AP Physics 2 Flashcards: Conservation Of Electric Energy

Study Conservation Of Electric Energy in AP Physics 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Physics 2

Conservation Of Electric Energy

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QUESTION
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Calculate the work done if a charge q=5Cq = 5C moves through ΔV=3V\Delta V = 3V.

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ANSWER

W=15 JW = 15 \text{ J}. Using W=qΔV=5×3=15W = q\Delta V = 5 \times 3 = 15 J.

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This deck focuses on Conservation Of Electric Energy, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 2.

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Flashcard 1: Calculate the work done if a charge q=5Cq = 5C moves through ΔV=3V\Delta V = 3V.

Answer: W=15 JW = 15 \text{ J}. Using W=qΔV=5×3=15W = q\Delta V = 5 \times 3 = 15 J.

Flashcard 2: What is the relationship between electric potential and potential energy?

Answer: U=qVU = qV. Potential energy equals charge times electric potential.

Flashcard 3: What is the potential energy of a charge in a field with zero potential difference?

Answer: Zero. No potential difference means no stored energy.

Flashcard 4: Identify the formula for converting potential difference to electric field strength.

Answer: E=ΔVdE = -\frac{\Delta V}{d}. Relationship between field strength and potential gradient.

Flashcard 5: What does the symbol kek_e represent in electric potential formulas?

Answer: Coulomb's constant. Fundamental constant in Coulomb's law and electric formulas.

Flashcard 6: Which factor does not affect electric potential energy in a uniform field?

Answer: The direction of dd. Direction doesn't affect energy magnitude in uniform fields.

Flashcard 7: Identify the relationship between electric field strength and potential difference.

Answer: E=ΔVdE = -\frac{\Delta V}{d}. Electric field is negative gradient of potential.

Flashcard 8: State the principle of conservation of electric energy.

Answer: Total electric energy remains constant in an isolated system. Fundamental principle: energy cannot be created or destroyed.

Flashcard 9: Define the term 'electric potential'.

Answer: Work done per unit charge to move a charge from infinity. Potential is work per unit charge from reference point.

Flashcard 10: What is the unit of electric potential in the SI system?

Answer: Volt (V). Standard SI unit for electric potential difference.

Flashcard 11: What is the formula for the work done by an electric field?

Answer: W=qEdW = qEd. Work equals force times distance in uniform field.

Flashcard 12: Identify the effect on potential energy if distance increases in a point charge field.

Answer: Decreases. Potential energy varies as 1/r1/r for point charges.

Flashcard 13: State how electric potential energy changes when moving against the field.

Answer: Increases. Moving against field requires work, increasing energy.

Flashcard 14: How does electric potential vary with distance from a point charge?

Answer: Inversely proportional. Potential follows inverse square law like electric field.

Flashcard 15: State what happens to potential energy when a charge moves with the field.

Answer: Decreases. Field does positive work, reducing potential energy.

Flashcard 16: What is the effect on potential energy if a charge is halved?

Answer: Halves. Energy is directly proportional to charge.

Flashcard 17: What is the potential energy of a 2C charge at a potential of 5V?

Answer: U=10 JU = 10 \text{ J}. Using U=qV=2×5=10U = qV = 2 \times 5 = 10 J.

Flashcard 18: Identify the unit of electric potential energy in the SI system.

Answer: Joule (J). Standard SI unit for energy in all forms including electric.

Flashcard 19: Calculate the electric potential energy for q=3Cq = 3C and V=4VV = 4V.

Answer: U=12 JU = 12 \text{ J}. Using U=qV=3×4=12U = qV = 3 \times 4 = 12 J.

Flashcard 20: Calculate the electric potential energy for q=4Cq = 4C and V=6VV = 6V.

Answer: U=24 JU = 24 \text{ J}. Using U=qV=4×6=24U = qV = 4 \times 6 = 24 J.

Flashcard 21: State how electric potential energy changes when moving against the field.

Answer: Increases. Moving against field requires work, increasing energy.

Flashcard 22: State the formula for electric potential due to a point charge.

Answer: V=keqrV = k_e \frac{q}{r}. Potential created by point charge qq at distance rr.

Flashcard 23: Calculate the electric potential energy for q=3Cq = 3C and V=4VV = 4V.

Answer: U=12 JU = 12 \text{ J}. Using U=qV=3×4=12U = qV = 3 \times 4 = 12 J.

