AP Physics 2 Flashcards: Electric Fields

Study Electric Fields in AP Physics 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Physics 2

Electric Fields

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QUESTION
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Explain the change in electric field strength if the charge is tripled.

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ANSWER

Field strength is tripled. Field strength is directly proportional to the source charge magnitude.

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This deck focuses on Electric Fields, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 2.

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Flashcard 1: Explain the change in electric field strength if the charge is tripled.

Answer: Field strength is tripled. Field strength is directly proportional to the source charge magnitude.

Flashcard 2: State the formula for the electric field between two parallel plates.

Answer: E=VdE = \frac{V}{d}. Uniform field between plates equals voltage divided by separation.

Flashcard 3: What is the electric field due to a charge distribution at infinity?

Answer: Zero. Field approaches zero as distance approaches infinity for finite charges.

Flashcard 4: What is the effect of a conductor on the external electric field?

Answer: Distorts and reduces the field inside. Conductor redistributes charges and creates field-free interior region.

Flashcard 5: What is the direction of the electric field due to a negative point charge?

Answer: Radially inward towards the charge. Electric field points toward negative charges in all directions.

Flashcard 6: What is the charge of an electron?

Answer: 1.6×1019-1.6 \times 10^{-19} C. Elementary negative charge magnitude in coulombs.

Flashcard 7: Explain the change in electric field strength if the charge is tripled.

Answer: Field strength is tripled. Field strength is directly proportional to the source charge magnitude.

Flashcard 8: How does the electric field between parallel plates depend on the area of the plates?

Answer: Field is independent of the plate area. Field depends only on charge density and plate separation, not area.

Flashcard 9: What is the electric field inside a conductor in electrostatic equilibrium?

Answer: Zero. Free charges redistribute to cancel internal fields in equilibrium.

Flashcard 10: What happens to the electric field if the distance from a point charge is doubled?

Answer: Field strength decreases by a factor of 4. Inverse square relationship: doubling distance quarters the field strength.

Flashcard 11: State Gauss's law for electric fields.

Answer: EdA=Qenclosedε0\oint E \cdot dA = \frac{Q_{enclosed}}{\varepsilon_0}. Fundamental relationship between electric flux and enclosed charge.

Flashcard 12: Determine the net electric field at a point equidistant from two equal charges.

Answer: Zero, if charges are opposite. Equal magnitudes but opposite directions cancel when charges are opposite.

Flashcard 13: What is the direction of electric field lines around a dipole?

Answer: From positive to negative charge. Field lines exit positive charges and enter negative charges.

Flashcard 14: What is the electric field at the surface of a conductor?

Answer: Perpendicular to the surface. Electric field must be normal to conductor surface in equilibrium.

Flashcard 15: What is the electric field due to a charge distribution at infinity?

Answer: Zero. Field approaches zero as distance approaches infinity for finite charges.

Flashcard 16: What is the electric field inside a conductor in electrostatic equilibrium?

Answer: Zero. Free charges redistribute to cancel internal fields in equilibrium.

Flashcard 17: Which principle explains the behavior of electric fields in superposition?

Answer: Principle of superposition. Vector addition of individual field contributions from multiple sources.

Flashcard 18: What is the effect of a grounded conductor on nearby electric field lines?

Answer: Field lines terminate on the conductor. Grounded conductors provide discharge path, terminating field lines.

Flashcard 19: What is the charge of an electron?

Answer: 1.6×1019-1.6 \times 10^{-19} C. Elementary negative charge magnitude in coulombs.

Flashcard 20: What is the direction of the electric field due to a negative point charge?

Answer: Radially inward towards the charge. Electric field points toward negative charges in all directions.

Flashcard 21: What is the effect of a conductor on the external electric field?

Answer: Distorts and reduces the field inside. Conductor redistributes charges and creates field-free interior region.

Flashcard 22: What is the electric field at the surface of a conductor?

Answer: Perpendicular to the surface. Electric field must be normal to conductor surface in equilibrium.

Flashcard 23: What is the effect of a grounded conductor on nearby electric field lines?

Answer: Field lines terminate on the conductor. Grounded conductors provide discharge path, terminating field lines.

Flashcard 24: State Coulomb's law in terms of force between two point charges.

Answer: F=kq1q2r2F = \frac{k |q_1 q_2|}{r^2}. Force between charges depends on product of charges and inverse square of distance.

Flashcard 25: What is the value of the electric constant kk in vacuum?

Answer: k=8.99×109 N m2/C2k = 8.99 \times 10^9 \text{ N m}^2/\text{C}^2. Standard value for the proportionality constant in vacuum.

Flashcard 26: State Gauss's law for electric fields.

Answer: EdA=Qenclosedε0\oint E \cdot dA = \frac{Q_{enclosed}}{\varepsilon_0}. Fundamental relationship between electric flux and enclosed charge.

Flashcard 27: State the unit of electric field strength in the SI system.

Answer: Newton per coulomb (N/C). Standard SI unit combining force (N) per unit charge (C).

Flashcard 28: What is the effect of doubling the distance between a charge and a point in the field?

Answer: Electric field decreases by a factor of 4. Inverse square law: field strength decreases by factor of four.

Flashcard 29: Identify the direction of the electric field around a positive point charge.

Answer: Radially outward from the charge. Electric field points away from positive charges in all directions.

