Fundamental Macromolecules and Concepts - Biochemistry
Card 0 of 960
Which of the following molecule(s) will increase in response to high blood pH?
Which of the following molecule(s) will increase in response to high blood pH?
Blood pH is maintained via the lungs and the kidneys. Lungs alter the amount of carbon dioxide expelled to maintain blood pH. Consider the reaction below.

Carbon dioxide is decreased when pH is low (high hydrogen ion concentration). Decreasing carbon dioxide will shift the reaction to the left and decrease the hydrogen ion concentration. Similarly, the body compensates for high blood pH by increasing carbon dioxide.
Kidneys alter blood pH by increasing or decreasing the excretion of bicarbonate ions. Using the reaction above, we can determine that increasing bicarbonate ion in blood will decrease hydrogen ion concentration whereas decreasing bicarbonate ion will increase hydrogen ion concentration. To combat high blood pH (low hydrogen ion concentration), the bicarbonate ion needs to increased in the blood. The kidneys do this by decreasing the excretion of the bicarbonate ions.
Blood pH is maintained via the lungs and the kidneys. Lungs alter the amount of carbon dioxide expelled to maintain blood pH. Consider the reaction below.
Carbon dioxide is decreased when pH is low (high hydrogen ion concentration). Decreasing carbon dioxide will shift the reaction to the left and decrease the hydrogen ion concentration. Similarly, the body compensates for high blood pH by increasing carbon dioxide.
Kidneys alter blood pH by increasing or decreasing the excretion of bicarbonate ions. Using the reaction above, we can determine that increasing bicarbonate ion in blood will decrease hydrogen ion concentration whereas decreasing bicarbonate ion will increase hydrogen ion concentration. To combat high blood pH (low hydrogen ion concentration), the bicarbonate ion needs to increased in the blood. The kidneys do this by decreasing the excretion of the bicarbonate ions.
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What is the pH of a solution of
?
What is the pH of a solution of ?
pH is calculated via the following equation:
![pH = -log[H^+]](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/701524/gif.latex)
refers to the concentration of hydrogen ions in the solution, which in this case is the same as the concentration of the acid since hydrochloric acid is a strong acid and will fully dissociate in solution. Thus, we have:

pH is calculated via the following equation:
refers to the concentration of hydrogen ions in the solution, which in this case is the same as the concentration of the acid since hydrochloric acid is a strong acid and will fully dissociate in solution. Thus, we have:
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What is buffering capacity?
What is buffering capacity?
Buffering capacity refers to how well a buffer works. A buffer is a substance that maintains a specific pH regardless of added acid or base. Thus, buffering capacity refers to how well a buffer maintains the pH of a solution despite the the effects of added acid or base. The other choices do not apply to this definition.
Buffering capacity refers to how well a buffer works. A buffer is a substance that maintains a specific pH regardless of added acid or base. Thus, buffering capacity refers to how well a buffer maintains the pH of a solution despite the the effects of added acid or base. The other choices do not apply to this definition.
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What is the pOH of a 0.5 M
solution?
What is the pOH of a 0.5 M solution?
Recall the equation for pH. Here is the calculation that should be performed:
![pH = -log[H^+]](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/703969/gif.latex)



Recall the equation for pH. Here is the calculation that should be performed:
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What is the main blood buffer system?
What is the main blood buffer system?
Our main blood buffer system works to protect against large pH changes in the blood. This system relates bicarbonate, carbonic acid, and carbon dioxide via the following equilibria:

While the phosphate buffer system is an important biological buffer, it is not the main buffer system in human blood.
Our main blood buffer system works to protect against large pH changes in the blood. This system relates bicarbonate, carbonic acid, and carbon dioxide via the following equilibria:
While the phosphate buffer system is an important biological buffer, it is not the main buffer system in human blood.
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What is the pOH of a
solution of
?
What is the pOH of a solution of
?
Here are the equations we need to use to find the pOH of our solution of sulfuric acid:

![pH = -log[H^+]](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/709045/gif.latex)


