepatic glucose production and compensate for impaired ketogenesis
3. Supplementation with L-carnitine to enhance the transport of medium-chain fatty acids into mitochondria for alternative oxidation pathways
4. Frequent feeding with glucose and avoidance of fasting to prevent dependence on fatty acid oxidation for energy production (correct answer)

Explanation: When you encounter fatty acid oxidation disorders like MCAD deficiency, focus on understanding how the body's energy metabolism shifts during fasting states. MCAD deficiency impairs the breakdown of medium-chain fatty acids (6-12 carbons), which are crucial for ketone production during periods when glucose stores are depleted. The correct answer is D because MCAD deficiency creates a metabolic trap during fasting. Normally, when glucose runs low, your body switches to fatty acid oxidation to produce ketones for brain fuel. With MCAD deficiency, this backup system fails, leading to hypoglycemia (low glucose) and hypoketosis (inadequate ketone production). Frequent glucose feeding and fasting avoidance prevent the body from needing this broken pathway entirely. Option A is problematic because medium-chain triglycerides would still require MCAD for proper oxidation - you're essentially feeding the patient the very substrates they can't metabolize effectively. Option B fails because glucagon stimulates gluconeogenesis and glycogenolysis, but during prolonged fasting, glucose stores become depleted and the body still needs functional fatty acid oxidation. Option C misunderstands the problem - carnitine helps transport long-chain fatty acids into mitochondria, but MCAD deficiency is an intramitochondrial enzyme problem, not a transport issue. For biochemistry exams, remember that enzyme deficiency questions often test whether you understand the metabolic consequences and appropriate bypass strategies. When a pathway is broken, the best intervention is usually avoiding the need for that pathway rather than trying to force it to work.

Question 16

1. Very long-chain fatty acids undergo incomplete β-oxidation due to product inhibition by the large number of acetyl-CoA molecules generated per fatty acid
2. The mitochondrial β-oxidation enzymes have lower substrate affinity (higher Km values) for very long-chain acyl-CoA compared to medium-chain substrates
3. Very long-chain fatty acids require peroxisomal pre-processing before mitochondrial β-oxidation, creating an additional rate-limiting step in the overall pathway (correct answer)
4. Medium-chain fatty acids can bypass the CPT system entirely and enter mitochondria directly, while very long-chain fatty acids are strictly dependent on the CPT shuttle

Explanation: When you encounter questions about fatty acid oxidation efficiency, think about the cellular compartmentalization of this process. Different chain-length fatty acids follow distinct metabolic pathways based on where they can be processed. Very long-chain fatty acids (C20-C24) cannot be directly processed by mitochondrial β-oxidation enzymes. Instead, they must first undergo partial oxidation in peroxisomes, which contain specialized enzymes that can handle these longer substrates. This peroxisomal processing shortens the fatty acids to medium-chain lengths before they're transported to mitochondria for complete β-oxidation. This two-step process creates an additional bottleneck that doesn't exist for shorter fatty acids, explaining the lower oxidation rates observed in the study. Option A is incorrect because product inhibition by acetyl-CoA would affect all fatty acid lengths proportionally, and cells have efficient mechanisms to clear acetyl-CoA through the citric acid cycle. Option B misses the compartmentalization issue—the problem isn't enzyme affinity within mitochondria, but rather that very long-chain fatty acids can't access these enzymes directly. Option D contains a fundamental error: medium-chain fatty acids still use the CPT system for mitochondrial entry, though they may have some alternative transport mechanisms. The key study tip here is to remember the "division of labor" in fatty acid oxidation: peroxisomes handle the initial processing of very long-chain fatty acids, while mitochondria complete the job. This compartmentalization creates inherent rate differences that aren't simply overcome by removing downstream limitations like CPT-I activity.

Question 17

1. The same amount of FADH₂ and NADH because both fatty acids have the same carbon length and undergo 8 cycles of β-oxidation
2. One less FADH₂ but the same amount of NADH because the existing double bond bypasses one acyl-CoA dehydrogenase reaction (correct answer)
3. One less FADH₂ and one less NADH because unsaturated fatty acid oxidation requires additional enzymatic steps that consume reducing equivalents
4. The same amount of FADH₂ but one additional NADH because enoyl-CoA isomerase generates extra reducing equivalents during double bond repositioning

Explanation: Both stearic acid (18:0) and oleic acid (18:1) undergo 8 cycles of β-oxidation to produce 9 acetyl-CoA. However, oleic acid has a cis-double bond at position 9. During β-oxidation, when this pre-existing double bond is encountered, it bypasses the acyl-CoA dehydrogenase step (which normally produces FADH₂), so oleic acid produces one less FADH₂. The number of NADH molecules remains the same because all β-hydroxyacyl-CoA dehydrogenase reactions still occur normally. Choice A ignores the effect of the double bond. Choice C is incorrect because no reducing equivalents are consumed. Choice D is wrong because isomerase doesn't generate NADH.