Flashcard 30: State the formula for the electric field between two parallel plates.

Answer: E=VdE = \frac{V}{d}. Uniform field between plates equals voltage divided by separation.

Flashcard 31: What is the formula for the electric field due to a point charge?

Answer: E=kQr2E = \frac{kQ}{r^2}. Coulomb's law applied to field strength, where kk is the electric constant.

Flashcard 32: Determine the electric field inside a hollow charged spherical conductor.

Answer: Zero. No charges inside hollow conductor means zero internal field.

Flashcard 33: What is the effect of doubling the distance between a charge and a point in the field?

Answer: Electric field decreases by a factor of 4. Inverse square law: field strength decreases by factor of four.

Flashcard 34: What is the relation between electric field and electric potential?

Answer: E=dVdxE = -\frac{dV}{dx}. Field is the negative gradient of potential in one dimension.

Flashcard 35: Define an electric dipole.

Answer: Two equal and opposite charges separated by a distance. Basic configuration creating electric dipole moment and field pattern.

Flashcard 36: What happens to the electric field if the distance from a point charge is doubled?

Answer: Field strength decreases by a factor of 4. Inverse square relationship: doubling distance quarters the field strength.

Flashcard 37: State Coulomb's law in terms of force between two point charges.

Answer: F=kq1q2r2F = \frac{k |q_1 q_2|}{r^2}. Force between charges depends on product of charges and inverse square of distance.

Flashcard 38: What is the direction of electric field lines around a dipole?

Answer: From positive to negative charge. Field lines exit positive charges and enter negative charges.

Flashcard 39: What is the effect of introducing a dielectric in a parallel plate capacitor?

Answer: Reduces the electric field. Dielectric materials decrease field strength by polarization effects.

Flashcard 40: Identify the electric field at the center of a uniformly charged ring.

Answer: Zero. Symmetry causes all field contributions to cancel at the center.

Flashcard 41: Determine the net electric field at a point equidistant from two equal charges.

Answer: Zero, if charges are opposite. Equal magnitudes but opposite directions cancel when charges are opposite.

Flashcard 42: What is the electric field at a point with zero electric potential?

Answer: Not necessarily zero. Field and potential are related but independent quantities.

Flashcard 43: Which quantity measures the work done per unit charge by an electric field?

Answer: Electric potential. Potential represents energy per unit charge in electric field.

Flashcard 44: What is the relation between electric field and electric potential?

Answer: E=dVdxE = -\frac{dV}{dx}. Field is the negative gradient of potential in one dimension.

Flashcard 45: What is the electric field at a point outside a charged sphere?

Answer: Same as a point charge: E=kQr2E = \frac{kQ}{r^2}. Spherical symmetry makes external field identical to point charge.

Flashcard 46: What is the relationship between electric field and force on a charge?

Answer: F=qEF = qE. Force equals charge multiplied by electric field strength.

Flashcard 47: Identify the electric field at the center of a uniformly charged ring.

Answer: Zero. Symmetry causes all field contributions to cancel at the center.

Flashcard 48: Find the electric field at a point midway between two equal positive charges.

Answer: Zero. Symmetry causes equal and opposite field contributions to cancel.

Flashcard 49: Define an electric dipole.

Answer: Two equal and opposite charges separated by a distance. Basic configuration creating electric dipole moment and field pattern.

Flashcard 50: Find the electric field at a point midway between two equal positive charges.

Answer: Zero. Symmetry causes equal and opposite field contributions to cancel.

Flashcard 51: Which principle explains the behavior of electric fields in superposition?

Answer: Principle of superposition. Vector addition of individual field contributions from multiple sources.

Flashcard 52: Identify the direction of the electric field around a positive point charge.

Answer: Radially outward from the charge. Electric field points away from positive charges in all directions.

Flashcard 53: What is the electric field at a point outside a charged sphere?

Answer: Same as a point charge: E=kQr2E = \frac{kQ}{r^2}. Spherical symmetry makes external field identical to point charge.

Flashcard 54: What is the effect of introducing a dielectric in a parallel plate capacitor?

Answer: Reduces the electric field. Dielectric materials decrease field strength by polarization effects.

Flashcard 55: What is the electric field at a point with zero electric potential?

Answer: Not necessarily zero. Field and potential are related but independent quantities.

Flashcard 56: How does the electric field between parallel plates depend on the area of the plates?

Answer: Field is independent of the plate area. Field depends only on charge density and plate separation, not area.

Flashcard 57: What is the formula for the electric field due to a point charge?

Answer: E=kQr2E = \frac{kQ}{r^2}. Coulomb's law applied to field strength, where kk is the electric constant.

Flashcard 58: State the unit of electric field strength in the SI system.

Answer: Newton per coulomb (N/C). Standard SI unit combining force (N) per unit charge (C).

Flashcard 59: What is the value of the electric constant kk in vacuum?

Answer: k=8.99×109 N m2/C2k = 8.99 \times 10^9 \text{ N m}^2/\text{C}^2. Standard value for the proportionality constant in vacuum.

Flashcard 60: Determine the electric field inside a hollow charged spherical conductor.

Answer: Zero. No charges inside hollow conductor means zero internal field.

Flashcard 61: What is the relationship between electric field and force on a charge?

Answer: F=qEF = qE. Force equals charge multiplied by electric field strength.