AP Physics 2 Flashcards: Electric Current

Study Electric Current in AP Physics 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Physics 2

Electric Current

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QUESTION
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Calculate the potential difference if I=1.5 AI = 1.5 \text{ A} and R=6 ΩR = 6 \text{ Ω}.

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ANSWER

V=9 VV = 9 \text{ V}. Apply V=IR=1.5×6=9V = IR = 1.5 \times 6 = 9 V.

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Flashcard 1: Calculate the potential difference if I=1.5 AI = 1.5 \text{ A} and R=6 ΩR = 6 \text{ Ω}.

Answer: V=9 VV = 9 \text{ V}. Apply V=IR=1.5×6=9V = IR = 1.5 \times 6 = 9 V.

Flashcard 2: What is the unit of electrical power?

Answer: Watt (W). Rate of energy transfer or consumption.

Flashcard 3: Convert 1 milliampere to amperes.

Answer: 1 mA=0.001 A1 \text{ mA} = 0.001 \text{ A}. Milli prefix means one thousandth.

Flashcard 4: Calculate the energy used if P=100 WP = 100 \text{ W} and t=2 hourst = 2 \text{ hours}.

Answer: E=200 WhE = 200 \text{ Wh}. Apply E=Pt=100×2=200E = Pt = 100 \times 2 = 200 Wh.

Flashcard 5: What is the formula for total resistance in series?

Answer: Rtotal=R1+R2+dotsR_{total} = R_1 + R_2 + \\dots. Individual resistances add in series circuits.

Flashcard 6: State the formula for calculating resistance using resistivity.

Answer: R=ρLAR = \frac{\rho L}{A}. Resistance depends on material, length, and cross-sectional area.

Flashcard 7: What is the definition of resistivity?

Answer: Resistance per unit length and area. Material property affecting electrical resistance.

Flashcard 8: What is the unit of resistance?

Answer: Ohm (Ω\text{Ω}). Named after Georg Ohm, symbol omega.

Flashcard 9: What is the effect of adding resistors in parallel on total resistance?

Answer: Total resistance decreases. Parallel paths reduce overall resistance.

Flashcard 10: What is the effect of temperature on resistance in conductors?

Answer: Resistance increases. Higher temperature increases atomic vibrations.

Flashcard 11: What is the formula for electrical power in terms of current and voltage?

Answer: P=IVP = IV. Power equals current times voltage.

Flashcard 12: Calculate the potential difference if I=1.5 AI = 1.5 \text{ A} and R=6 ΩR = 6 \text{ Ω}.

Answer: V=9 VV = 9 \text{ V}. Apply V=IR=1.5×6=9V = IR = 1.5 \times 6 = 9 V.

Flashcard 13: What does an ohmmeter measure?

Answer: Resistance. Instrument for measuring electrical resistance.

Flashcard 14: How is current measured?

Answer: Using an ammeter. Ammeter connected in series with circuit.

Flashcard 15: Calculate the energy used if P=100 WP = 100 \text{ W} and t=2 hourst = 2 \text{ hours}.

Answer: E=200 WhE = 200 \text{ Wh}. Apply E=Pt=100×2=200E = Pt = 100 \times 2 = 200 Wh.

Flashcard 16: What is the power formula using voltage and resistance?

Answer: P=V2RP = \frac{V^2}{R}. Alternative power formula using voltage and resistance.

Flashcard 17: What does an ohmmeter measure?

Answer: Resistance. Instrument for measuring electrical resistance.

Flashcard 18: What is the formula for voltage in terms of work and charge?

Answer: V=WqV = \frac{W}{q}. Voltage is work per unit charge.

Flashcard 19: Calculate the current if V=12 VV = 12 \text{ V} and R=4 ΩR = 4 \text{ Ω}. Use Ohm's Law.

Answer: I=3 AI = 3 \text{ A}. Apply I=VR=124=3I = \frac{V}{R} = \frac{12}{4} = 3 A.

Flashcard 20: Calculate resistance if V=10 VV = 10 \text{ V} and I=2 AI = 2 \text{ A}. Use Ohm's Law.

Answer: R=5 ΩR = 5 \text{ Ω}. Apply R=VI=102=5R = \frac{V}{I} = \frac{10}{2} = 5 Ω.

Flashcard 21: What is the effect of increasing voltage on current, assuming constant resistance?

Answer: Current increases. Direct proportional relationship from Ohm's Law.

Flashcard 22: What is the formula for total resistance in parallel?

Answer: 1Rtotal=1R1+1R2+dots\frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \\dots. Reciprocals of resistances add in parallel circuits.

Flashcard 23: State Ohm's Law formula.

Answer: V=IRV = IR. Voltage equals current times resistance.

Flashcard 24: What is the formula for voltage in terms of work and charge?

Answer: V=WqV = \frac{W}{q}. Voltage is work per unit charge.

Flashcard 25: State Ohm's Law formula.

Answer: V=IRV = IR. Voltage equals current times resistance.

