AP Chemistry › Laboratory Techniques and Analysis
A scientist wants to separate and purify a small, positively charged protein. Which of the following techniques might be employed to accomplish this task?
Size exclusion chromatography and cation exchange chromatography
Reverse phase chromatography
Normal phase chromatography
Thin layer chromatography
None of these
Size exclusion chromatography is a good technique for separating proteins based on size due to tiny pores in the beads in the column (the smaller proteins will elute out last). Cation exchange chromatography is a good technique for separating proteins based on charge due to negatively charged beads in the column (the positively charged molecules will elute out last). Normal and reverse phase chromatography are methods of separation based on a molecule's polarity; in normal phase chromatography, a nonpolar mobile phase is employed so that polar, hydrophilic molecules elute last. The opposite is true for reverse phase chromatography - a polar, aqueous mobile phase is used and any nonpolar molecules tend to adsorb to the hydrophobic beads, causing them to elute out last. Thin layer chromatography is not a good method of purifying substances, rather, it is a better indicator of reaction progress via elucidation of the retardation factor, .
In reverse phase chromatography, the more __________ molecules will be eluted __________.
hydrophobic . . . last
hydrophobic . . . first
hydrophilic . . . last
More than one of these
None of these answers
In reverse phase chromatography, the more hydrophobic molecules will be eluted last (the more hydrophilic molecules will be eluted first). This is due to the mobile phase being polar, and thus the nonpolar/hydrophobic molecules adsorbing to the stationary phase. The opposite is true in normal phase chromatography - this technique employs a nonpolar mobile phase and a polar stationary phase. The polar stationary phase will attract polar molecules, and thus the nonpolar molecules will be eluted first along with the nonpolar/hydrophobic mobile phase.
A scientist wants to separate and purify a small, positively charged protein. Which of the following techniques might be employed to accomplish this task?
Size exclusion chromatography and cation exchange chromatography
Reverse phase chromatography
Normal phase chromatography
Thin layer chromatography
None of these
Size exclusion chromatography is a good technique for separating proteins based on size due to tiny pores in the beads in the column (the smaller proteins will elute out last). Cation exchange chromatography is a good technique for separating proteins based on charge due to negatively charged beads in the column (the positively charged molecules will elute out last). Normal and reverse phase chromatography are methods of separation based on a molecule's polarity; in normal phase chromatography, a nonpolar mobile phase is employed so that polar, hydrophilic molecules elute last. The opposite is true for reverse phase chromatography - a polar, aqueous mobile phase is used and any nonpolar molecules tend to adsorb to the hydrophobic beads, causing them to elute out last. Thin layer chromatography is not a good method of purifying substances, rather, it is a better indicator of reaction progress via elucidation of the retardation factor, .
In reverse phase chromatography, the more __________ molecules will be eluted __________.
hydrophobic . . . last
hydrophobic . . . first
hydrophilic . . . last
More than one of these
None of these answers
In reverse phase chromatography, the more hydrophobic molecules will be eluted last (the more hydrophilic molecules will be eluted first). This is due to the mobile phase being polar, and thus the nonpolar/hydrophobic molecules adsorbing to the stationary phase. The opposite is true in normal phase chromatography - this technique employs a nonpolar mobile phase and a polar stationary phase. The polar stationary phase will attract polar molecules, and thus the nonpolar molecules will be eluted first along with the nonpolar/hydrophobic mobile phase.
Which choice of lab equipment is never used to make accurate volume measurements?
Beaker
Graduated cylinder
Burette
Volumetric flask
Graduated cylinders are often used for measuring volumetric quantities. As these have several markings, they are considered accurate. Volumetric flasks are also used to accurately measure liquid volume quantities. Lastly, burettes are used to accurately measure volumes of liquid during titrations.
In contrast, beakers are not typically used to measure accurate quantities of liquid; though they have markings on them, these are approximate measurements. Graduated cylinders are often used to accurately measure out a liquid, and beakers to then hold the liquid.
A chemistry student is trying to identify the reaction order for a reaction based on her interpretation of the above graph. The student identifies the reaction as a first-order reaction. Is this student correct in their conclusion? Why?
Yes. A graph of the natural logarithm of the concentration of a reactant versus time yields a straight line with a negative slope for a first-order reaction.
Yes. Regardless of the order of the reaction, a graph of the natural logarithm of the concentration of a reactant versus time will always yield a straight line with a negative slope.
No. A graph of the natural logarithm of the concentration of a reactant versus time yields a straight line with a negative slope for a zeroth-order reaction.