Question 18

1. Liver has higher endogenous carnitine synthesis capacity compared to muscle, making it less dependent on exogenous carnitine supplementation
2. Carnitine supplementation preferentially accumulates in muscle tissue due to higher expression of carnitine transporters compared to liver
3. The liver expresses alternative fatty acid transport mechanisms that can partially compensate for reduced CPT system function during carnitine deficiency
4. Muscle relies more heavily on fatty acid oxidation for energy production, while liver can effectively use amino acid catabolism during carnitine deficiency (correct answer)

Explanation: When analyzing tissue-specific responses to metabolic therapies, focus on each tissue's primary energy demands and metabolic flexibility during different physiological states. The differential response occurs because muscle and liver have fundamentally different energy needs and metabolic capabilities during fasting. Skeletal muscle relies heavily on fatty acid β-oxidation for sustained energy production, especially during periods of increased demand or fasting. The carnitine palmitoyltransferase (CPT) system is absolutely critical for transporting long-chain fatty acids into mitochondria for oxidation. When carnitine is deficient, muscle loses this primary energy source and experiences weakness. Oral supplementation restores fatty acid oxidation capacity, directly improving muscle function. In contrast, the liver possesses remarkable metabolic flexibility. During carnitine deficiency and fasting, hepatocytes can effectively shift to amino acid catabolism through gluconeogenesis and the urea cycle to maintain energy production and glucose homeostasis. This metabolic versatility allows liver function to remain relatively stable despite impaired fatty acid oxidation. Option A is incorrect because both tissues have similar carnitine synthesis capacity, and the liver actually has higher carnitine concentrations normally. Option B misrepresents transporter distribution—muscle doesn't preferentially accumulate supplemented carnitine. Option C incorrectly suggests the liver has alternative fatty acid transport mechanisms that bypass the CPT system, which doesn't exist for long-chain fatty acids. Remember: tissue-specific responses to metabolic disorders often reflect each tissue's primary energy substrate preferences and alternative pathway availability. Muscle depends heavily on fat oxidation, while liver can easily switch between multiple energy sources.

Question 19

1. Differential expression of CPT-I isoforms that have different sensitivities to malonyl-CoA inhibition between liver and muscle tissue (correct answer)
2. Tissue-specific responses to insulin, where muscle becomes insulin resistant while liver maintains insulin sensitivity during fasting
3. Higher glucagon receptor density in liver compared to muscle, leading to greater activation of fatty acid oxidation pathways
4. Preferential fatty acid uptake by liver due to increased albumin-bound fatty acid delivery from portal circulation during fasting

Explanation: Liver expresses CPT-I A isoform which is less sensitive to malonyl-CoA inhibition, while muscle expresses CPT-I B isoform which is more sensitive to malonyl-CoA. During fasting, malonyl-CoA levels decrease but remain sufficient to inhibit muscle CPT-I B while allowing liver CPT-I A to remain active. This allows liver to oxidize fatty acids for ketogenesis while preserving glucose for muscle use. Choice B is incorrect because muscle doesn't become insulin resistant during normal fasting. Choice C oversimplifies the mechanism. Choice D is wrong because fatty acid delivery doesn't explain the differential regulation.

Question 20

1. Elevated plasma free fatty acids, decreased ketone bodies, and normal glucose levels with mild hypoglycemia developing after prolonged fasting (correct answer)
2. Decreased plasma free fatty acids, elevated ketone bodies, and severe hypoglycemia within 6 hours of fasting
3. Normal plasma free fatty acids, decreased ketone bodies, and hyperglycemia due to increased gluconeogenesis from amino acids
4. Elevated plasma free fatty acids, normal ketone bodies, and severe lactic acidosis due to impaired oxidative metabolism

Explanation: CPT-I is the rate-limiting enzyme for fatty acid entry into mitochondria for β-oxidation. Without functional CPT-I, fatty acids cannot be oxidized, leading to: (1) elevated plasma free fatty acids (mobilized but not oxidized), (2) decreased ketone bodies (since ketogenesis requires β-oxidation), and (3) eventual hypoglycemia during prolonged fasting when glucose stores are depleted and fatty acid oxidation cannot provide alternative fuel. Choice B is incorrect because fatty acids would be elevated, not decreased. Choice C is wrong because fatty acids would be elevated and hyperglycemia wouldn't occur. Choice D is incorrect because lactic acidosis is not a primary feature of CPT-I deficiency.