Study Stoichiometry in AP Chemistry with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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Flashcard 1: What is the first step in a stoichiometry problem?
Answer: Write a balanced chemical equation. Ensures atom conservation for stoichiometric calculations.
Flashcard 2: What is the formula to calculate the number of particles from moles?
Answer: particles=moles×6.022×1023. Multiplies moles by Avogadro's number for particle count.
Flashcard 3: How many moles of H2 are needed to produce 2 moles of NH3 in N2+3H2→2NH3?
Answer: 3 moles. 3:2 mole ratio from balanced equation coefficients.
Flashcard 4: Calculate the percent composition of oxygen in H2O.
Answer: 88.81%. Oxygen mass (16) divided by H2O mass (18) ×100%.
Flashcard 5: Find the molar mass of CO2.
Answer: 44 g/mol. Carbon (12) + 2 oxygen atoms (16 each) = 44 g/mol.
Flashcard 6: Identify the unit for molar mass.
Answer: grams per mole (g/mol). Standard unit expressing mass per mole of substance.
Flashcard 7: Which unit is used to express concentration in stoichiometry?
Answer: Molarity (M). Standard concentration unit for solution calculations.
Flashcard 8: What is the formula for percent yield?
Answer: Percent yield=theoretical yieldactual yield×100. Compares actual to theoretical yield as a percentage.
Flashcard 9: Calculate the percent composition of oxygen in H2O.
Answer: 88.81%. Oxygen mass (16) divided by H2O mass (18) × 100%.
Flashcard 10: Calculate the molarity of a solution with 10 moles in 5 L.
Answer: 2 M. 5 L10 moles=2 M concentration.
Flashcard 11: Identify the limiting reactant in 4 moles N2 and 10 moles H2 for N2+3H2→2NH3.
Answer: H2. Need 12 moles H2 but only have 10; H2 limits.
Flashcard 12: What is the stoichiometric coefficient for H2 in 2H2+O2→2H2O?
Answer:
- Coefficient shows 2 molecules react in balanced equation.
Flashcard 13: What is the molar mass of H2SO4?
Answer: 98.1 g/mol. 2H (2) + S (32) + 4O (64) = 98 g/mol total.
Flashcard 14: Which unit is used to express concentration in stoichiometry?
Answer: Molarity (M). Standard concentration unit for solution calculations.
Flashcard 15: What is the molecular formula for a compound with empirical formula CH2O and molar mass 180 g/mol?
Answer: C6H12O6. 180÷30=6, so multiply CH2O by 6.
Flashcard 16: What is the molecular formula for a compound with empirical formula CH2O and molar mass 180 g/mol?
Answer: C6H12O6. 180÷30=6, so multiply CH2O by 6.
Flashcard 17: What is the concentration of a solution with 5 moles of solute in 2 L of solution?
Answer: 2.5 M. 2 L5 moles=2.5 M concentration.
Flashcard 18: What is the first step in a stoichiometry problem?
Answer: Write a balanced chemical equation. Ensures atom conservation for stoichiometric calculations.
Flashcard 19: Determine the empirical formula for a compound with 40% carbon, 6.7% hydrogen, and 53.3% oxygen.
Answer: CH2O. Convert percentages to moles, then find simplest ratio.
Flashcard 20: What is the excess reactant in 2H2+O2→2H2O with 5 moles H2 and 2 moles O2?
Answer: O2. Remains after limiting reactant is completely consumed.
Flashcard 21: Determine the limiting reactant in 2H2+O2→2H2O given 5 moles H2 and 2 moles O2.
Answer: H2. Needs 2.5 moles O2, but only 2 available, so H2 limits.
Flashcard 22: How is actual yield different from theoretical yield?
Answer: Actual yield is the measured amount of product obtained. Theoretical assumes perfect conditions; actual is experimental.
Flashcard 23: How is theoretical yield calculated?
Answer: Use stoichiometry from the balanced equation. Assumes complete reaction with limiting reactant consumed.
Flashcard 24: What is the formula to calculate the number of particles from moles?
Answer: particles=moles×6.022×1023. Multiplies moles by Avogadro's number for particle count.