No. A graph of the natural logarithm of the concentration of a reactant versus time yields a straight line with a negative slope for a second-order reaction.
Additional information is necessary in order to determine whether the graph corresponds to a first-order reaction.
A first-order reaction can be expressed in different ways. One way is the following:
where:
= concentration of reactant at a given time,
= initial concentration of reactant at time
= rate constant of the reaction
= amount of time that has passed since the start of the reaction
By taking the natural logarithm of both sides, we can obtain an alternative form of the equation, expressed as:
This second equation is useful for graphing, because it fits the general equation of . In this case,
represents the
-axis,
represents the
-axis,
represents the
-intercept, and
represents the slope. Thus, the graph in the question stem is indeed indicative of a first-order reaction.
In the case of a zeroth-order reaction, the equation is:
Therefore, for a zeroth-order reaction, a straight line with a negative slope will only result from a graph of the concentration of a reactant versus time.
And lastly, in the case of a second-order reaction, the equation is:
Hence, a graph of the inverse concentration of a reactant versus time will yield a straight line with a positive slope, and this is indicative of a second-order reaction.
If a solution of water has a pressure of 200atm and a temperature of 474 degrees Celsius, what changes could be made to bring the sample to its critical point?
Increase the pressure and decrease the temperature
Increase the pressure and increase the temperature
Decrease the pressure and increase the temperature
Decrease the pressure and decrease the temperature
The critical point cannot be reached from these starting conditions
The critical point for water is at 218atm and 374 degrees Celcius, but on this graph it can be found at the end of the line between the gas and liquid portions of the water phase graph (you can see it end with a dot). This means we need to increase our pressure and decrease our temperature in order to reach the critical point from our initial conditions.
If a solution of water has a pressure of 200atm and a temperature of 474 degrees Celsius, what changes could be made to bring the sample to its critical point?
Increase the pressure and decrease the temperature
Increase the pressure and increase the temperature
Decrease the pressure and increase the temperature
Decrease the pressure and decrease the temperature
The critical point cannot be reached from these starting conditions
The critical point for water is at 218atm and 374 degrees Celcius, but on this graph it can be found at the end of the line between the gas and liquid portions of the water phase graph (you can see it end with a dot). This means we need to increase our pressure and decrease our temperature in order to reach the critical point from our initial conditions.
A chemistry student is trying to identify the reaction order for a reaction based on her interpretation of the above graph. The student identifies the reaction as a first-order reaction. Is this student correct in their conclusion? Why?
Yes. A graph of the natural logarithm of the concentration of a reactant versus time yields a straight line with a negative slope for a first-order reaction.
Yes. Regardless of the order of the reaction, a graph of the natural logarithm of the concentration of a reactant versus time will always yield a straight line with a negative slope.
No. A graph of the natural logarithm of the concentration of a reactant versus time yields a straight line with a negative slope for a zeroth-order reaction.
No. A graph of the natural logarithm of the concentration of a reactant versus time yields a straight line with a negative slope for a second-order reaction.
Additional information is necessary in order to determine whether the graph corresponds to a first-order reaction.
A first-order reaction can be expressed in different ways. One way is the following:
where:
= concentration of reactant at a given time,
= initial concentration of reactant at time
= rate constant of the reaction
= amount of time that has passed since the start of the reaction
By taking the natural logarithm of both sides, we can obtain an alternative form of the equation, expressed as:
This second equation is useful for graphing, because it fits the general equation of . In this case,
represents the
-axis,
represents the
-axis,
represents the
-intercept, and
represents the slope. Thus, the graph in the question stem is indeed indicative of a first-order reaction.
In the case of a zeroth-order reaction, the equation is:
Therefore, for a zeroth-order reaction, a straight line with a negative slope will only result from a graph of the concentration of a reactant versus time.
And lastly, in the case of a second-order reaction, the equation is:
Hence, a graph of the inverse concentration of a reactant versus time will yield a straight line with a positive slope, and this is indicative of a second-order reaction.
If a solution of water has a pressure of 200atm and a temperature of 474 degrees Celsius, what changes could be made to bring the sample to its critical point?
Increase the pressure and decrease the temperature
Increase the pressure and increase the temperature
Decrease the pressure and increase the temperature
Decrease the pressure and decrease the temperature
The critical point cannot be reached from these starting conditions
The critical point for water is at 218atm and 374 degrees Celcius, but on this graph it can be found at the end of the line between the gas and liquid portions of the water phase graph (you can see it end with a dot). This means we need to increase our pressure and decrease our temperature in order to reach the critical point from our initial conditions.