Calculating Higher-Order Derivatives Practice Test

$f''(x)=rac{1}{4}(1+x)^{-3/2}$

$f''(x)=-rac{3}{4}(1+x)^{-5/2}$

$f''(x)=rac{1}{2}(1+x)^{-1/2}$

$f''(x)=-rac{1}{2}(1+x)^{-1/2}$

$f''(x)=-rac{1}{4}(1+x)^{-3/2}$