Here are the equations we need to use to find the pOH of our solution of sulfuric acid:
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The higher the concentration of
, the lower the affinity hemoglobin has for binding oxygen. Why is this the case?
The higher the concentration of , the lower the affinity hemoglobin has for binding oxygen. Why is this the case?
Carbon dioxide concentration is low in the blood surrounding the lungs and high in those around muscle, relatively speaking, because cell respiration by the muscles produces carbon dioxide. Therefore, hemoglobin binds oxygen quite well at the lungs, as it should in order for us to be able to breathe, and then binds it much less effectively around the muscles. This allows the oxygen to unbind and enter the muscle tissue (this process is facilitated by myoglobin) where it is used by the actively respiring muscle cells.
Carbon dioxide concentration is low in the blood surrounding the lungs and high in those around muscle, relatively speaking, because cell respiration by the muscles produces carbon dioxide. Therefore, hemoglobin binds oxygen quite well at the lungs, as it should in order for us to be able to breathe, and then binds it much less effectively around the muscles. This allows the oxygen to unbind and enter the muscle tissue (this process is facilitated by myoglobin) where it is used by the actively respiring muscle cells.
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Heavy exercise results in heavy breathing in order to maximize oxygen and rid excess carbon dioxide, but it also results in a temporary increase in lactic acid levels (lactic acidosis) near the working muscles. This slightly lowers the pH of the blood. Why would rapidly eliminating carbon dioxide help raise the pH of the blood back to normal levels?
Heavy exercise results in heavy breathing in order to maximize oxygen and rid excess carbon dioxide, but it also results in a temporary increase in lactic acid levels (lactic acidosis) near the working muscles. This slightly lowers the pH of the blood. Why would rapidly eliminating carbon dioxide help raise the pH of the blood back to normal levels?
Carbonic anhydrase in red blood cells catalyzes the following equilibrium reaction:

The carbonic acid formed then naturally gives up a proton to form
. This is why elevated
levels lower the blood pH. When more
is removed through more rapid breathing, this shifts the equilibrium reaction back to the left (Le Chatelier's principle), prompting more
and
to turn into
which then turns into
and
. Thus, carbonic anhydrase now catalyzes the reaction toward the left in this scenario, raising the pH.
is neither an acidic nor basic molecule by itself (and if it were basic then ridding of it would actually lower the pH further), and while the answer involving oxygen may be tempting, oxygen is not found dissolved in blood plasma; it is bound to hemoglobin, and thus it does not bind protons in the blood to form water.
Carbonic anhydrase in red blood cells catalyzes the following equilibrium reaction:
The carbonic acid formed then naturally gives up a proton to form . This is why elevated
levels lower the blood pH. When more
is removed through more rapid breathing, this shifts the equilibrium reaction back to the left (Le Chatelier's principle), prompting more
and
to turn into
which then turns into
and
. Thus, carbonic anhydrase now catalyzes the reaction toward the left in this scenario, raising the pH.
is neither an acidic nor basic molecule by itself (and if it were basic then ridding of it would actually lower the pH further), and while the answer involving oxygen may be tempting, oxygen is not found dissolved in blood plasma; it is bound to hemoglobin, and thus it does not bind protons in the blood to form water.
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Suppose that a biochemist is interested in studying the carbonic acid/bicarbonate buffer system in humans. To that end, the biochemist needs to make a
solution of
carbonic acid/bicarbonate buffer at a pH of 7.4. Assuming that the dissociation of bicarbonate is negligible, how many moles each of carbonic acid and sodium bicarbonate does the biochemist need in order to achieve a solution at this pH?
Note: The pKa of carbonic acid is 6.35.
Suppose that a biochemist is interested in studying the carbonic acid/bicarbonate buffer system in humans. To that end, the biochemist needs to make a solution of
carbonic acid/bicarbonate buffer at a pH of 7.4. Assuming that the dissociation of bicarbonate is negligible, how many moles each of carbonic acid and sodium bicarbonate does the biochemist need in order to achieve a solution at this pH?
Note: The pKa of carbonic acid is 6.35.
In this question, we're told that a buffer solution consisting of carbonic acid and bicarbonate needs to be prepared. The solution needs to have a concentration of
, a volume of
, and a pH of
.
First, we need to recognize that in order to solve this problem, we'll need to utilize the Henderson-Hasselbalch equation.

The acid in the above expression will be carbonic acid, and its conjugate base is bicarbonate. We can plug in the values we have for pH and pKa to obtain the ratio of base to acid.



Now that we have the ratio of base to acid, we can figure out what fraction of our solution will be base, and what fraction of it will be acid. To find this fraction, we have to realize that for every
moles of base, there is
mole of acid. Thus, there are a total of
moles of acid and base.


Next, we need to take into account the volume and molarity that we want in our desired solution in order to find the total number of moles for our final solution.

