When adding with another negative number, just treat as an addition problem and then add a negative sign in front. Our answer is .

There are many ways to think about solving integer equatons. This one is equivalent to , which equals .

Add the ones digit.

Carry over the 1 since 11 is ten or greater, and then add the tens digit with the carryover.

Repeat the process for the hundreds digit with the carry over.

Combine all the digits.

The answer is .

To solve , first add the ones digit.

The ones digit is 4. Since 14 is ten or greater, carry the tens digit to the next number.

Add the tens digit with the one carried over.

The tens digit is 1. Since 11 is ten or greater, carry the tens digit to the next number. There are no hundreds digit with 98. Add both the thousands and hundreds digit to the carry over.

Combine this with the tens and ones digits.

The answer is:

Add the ones digits.

The ones digit of the final answer is 2. The carryover is the tens place since this number is 10 or greater.

Add the tens digits with the carryover.

The tens digit of the final answer is 4. The carryover is the tens place.

Add the hundreds digits with the carryover. The hundreds digit of 19 is zero.

Combine all the numbers.

The answer is:

Add the ones digits.

Since there is a tens place, this number will be the carryover.

Combine the numbers.

The answer is:

Find the sum of seven hundred and fifty-six.

Begin by recalling what sum means.

Sum means addition, so we need to add:

Now, because we hav 0's in our ones and tens places, we can simply tack on the 56 to get

Add the ones place.

Add the tens place.

Combine the tens and ones places.

The answer is .

Since is greater than and is negative, our answer is negative. We treat as a normal subtraction. Answer is .

This is just a simple addition problem. The sum of and is .