Flashcard 24: What does the conservation of electric energy imply for potential changes?

Answer: Sum of changes is zero. Net energy change is zero in conservative systems.

Flashcard 25: Calculate the potential energy change for q=1Cq = 1C and ΔV=2V\Delta V = -2V.

Answer: ΔU=2 J\Delta U = -2 \text{ J}. Using ΔU=qΔV=1×(2)=2\Delta U = q\Delta V = 1 \times (-2) = -2 J.

Flashcard 26: Calculate the electric potential energy for q=4Cq = 4C and V=6VV = 6V.

Answer: U=24 JU = 24 \text{ J}. Using U=qV=4×6=24U = qV = 4 \times 6 = 24 J.

Flashcard 27: What is the effect of increasing charge on electric potential energy?

Answer: It increases linearly. Potential energy is directly proportional to charge.

Flashcard 28: What is the change in potential energy if a charge is moved to a lower potential?

Answer: Decreases. Lower potential means reduced stored energy.

Flashcard 29: Which factor does not affect electric potential energy in a uniform field?

Answer: The direction of dd. Direction doesn't affect energy magnitude in uniform fields.

Flashcard 30: Identify the relationship between work done and electric potential energy.

Answer: W=ΔUW = -\Delta U. Work done equals negative change in potential energy.

Flashcard 31: Identify the unit of electric potential energy in the SI system.

Answer: Joule (J). Standard SI unit for energy in all forms including electric.

Flashcard 32: Find the change in electric potential energy if q=2Cq = 2C and ΔV=5V\Delta V = 5V.

Answer: ΔU=10 J\Delta U = 10 \text{ J}. Using ΔU=qΔV=2×5=10\Delta U = q\Delta V = 2 \times 5 = 10 J.

Flashcard 33: What happens to electric potential energy if charge is doubled?

Answer: It doubles. Energy is directly proportional to charge magnitude.

Flashcard 34: Calculate the work done if a charge q=5Cq = 5C moves through ΔV=3V\Delta V = 3V.

Answer: W=15 JW = 15 \text{ J}. Using W=qΔV=5×3=15W = q\Delta V = 5 \times 3 = 15 J.

Flashcard 35: What is the unit of Coulomb's constant kek_e?

Answer: Nm2/C2\text{N} \cdot \text{m}^2/\text{C}^2. Units derived from Coulomb's law force equation.

Flashcard 36: What is the formula for electric potential energy?

Answer: U=qVU = qV. Energy stored in charge qq at electric potential VV.

Flashcard 37: Which physical quantity is conserved in an isolated electric system?

Answer: Electric energy. Total electric energy remains constant in isolated systems.

Flashcard 38: Find the change in electric potential energy if q=2Cq = 2C and ΔV=5V\Delta V = 5V.

Answer: ΔU=10 J\Delta U = 10 \text{ J}. Using ΔU=qΔV=2×5=10\Delta U = q\Delta V = 2 \times 5 = 10 J.

Flashcard 39: What does the symbol kek_e represent in electric potential formulas?

Answer: Coulomb's constant. Fundamental constant in Coulomb's law and electric formulas.

Flashcard 40: Identify what must be true for electric energy conservation in a circuit.

Answer: Closed circuit, no external work. Requirements for energy conservation in electrical systems.

Flashcard 41: What is the unit of electric potential in the SI system?

Answer: Volt (V). Standard SI unit for electric potential difference.

Flashcard 42: Identify the effect on potential energy if distance increases in a point charge field.

Answer: Decreases. Potential energy varies as 1/r1/r for point charges.

Flashcard 43: What quantity does the symbol UU represent in electric energy equations?

Answer: Electric potential energy. Standard symbol for electric potential energy in physics.

Flashcard 44: Identify the formula for converting potential difference to electric field strength.

Answer: E=ΔVdE = -\frac{\Delta V}{d}. Relationship between field strength and potential gradient.

Flashcard 45: What happens to electric potential energy if charge is doubled?

Answer: It doubles. Energy is directly proportional to charge magnitude.

Flashcard 46: What is the unit of Coulomb's constant kek_e?

Answer: Nm2/C2\text{N} \cdot \text{m}^2/\text{C}^2. Units derived from Coulomb's law force equation.

Flashcard 47: What is the potential energy of a 2C charge at a potential of 5V?

Answer: U=10 JU = 10 \text{ J}. Using U=qV=2×5=10U = qV = 2 \times 5 = 10 J.