Equipped with knowing how many total moles we want in our desired solution, in addition to the portion of our solution that is acid and the portion that is base, we can at last calculate how many moles each of carbonic acid and bicarbonate we need in our solution.
Carbonic acid:

Bicarbonate:

In this question, we're told that a buffer solution consisting of carbonic acid and bicarbonate needs to be prepared. The solution needs to have a concentration of , a volume of
, and a pH of
.
First, we need to recognize that in order to solve this problem, we'll need to utilize the Henderson-Hasselbalch equation.
The acid in the above expression will be carbonic acid, and its conjugate base is bicarbonate. We can plug in the values we have for pH and pKa to obtain the ratio of base to acid.
Now that we have the ratio of base to acid, we can figure out what fraction of our solution will be base, and what fraction of it will be acid. To find this fraction, we have to realize that for every moles of base, there is
mole of acid. Thus, there are a total of
moles of acid and base.
Next, we need to take into account the volume and molarity that we want in our desired solution in order to find the total number of moles for our final solution.
Equipped with knowing how many total moles we want in our desired solution, in addition to the portion of our solution that is acid and the portion that is base, we can at last calculate how many moles each of carbonic acid and bicarbonate we need in our solution.
Carbonic acid:
Bicarbonate:
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If the pH of blood is considered to be 7.4 and the pKa of a compound in the blood is 6.4, what is the ratio of the acid form of the compound to the base form of the compound?
If the pH of blood is considered to be 7.4 and the pKa of a compound in the blood is 6.4, what is the ratio of the acid form of the compound to the base form of the compound?
Using the Henderson Hasselbach equation:



Thus, the ratio of acid to base = 
Using the Henderson Hasselbach equation:
Thus, the ratio of acid to base =
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Calculate the pH of an ammonia buffer when the molar ratio of
is
. The pKa to be used is 9.75.
Calculate the pH of an ammonia buffer when the molar ratio of is
. The pKa to be used is 9.75.
This question requires you to use the Henderson-Hasselbach equation, one of the most important equations in biochemistry. The equation is:
![pH = pKa + log\frac{[A^-]}{[HA]}](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/786811/gif.latex)
where
is the concentration of the conjugate base, and
is the concentration of the acid. In this scenario,
is the conjugate base, while
is the acid. With the numbers given in this question, the equation should look like this:



This question requires you to use the Henderson-Hasselbach equation, one of the most important equations in biochemistry. The equation is:
where is the concentration of the conjugate base, and
is the concentration of the acid. In this scenario,
is the conjugate base, while
is the acid. With the numbers given in this question, the equation should look like this:
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What is the hydrogen ion concentration of an
solution with a pH of 3.5?
What is the hydrogen ion concentration of an solution with a pH of 3.5?
Here is the equation used to find the correct answer:
![pH = -log[H^{_{+}}]](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/786758/gif.latex)
![[H^{^{+}}] = 10^{-pH}](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/786759/gif.latex)
![[H^{^{+}}] = 10^{^{-3.5}}](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/786760/gif.latex)
![[H^{^{+}}] = 0.00032](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/786761/gif.latex)
Here is the equation used to find the correct answer:
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Is water an acid or a base?
Is water an acid or a base?
Water,
, is an amphoteric substance--it can act as either an acid or a base. In certain circumstances, water can act as a Bronsted-Lowry acid by donating a proton.

As seen above,
donated one of its hydrogen atoms, becoming
.
In other cases, water can act as a Bronsted-Lowry base by accepting a proton.

As seen above,
accepted a hydrogen atom to become
.
Therefore, water can act as either an acid or a base depending on the situation. There are other amphoteric substances, but water is definitely the most common.
Water, , is an amphoteric substance--it can act as either an acid or a base. In certain circumstances, water can act as a Bronsted-Lowry acid by donating a proton.
As seen above, donated one of its hydrogen atoms, becoming
.
In other cases, water can act as a Bronsted-Lowry base by accepting a proton.
As seen above, accepted a hydrogen atom to become
.
Therefore, water can act as either an acid or a base depending on the situation. There are other amphoteric substances, but water is definitely the most common.
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What is the pH of a
solution of
?
What is the pH of a solution of
?
Here is the equation that you need to find the answer.
![pH = -log[H^{+}]](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/793872/gif.latex)