Flashcard 25: Find the moles of H2O in 36 grams.
Answer: 2 moles. 36÷18=2 using H2O molar mass of 18 g/mol.
Flashcard 26: What is the stoichiometric coefficient for H2 in 2H2+O2→2H2O?
Answer:
- Coefficient shows 2 molecules react in balanced equation.
Flashcard 27: Identify the limiting reactant in 4 moles N2 and 10 moles H2 for N2+3H2→2NH3.
Answer: H2. Need 12 moles H2 but only have 10; H2 limits.
Flashcard 28: How do you calculate mass from moles?
Answer: mass (g)=moles×molar mass (g/mol). Multiplies moles by molar mass to get mass in grams.
Flashcard 29: Find the volume of gas at STP for 1 mole.
Answer: 22.4 L. Standard molar volume at 0°C and 1 atm pressure.
Flashcard 30: What is the percent yield if the theoretical yield is 100g and actual yield is 80g?
Answer: 80%. 10080×100%=80% efficiency.
Flashcard 31: Calculate the number of molecules in 2 moles of H2.
Answer: 1.204×1024 molecules. 2×6.022×1023 molecules per mole.
Flashcard 32: What is the molar mass of H2SO4?
Answer: 98.1 g/mol. 2H (2) + S (32) + 4O (64) = 98 g/mol total.
Flashcard 33: Convert 3 moles of NaCl to grams.
Answer: 175.5 grams. 3×58.5=175.5 using NaCl molar mass.
Flashcard 34: Calculate the percent composition of oxygen in H2O.
Answer: 88.81%. Oxygen mass (16) divided by H2O mass (18) × 100%.
Flashcard 35: How do you calculate mass from moles?
Answer: mass (g)=moles×molar mass (g/mol). Multiplies moles by molar mass to get mass in grams.
Flashcard 36: What is the stoichiometric coefficient for H2 in 2H2+O2→2H2O?
Answer:
- Coefficient shows 2 molecules react in balanced equation.
Flashcard 37: Determine the empirical formula for a compound with 40% carbon, 6.7% hydrogen, and 53.3% oxygen.
Answer: CH2O. Convert percentages to moles, then find simplest ratio.
Flashcard 38: Determine the moles of NaOH needed to neutralize 1 mole of HCl.
Answer: 1 mole. 1:1 mole ratio from balanced acid-base equation.
Flashcard 39: Determine the limiting reactant in 2H2+O2→2H2O given 5 moles H2 and 2 moles O2.
Answer: H2. Needs 2.5 moles O2, but only 2 available, so H2 limits.
Flashcard 40: Define molar mass.
Answer: The mass of one mole of a substance in grams. Equals the atomic/molecular weight expressed in g/mol.
Flashcard 41: State Avogadro's number.
Answer: 6.022×1023. The number of particles in one mole of any substance.
Flashcard 42: Find the volume of gas at STP for 1 mole.
Answer: 22.4 L. Standard molar volume at 0°C and 1 atm pressure.
Flashcard 43: What is the first step in a stoichiometry problem?
Answer: Write a balanced chemical equation. Ensures atom conservation for stoichiometric calculations.
Flashcard 44: What is the molecular formula for a compound with empirical formula CH2O and molar mass 180 g/mol?
Answer: C6H12O6. 180÷30=6, so multiply CH2O by 6.
Flashcard 45: Calculate the mass of 0.5 moles of C6H12O6.
Answer: 90 grams. 0.5×180=90 using glucose molar mass.
Flashcard 46: How is theoretical yield calculated?
Answer: Use stoichiometry from the balanced equation. Assumes complete reaction with limiting reactant consumed.
Flashcard 47: What is the concentration of a solution with 5 moles of solute in 2 L of solution?
Answer: 2.5 M. 2 L5 moles=2.5 M concentration.
Flashcard 48: Identify the unit for molar mass.
Answer: grams per mole (g/mol). Standard unit expressing mass per mole of substance.
Flashcard 49: Find the moles of H2O in 36 grams.
Answer: 2 moles. 36÷18=2 using H2O molar mass of 18 g/mol.
Flashcard 50: What is the excess reactant in 2H2+O2→2H2O with 5 moles H2 and 2 moles O2?
