AP Physics 2 Flashcards: Magnetism And Moving Charges

Study Magnetism And Moving Charges in AP Physics 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Physics 2

Magnetism And Moving Charges

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QUESTION
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What is the formula for the magnetic force on a moving charge?

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ANSWER

F=qvBsin(θ)F = qvB \, \sin(\theta). Force depends on charge, velocity, field strength, and angle between vv and BB.

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This deck focuses on Magnetism And Moving Charges, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 2.

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Flashcard 1: What is the formula for the magnetic force on a moving charge?

Answer: F=qvBsin(θ)F = qvB \, \sin(\theta). Force depends on charge, velocity, field strength, and angle between vv and BB.

Flashcard 2: What is the value of μ0\mu_0, the permeability of free space?

Answer: 4π×107Tm/A4\pi \times 10^{-7} \, T\cdot m/A. Fundamental physical constant used in magnetic field calculations.

Flashcard 3: Identify the symbol for magnetic permeability of free space.

Answer: μ0\mu_0. Fundamental constant relating current to magnetic field in vacuum.

Flashcard 4: What is the effect of a magnetic field on a loop of current?

Answer: Torque acts on the loop. Current loop behaves like magnetic dipole in external field.

Flashcard 5: What is the effect of a magnetic field on a stationary charge?

Answer: No force is exerted. Magnetic force requires motion; stationary charges are unaffected.

Flashcard 6: What is the relationship between electric and magnetic fields in electromagnetic waves?

Answer: Perpendicular to each other. EM waves consist of oscillating EE and BB fields at right angles.

Flashcard 7: State the right-hand rule for the direction of magnetic force.

Answer: Thumb: velocity, Fingers: field, Palm: force. Use right hand to determine force direction on positive charges.

Flashcard 8: What is the force between two parallel current-carrying wires?

Answer: Attractive if currents are in the same direction. Parallel currents attract; antiparallel currents repel each other.

Flashcard 9: What does Lenz's Law state about electromagnetic induction?

Answer: Induced current opposes the change causing it. Nature opposes changes in magnetic flux through circuits.

Flashcard 10: State the formula for the magnetic field inside a solenoid.

Answer: B=μ0nIB = \mu_0 n I. Field strength proportional to current and turns per unit length.

Flashcard 11: State the right-hand rule for the direction of magnetic force.

Answer: Thumb: velocity, Fingers: field, Palm: force. Use right hand to determine force direction on positive charges.

Flashcard 12: Define the term 'magnetic dipole moment'.

Answer: Measure of the strength of a magnetic source. Quantifies the magnetic field strength produced by a current distribution.

Flashcard 13: Identify the unit of magnetic flux.

Answer: Weber (Wb). Named after Wilhelm Weber; unit of magnetic flux linkage.

Flashcard 14: What is the effect of a magnetic field on a stationary charge?

Answer: No force is exerted. Magnetic force requires motion; stationary charges are unaffected.

Flashcard 15: What is the relationship between electric and magnetic fields in electromagnetic waves?

Answer: Perpendicular to each other. EM waves consist of oscillating EE and BB fields at right angles.

Flashcard 16: Calculate the magnetic force on a $3m$ wire carrying 5A5A in a 0.2T0.2T field.

Answer: 3N3 \, N. Using F=ILBF = ILB: 5×3×0.2=3N5 \times 3 \times 0.2 = 3N.

Flashcard 17: What is the direction of the magnetic field around a current-carrying wire?

Answer: Circular around the wire. Right-hand rule: thumb along current, fingers curl with field.

Flashcard 18: State the formula for the magnetic field of a circular loop at its center.

Answer: B=μ0I2RB = \frac{\mu_0 I}{2R}. Field at center is half that of an infinite straight wire.

Flashcard 19: State the Biot-Savart Law for the magnetic field due to a current element.

Answer: dB=μ0Idlsin(θ)4πr2dB = \frac{\mu_0 I dl \sin(\theta)}{4\pi r^2}. Fundamental law relating current elements to magnetic field production.

Flashcard 20: Identify the direction of the magnetic force on a negative charge.

Answer: Opposite to the right-hand rule direction. Negative charges experience force opposite to positive charge direction.

Flashcard 21: Define Ampère's Law.

Answer: Line integral of BB around a closed path equals μ0I\mu_0 I. Relates magnetic field circulation to enclosed current.

Flashcard 22: Calculate the magnetic field at a point 5cm5cm from a wire carrying 6A6A current.