Thus, the pH of this solution is closest to
.
Here is the equation that you need to find the answer.
Thus, the pH of this solution is closest to .
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If a patient's lab values from the doctor's office show a blood plasma pH of 7.1, which of the following could be the correct diagnosis?
If a patient's lab values from the doctor's office show a blood plasma pH of 7.1, which of the following could be the correct diagnosis?
Normal blood pH is 7.4. A decrease in pH could indicate acidosis, which is associated with too much
in the blood. Respiratory acidosis occurs as the result of the lungs failing to eliminate enough
.
Normal blood pH is 7.4. A decrease in pH could indicate acidosis, which is associated with too much in the blood. Respiratory acidosis occurs as the result of the lungs failing to eliminate enough
.
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What is the
concentration in an
solution with a pH of
?
What is the concentration in an
solution with a pH of
?
Here is the equation needed to find the correct answer to this question.
![[H^{+}] = 10^{-pH^{}}](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/817266/gif.latex)
![[H^{+}]= 10^{-4}](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/817267/gif.latex)
![[H^{+}]=0.0001](https://vt-vtwa-assets.varsitytutors.com/vt-vtwa/uploads/formula_image/image/817268/gif.latex)
Here is the equation needed to find the correct answer to this question.
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The bicarbonate buffer system used by the human body is crucial for maintaining physiological pH. The carbonic acid and bicarbonate are the conjugate acid-base pair involved.
Why would would hyperventilation cause blood pH to change? Would it increase or decrease?
The bicarbonate buffer system used by the human body is crucial for maintaining physiological pH. The carbonic acid and bicarbonate are the conjugate acid-base pair involved.
Why would would hyperventilation cause blood pH to change? Would it increase or decrease?
Less carbon dioxide in the lungs from the constant exhalation will cause the decrease in the hydrogen ion concentration in the blood, resulting in a rise in pH.
Less carbon dioxide in the lungs from the constant exhalation will cause the decrease in the hydrogen ion concentration in the blood, resulting in a rise in pH.
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If a patient's blood becomes acidic, which of the following will occur?
If a patient's blood becomes acidic, which of the following will occur?
The pH of plasma is regulated by the following equilibria:

According to Le Chatlier's Principle, when the concentration of protons increases (plasma becomes acidic) the equilibrium shift will be to the left of the equation. Therefore, there will be an initial increase of carbon dioxide. However, the body needs to rid itself of the excess carbon dioxide. This happens via hyperventilation - the increased breathing out of carbon dioxide.
The pH of plasma is regulated by the following equilibria:
According to Le Chatlier's Principle, when the concentration of protons increases (plasma becomes acidic) the equilibrium shift will be to the left of the equation. Therefore, there will be an initial increase of carbon dioxide. However, the body needs to rid itself of the excess carbon dioxide. This happens via hyperventilation - the increased breathing out of carbon dioxide.
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Which of the following statements are incorrect?
Which of the following statements are incorrect?

The spontaneity of a reaction says nothing about the reaction's speed. For a spontaneous reaction, the change in Gibbs free energy is negative. In other words, the products have lower energy than the reactants. With low temperatures and negative enthalpy, a reaction can still proceed spontaneously if entropy decreases.
The spontaneity of a reaction says nothing about the reaction's speed. For a spontaneous reaction, the change in Gibbs free energy is negative. In other words, the products have lower energy than the reactants. With low temperatures and negative enthalpy, a reaction can still proceed spontaneously if entropy decreases.
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A reaction has a change in Gibbs free energy (
) of
. This reaction is __________.
A reaction has a change in Gibbs free energy () of
. This reaction is __________.
The Gibbs Free Energy (
)of a reaction tells us whether or not the reaction is favorable. A favorable reaction is also known as spontaneous, and has a negative
. A non-favorable reaction is non-spontaneous, and has a positive
. The term exergonic (meaning energy exits the system) is also used for a reaction with a negative
, while the term endergonic (meaning energy enters the system) is used for a reaction with a positive
. Therefore, a reaction with
is both exergonic and spontaneous.
The Gibbs Free Energy ()of a reaction tells us whether or not the reaction is favorable. A favorable reaction is also known as spontaneous, and has a negative
. A non-favorable reaction is non-spontaneous, and has a positive
. The term exergonic (meaning energy exits the system) is also used for a reaction with a negative
, while the term endergonic (meaning energy enters the system) is used for a reaction with a positive
. Therefore, a reaction with
is both exergonic and spontaneous.
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