AP Chemistry › Chemical Reactions
What is the coefficient for oxygen gas when the following equation is balanced?
The balanced reaction for the combustion of pentane is:
When balanced, oxygen gas has a coefficient of eight.
To balance the equation, it is easiest to leave oxygen and hydrogen for last. This means we should start with carbon.
Now that carbon is balanced, we can look at hydrogen.
Finally, we can balance the oxygen.
The final reaction uses five carbon atoms, twelve hydrogen atoms, and sixteen oxygen atoms per side.
Consider the following balanced equation for the solubility of barium hydroxide in an aqueous solution.
What is the equilibrium expression for the balanced reaction?
When writing the equilibrium expression for an insoluble salt, remember that pure solids and liquids are not included in the expression. Also, the coefficients for the compounds in the balanced reaction become the exponents for the compounds in the equilibrium expression.
Given a generalized chemical reaction, we can determine the equilibrium constant expression.
In our reaction, the reactant is a pure solid and is not included in the equilibrium calculation.
Which of the following describes an oxidation-reduction reaction?
The transfer of electrons between species, and the subsequent changes in oxidation states
A reaction in which one species molecule is oxidized then reduced
A type of chemical reaction that always involves acids and bases
None of these
A type of reaction in which one reactant is broken down into two products
In an oxidation reaction, one species is oxidized (loses electrons). During a reduction reaction, one species is reduced (gains electrons). These transfers of electrons results in the change of oxidation states. One way to help you remember which reaction is which, is by using the mnemonic: OIL RIG - Oxidation Is Loss of electrons; Reduction Is Gain of electrons.
Consider the following reaction:
What is the equilibrium constant for this reaction?
When writing the equilibrium expression for a reaction, remember that the products are on the top of the expression and the reactants are on the bottom. Any coefficients in the balanced reaction become the exponents in the equilibrium constant.
A general formula and corresponding equilibrium expression are given here:
Our equation has only one product, but follows the same format.
Note that pure solids and liquids are not included in the equilibrium expression, but pure gases (such as nitrogen) are. This is because the pressure of pure gases can affect equilibrium, but manipulating pure solids or liquids cannot.
What is the type of reaction seen below?
Double-replacement
Single-replacement
Addition
Decomposition
By looking at the reaction, we see that the cations for the reactants have their anions switched in the products. This means that the reaction follows the general outline:
This is an example of a double-replacement reaction.
Addition reactions convert two reactants to a single product, while decomposition reactions convert a single reactant to multiple products. Single-replacement reactions only switch one cation-anion pair.
Determine which compound or ion is the oxidizing agent in the given reaction.
The oxidizing agent is the element that causes the other element to be oxidized, and is itself being reduced in the equation. Reduction is defined as the gain of electrons, meaning the element would get "more negative."
In this reaction, aluminum transitions from an oxidation state of 3+ to an oxidation state of 0. This indicates a reduction, as the atom has gained more electrons and reduced charge. is thus the oxidizing agent in this reaction.
Predict the products for the following reaction if it were double displacement.
In a double displacement reaction, or double replacement reaction, opposite ions combine. What this means is that the cation of one compound will recombine and bond to the anion of the other compound and vice versa.
In this example, we have to remember the ideal convention of cations being written before the anion in the compound. So in AB, we can presume A being the cation and B being the anion. The same goes for CD - C is the cation and D is the anion.
With this in mind, we can now easily see how the replacement would be possible.
If A is a cation, and was originally bound to B (anion), the only other anion it is left with to bind is D. If C is a cation, and was originally bound to D (anion), it is only left with the option of binding to the now-free B anion.
That's why it is:
Which of the following factors will change the equilibrium constant, Keq?
Change in temperature
Change in solvent volume
Introducing additional reactants
Introducing additional products
Adding a chemical that will cause side reactions
The only factor that changes the equilibrium constant is temperature. Changes in concentration of reactants or products by any means (whether addition, taking away solvent, or adding a chemical that will cause side reactions) will remove the system from equilibrium, but will not change the equilibrium constant.
Consider the following balanced reaction:
What is the equilibrium expression for this reaction?
When writing the equilibrium expression for a reaction, remember that the products are on the top of the expression and the reactants are on the bottom. Any coefficients in the balanced reaction become the exponents in the equilibrium constant.
A general formula and corresponding equilibrium expression are given here:
Our equation follows the same format. Note, however, that pure solids and liquids are not included in the equilibrium expression, but pure gases (such as hydrogen) are. This is because the pressure of pure gases can affect equilibrium, but manipulating pure solids or liquids cannot.
If the equilibrium constant lies farther to the right, this indicates that the reaction __________.
is more complete
is less complete
does not have a bearing on the reaction
includes a catalyst
The equilibrium constant is given by the concentraton of products over the concentration of reactants. If it lies to the right, it means that it favors the forward reaction, and thus the reaction is "more complete" or closer to completion.