Answer: 2.4×105T2.4 \times 10^{-5} \, T. Using B=μ0I2πrB = \frac{\mu_0 I}{2\pi r} with given values.

Flashcard 23: What is the path of a charged particle in a uniform magnetic field?

Answer: Circular or helical. Magnetic force provides centripetal acceleration for curved motion.

Flashcard 24: State the formula for the magnetic field of a circular loop at its center.

Answer: B=μ0I2RB = \frac{\mu_0 I}{2R}. Field at center is half that of an infinite straight wire.

Flashcard 25: State the effect of a uniform magnetic field on the speed of a charged particle.

Answer: Speed remains constant. Magnetic force is perpendicular to velocity, doing no work.

Flashcard 26: What does a solenoid generate when a current flows through it?

Answer: Uniform magnetic field inside. Coil of wire creates strong, uniform field along its axis.

Flashcard 27: What is the formula for the Lorentz force?

Answer: F=q(E+v×B)F = q(E + v \times B). Combines electric and magnetic forces on a moving charge.

Flashcard 28: Find the magnetic force on a 2C2C charge moving at 3m/s3m/s in a 4T4T field at 9090^{\circ}.

Answer: 24N24 \, N. Using F=qvBF = qvB: 2×3×4=24N2 \times 3 \times 4 = 24N at maximum angle.

Flashcard 29: Calculate the magnetic force on a 0.5C0.5C charge at rest in a 2T2T field.

Answer: 0N0 \, N. No velocity means no magnetic force on the charge.

Flashcard 30: Define Ampère's Law.

Answer: Line integral of BB around a closed path equals μ0I\mu_0 I. Relates magnetic field circulation to enclosed current.

Flashcard 31: What is the magnetic moment of a loop of current?

Answer: μ=IA\mu = I \cdot A. Product of current and loop area defines magnetic strength.

Flashcard 32: Identify the unit of magnetic flux.

Answer: Weber (Wb). Named after Wilhelm Weber; unit of magnetic flux linkage.

Flashcard 33: What is the formula for magnetic flux?

Answer: Φ=BAcos(θ)\Phi = B \cdot A \cdot \cos(\theta). Flux depends on field strength, area, and angle between them.

Flashcard 34: What is the Hall effect?

Answer: Voltage developed across a conductor in a magnetic field. Moving charges in magnetic field separate, creating potential difference.

Flashcard 35: Calculate the magnetic field at a point 5cm5cm from a wire carrying 6A6A current.

Answer: 2.4×105T2.4 \times 10^{-5} \, T. Using B=μ0I2πrB = \frac{\mu_0 I}{2\pi r} with given values.

Flashcard 36: What does Lenz's Law state about electromagnetic induction?

Answer: Induced current opposes the change causing it. Nature opposes changes in magnetic flux through circuits.

Flashcard 37: Identify the direction of the magnetic moment vector of a current loop.

Answer: Perpendicular to the plane of the loop. Vector points normal to loop plane using right-hand rule.

Flashcard 38: State the relationship between current and magnetic field in a solenoid.

Answer: Directly proportional. More current produces stronger magnetic field inside solenoid.

Flashcard 39: Identify the direction of the magnetic force on a negative charge.

Answer: Opposite to the right-hand rule direction. Negative charges experience force opposite to positive charge direction.

Flashcard 40: Calculate the magnetic force on a 0.5C0.5C charge at rest in a 2T2T field.

Answer: 0N0 \, N. No velocity means no magnetic force on the charge.

Flashcard 41: What is the formula for the Lorentz force?

Answer: F=q(E+v×B)F = q(E + v \times B). Combines electric and magnetic forces on a moving charge.

Flashcard 42: State the relationship between current and magnetic field in a solenoid.

Answer: Directly proportional. More current produces stronger magnetic field inside solenoid.

Flashcard 43: Define the unit of magnetic field strength.

Answer: Tesla (T). Named after Nikola Tesla; measures magnetic field intensity.

Flashcard 44: State the effect of a uniform magnetic field on the speed of a charged particle.

Answer: Speed remains constant. Magnetic force is perpendicular to velocity, doing no work.

Flashcard 45: What is the SI unit for electric charge?

Answer: Coulomb (C). Fundamental unit for quantifying electric charge in physics.

Flashcard 46: Identify the direction of the magnetic moment vector of a current loop.

Answer: Perpendicular to the plane of the loop. Vector points normal to loop plane using right-hand rule.