Flashcard 48: What is the change in potential energy if a charge is moved to a lower potential?

Answer: Decreases. Lower potential means reduced stored energy.

Flashcard 49: Calculate the potential energy change for q=1Cq = 1C and ΔV=2V\Delta V = -2V.

Answer: ΔU=2 J\Delta U = -2 \text{ J}. Using ΔU=qΔV=1×(2)=2\Delta U = q\Delta V = 1 \times (-2) = -2 J.

Flashcard 50: State the formula for electric potential due to a point charge.

Answer: V=keqrV = k_e \frac{q}{r}. Potential created by point charge qq at distance rr.

Flashcard 51: What is the effect on potential energy if a charge is halved?

Answer: Halves. Energy is directly proportional to charge.

Flashcard 52: What does the conservation of electric energy imply for potential changes?

Answer: Sum of changes is zero. Net energy change is zero in conservative systems.

Flashcard 53: What is the formula for the work done by an electric field?

Answer: W=qEdW = qEd. Work equals force times distance in uniform field.

Flashcard 54: State the expression for the electric potential difference in a uniform field.

Answer: ΔV=Ed\Delta V = Ed. Potential difference in uniform field over distance dd.

Flashcard 55: State what happens to potential energy when a charge moves with the field.

Answer: Decreases. Field does positive work, reducing potential energy.

Flashcard 56: State the formula for electric potential energy in a uniform electric field.

Answer: U=qEdU = qEd. Energy stored in charge within uniform electric field.

Flashcard 57: How does electric potential energy change with distance in a uniform field?

Answer: Decreases with distance. Energy decreases as charge moves with field direction.

Flashcard 58: State the formula for electric potential energy in a uniform electric field.

Answer: U=qEdU = qEd. Energy stored in charge within uniform electric field.

Flashcard 59: How does electric potential vary with distance from a point charge?

Answer: Inversely proportional. Potential follows inverse square law like electric field.

Flashcard 60: Identify the relationship between work done and electric potential energy.

Answer: W=ΔUW = -\Delta U. Work done equals negative change in potential energy.

Flashcard 61: Identify the relationship between electric field strength and potential difference.

Answer: E=ΔVdE = -\frac{\Delta V}{d}. Electric field is negative gradient of potential.

Flashcard 62: State the principle of conservation of electric energy.

Answer: Total electric energy remains constant in an isolated system. Fundamental principle: energy cannot be created or destroyed.

Flashcard 63: Calculate the potential energy for q=3Cq = 3C and V=2VV = -2V.

Answer: U=6 JU = -6 \text{ J}. Using U=qV=3×(2)=6U = qV = 3 \times (-2) = -6 J.

Flashcard 64: What is the effect of increasing charge on electric potential energy?

Answer: It increases linearly. Potential energy is directly proportional to charge.

Flashcard 65: What is the potential energy of a charge in a field with zero potential difference?

Answer: Zero. No potential difference means no stored energy.

Flashcard 66: What quantity does the symbol UU represent in electric energy equations?

Answer: Electric potential energy. Standard symbol for electric potential energy in physics.

Flashcard 67: Define the term 'electric potential'.

Answer: Work done per unit charge to move a charge from infinity. Potential is work per unit charge from reference point.

Flashcard 68: Which physical quantity is conserved in an isolated electric system?

Answer: Electric energy. Total electric energy remains constant in isolated systems.

Flashcard 69: Calculate the potential energy for q=3Cq = 3C and V=2VV = -2V.

Answer: U=6 JU = -6 \text{ J}. Using U=qV=3×(2)=6U = qV = 3 \times (-2) = -6 J.

Flashcard 70: How does electric potential energy change with distance in a uniform field?

Answer: Decreases with distance. Energy decreases as charge moves with field direction.

Flashcard 71: What is the formula for the potential energy of a dipole in an electric field?

Answer: U=pEcosθU = -pE \cos \theta. Energy depends on dipole moment and field alignment.

Flashcard 72: Identify what must be true for electric energy conservation in a circuit.

Answer: Closed circuit, no external work. Requirements for energy conservation in electrical systems.

Flashcard 73: State the expression for the electric potential difference in a uniform field.

Answer: ΔV=Ed\Delta V = Ed. Potential difference in uniform field over distance dd.

Flashcard 74: What is the relationship between electric potential and potential energy?

Answer: U=qVU = qV. Potential energy equals charge times electric potential.