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This deck focuses on Parametric Functions, giving you a quick way to review the definitions, rules, and examples that matter most for AP Precalculus.
Study Parametric Functions in AP Precalculus with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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Determine the Cartesian equation from x=4cos(t), y=5sin(t).
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16x2+25y2=1. Ellipse with semi-axes 4 and 5.
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This deck focuses on Parametric Functions, giving you a quick way to review the definitions, rules, and examples that matter most for AP Precalculus.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: 16x2+25y2=1. Ellipse with semi-axes 4 and 5.
Answer: A variable, often t, that both x and y are functions of. The independent variable that controls both coordinates.
Answer: y=2x+1. From x=1+2t get t=2x−1, substitute.
Answer: x2+y2=1. Unit circle using fundamental trigonometric identity.
Answer: To describe geometric figures and motions. Enables modeling of complex paths and trajectories.
Answer: y=53(x+2)−1. From x=5t−2 get t=5x+2, substitute.
Answer: An equation that expresses variables as functions of a parameter. Both x and y depend on the same parameter.
Answer: x=t, y=t2. Simplest parametrization using t as x-coordinate.
Answer: x=t, y=c. Parameter varies while y remains constant.
Answer: An independent variable that defines a set of equations. The controlling variable in parametric representation.
Answer: x=t, y=mt+c. Standard form with slope m and parameter t.
Answer: y=2(x−1). Solve for t from first equation, substitute into second.
Answer: x=c, y=t. Parameter varies while x remains constant.
Answer: x=1+3t, y=2+6t, 0≤t≤1. Direction vector (3,6) with parameter range [0,1].
Answer: x=t, y=at2. General parabola form with coefficient a.
Answer: y=9−(4x)2. Substitute t=4x into the y equation.
Answer: It is the independent variable or parameter. Controls the position along the curve as it varies.
Answer: x=t, y=3t+2. Set parameter t=x for simplest form.
Answer: x=rcos(t), y=rsin(t). Standard form using trigonometric functions with radius r.
Answer: y=34x. Eliminate t by solving x=3t gives t=3x.
Answer: y=2x−3. From x=1+t, get t=x−1, substitute.
Answer: 4x2+9y2=1. Use identity cos2(t)+sin2(t)=1.
Answer: 9x2+16y2=1. Ellipse using sine for x and cosine for y.
Answer: The semi-major and semi-minor axes. The lengths of the ellipse's major and minor axes.
Answer: They allow the description of curves not functions. Can represent curves that fail the vertical line test.
Answer: x=2+3t, y=1+3t, 0≤t≤1. Direction vector (3,3) from start to end point.
Answer: x=t, y=2t+c. Same slope but different y-intercept constant.
Answer: x2+y2=4. Circle with radius 2 centered at origin.
Answer: y=4x2. Eliminate parameter: t=2x, so y=(2x)2.
Answer: x=rcos(t), y=rsin(t). General circle equation with specified radius.
Answer: x=x0+at, y=y0+bt. Point (x0,y0) with direction vector (a,b).
Answer: x2+y2=25. Apply Pythagorean identity to eliminate parameter.
Answer: x=x1+(x2−x1)t, y=y1+(y2−y1)t. Linear interpolation between two given points.
Answer: x=acos(t), y=bsin(t). Uses different coefficients for horizontal and vertical radii.