Answer: O2. Remains after limiting reactant is completely consumed.
Flashcard 51: How do you calculate mass from moles?
Answer: mass (g)=moles×molar mass (g/mol). Multiplies moles by molar mass to get mass in grams.
Flashcard 52: Determine the moles of NaOH needed to neutralize 1 mole of HCl.
Answer: 1 mole. 1:1 mole ratio from balanced acid-base equation.
Flashcard 53: Convert 0.25 moles of Mg to atoms.
Answer: 1.505×1023 atoms. 0.25×6.022×1023 atoms per mole.
Flashcard 54: Calculate the number of molecules in 2 moles of H2.
Answer: 1.204×1024 molecules. 2×6.022×1023 molecules per mole.
Flashcard 55: What is empirical formula?
Answer: The simplest whole-number ratio of atoms. Shows simplest ratio without molecular complexity.
Flashcard 56: What is the percent yield if the theoretical yield is 100g and actual yield is 80g?
Answer: 80%. 10080×100%=80% efficiency.
Flashcard 57: Which unit is used to express concentration in stoichiometry?
Answer: Molarity (M). Standard concentration unit for solution calculations.
Flashcard 58: Find the moles of H2O in 36 grams.
Answer: 2 moles. 36÷18=2 using H2O molar mass of 18 g/mol.
Flashcard 59: What is the formula for molarity?
Answer: Molarity (M)=liters of solutionmoles of solute. Relates amount of solute to solution volume.
Flashcard 60: Convert 3 moles of NaCl to grams.
Answer: 175.5 grams. 3×58.5=175.5 using NaCl molar mass.
Flashcard 61: Calculate the volume at STP for 0.5 moles of gas.
Answer: 11.2 L. 0.5×22.4=11.2 liters at STP.
Flashcard 62: Find the molar mass of CO2.
Answer: 44 g/mol. Carbon (12) + 2 oxygen atoms (16 each) = 44 g/mol.
Flashcard 63: Convert 3 moles of NaCl to grams.
Answer: 175.5 grams. 3×58.5=175.5 using NaCl molar mass.
Flashcard 64: Calculate the mass of 0.5 moles of C6H12O6.
Answer: 90 grams. 0.5×180=90 using glucose molar mass.
Flashcard 65: What is the formula to calculate the number of moles from mass?
Answer: moles=molar mass (g/mol)mass (g). Divides mass by molar mass to find amount in moles.
Flashcard 66: What is empirical formula?
Answer: The simplest whole-number ratio of atoms. Shows simplest ratio without molecular complexity.
Flashcard 67: Determine the limiting reactant in 2H2+O2→2H2O given 5 moles H2 and 2 moles O2.
Answer: H2. Needs 2.5 moles O2, but only 2 available, so H2 limits.
Flashcard 68: What is the concentration of a solution with 5 moles of solute in 2 L of solution?
Answer: 2.5 M. 2 L5 moles=2.5 M concentration.
Flashcard 69: Calculate the mass of 0.5 moles of C6H12O6.
Answer: 90 grams. 0.5×180=90 using glucose molar mass.
Flashcard 70: How is actual yield different from theoretical yield?
Answer: Actual yield is the measured amount of product obtained. Theoretical assumes perfect conditions; actual is experimental.
Flashcard 71: How many moles of H2 are needed to produce 2 moles of NH3 in N2+3H2→2NH3?
Answer: 3 moles. 3:2 mole ratio from balanced equation coefficients.
Flashcard 72: How is theoretical yield calculated?
Answer: Use stoichiometry from the balanced equation. Assumes complete reaction with limiting reactant consumed.
Flashcard 73: Identify the unit for molar mass.
Answer: grams per mole (g/mol). Standard unit expressing mass per mole of substance.
Flashcard 74: Find the volume of gas at STP for 1 mole.
Answer: 22.4 L. Standard molar volume at 0°C and 1 atm pressure.
Flashcard 75: Determine the empirical formula for a compound with 40% carbon, 6.7% hydrogen, and 53.3% oxygen.
Answer: CH2O. Convert percentages to moles, then find simplest ratio.