Flashcard 26: What is the formula for electric current in terms of charge and time?

Answer: I=qtI = \frac{q}{t}. Current is charge divided by time.

Flashcard 27: What is the effect of increasing resistance on current?

Answer: Current decreases. Inverse relationship from Ohm's Law.

Flashcard 28: What is the unit of resistivity?

Answer: Ωm\text{Ωm} (Ohm meter). Resistance times meters per square meter.

Flashcard 29: What is the effect of adding resistors in series on total resistance?

Answer: Total resistance increases. Resistors in series add directly.

Flashcard 30: What is Kirchhoff's Junction Rule?

Answer: Sum of currents entering = sum leaving. Conservation of charge at circuit junctions.

Flashcard 31: Identify the direction of conventional current flow.

Answer: From positive to negative terminal. Conventional current flows opposite to electron flow.

Flashcard 32: Describe the motion of electrons in a conductor.

Answer: Drift towards positive terminal. Electrons move opposite to conventional current direction.

Flashcard 33: What is the formula for total resistance in parallel?

Answer: 1Rtotal=1R1+1R2+dots\frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \\dots. Reciprocals of resistances add in parallel circuits.

Flashcard 34: What is the effect of increasing voltage on current, assuming constant resistance?

Answer: Current increases. Direct proportional relationship from Ohm's Law.

Flashcard 35: What is the effect of adding resistors in parallel on total resistance?

Answer: Total resistance decreases. Parallel paths reduce overall resistance.

Flashcard 36: Express 5 kilowatts in watts.

Answer: 5 kW=5000 W5 \text{ kW} = 5000 \text{ W}. Kilo prefix means one thousand.

Flashcard 37: What is the unit for electric charge?

Answer: Coulomb (C). Amount of electric charge, named after Coulomb.

Flashcard 38: Define electric current.

Answer: Flow of electric charge. Rate of charge flow through a conductor.

Flashcard 39: Calculate the power if I=2 AI = 2 \text{ A} and R=3 ΩR = 3 \text{ Ω}. Use P=I2RP = I^2R.

Answer: P=12 WP = 12 \text{ W}. Apply P=I2R=22×3=12P = I^2R = 2^2 \times 3 = 12 W.

Flashcard 40: What is the effect of increasing resistance on current?

Answer: Current decreases. Inverse relationship from Ohm's Law.

Flashcard 41: Calculate the current if V=12 VV = 12 \text{ V} and R=4 ΩR = 4 \text{ Ω}. Use Ohm's Law.

Answer: I=3 AI = 3 \text{ A}. Apply I=VR=124=3I = \frac{V}{R} = \frac{12}{4} = 3 A.

Flashcard 42: Identify the direction of conventional current flow.

Answer: From positive to negative terminal. Conventional current flows opposite to electron flow.

Flashcard 43: What is the relationship between power, current, and resistance?

Answer: P=I2RP = I^2R. Power dissipated as heat in resistive circuits.

Flashcard 44: What is the formula for total resistance in series?

Answer: Rtotal=R1+R2+dotsR_{total} = R_1 + R_2 + \\dots. Individual resistances add in series circuits.

Flashcard 45: Calculate the total resistance for R1=5 ΩR_1 = 5 \text{ Ω} and R2=10 ΩR_2 = 10 \text{ Ω} in parallel.

Answer: Rtotal=3.33 ΩR_{total} = 3.33 \text{ Ω}. Apply 1Rtotal=15+110=310\frac{1}{R_{total}} = \frac{1}{5} + \frac{1}{10} = \frac{3}{10}, so Rtotal=3.33R_{total} = 3.33 Ω.

Flashcard 46: What is the power formula using voltage and resistance?

Answer: P=V2RP = \frac{V^2}{R}. Alternative power formula using voltage and resistance.

Flashcard 47: Calculate the total resistance for R1=5 ΩR_1 = 5 \text{ Ω} and R2=10 ΩR_2 = 10 \text{ Ω} in parallel.

Answer: Rtotal=3.33 ΩR_{total} = 3.33 \text{ Ω}. Apply 1Rtotal=15+110=310\frac{1}{R_{total}} = \frac{1}{5} + \frac{1}{10} = \frac{3}{10}, so Rtotal=3.33R_{total} = 3.33 Ω.

Flashcard 48: What is the unit of electrical power?

Answer: Watt (W). Rate of energy transfer or consumption.

Flashcard 49: How is current measured?

Answer: Using an ammeter. Ammeter connected in series with circuit.

Flashcard 50: What is the SI unit for electric current?

Answer: Ampere (A). Standard unit defined as one coulomb per second.

Flashcard 51: Convert 1 milliampere to amperes.

Answer: 1 mA=0.001 A1 \text{ mA} = 0.001 \text{ A}. Milli prefix means one thousandth.

Flashcard 52: State the formula for electrical energy in terms of power and time.

Answer: E=PtE = Pt. Energy equals power multiplied by time.