Flashcard 47: What is the magnetic field formula for a long straight wire?

Answer: B=μ0I2πrB = \frac{\mu_0 I}{2\pi r}. Field strength decreases with distance; circular field lines around wire.

Flashcard 48: What is the path of a charged particle in a uniform magnetic field?

Answer: Circular or helical. Magnetic force provides centripetal acceleration for curved motion.

Flashcard 49: What is the force between two parallel current-carrying wires?

Answer: Attractive if currents are in the same direction. Parallel currents attract; antiparallel currents repel each other.

Flashcard 50: What is the Hall effect?

Answer: Voltage developed across a conductor in a magnetic field. Moving charges in magnetic field separate, creating potential difference.

Flashcard 51: What is the direction of the magnetic field inside a solenoid?

Answer: Parallel to the axis of the solenoid. Field lines run straight through the solenoid's center.

Flashcard 52: Calculate the magnetic force on a $3m$ wire carrying 5A5A in a 0.2T0.2T field.

Answer: 3N3 \, N. Using F=ILBF = ILB: 5×3×0.2=3N5 \times 3 \times 0.2 = 3N.

Flashcard 53: Define the term 'magnetic flux'.

Answer: Product of magnetic field and area normal to it. Measures how much magnetic field passes through a surface.

Flashcard 54: State the formula for the magnetic force on a current-carrying wire.

Answer: F=ILBsin(θ)F = ILB \sin(\theta). Force on wire depends on current, length, field, and orientation angle.

Flashcard 55: State the formula for the magnetic force on a current-carrying wire.

Answer: F=ILBsin(θ)F = ILB \sin(\theta). Force on wire depends on current, length, field, and orientation angle.

Flashcard 56: What is the value of μ0\mu_0, the permeability of free space?

Answer: 4π×107Tm/A4\pi \times 10^{-7} \, T\cdot m/A. Fundamental physical constant used in magnetic field calculations.

Flashcard 57: What is the SI unit for electric charge?

Answer: Coulomb (C). Fundamental unit for quantifying electric charge in physics.

Flashcard 58: Define the term 'magnetic flux'.

Answer: Product of magnetic field and area normal to it. Measures how much magnetic field passes through a surface.

Flashcard 59: What is the direction of the magnetic field around a current-carrying wire?

Answer: Circular around the wire. Right-hand rule: thumb along current, fingers curl with field.

Flashcard 60: State the Biot-Savart Law for the magnetic field due to a current element.

Answer: dB=μ0Idlsin(θ)4πr2dB = \frac{\mu_0 I dl \sin(\theta)}{4\pi r^2}. Fundamental law relating current elements to magnetic field production.

Flashcard 61: Identify the condition for maximum magnetic force on a charge.

Answer: θ=90\theta = 90^{\circ}. Perpendicular alignment gives maximum sin(θ)=1\sin(\theta) = 1.

Flashcard 62: What is the formula for the magnetic force on a moving charge?

Answer: F=qvBsin(θ)F = qvB \, \sin(\theta). Force depends on charge, velocity, field strength, and angle between vv and BB.

Flashcard 63: What is the magnetic moment of a loop of current?

Answer: μ=IA\mu = I \cdot A. Product of current and loop area defines magnetic strength.

Flashcard 64: Identify the condition for maximum magnetic force on a charge.

Answer: θ=90\theta = 90^{\circ}. Perpendicular alignment gives maximum sin(θ)=1\sin(\theta) = 1.

Flashcard 65: What is the magnetic field formula for a long straight wire?

Answer: B=μ0I2πrB = \frac{\mu_0 I}{2\pi r}. Field strength decreases with distance; circular field lines around wire.

Flashcard 66: What is the effect of a magnetic field on a loop of current?

Answer: Torque acts on the loop. Current loop behaves like magnetic dipole in external field.

Flashcard 67: What is the formula for magnetic flux?

Answer: Φ=BAcos(θ)\Phi = B \cdot A \cdot \cos(\theta). Flux depends on field strength, area, and angle between them.

Flashcard 68: Define the term 'magnetic dipole moment'.

Answer: Measure of the strength of a magnetic source. Quantifies the magnetic field strength produced by a current distribution.

Flashcard 69: Find the magnetic force on a 2C2C charge moving at 3m/s3m/s in a 4T4T field at 9090^{\circ}.

Answer: 24N24 \, N. Using F=qvBF = qvB: 2×3×4=24N2 \times 3 \times 4 = 24N at maximum angle.