Flashcard 76: Find the volume of 3 moles of gas at STP.
Answer: 67.2 L. 3×22.4=67.2 liters at standard conditions.
Flashcard 77: Identify the unit for molar mass.
Answer: grams per mole (g/mol). Standard unit expressing mass per mole of substance.
Flashcard 78: What is the formula for molarity?
Answer: Molarity (M)=liters of solutionmoles of solute. Relates amount of solute to solution volume.
Flashcard 79: How is theoretical yield calculated?
Answer: Use stoichiometry from the balanced equation. Assumes complete reaction with limiting reactant consumed.
Flashcard 80: What is the excess reactant in 2H2+O2→2H2O with 5 moles H2 and 2 moles O2?
Answer: O2. Remains after limiting reactant is completely consumed.
Flashcard 81: What is the excess reactant in 2H2+O2→2H2O with 5 moles H2 and 2 moles O2?
Answer: O2. Remains after limiting reactant is completely consumed.
Flashcard 82: How do you calculate mass from moles?
Answer: mass (g)=moles×molar mass (g/mol). Multiplies moles by molar mass to get mass in grams.
Flashcard 83: What is the molecular formula for a compound with empirical formula CH2O and molar mass 180 g/mol?
Answer: C6H12O6. 180÷30=6, so multiply CH2O by 6.
Flashcard 84: Determine the moles of NaOH needed to neutralize 1 mole of HCl.
Answer: 1 mole. 1:1 mole ratio from balanced acid-base equation.
Flashcard 85: Determine the empirical formula for a compound with 50% sulfur and 50% oxygen by mass.
Answer: SO2. Equal mass percentages give 1:2 atomic ratio S:O.
Flashcard 86: Identify the limiting reactant in 4 moles N2 and 10 moles H2 for N2+3H2→2NH3.
Answer: H2. Need 12 moles H2 but only have 10; H2 limits.
Flashcard 87: What is the formula for percent yield?
Answer: Percent yield=theoretical yieldactual yield×100. Compares actual to theoretical yield as a percentage.
Flashcard 88: Determine the limiting reactant in 2H2+O2→2H2O given 5 moles H2 and 2 moles O2.
Answer: H2. Needs 2.5 moles O2, but only 2 available, so H2 limits.
Flashcard 89: What is the formula to calculate the number of moles from mass?
Answer: moles=molar mass (g/mol)mass (g). Divides mass by molar mass to find amount in moles.
Flashcard 90: What is the stoichiometric coefficient for H2 in 2H2+O2→2H2O?
Answer:
- Coefficient shows 2 molecules react in balanced equation.
Flashcard 91: What is the formula for molarity?
Answer: Molarity (M)=liters of solutionmoles of solute. Relates amount of solute to solution volume.
Flashcard 92: What is the formula to calculate the number of particles from moles?
Answer: particles=moles×6.022×1023. Multiplies moles by Avogadro's number for particle count.
Flashcard 93: How many grams of O2 are needed to react with 4 moles of C in C+O2→CO2?
Answer: 128 grams. 4×32=128 grams using 1:1 mole ratio.
Flashcard 94: What is the formula to calculate the number of moles from mass?
Answer: moles=molar mass (g/mol)mass (g). Divides mass by molar mass to find amount in moles.
Flashcard 95: How many moles of H2 are needed to produce 2 moles of NH3 in N2+3H2→2NH3?
Answer: 3 moles. 3:2 mole ratio from balanced equation coefficients.
Flashcard 96: What is empirical formula?
Answer: The simplest whole-number ratio of atoms. Shows simplest ratio without molecular complexity.
Flashcard 97: What is the percent yield if the theoretical yield is 100g and actual yield is 80g?
Answer: 80%. 10080×100%=80% efficiency.
Flashcard 98: Calculate the mass of 0.5 moles of C6H12O6.
Answer: 90 grams. 0.5×180=90 using glucose molar mass.
Flashcard 99: State Avogadro's number.
Answer: 6.022×1023. The number of particles in one mole of any substance.
Flashcard 100: What is the formula for molarity?
Answer: Molarity (M)=liters of solutionmoles of solute. Relates amount of solute to solution volume.